3. Calculate the amount of C2H5OH in moles present in 5.0 g of ethanol. Calculate the number of C atoms present in the same amount of glucose. g

Answer:

0 kJ/mol.

Explanation:

Hello,

In this case, since the chemical potential can be represented in terms of the Gibbs free energy of formation:

[tex]\mu = \frac{\Delta _fG}{n}[/tex]

Thus, since the Gibbs free energy of formation of an element is zero, the chemical potential is also zero, or just 0 kJ/mol.

Best regards.

Answer:

The answer to your question is given below.

Explanation:

When there is an adequate supply of oxygen available to react with the fuel of a bunsen burner, the flame produce is a non luminous bunsen flame.

This flame i.e non luminous flame produced is much hotter than the luminous and three zones can be seen in the flame. This zones are

1. The zone of unburnt gas.

2. The luminous zone.

3. The outermost non luminous zone.

When an adequate supply of oxygen is available to react with the fuel of a Bunsen burner, there is complete combustion of the fuel and a non-luminous flame is produced.

Complete combustion occurs where there is plentiful supply of oxygen. During the reaction, more heat energy is produced as the flame is non-luminous and less soot is produced.

A non-luminous flame is a flame which produces less light but more heat energy. It is usually blue in color and consists of three zones. These zones are:

1. The zone of unburnt gas.

2. The luminous zone.

3. The outermost non luminous zone.

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Answer:

D

Explanation:

In this time there are made a lot of nuclear bombs so itatters on how what how much damage it makes according to its capacity in my opinion.

Nuclear reaction of which nuclear fusion is a type  which depends on the nucleons that fuse as the total mass of single nucleus is less than that of two original nuclei.

There are two types of nuclear reactions which are nuclear fusion and nuclear fission .They involve the combination and disintegration of the element's nucleus respectively.

In nuclear fission, the nucleus of the atom is bombarded with electrons of low energy which splits the nucleus in to two parts .Large amount of energy is released in the process.It is used in nuclear power reactors as it produces large amount of energy.

In nuclear fusion,on the other hand, is a reaction which occurs when two or more atoms combine to form a heavy nucleus.Large amount of energy is released in the process which is greater than that of the energy which is released in nuclear fission process.

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Answer:

Amount of water in mL = 1.75⁹ × 10 ml (Approx)

Explanation:

Given:

Length of pool = 34 m

Width of pool = 31 m

Height of pool = 4.98 ft

Find:

Amount of water in mL

Computation:

1 ft = 0.3048 m

Height of pool = 4.98 (0.3048)

Height of pool = 1.5179 m

Volume of pool = (34)(31)(1.5179)

Volume of pool = 1,754.70 m³

1 m³ = 10⁶ ml

Amount of water in mL = 1,754.70 × 10⁶ ml

Amount of water in mL = 1.75⁹ × 10 ml (Approx)

Answer:

The correct answer is 84.81 °C.

Explanation:

Based on the given information, the volume or mass of coffee is 250 ml, and the mass of metal spoon is 80 grams. The specific heat capacity of metal spoon is 0.80 J/g °C, and the specific heat capacity of coffee is 4.18 J/g °C. In the given case, heat is lost from the coffee and is gained by the spoon.  

For finding the final temperature of the coffee, the formula to be used is Q = msΔT, here m is the mass, s is the specific heat, and ΔT is the change in temperature.  

Heat lost from the coffee = Heat gained by the spoon

250 × 4.18 (90 - T2) = 80 × 0.8 (T2 - 0)

1045 (90 - T2) = 64 (T2 -0)

94050 - 1045 T2 = 64 T2

94050 = 1045 T2 + 64 T2

94050 = 1109 T2

T2 = 84.84 °C

Answer:

The value is  [tex]x = 2.565 *10^{3} \ kJ/kg[/tex]

Explanation:

From the question we are told that

  The  no of moles of the sample is  n = 0.0447 mole

  The formula weight is  [tex]M = 114 \ g/mol[/tex]

   The  mass of water is  [tex]m = 6.19 *10^{2}\ g[/tex]

   The amount of the fuel is  [tex]f= 6.13*10^{-1} \ nutritional \ Cal[/tex]

   The temperature rise is  [tex]\Delta T = 5.05^o[/tex]

Generally

      [tex]1 \ nutritional \ Cal => 4.184*10^{3} \ kJ/kg[/tex]

=>  [tex]f= 6.13*10^{-1} \ nutritional \ Cal \to x[/tex]

=>     [tex]x = \frac{6.13 *10^{-1} * 4.184 *10^{3}}{1}[/tex]

=>     [tex]x = 2.565 *10^{3} \ kJ/kg[/tex]

Answer:

option a. Temperature is equal to 273 k. Is the correct one

A boils when its vapour pressure is equal to, or greater than, the external pressure pushing on it. Therefore, option (b) is correct.

A boiling point of a liquid can be defined as the temperature at which the vapour pressure becomes equal to the atmospheric pressure of the liquid. The liquid is converted into a vapour at this temperature.

With the addition of heat that the liquid changes into vapour without any increase in temperature. The vapour pressure increases until it is equal to the pressure of the gas surrounding it as a liquid is heated. Bubbles of vaporized liquid are formed within the liquid and rise to the surface.

At the boiling temperature, the vapour inside the bubble will exert enough pressure to prevent the bubble from collapsing. The molecules of a liquid will able to overcome the forces of attraction between molecules to create vapour.

Therefore, at boiling point, the vapour pressure is equal to, or greater than, the external pressure pushing on it.

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Answer:

[tex]\text{Rate} = k\, [\mathrm{H_2\, (g)}]\cdot [\mathrm{NO\, (g)}]^2[/tex].

[tex]\rm N_2O\, (g)[/tex] is the intermediate.

Explanation:

Balanced overall reaction: [tex]\rm 2\, H_2\, (g) + 2\, NO\, (g) \to N_2\, (g) + 2\, H_2O\, (g)[/tex].

Proposed mechanism:

Start with the slowest, rate-determining step of the proposed mechanism. Here, the rate-determining step is [tex]\rm H_2\, (g) + 2\, NO\, (g) \to N_2O\, (g) + H_2O \, (g)[/tex].

There are two species on the reactant side of this intermediate reaction: [tex]\rm H_2\, (g)[/tex]  and [tex]\rm NO_2\, (g)[/tex]. The concentration of both of them should be in the rate expression of this step.

On the other hand, the coefficient of [tex]\rm H_2\, (g)[/tex] is one while the coefficient of [tex]\rm NO_2\, (g)[/tex] is two. Therefore, in the rate expression of this step, the concentration of [tex]\rm H_2\, (g)\![/tex] should have a power of one, while the concentration of [tex]\rm NO_2\, (g)\![/tex] should have a power of two.

include the rate constant [tex]k[/tex] to obtain the rate expression of the rate-determining slow step:

[tex]\text{Rate} = k\, [\mathrm{H_2\,(g)}]\cdot [\mathrm{NO\, (g)}]^2[/tex].

Make sure that all species in this rate expression are on the reactant side of the overall balanced reaction. Otherwise, further steps would be required to obtain the rate law of the overall reaction.

Therefore, by this proposed mechanism, the rate law of the overall reaction would be [tex]\text{Rate} = k\, [\mathrm{H_2\,(g)}]\cdot [\mathrm{NO\, (g)}]^2[/tex].

In a proposed reaction mechanism, a species is an intermediate if it appeared in one of the proposed steps, but not in the balanced overall equation.

The two steps of this proposed mechanism mentioned five species:

With the exception of [tex]\rm N_2O\, (g)[/tex], all the other species appeared in the overall balanced equation. Therefore, [tex]\rm N_2O\, (g)\![/tex] is the intermediate.

Answer:

See figure 1

Explanation:

For this question, we can analyze each molecule:

-) (E)-5-Methyl-2-hexene

In this case, we have a carbon chain of 6 carbons. We have a double bond between carbons 3 and 2. Also, we have a methyl group is placed on carbon 5. Finally, the "E" configuration makes reference to the double bond,  the groups on each side of the double bond must have an opposite configuration.

-) 2,5-Diethyl-1-methylcyclohexanol

In this molecule, we have a carbon chain of 2 carbons. In carbon 2 we have two chlorine atoms. In carbon 1 we have a fluorine atom and a chlorine atom. The "S" configuration makes reference to carbon 1 (the chiral carbon), so we have to assign the priorities for each group bonded to carbon 1:

1 = Chlorine

2 = Fluorine

3 = Carbon 2

4 = Hydrogen

If we need an "S" configuration the priorities must be placed in such a way that we have a counterclockwise orientation.

-) 2,5-Diethyl-1-methylcyclohexanol

In this molecule, we have a cyclic carbon chain of 6 carbons. In carbon 1 we have an "OH" group and a methyl group. In carbon s 2 and 5, we have ethyl groups.

See figure 1

I hope it helps!

Answer:

Hey!I think I can help....

Simple Distillation cannot be used to separate a mixture of two or more miscible liquids Fractional Distillation is used to separate such a mixture into its component parts or fractions. The fractions distil over in ascending order of their boiling points,starting with the fraction with the lowest boiling points. For efficient fractional distillation,the difference in the boiling points between successive fractions must be more than 10°C.In the laboratory,the apparatus for fractional distillation is same as the apparatus for simple distillation, except that a fractioning column is introduced between the distillation flask and the condenser.The fractionating column is packed with glass beads,and does the actual separation. The upper part of the column is at a lower temperature than the lower part .Only the vapour with the same temperature as the upper part of the fractionating column passes on the condenser.(This is the fraction with the lowest boiling point)Vapours with higher boiling points condense as they enter the upper part of the fractionating column and the flow back into the distillation flask.This process is repeated until the fraction with the lowest boiling point is distilled over completely. Then,the temperature in the upper part of yhe column rises until the boiling point of the next fraction is reached. This fraction then starts distilling over.The fractional distillation process continues until Al the component fractions in the mixture distil over.Crude oil or petroleum contains many important natural products such as petrol,kerosene,diesel, heavey oil,natural gases and bitumen.Each of these products can be recovered in its pure form by fractional distillation. The fractional distillation plant is made up of two maim parts----boiler,where the crude oil is kept boiling, and the fractionating tower,where yhe actual separation takes place.The fractions with the lower boiling points will emerge near the top part of the tower while those with higher boiling points will come out near the lower part of the tower..... Thank you for the question, I hope it helps you...Thank you.

Answer:

There are 6

Explanation:

The significant figures in that number are  5 4 0 0 4 7

Hope this helps:)

Answer:

One oxygen atom is tetrahedral while the other is trigonal planar

Explanation:

Acetic acid contains two oxygen atoms. The two oxygen atoms are different and have different geometries.

The first oxygen atom which is part of the carbonyl moiety in the molecule is in a trigonal planar geometry since it is sp2 hybridized.

The second oxygen atom is in sp3 hybridized state hence it is tetrahedral.

Thus one oxygen atom is tetrahedral and the other is trigonal planar in acetic acid.

Answer:

A federal taxes

Explanation:

because these are taxes paid to the federal government of a state

Answer:

Hey there!

As the name suggests, you pay Federal Taxes to the government.

Let me know if this helps :)

Answer:

From the most resources to the least, it is 3, 4, 2, 1.

Explanation:

Pork is a large animal but not as much as a cow but it also does not produce as much meat as a cow. In terms of land required and total meat produced, pork is the highest on this list so it is option B.

The most amount of land and resources are taken up by cows, but they also produce a lot more meat than porks so they are in the second place on this list.

Chickens require a small amount of space but produce little meat.

If we guess that each egg weighs 60 grams, 1 kg of eggs equals to almost 17 eggs which a single chicken can produce easily. So the eggs require the least resources which means that they are option A.

I hope this answer helps.

Answer:

Explanation:

Dispersion force is caused by weak Van der Waals attraction between molecules.

Because chloroamine and water are both polar solvents, dipole-dipole force of attraction exists between them. There is also hydrogen bonding present from the water molecules.

Answer: The forces present include;

1. Hydrogen bonding

2. Dispersion bonding

3. Dipole to Dipole bonding.

Explanation:

1. Hydrogen bonding is an electrostatic force that occur between atoms of hydrogen which is covalently bonded to electronegative atoms.

2. Dispersion force is type of force that occur between molecules which is caused by weak Van der Waals attraction between molecules.

3. Dipole -Dipole force occur when atoms with partial charges within a molecule attract themselves with another opposite opposite partial charge that is around the molecule.

Therefore,

Because chloroamine and water are both polar solvents, hydrogen bond, dispersion force and dipole-dipole force of attration occur between them. The hydrogen bonding occur between the water molecules.

The question is incomplete, the complete question is;

Consider the following reaction at 298K.

2 H+(aq) + 2 Cr2+(aq) =H2(g) + 2 Cr3+(aq)

Which of the following statements are correct?

Choose all that apply.

K > 1

ΔGo < 0

Eocell < 0

n = 2 mol electrons

The reaction is reactant-favored.

Answer:

K > 1

ΔGo < 0

n = 2 mol electrons

Explanation:

If we look at the reaction; 2 H+(aq) + 2 Cr2+(aq) -----> H2(g) + 2 Cr3+(aq), we will notice that the reaction is a spontaneous reaction because E°cell= 0-(-0.41) = 0.41 V

If the reaction is a spontaneous electrochemical process, we expect it to be product favoured with K>1. Also, a spontaneous reaction must have ∆G<0.

Lastly, we can see that two electrons were transferred according to the balanced equation for the electrochemical reaction.

Answer:

An aerosol is a colloidal A. liquid suspended in a C. gas.

Explanation:

Hence an aerosol is a colloidal solid or liquid suspended in a gas Smoke or fog, for example.

Aerosol is a system of equally dispersed, finely divided liquid or solid particles passing through a gas, often air. Dust and other aerosol particles, which serve as the nuclei for condensation and freezing, are crucial to the precipitation process.

Secondary aerosols develop when gas is converted into a particle, whereas primary aerosols are made up of particles that are added directly to the gas. Key aerosol categories include sulfates, organic carbon, black carbon, nitrates, mineral dust, and sea salt. These substances typically clump together to create complicated mixtures.

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Answer:

NHCOR

Explanation:

In electrophilic aromatic substitution, certain substituents on the aromatic ring such as

-NHCOR are known to enhance ortho-para substitution. These ortho-para activating groups stabilizes the intermediate cation.

These ortho-para activating groups usually consists of species that donate electron density towards the reaction centre thereby stabilizing the carbocation and making the reaction faster.

Answer:

Option C:

1s2 2s2 2p6 3s1 3p4

Explanation:

At a ground level, Phosphorous has an electronic configuration of 1s2 2s2 2p6 3s2 3p3 (using the spdf notation).

Once the atom becomes excited, an electron from the 3s sub-level will gain energy and jump over to the 3p sub-level, making the configuration 1s2 2s2 2p6 3s1 3p4.

The number of electrons at the 3p sub-level will now become 4 because of the addition of the new electron while the number of atoms at the 3S sub-level will reduce to 1 because an electron left this sub-level.

Answer:

5.99 moles of [tex]UF_6[/tex]

Explanation:

In this case, we can start with the decomposition of [tex]UF_6[/tex], so:

[tex]UF_6~->~U~+~3F_2[/tex] (Reaction 1)

The [tex]F_2[/tex] can react with carbon to produce [tex]CF_4[/tex]:

[tex]CF_4~+~2F_2~->~CF_4[/tex] (Reaction 2)

If we 8.99 mol of [tex]CF_4[/tex], we can calculate the moles of [tex]F_2[/tex] that we need. In reaction 2 we have a molar ratio of 1:2 (2 moles of [tex]F_2[/tex] will produce 1 mol of [tex]CF_4[/tex]):

[tex]8.99~mol~CF_4\frac{2~mol~F_2}{1~mol~CF_4}~=~17.98~mol~F_2[/tex]

With this value and using the molar ratio in reaction 1 (3 moles of [tex]F_2[/tex] are producing by each mol of [tex]UF_6[/tex]), so:

[tex]17.98~mol~F_2\frac{1~mol~UF_6}{3~mol~F_2}~=~5.99~mol~UF_6[/tex]

So, we will need 5.99 moles of [tex]UF_6[/tex] to produce 8.99 mol of [tex]CF_4[/tex].

I hope it helps!

Answer:

1. HEAT OF SOLUTION IS 1149.47 J

2. HEAT OF SOLUTION PER MOLE OF NaOH IS 41989.77 J/MOL OR 41.989 KJ/MOL

3. THE REACTION IS EXOTHERMIC

Explanation:

Mass of water = 150 g

Mass of NaOH = 1.095 g

Change in temperature = 25.32 - 23.50 = 1.82 C

Total mass of the mixture = 150 + 1.095 = 151.095 g

Specific heat capacity of water = 4.18 J/ g C

So to calculate the heat of solution, we have:

1. Heat of solution = mass * specific heat * change in temperature

Heat of solution = 151.095 * 4.18 * 1.82

Heat of solution = 1149.47 J

The heat of solution is therefore 1149.47 J or 1.15 kJ

2. Heat of solution per mole

1.095 g of NaOH produces 1149.47 J of heat

1 mole of NaOH contains 40 g

In other words:

1.095 g = 1149.47 J

40 g = x J

xJ = 40 * 1149.47 / 1.095

xJ = -41989.77 J

The heat of solution per mole of NaOH is -41.989 kJ / mol

3. The reaction is exothermic that is heat is evolved from the reaction. This is indicated by the negative sign.

Answer:

HCl.

Explanation:

Of all the type of bond, Ionic bonds are the strongest. Among all the compounds in the options only HCl has ionic bond, rest have covalent bonds. So, the strongest intermolecular forces is in HCl.  Ionic bond are formed with the transfer of electrons, one atom is donor and the other is acceptor.

Answer:

Explanation:

We are to write a chemical equation for the reaction that occurs in the following cell: Cu|Cu2+(aq)||Ag+(aq)|Ag.

And to determine which one of the two metals, (copper and silver) is the anode and which is the cathode?

The chemical equation for the reaction is as follows:

[tex]\mathbf{Cu + 2Ag^+ \to Cu^{2+}+2Ag}[/tex]

The atoms of the Copper electrodes undergo oxidation and loses two electrons each to form copper II ions [tex](Cu^{2+})[/tex] which go into the solution. The copper then becomes negatively charged and functions as the negative electrode i.e the anode

The oxidation half reaction is:

[tex]\mathsf{Cu \to Cu^{2+} + 2e^-}[/tex]

The silver ions [tex]Ag^+[/tex] becomes reduced by gaining  two electrons each from the metallic copper which was deposited into the silver electrode. The  silver electrode thus becomes positively charged and functions as the positive electrode. i.e the cathode.

The reduction half reaction is:

[tex]\mathtt{Ag^+ + 1 e^- \to Ag}[/tex]

The question is incomplete. Here is the complete question.

Acetic acid and water react to form hydronium cation and acetate anion, like this:

[tex]HCH_{3}CO_{2}_{(aq)}+H_{2}O_{(l)} -> H_{3}O^{+}_{(aq)}+CH_{3}CO_{2}^{-}_{(aq)}[/tex]

Imagine 226 mmol of [tex]CH_{3}CO_{2}^{-}[/tex] are added to a flask containing a mixture of [tex]HCH_{3}CO_{2}[/tex], [tex]H_{2}O[/tex],[tex]H_{3}O^{+}[/tex] and [tex]CH_{3}CO_{2}^{-}[/tex] at equilibrium and then answer the following questions:

1) What's the rate of the reverse reaction before any [tex]CH_{3}CO_{2}^{-}[/tex] has been added to the flask?

a) 0

b) Greater than 0, but less than the rate of the forward reaction

c) Greater than 0, but equal to the rate of the forward reaction

d) Greater than 0, but  greater than the rate of the forward reaction

2) What is the rate of the reverse reaction just after the [tex]CH_{3}CO_{2}^{-}[/tex] has been added to the flask?

a) 0

b) Greater than 0, but less than the rate of the forward reaction

c) Greater than 0, but equal to the rate of the forward reaction

d) Greater than 0, but  greater than the rate of the forward reaction

3) What is the rate of the reverse reaction when the system has again reached equilibrium?

a) 0

b) Greater than 0, but less than the rate of the forward reaction

c) Greater than 0, but equal to the rate of the forward reaction

d) Greater than 0, but  greater than the rate of the forward reaction

4) How much more [tex]CH_{3}CO_{2}^{-}[/tex]  is in the flask when the system has again reached equilibrium?

a) None

b) Some, but less than 226 mmol

c) 226 mmol

d) More than 226 mmol.

Answer: 1) c) Greater than 0, but equal to the rate of the forward reaction

2) d) Greater than 0, but  greater than the rate of the forward reaction

3) c) Greater than 0, but equal to the rate of the forward reaction

4) b) Some, but less than 226 mmol

Explanation: A reversible chemical reaction reaches its equilibrium when forward and reverse reaction are at the same rate. At that point, equilibrium has a constant called K.

Equilibrium constant depends on the concentration of its products and reagents.

For the reaction [tex]HCH_{3}CO_{2}_{(aq)}+H_{2}O_{(l)} -> H_{3}O^{+}_{(aq)}+CH_{3}CO_{2}^{-}_{(aq)}[/tex],

the forward is towards production of [tex]CH_{3}CO_{2}^{-}[/tex] and reverse is towards the production of [tex]HCH_{3}CO_{2}[/tex].

1) When equilibrium is reached, forward and reverse are at the same rate and are different from zero.

2) When adding a compound, the equilibrium is broken. So, to go back to the equilibrium, reaction tend to counteract the change. In the case of acetic acid and water above, when adding acetate anion, the reverse reaction will produce more acetic acid to restore equilibrium, so reverse reaction will be at a greater rate and different from 0.

3) After a while when the system is back to the equilibrium, the rate will be equal again.

4) After second equilibrium, acetate anion will have less mmol than when this new equilibrium state started.

Answer:[tex]\rho=7.87g/mL[/tex]

Explanation:

Hello,

In this case, we are analyzing a problem in which the Archimedes principle is considered, thus, as the volume of the metal rod is determined by the difference between the mass of the water and the mass of the water and the rod:

[tex]V_{rod}=15.00mL-10.00mL=5.00mL[/tex]

In such a way, the density turns out:

[tex]\rho =\frac{m_{rod}}{V_{rod}}=\frac{39.35g}{5.00mL} \\ \\\rho=7.87g/mL[/tex]

Regards.

Answer: [tex]T_{f}[/tex] = -29.96 °C

Explanation: A solution has a lower freezing point compared to the pure solvent, due to the solute lowering the vapor pressure of the solvent.

The "new" freezing point is calculated as:

[tex]\Delta T_{f} = K_{f}.m[/tex]

[tex]K_{f}[/tex] is the molal freezing-point depression constant

m is molality concentration, i.e., moles of solute per kilogram of solvent

Before calculating freezing point, let's find moles of ethylene glycol ([tex]C_{2}H_{6}O_{2}[/tex]) in the solution:

Molar mass [tex]C_{2}H_{6}O_{2}[/tex] = 62.08 g/mol

For 500 g:

[tex]n = \frac{500}{62.08}[/tex]

n = 8.05 moles

The molality concentration for 0.5kg of water:

m = [tex]\frac{8.05}{0.5}[/tex]

m = 16.11

The freezing point will be:

[tex]\Delta T_{f} = K_{f}.m[/tex]

[tex]\Delta T_{f} = -1.86*16.11[/tex]

[tex]\Delta T_{f} = -29.96[/tex]

Freezing point of a solution of Ethylene Glycol and Water is -29.96°C

Answer:

0.119 moles

Explanation:

Given that,

Mass measured by Nurse Antonio is 7 grams of NaCl

To find,

The no of moles of NaCl

Solution,

The number of moles is given by

[tex]n=\dfrac{m}{M}[/tex]

m is given mass

M is molar mass

For NaCl, molar mass is 23+35.5 = 58.5 grams

So,

[tex]n=\dfrac{7}{58.5}\\\\n=0.119\ \text{moles}[/tex]

Therefore, there are 0.119 moles of NaCl.

Answer:

[tex]m=406.26g[/tex]

Explanation:

Hello,

In this case, since the density is defined as the degree of compactness of a substance and it mathematically defined as the ratio of the mass and volume:

[tex]\rho = \frac{m}{V}[/tex]

By knowing that its density is 1.11 g/mL, the mass in 366 mL is:

[tex]m=\rho V=366mL*1.11\frac{g}{mL}\\ \\m=406.26g[/tex]

Regards.

Answer:

90%

Explanation:

it will be 81/90 ×100/1

81 over 90 × 100 over 1