3. The complex ion Co(H2O)6 2(aq) is pink when placed in solution. Addition of chloride ions creates an equilibrium with CoCl42- in the solution, which is blue in color. Write the balanced equation for the equilibrium. If CoCl42- solubility is endothermic, predict what will happen to the solution color if the solution is heated. What will happen if the solution is cooled

Answer:

They are symbols of elements.

Ra is the symbol of the element Radium

Ah is the symbol of the element Arrhenium

Ma  is the symbol of the element Molybdenum

Ga  is the symbol of the element Gallium

La  is the symbol of the element Lanthanum

Answer:

Ra is the symbol of the element Radium

Ah is the symbol of the element Arrhenium

Ma  is the symbol of the element Molybdenum

Ga  is the symbol of the element Gallium

La  is the symbol of the element Lanthanum

Explanation:

They are elements

Answer:

[tex]m_{Ag}=135.8gAg[/tex]

[tex]Y=88.4\%[/tex]

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

[tex]m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\ m_{Ag}=135.8gAg[/tex]

Next, given the actual yield of 120 g, we compute the percent yield via:

[tex]Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%[/tex]

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Answer:

2)

[tex]\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%[/tex]

3)

[tex]\% Ag=93.1\%\\\\\% O=6.9\%[/tex]

Explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

[tex]\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%[/tex]

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

[tex]\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%[/tex]

Best regards!

Explanation:

as the Hydrogen (acid) ion decreases there is a corresponding increase in the Hydroxide (basic) ion.

Answer:

Less in the top

your well wisher

Answer:

83.7% oxygen, 16.3% hydrogen

Explanation:

Mass of compound = 16.75 g

Mass of Oxygen = 14.02 g

Mass of Hydrogen =  2.73 g

Percentage composition = Mass of element /  Mass of compound    100%

Percentage composition of Oxygen = 14.02 g / 16.75 g    * 100%

Percentage composition of Oxygen = 0.837 * 100 = 83.7%

Percentage composition of Hydrogen = 2.73 g / 16.75 g    * 100%

Percentage composition of Hydrogen = 0.163 * 100 = 16.3%

The correct option is;

83.7% oxygen, 16.3% hydrogen

Answer:

83.7% oxygen, 16.3% hydrogen

Explanation:

To determine the percent composition we can divide, our mass by total mass and afterwards, multiply by 100.

(Mass of O / Total mass) . 100 = % O

(Mass of H / Total mass) . 100 = % H

Remember that:

% O + % H = 100

Mass of O / Total mass + Mass of H / Total mass = 1

(14.02 g / 16.75g) . 100 = 83.7 %

(2.73 g /16.75g) . 100 = 16.3 %

Answer: B. It must show that the mass of each element involved is conserved  by a chemical reaction.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The correct statement why a chemical equation must be balanced is It must show that the mass of each element involved is conserved  by a chemical reaction.

Answer:

B. It must show that the mass of each element involved is conserved

by a chemical reaction.

Explanation:

a p e x, just took the quiz

Answer:

Zn + 2HCl → ZnCl₂ + H₂

Explanation:

First we write the equation using the molecular formulas instead of words:

We know zinc chloride is ZnCl₂ as the problem tells us the oxidation state of zinc in the products is +2, and chloride means Cl⁻¹.

Now we proceed to balance the reaction:

There are 2 Cl atoms and 2 H atoms on the right side, so we add a coefficient of 2 to HCl on the left side:

Answer:

Gravitational potential energy depends on basically two factor;

Explanation:

The distances between both the bodies, as well as the mass within each object, are factors that influence gravitational potential energy.

Answer:

K^2O

Explanation:

I remember a question like this one and I got it right its K^2O

(aka its C)

Answer:

zoo wee mama

Explanation:

The particles that make up an object are held together by bonds. Insulators have strong bonds that hold their particles rigidly in place. This prevents particles from gaining energy and increasing the temperature. Wool, dry air, plastics, and polystyrene foam are all examples of good insulators.

Answer:

4.4 mol.

Explanation:

Hello!

In this case, since the formula for calculating the molarity is:

[tex]M=n/V[/tex]

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

[tex]n=V*M[/tex]

Thus, we plug in the given data to obtain:

[tex]n=2.5L*1.75mol/L=4.4mol[/tex]

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Answer:

4.4 mol.

Explanation:

Have a great day

Answer:

Deer, Eagle, Raccoon, frog, turtle, fish, dragonfly.

Explanation:

They interact from the life cycle they eat each other...

Answer:

0.500-Molarity solution

Explanation:

The moles of the compound is given as the number of atomic mass unit in the compound. The moles of potassium nitrate in the solution are 0.6 mol

The molarity is the concentration unit, and it can be defined as the moles of compound present in the liter of solution.

The molarity can be expressed as:

[tex]\rm Molarity=\dfrac{Moles}{Volume(L)}[/tex]

The given potassium nitrate solution has, molarity = 2 M

The volume of the solution is 0.3 L.

Substituting the values for the moles of the compound:

[tex]\rm 2\;M=\dfrac{Moles}{0.3\;L} \\\\Moles=2\;\times\;0.3\;mol\\Moles=0.6\;mol[/tex]

The moles of potassium nitrate in 2 M solution is 0.6 mol.

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Answer: 22.3 *10^23 S atoms

Explanation:

Answer:

it should be C. the filtering of ground water. have a good day!

Answer:

Explanation:

Molarity of NaOAc needed

Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.

pH = pKa + log [NaOAc]/[HOAc]

5.00 = 4.75 + log[NaOAc]/[1.00M]

5.00 - 4.75 = log [NaOAc] - log[1.00M]

log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78

Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.

Determine Volume of Base Needed

(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base

Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.

Checking Results:

5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00    QED.

The volume of 1.00 M sodium acetate solution needed to prepare an acetic/acetate buffer of pH 5.00 using 10.0 mL of 1.00M acetic acid solution is 17.8 mL.

We can find the volume of the acetate solution with the Henderson-Hasselbalch equation:

[tex]pH = pka + log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]})[/tex]   (1)  

Where:

[CH₃COOH] = 1.00 M                      

[CH₃COONa] =?

pH = 5.00

pKa = 4.75

From equation (1), we have:

[tex] log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]}) = pH - pKa [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{pH - pKa} [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{5.00 - 4.75} = 1.78 [/tex]

Now, the volume of the acetate solution is:

[tex]\frac{n_{CH_{3}COONa}/Vt}{n_{CH_{3}COOH}/Vt} = 1.78[/tex]  

Since the total volume is the same, we have:

[tex]\frac{n_{CH_{3}COONa}}{n_{CH_{3}COOH}} = 1.78[/tex]  

[tex] \frac{[CH_{3}COONa]_{i}*V_{b}}{[CH_{3}COOH]_{i}*Va} = 1.78 [/tex]  

Solving for Vb

[tex] Vb = \frac{1.78*[CH_{3}COOH]_{i}*Va}{[CH_{3}COONa]_{i}} = \frac{1.78*1.00M*10.0mL}{1.00 M} = 17.8 mL [/tex]

Therefore, we need to add 17.8 mL of sodium acetate solution.

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I hope it helps you!  

Answer:

4.584*10^23 molecules

Explanation:

Find molar mass of nitrogen and oxygen on periodic table.

find molar mass of nitrogen dioxide

use this to find moles of nitrogen dioxide

multiply by avagadros number

Answer:

Mole fraction of KCl = 0.4056

Explanation:

We'll begin by calculating the number of mole of each compound. This can be obtained as follow:

For NaCl:

Mass NaCl = 0.564 g

Molar mass of NaCl = 58.44 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 0.564 / 58.44

Mole of NaCl = 0.0097 mole

For KCl:

Mass KCl = 1.52 g

Molar mass of KCl = 74.55 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1.52 / 74.55

Mole of KCl = 0.0204 mole

For LiCl:

Mass LiCl = 0.857 g

Molar mass of LiCl = 42.39 g/mol

Mole of LiCl =?

Mole = mass /Molar mass

Mole of LiCl = 0.857 / 42.39

Mole of LiCl = 0.0202 mole

Next, we shall determine the total mole in the mixture. This can be obtained as follow:

Mole of NaCl = 0.0097 mole

Mole of KCl = 0.0204 mole

Mole of LiCl = 0.0202 mole

Total mole =?

Total mole = Mole of NaCl + Mole of KCl + Mole of LiCl

Total mole = 0.0097 + 0.0204 + 0.0202

Total mole = 0.0503 mole

Finally, we shall determine the mole fraction of KCl in the mixture. This can be obtained as follow:

Mole of KCl = 0.0204 mole

Total mole = 0.0503 mole

Mole fraction of KCl =?

Mole fraction of KCl = Mole of KCl /Total mole

Mole fraction of KCl = 0.0204 / 0.0503

Mole fraction of KCl = 0.4056

Answer:

.4 is correct

Explanation:

Answer:

2.562

Explanation:

First we convert 127 g of H₂CO₃ to moles, using its molar mass:

Then we convert 800 mL to L:

Finally we can calculate the concentration of the solution as molarity:

Answer:

7.40×10²² molecules.

Explanation:

From the question given above, the following data were obtained:

Volume of oxygen = 2.75 L

Number of molecules of oxygen =?

Next, we shall determine the number of mole of oxygen present. This can be obtained as follow:

22.4 L contains 1 mole of oxygen at STP.

Therefore, 2.75 L will contain = 2.75 / 22.4 = 0.123 mole of oxygen at STP.

Finally, we shall determine the number of molecules of oxygen present. This can be obtained as follow:

From Avogadro's hypothesis:

1 mole of oxygen = 6.02×10²³ molecules

Therefore,

0.123 mole of oxygen = 0.123 × 6.02×10²³

0.123 mole of oxygen = 7.40×10²² molecules.

Thus, the cylinder contains 7.40×10²² molecules of oxygen.

Answer:

c. fluorine

Explanation:

A single replacement reaction is defined as the chemical reaction in which a strong molecule replaces the weak molecule from a compound.

In a single replacement reaction, the chloride ion in NaCl can be replaced     by fluorine and gives Sodium fluoride as fluorine (F) is stronger than chlorine (Cl) and from other given molecules also. So the single replacement reaction between NaCl and F will be:

NaCl + F2 => NaF + Cl2

Hence, the correct answer is "c. fluorine".

Answer:

a switch

Explanation:

Answer:

a switch is the answer hope it helps

Answer:

1

Explanation:

touching a metal spoon ....................water.

Answer:

AU9NJ-BLVHV-TCLJS-54YTB

Answer:

ΔH = -44.029 KJ/mol

Explanation:

We are told that 60.0 g of NaOH is dissolved in one litre of water.

From conversion, 1 litre = 1000 g

From tables, specific heat capacity of water; c = 4.18 J/g/°C

We are given ΔT = 15.8 °C

Formula for the heat absorbed by the solution is given as;

Q = mcΔT

Where;

Q = Heat gained by the water

m = Mass of the water

c = Specific heat of water

ΔT = change in temperature

Thus;

Q = 1000 × 4.18 × 15.8

Q = 66044 J

The solution absorbed 66044 J and therefore it means that the dissolution of the salt gave off 66044 J.

Thus;

Enthalpy is; ΔH = -66044 J

Now, Mass of NaOH is 60 g.

We know that molar Mass of NaOH is 39.997 g/mol. Thus;

Converting to moles, we have;

n = 60/39.997

n = 1.5 mol

Now, enthalpy when 1.5 moles of NaOH are dissolved in water will be;

ΔH = -66044 J/1.5 moles

ΔH = -44029.33 J/mol

ΔH = -44.029 KJ/mol

Answer:

The answer is A. Surface currents are caused by wind deep water currents are caused by difference in water density.