3 coins are flipped.

Answer:

Domain: [-2,1)

Range: [0,4]

Step-by-step explanation:

The required domain and range of the function graphed are -2 ≤ x < 1 and 0 ≤ y ≤ 4.

Given that,
To determine the domain and range of the function graphed below, in interval notation.

Range, it is the set of the values that come out to an outcome for a certain mathematical operations.

Here,
The projected line of the curve on the horizontal axis is from greater and equal to -2 to less than 1,
Domain = -2 ≤ x < 1
The projected line of the curve on  the vertical axis is from greater or equal to 0 to less than or equal to 4,
Range = 0 ≤ y ≤ 4.

Thus, the required domain and range of the function graphed are -2 ≤ x < 1 and 0 ≤ y ≤ 4.

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Step-by-step explanation:

put the value of f(x)

I think that you know

hope it is helpful for you

Answer:

4x + 2h - 1

Step-by-step explanation:

[tex]\frac{f(x+h) - f(x)}{h}[/tex]

[tex]\frac{(2(x+h)^2 - (x + h) + 5) - (2x^2 - x + 5)}{h}[/tex]

[tex]\frac{2x^2 + 4xh + 2h^2 - x - h + 5 - 2x^2 + x - 5}{h}[/tex]

[tex]\frac{4xh + 2h^2 - h}{h}[/tex]

4x + 2h - 1

Answer:

3x-3

Step-by-step explanation:

3x has a variable attach, because no other numbers have a variable attached leave it alone.

2+(-5) are like terms so combine these two. 2+(-5)=-3

now put back in the equation

3x-3

Answer:

24 .30ms is the answer I think so if the answer is correct plz mark me as brainliest.

The papaya's speed just before it hits the water will be 24.24 m/s.

The rate at which objects moves is called speed. It is given by

[tex]s = \frac{d}{t}[/tex]

An object held above the ground has a potential energy related to the height at which it is held,

PE = mgh

If you drop the object, its potential energy will become the kinetic energy of motion:

KE = ½ mv²

½ mv² = mgh

v  = √(2gh)

v =  √(2*9.8*30)

v =  24.24 m/s

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Answer:

No it is not

Step-by-step explanation:

The median is 84200

The mean is 85300

Low income is 65100

High income is 103400

From this information, we can see a skewed data. The mean would not be a good estimate value. Rather the center (median) would be more appropriate.

When we calculate the middle value for this data

65100+103400 = 168500/2 = 84250

84250 is closer to the median score of 84200. The median is best in the presence of outliers.

Answer:

227.5

Step-by-step explanation:

basically for a triangle prism you would do is

(1÷2) since it's a triangle and multiple all 3 angels

ex: 1/2 × 5 × 7 × 13

Answer:

227.5 cubic yards

Step-by-step explanation:

Formula for area of triangular prism is:

1/2 • length x height x width

Use formula with the given dimensions:

1/2 • 7 • 5 • 13 = 227.5

Answer:

√3 x^5y

First, let's do √3

√3=1.7

1.7 • x^5 • y

if you want

1.7 • X^4• x• y.

There are tons of equivalent's!

Answer:

7/13

Step-by-step explanation:

Half the deck is red so there are 26 reds.

There are 4 kings but we already counted two of these in the 26.

So there are 26+2 red or king cards total.

The probability of selecting a king or red is 28/52.

This can be reduced by dividing top and bottom by 4: 7/13.

Answer:

Below

Step-by-step explanation:

It is 5 1/4 PERCENT not just 5 1/4.

5 1/4 % = 5.25%

= 5.25/100

= 0.0525.

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

[tex]H_0: \mu = 13252[/tex]

At the alternative hypothesis, we test if the mean cost has increased, that is:

[tex]H_1: \mu > 13252[/tex]

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that [tex]\mu = 13252[/tex]

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that [tex]n = 20, X = 15560, s = 3500[/tex]

Value of the test statistic:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}[/tex]

[tex]t = 2.95[/tex]

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Answer:

10^3000

Step-by-step explanation:

1000¹⁰⁰⁰

= (10³)¹⁰⁰⁰

= 10^(3×1000)

= 10³⁰⁰⁰ or 10^3000

Answered by GAUTHMATH

Answer:

?????????????????

Step-by-step explanation:

????????

Answer:

[tex] \frac{ - 3}{ {x}^{2} - 5x + 6 }[/tex]

hope it helps

Answer:

i cant see the image

Step-by-step explanation:

Answer:

three

P A R

A R A D

A D I S E 

P Q R

A B C D

A B C D E

There are three such pairs of letters. 

Answer:

3/2 x^5 y

Step-by-step explanation:

3x^5y^3

----------------

2y^2

Simplify the y terms

y^3 / y^2 = y^(3-2) = y

3/2 x^5 y

Answer:

[tex] \frac{3}{2} x {}^{5} y {}^{} [/tex]

Step-by-step explanation:

it's all in the image

Answer:

35.1

Step-by-step explanation:

45×78/100 that's 100% correct

Given:

Two coins are tossed.

To find:

1. P(H on first coin)?

2. P(H on second coin)?

3. List the paired outcomes for tossing two coins.

4. How many ways are there for two coins to land?

5. What is P(HH)?

Solution:

If a a coin is tossed, then we have to possible outcomes, i.e., heads (H) and tails (T).

It is given that two coins are tossed.

1. The probability of getting a heads on first coin is:

[tex]P(H \text{ on first coin})=\dfrac{1}{2}[/tex]

2. The probability of getting a heads on second coin is:

[tex]P(H \text{ on second coin})=\dfrac{1}{2}[/tex]

3. If two coins are tossed, then the total possible outcomes are:

[tex]\{HH,HT,TH,TT\}[/tex]

4. The number of ways for two coins to land is 4.

5. The probability of the heads on both tosses is:

[tex]P(HH)=\dfrac{1}{4}[/tex]

Therefore, the required solution are:

1. [tex]P(H \text{ on first coin})=\dfrac{1}{2}[/tex]

2. [tex]P(H \text{ on second coin})=\dfrac{1}{2}[/tex]

3. List of possible outcomes is [tex]\{HH,HT,TH,TT\}[/tex].

4. Number of possible outcomes is 4.

5. [tex]P(HH)=\dfrac{1}{4}[/tex]

Answer:

aasha here it is.

Step-by-step explanation:

3x−1)(2x+3)

    6x2+7x−3

=6x2+9x−2x−3

=3x(2x+3)−1(2x+3)

=(2x+3)(3x−1)

and hiii

Answer:

multiplication by -1 will reflect over the x-axis

multiplication by a positive number will "scale" or "stretch" the function

Step-by-step explanation:

Answer:

Both the numbers are 8.

Step-by-step explanation:

Let the two numbers are p and 64/p.

The sum is given by

[tex]S = p +\frac{64}{p}\\\\\frac{dS}{dp}= 1 - \frac{64}{p^2}\\\\\frac{dS}{dp}=0\\\\\frac{64}{p^2}=1\\\\p= \pm 8[/tex]

So, the sum is minimum for p = 8 0r - 8, so the two numbers 8.

Answer:

Step-by-step explanation:

This is a related rates problem from calculus using implicit differentiation. The main equation is Pythagorean's Theorem. Basically, what we are looking for is [tex]\frac{dx}{dt}[/tex] when y = 6 and [tex]\frac{dy}{dt}=-2[/tex].

The equation for Pythagorean's Theorem is

[tex]x^2+y^2=c^2[/tex] where x and y are the legs and c is the hypotenuse. The length of the hypotenuse is 10, so when we find the derivative of this function with respect to time, and using implicit differentiation, we get:

[tex]2x\frac{dx}{dt}+2y\frac{dy}{dt}=0[/tex] and divide everything by 2 to simplify:

[tex]x\frac{dx}{dt}+y\frac{dy}{dt}=0[/tex]. Looking at that equation, it looks like we need a value for x, y, [tex]\frac{dx}{dt}[/tex] and [tex]\frac{dy}{dt}[/tex].

Since we are looking for [tex]\frac{dx}{dt}[/tex], that can be our only unknown and everything else has to have a value. So what do we know?

If we construct a right triangle with 10 as the hypotenuse and use 6 for y, we can solve for x (which is the only unknown we have, actually). Using Pythagorean's Theorem to solve for x:

[tex]x^2+6^2=10^2[/tex] and

[tex]x^2+36=100[/tex] and

[tex]x^2=64[/tex] so

x = 8.

NOW we can fill in the derivative and solve for [tex]\frac{dx}{dt}[/tex].

Remember the derivative is

[tex]x\frac{dx}{dt}+y\frac{dy}{dt}=0[/tex] so

[tex]8\frac{dx}{dt}+6(-2)=0[/tex] and

[tex]8\frac{dx}{dt}-12=0[/tex] and

[tex]8\frac{dx}{dt}=12[/tex] so

[tex]\frac{dx}{dt}=\frac{12}{8}=\frac{6}{4}=\frac{3}{2}=1.5 m/sec[/tex]

Answers:

==========================================================

Explanation:

Recall the following

N = set of natural numbers

N = {1,2,3,4,5,6,...}

W = set of whole numbers

W = {0,1,2,3,4,5,6,...}

The sets N and W are nearly the same set, except for W has 0 involved, while N does not. The triple dots say that pattern goes on forever.

From those infinite sets, we form the two finite subsets A and B like so

A = {x : x < 6, x is in N}

A = {x such that x < 6 and x is a natural number}

A = {1,2,3,5}

B = {y : y < 4, y is in W}

B = {y such that y < 4 and y is a whole number}

B = {0,1,2,3}

-------------------------------------------------

In short, we have these two finite sets

The notation A-B indicates we'll start with set A and kick out members of set B that are also in set A. This is known as set subtraction.

So we'll write out set A to get {1,2,3,4,5}

Then we cross off 1,2,3 in this set because these values are found in set B

We're left with {4,5}

Therefore A-B = {4,5}

---------------------------------------------------

To compute B-A, we do the same idea but in reverse.

Start with set B

{0,1,2,3}

and erase the items 1,2,3 since they are found in set A

We then find that

B-A = {0}

Even though we have 1 item, don't forget about the curly braces to say we have a set. Any set that has exactly 1 item in it is considered a singleton set.

Keep in mind that the singleton {0} is not the empty set. The empty set would have nothing inside it and we would say { } instead.

The first sum is a geometric series:

[tex]1+\dfrac15+\dfrac1{5^2}+\dfrac1{5^3}+\cdots+\dfrac1{5^n}+\cdots=\displaystyle\sum_{n=0}^\infty\frac1{5^n}[/tex]

Recall that for |x| < 1, we have

[tex]\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n[/tex]

Here we have |x| = |1/5| = 1/5 < 1, so the first sum converges to 1/(1 - 1/5) = 5/4.

The second sum is exponential:

[tex]1+5+\dfrac{5^2}{2!}+\dfrac{5^3}{3!}+\cdots+\dfrac{5^n}{n!}+\cdots=\displaystyle\sum_{n=0}^\infty \frac{5^n}{n!}[/tex]

Recall that

[tex]\exp(x)=\displaystyle\sum_{n=0}^\infty\frac{x^n}{n!}[/tex]

which converges everywhere, so the second sum converges to exp(5) or e⁵.

Answer:

Step-by-step explanation:

4*(n +5) - 2*(5 + 7n) = -70

4*n + 4*5 + 5*(-2) + 7n*(-2) = -70

4n + 20 - 10 - 14n = -70

4n - 14n + 20 - 10 = -70

- 10n + 10 = -70

Subtract 10 from both sides

-10n = -70 - 10

-10n = -80

Divide both sides by (-10)

n = -80/-10

n = 8

Step-by-step explanation:

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