3. A triangle has side of 5, angle of 85*, and an angle of 40
Triangle

If we are told that the counterfeit coin is too light, we can identify it with a minimum of ⌈log3(n)⌉ weighings.

First, we divide the n coins into three groups of equal size. We then weigh any two of these groups against each other. If the scale tips, the counterfeit coin is in the lighter group, and we repeat this process with that group of coins. If the scale is balanced, the counterfeit coin is in the remaining group, and we repeat the process with that group of coins.

We continue to divide the remaining coins into three groups of equal size and weigh two of them against each other until we are left with a single coin, which must be the counterfeit coin.

Since each weighing reduces the number of possible coins by a factor of 3, we need at most ⌈log3(n)⌉ weighings to identify the counterfeit coin.

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The equations of straight lines are \hat{y} = 2h, \hat{y} = 23r + 4 and \hat{y}= 2s + 3t. Option(A),(B) and (F) are correct.

A line in the coordinate plane can be described with the help of a linear equation, that is, an equation that has a first-degree expression, like y = 2x – 3.

There are many ways to put the equation of a line in the form y = mx + b,

where m is the slope and

b is the y-intercept,

but they all require the use of algebraic properties of equations, such as addition, subtraction, multiplication, division, and substitution.

The equations of straight lines among the following are:  \hat{y} = 2h,  \hat{y} = 23r + 4 and \hat{y}= 2s + 3t

Hence, the correct options are:Option A: \hat{y} = 2h , Option B: \hat{y} = 23r + 4  and Option F: \hat{y}= 2s + 3t.

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The sum of the two coefficients will be the effect of D1 on Y when D2=0.

The sum of the regression coefficients on D1 and I1 will be the effect of D1 on Y when D2=0. In other words, it is the effect of a change of D1 on Y when D2=0, holding all other variables constant.

This can be better understood by understanding what interaction variable I1 represents. I1 is the interaction between D1 and D2 and is equal to D1*D2. So, the coefficient of I1 is the effect of D1 when D2=1 and the coefficient of D1 is the effect of D1 when D2=0. Therefore, the sum of the two coefficients will be the effect of D1 on Y when D2=0.

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0.5 does not equal 1, the point (-0.5, sin(4π/3)) is not on the unit circle.

The origin of a coordinate plane serves as the center of the unit circle, which has a radius of 1. The values of the trigonometric functions (sine, cosine, tangent, etc.) at different angles are frequently seen and calculated in trigonometry. The lengths of any point's x- and y-coordinates upon that circle remain equal to the cosine and the sine of an angle since the unit circle's radius is 1, respectively.

The equation of a unit circle is given by:

x^2 + y^2 = 1

For the given coordinates (-0.5, sin(4π/3)), substitute the values:

(-0.5)^2 + sin^2(4π/3) = 0.25 + sin^2(240°)

The value of sin(240°) = -0.5:

0.25 + (-0.5)^2 = 0.25 + 0.25 = 0.5

Since 0.5 does not equal 1, the point (-0.5, sin(4π/3)) is not on the unit circle.

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Using Law of Cosines, the square root of a negative number is not a real number, there is no solution for x.

We can use the Law of Cosines to solve this problem. Let's label the distance between Samir and Ayisha as "x". Then, using the Law of Cosines, we have:

cos(18°) = (80² + x² - 82²) / (2 * 80 * x)

Simplifying this equation, we get:

cos(18°) = (x² - 2x + 3996) / (160x)

Multiplying both sides by 160x, we have:

160x * cos(18°) = x² - 2x + 3996

Simplifying, we get:

0 = x² - 2x + 3996 - 160x * cos(18°)

Now we can use the quadratic formula to solve for x:

[tex]x = [2 \pm \sqrt{(4 - 4(1)(3996 - 160cos(18^o))) ]} / 2[/tex]

[tex]x = [1 \pm \sqrt{(1 - (3996 - 160cos(1^o°)))} ]\\x = [1 \pm \sqrt{(160cos(18^o) - 3995)]}[/tex]

Plugging in the value of cos(18°) (which is approximately 0.951), we get:

[tex]x = [1 \pm \sqrt{(160(0.951) - 3995)}]x = [1 \pm \sqrt{(-2494.4)}][/tex]

Since the square root of a negative number is not a real number, there is no solution for x. Therefore, the problem may be incorrect or incomplete.

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The chance that a hypothesis test will incorrectly reject the null hypothesis when the p-value cutoff is 1%. The correct option is A.

A hypothesis test is used to test the validity of a hypothesis by calculating the probability that a sample statistic occurred by chance.

The null hypothesis is the hypothesis that is being tested, and it is usually assumed to be true unless there is evidence to the contrary.

The p-value is the probability of obtaining a sample statistic at least as extreme as the one observed, assuming the null hypothesis is true. If the p-value is less than the significance level, which is the p-value cutoff chosen by the researcher, then the null hypothesis is rejected.

If the p-value is greater than or equal to the significance level, then the null hypothesis is not rejected. The p-value cutoff is the significance level chosen by the researcher, and it represents the maximum probability of rejecting the null hypothesis when it is actually true.

In this case, the p-value cutoff is 1%, which means that the maximum probability of rejecting the null hypothesis when it is actually true is 1%. Therefore, the chance that a hypothesis test will incorrectly reject the null hypothesis when the p-value cutoff is 1%.

Therefore, the correct option is A.

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The number we are looking for is N = 2 × 2^3 × 3^2 = 72.

Let's first recall some properties of the number of divisors of an integer. If we factorize an integer n as a product of prime powers, say

n = p_1^a_1 × p_2^a_2 × ... × p_k^a_k

then the number of divisors of n is given by

d(n) = (a_1 + 1) × (a_2 + 1) × ... × (a_k + 1).

Using this fact, we can deduce some information about the number we are looking for. Let's call it N. We know that N has 8 divisors, so it must be of the form

N = p_1^2 × p_2^2, or N = p_1^7,

where p_1 and p_2 are distinct prime numbers.

Now, we are told that each of N/2 and N/3 has four divisors. We can use the same fact about the number of divisors to conclude that

N/2 = q_1^3 × q_2, or N/2 = q_1^1 × q_2^3,

and

N/3 = r_1^3 × r_2, or N/3 = r_1^1 × r_2^3,

where q_1, q_2, r_1, and r_2 are distinct prime numbers.

To simplify the notation, let's introduce the variables a, b, c, d, e, and f, defined by

p_1 = q_1^a × q_2^b,

p_2 = r_1^c × r_2^d,

N/2 = q_1^e × q_2^f,

N/3 = r_1^g × r_2^h.

Using the information we have so far, we can write down equations for a, b, c, d, e, f, g, and h in terms of unknown exponents:

a + 1 × (b + 1) = e + 1 × (f + 1) = 4,

c + 1 × (d + 1) = g + 1 × (h + 1) = 4,

2a × 2b = ef,

2c × 2d = gh.

We can solve this system of equations by trial and error. For example, we can start by trying all possible values of a and b such that 2a × 2b = 4. This gives us two possibilities: a = 0, b = 2, or a = 1, b = 1. Using the first possibility, we get e = 3, f = 1, which leads to N/2 = q_1^3 × q_2, and hence N = 2 × q_1^3 × q_2^2. Substituting this into the equation for the sum of divisors, we get

(1 + q_1 + q_1^2 + q_1^3) × (1 + q_2 + q_2^2) = 216.

We can solve this equation by trial and error as well, or by observing that 216 = 2^3 × 3^3, and hence the two factors on the left-hand side must be equal to 2^3 and 3^3, respectively. This gives us the unique solution q_1 = 2 and q_2 = 3, and hence N = 2 × 2^3 × 3^2 = 72.

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Each person in the United States uses an average of 18 metric tons of mineral resources each year.

Step by step explanation:According to the USGS, each person in the United States uses an average of 18 metric tons of mineral resources each year. It has been stated that many of the minerals we use in our daily lives are found in things we use every day, such as electronic devices, personal care products, and vehicles.

Mineral resources are utilized in many aspects of our lives, including construction, transportation, energy production, and electronics. As a result, minerals are an essential component of the modern economy.

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Answer: The correct answer to this problem would be C, or 32/3.

Step-by-step explanation:

The average rate of change in a function is the rate at which one value changes with respect to another value.

Given function: f(x) = 2x² + x + 5 on interval [-2, 2]

Therefore,

Average rate of change = f(2)-f(-2)/2-(-2)

f(2) = 2(2)² + 2 + 5

f(2) = 15

f(-2) = 2(-2)² - 2 + 5

f(2) = 11

Substitute the values,

Average rate = 5-11/2+2

Average rate = 4/4

Average rate = 1

So, the average rate of change is

Leading me to believe option C is correct.

Answer:

4=1.28

6=1.92

10=3.2

25=8

1=0.32

3.125≈3 = 1

2=0.64

7=2.24

Step-by-step explanation:

hope this helpz

The scientific and standard notation and clue obtained from the clue sheet are;

1. Name starts with; J

2. Difference = 145 million miles = Weight = 145 lbs

3. Height: 5 ft, 6 in

4. I. 2.54 × 10⁸ miles corresponding to letter I

II. 0.0005825 corresponds to letter G

III. 5.0432 × 10⁶ corresponds to letter N

IV. 1.547 × 10³ corresponds to letter R

V. 4.977 × 10⁻² corresponds to letter W

VI. 1.3 × 10¹⁰ light years away; corresponds to letter D

VII. 5.04 × 10⁻⁵ corresponds to letter A

The suspects hubby is DRAWING

Scientific notation is a format used to express very large or very small numbers such that they are much easier to work with. The scientific notation format is; a × 10ⁿ, where; a is the coefficient, which is a number between 1 and 10 (10 excluded), and n is an integer.

1. G = (6.07 × 10⁷)/(7.035 × 10³) ≈ 8628.29

J = (6.03 × 10⁻³)/(5.05 × 10⁻⁷) ≈ 11940.59

Therefore; J > G

The suspects name starts with J

2. The distance the telescope in the laboratory allows the viewer to see = 1.5 × 10⁹ miles away

The distance the other telescope a few hours away allows the viewer to see = 1.355 × 10⁹ miles away

The difference between the distances = (1.5 - 1.355) × 10⁹ miles = 1.45 × 10⁸ miles

The difference in the distance is 1.45 × 10⁸ miles = 145 million miles

The suspect weight is 145 lbs

3. The numbers are;

Feet; 532.063 × 10³ = 5.32063 × 10⁵

Inches; 5,030,045 = 5.030045 × 10⁶

The height of the suspect is 5 feet 6 inches (5'6'') = 5.5 feet

Height; = 5 ft, 6 in

4. I. The difference in distances between Earth and Saturn can be found as follows;

The difference in the distances = (1000 - 746) million miles = 254 million miles apart

Scientific notation is the expression of numbers in the form consisting of a number between 1 and 10, multiplied by 10 raised to a power

254 million miles = 2.54 × 10⁸ miles

The corresponding letter from the code cracker is; I

II Standard notation is the expression of numbers in the standard form without the use of exponents or special symbols

The number 5.825 × 10⁻⁴ in standard notation is; 0.0005825

The corresponding letter from the code cracker is; G

III. The number 504.32 × 10⁴ in scientific notation can be obtained by moving the decimal point two places to the left followed by increasing the index of 10 by 2 as follows;

504.32 × 10⁴ = 5.0432 × 10⁶

The corresponding letter from the code cracker is; N

IV. The sum of the numbers 1.202 × 10³ and 3.45 × 10² can be obtained by expressing both numbers to the same power of 10 as follows;

1.202 × 10³ + 3.45 × 10² = 12.02 × 10² + 3.45 × 10² = 15.47 × 10²

15.47 × 10² = 1.547 × 10³

Therefore; 1.202 × 10³ + 3.45 × 10² = 1.547 × 10³

The corresponding letter from the code cracker is; R

V. The difference of the numbers can be obtained as follows;

5.023 × 10⁻² - 4.6 × 10⁻⁴ = 502.3 × 10⁻⁴ - 4.6 × 10⁻⁴ = 497.7 × 10⁻⁴

497.7 × 10⁻⁴ = 4.977 × 10⁻²

Therefore; 5.023 × 10⁻² - 4.6 × 10⁻⁴ = 4.977 × 10⁻²

The corresponding letter from the code cracker is; W

VI. 13 billion light years = 13 × 10⁹ light years = 1.3 × 10¹⁰ light years

The distance a standard telescope can allow to be seen is 1.3 × 10¹⁰ light years away

The corresponding letter from the code cracker is; D

VII. 0.0000504 in scientific notation is; 5.04 × 10⁻⁵

The corresponding letter from the code cracker is; A

IGNRWDA

The suspects favorite hubby is DRAWING

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Answer:

C. Rachel is saving $5 per week.

Step-by-step explanation:

The initial savings are $10, as it is the y-intercept.

And to obtain the slope we can take 2 points from the graph.

A(0,10)

B(1,15)

m=(y2-y1)/ (x2-x1)

m=(15-10)/ (1-0)

m= 5/1

m= 5 savings in dollars per (1) week

The completed table:

                                  Die

                     1          2          3         4          5        6

 Head      H - 1     H - 2    H - 3   H - 4   H - 5    H - 6

  Tail        T - 1      T - 2    T - 3    T - 4    T - 5   T - 6

We have,

The set of all possible outcomes when rolling the die and flipping the coin is the sample space.

The total number of outcomes.

= 6 x 2

= 12 outcomes.

Each cell in the table will represent one possible outcome.

Here's the completed table:

                                  Die

                     1          2          3         4          5        6

 Head      H - 1     H - 2    H - 3   H - 4   H - 5    H - 6

  Tail        T - 1      T - 2    T - 3    T - 4    T - 5   T - 6

Thus,

The completed table is given above.

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based on these assumptions, the country will first experience shortages of food in approximately year 25 (measured from the present).

We can use the concept of exponential growth to model the population and food supply of the country.

Let P(t) be the population of the country at time t (measured in years since the present), and F(t) be the amount of food supply (measured in units of people) at time t. Then, we have:

P(0) = 4 million (initial population)

P(t) = P(0) × (1 + r) raise to the power of t, where r is the annual growth rate of the population (5%) and t is the time in years since the present

F(0) = 8 million (initial food supply)

F(t) = F(0) + p × g, where p is the population growth rate (5%) and g is the additional food supply per person (0.25)

We want to find the year when the food supply first becomes inadequate for the population. This happens when:

P(t) > F(t)

Substituting the expressions for P(t) and F(t), we get:

P(0) × (1 + r)t > F(0) + p × g × t

Simplifying this inequality, we get:

4 × (1.05)t > 8 + 0.25t

Dividing both sides by 4, we get:

(1.05)t > 2 + 0.0625t

We can use trial and error or a graphing calculator to solve this inequality. One way is to try different values of t until we find a value that satisfies the inequality. For example, we can try t = 20:

(1.05)²⁰ = 2.6533...

2 + 0.0625 × 20 = 3.25

Since (1.05)²⁰ < 2 + 0.0625 × 20, this means that the food supply is still adequate at t = 20.

We can try larger values of t until we find a value that satisfies the inequality. For example, we can try t = 25:

(1.05)²⁵ = 3.386...

2 + 0.0625 × 25 = 3.15625

Since (1.05)²⁵ > 2 + 0.0625 × 25, this means that the food supply is no longer adequate at t = 25.

Therefore, According to these projections, the nation's first food shortages will occur around the year 25. (measured from the present).

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If the null hypothesis were correct, there would be a 0.47 percent chance of getting a sample proportion that deviates from the population proportion's hypothesised value

Proportion refers to the relationship between two quantities or numbers, indicating how they are related to each other in size or amount.

The best interpretation of a Z score of 0.47 for a sample proportion is:

b. If the null hypothesis were correct, there would be a 0.47 percent chance of getting a sample proportion that deviates from the population proportion's hypothesised value.

This interpretation is in line with the definition of a Z score, which is a measure of how many standard deviations a sample statistic (in this case, the sample proportion) is not what would be anticipated if the null hypothesis were true. A Z score of 0.47 means that the sample proportion is 0.47 standard deviations away from the expected value under the null hypothesis. Therefore, the interpretation that the probability of obtaining a sample proportion as far or farther than observed from the hypothesized value of the population proportion is 0.47, assuming the null hypothesis is true, is the most appropriate.

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Answer 1: The solution to the equation is x = 4.

Answer 2:

The graph shows that the revenues for online ads have steadily increased since the paper started its online version, while the revenues for printed ads have been steadily decreasing.

Answer 3a:

Beach A is decreasing at a faster rate than Beach B, with its width decreasing from around 400 feet in 1995 to around 250 feet in 2015.

Answer 3b:

Between the years 2011 and 2012, the beaches have approximately the same width.

Answer 3c:

To get a better approximation of when the two beaches will have the same width, the rate of erosion of each beach should be calculated over time.

Equation is an statement that two expressions have the same value, and can be written using symbols, numbers and/or variables.

Answer 1: The equation 2.5x − 10.5 = 64(0.5x) can be solved by completing the table below:

x | 2.5x | 0.5x | 64(0.5x) | 2.5x - 10.5 | 2.5x - 64(0.5x)

--|------|------|-----------|--------------|-----------------

1 | 2.5  | 0.5  | 32        | -8.5         | -29.5

2 | 5    | 1    | 64        | -5.5         | -21.5

3 | 7.5  | 1.5  | 96        | -3.5         | -13.5

4 | 10   | 2    | 128       | -0.5         | -5.5

Answer 2:

The graph shows that the revenues for online ads were approximately equal to the revenues for printed ads around 2006, which is the 12th year after the online version of the paper was started.

Answer 3a:

Beach A is decreasing at a faster rate than Beach B, with its width decreasing from around 400 feet in 1995 to around 250 feet in 2015. Beach B's width is decreasing at a slower rate, from around 500 feet in 1995 to around 350 feet in 2015.

Answer 3b:

Between the years 2011 and 2012, the beaches have approximately the same width.

Answer 3c:

To get a better approximation of when the two beaches will have the same width, the rate of erosion of each beach should be calculated over time. This can be done by plotting the width of each beach over time and calculating the slope of the line, which will give an indication of the rate of erosion.

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1: The solution to the equation is x = 4.

2: The graph shows that the revenues for online ads have steadily increased since the paper started its online version, while the revenues for printed ads have been steadily decreasing.

3a: Beach A is decreasing at a faster rate than Beach B, with its width decreasing from around 400 feet in 1995 to around 250 feet in 2015.

3b: Between the years 2011 and 2012, the beaches have approximately the same width.

3c: To get a better approximation of when the two beaches will have the same width, the rate of erosion of each beach should be calculated over time.

Equation is an statement that two expressions have the same value, and can be written using symbols, numbers and/or variables.

1: The equation 2.5x − 10.5 = 64(0.5x) can be solved by completing the table below:

x | 2.5x | 0.5x | 64(0.5x) | 2.5x - 10.5 | 2.5x - 64(0.5x)

--|------|------|-----------|--------------|-----------------

1 | 2.5  | 0.5  | 32        | -8.5         | -29.5

2 | 5    | 1    | 64        | -5.5         | -21.5

3 | 7.5  | 1.5  | 96        | -3.5         | -13.5

4 | 10   | 2    | 128       | -0.5         | -5.5

2: The graph shows that the revenues for online ads were approximately equal to the revenues for printed ads around 2006, which is the 12th year after the online version of the paper was started.

3a: Beach A is decreasing at a faster rate than Beach B, with its width decreasing from around 400 feet in 1995 to around 250 feet in 2015. Beach B's width is decreasing at a slower rate, from around 500 feet in 1995 to around 350 feet in 2015.

3b: Between the years 2011 and 2012, the beaches have approximately the same width.

3c: To get a better approximation of when the two beaches will have the same width, the rate of erosion of each beach should be calculated over time. This can be done by plotting the width of each beach over time and calculating the slope of the line, which will give an indication of the rate of erosion.

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Answer:

Step-by-step explanation:

The answer is true

(a) False; A subspace is formed by the set of vectors that do not belong to the column space.

(b) True; If the matrix contains solely the zero vector, then it is the zero matrix.

(c) True; The column space of a particular matrix is equivalent to the column space of another specified matrix.

(d) False; The column space of one matrix is identical to the column space of another matrix.

(a) False; if A = [1 0; 0 0], then the column space of A is { e1 }, where e1 is the standard unit vector in the plane. If v is not in the column space of A, but w is not in the column space of A, then v + w is not in the column space of A.

Therefore, the set of vectors that are not in the column space of A does not form a subspace.

(b) True; if every vector in Rn is in the null space of A, then in particular, every standard unit vector is in the null space of A. Thus, the ith column of A is zero for i = 1, . . . , n, so A is the zero matrix.

(c) True; the column space of A is generated by the columns of A, while the column space of AB is generated by linear combinations of the columns of AB. By definition of matrix multiplication, the columns of AB are linear combinations of the columns of A, so the column space of AB is a subspace of the column space of A. Conversely, let b be in the column space of A. Then there is an x in Rm such that Ax = b. Thus, ABx = A(Bx), so b is in the column space of AB. Therefore, the column space of A is a subspace of the column space of AB. Hence the two column spaces are equal.

(d) False; if A = [1 0; 0 0] and B = [0 0; 0 1], then the column space of A is { e1 }, while the column space of B is { e2 }. The column space of AB is { 0 }, so it is not equal to either column space.

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The ball reaches a maximum height of approximately 146 feet, to the nearest foot.

Maximum Height refers to the highest point of the structure or sign as measured from the average natural ground level at the base of the supporting structure.

The ball is thrown upward with an initial velocity of 75 feet per second, implying that v0 = 75. We are also told that the ball is thrown from a height of 4 feet, implying that h0 = 4.

The function: can be used to model the ball's vertical motion.

16t2 + v0t + h0 = h(t).

Substituting v0 and h0 values yields:

h(t) = -16t^2 + 75t + 4

To determine the maximum height of the ball, we must first locate the vertex of the parabolic function h. (t). The vertex of the parabola is given by the equation y = ax2 + bx + c:

x = -b / 2a

y = c - b^2 / 4a

a = -16, b = 75, and c = 4 in this case. Substituting these values into the above formulas yields:

t = -75 / 2(-16) = 2.34 sec

h(t) = 4 - (752) / (4(-16)) 146 ft.

As a result, the ball reaches a maximum height of about 146 feet to the nearest foot.

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The rounded value of 25.71 to 2 decimal places is 25.71 itself.

To round 25.71 to 2 decimal places, we need to look at the third decimal place, which is 1.

If the third decimal place is 5 or greater, we round up the second decimal place. If the third decimal place is less than 5, we simply drop it and keep the second decimal place as is.

In this case, the third decimal place is 1, which is less than 5, so we simply drop it and keep the second decimal place as is. Therefore, 25.71 rounded to 2 decimal places is:

25.71 ≈ 25.71 (no rounding necessary)

So, the rounded value of 25.71 to 2 decimal places is 25.71 itself.

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Assuming a 0.05 significance level, both hypothesis tests would reject the null hypothesis. This means that there is enough evidence to suggest that the shopping cart icon's design affects the users' behavior. Therefore, the design should be changed to improve the user's experience.

Step by step explanation:

The problem is not stated, so we need to make some assumptions. We will assume that the hypothesis tests were done to determine whether a change in the shopping cart icon design would affect the users' behavior.

The null hypothesis (H0) is that the design of the shopping cart icon does not affect the users' behavior, while the alternative hypothesis (Ha) is that the design of the shopping cart icon affects the users' behavior.

The significance level is 0.05, which means that we are willing to accept a 5% chance of making a type I error (rejecting the null hypothesis when it is actually true).

If both hypothesis tests reject the null hypothesis, it means that the p-values were less than 0.05, and there is enough evidence to suggest that the design of the shopping cart icon affects the users' behavior.

Therefore, it is recommended to proceed with changing the design of the shopping cart icon to improve the user's experience.

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Answer:

73°

Step-by-step explanation:

As it is a hexagon, the sum of the interior angles in 720°

4x+165+132+131=720 4x=292 x=73°

The correct option is B. The trips will each bus has to make to get everyone to the stadium is 40 trips.

The number of fans who will need to use satellite parking is:

150,000 x 0.52 = 78,000

Each bus can carry 65 fans, so the total number of trips required is:

78,000 / 65 = 1200

Therefore, each bus will need to make 1200/30 = 40 trips

Satellite parking typically offers lower rates than the central parking area and provides a shuttle service to transport passengers to and from the main terminal. This type of parking is a popular option for travelers who need to park their car for an extended period of time, such as those going on vacation or business trips.

Satellite parking can be located either on-site or off-site, depending on the transportation hub. Some airports have several satellite parking lots located at various distances from the main terminal, while others have a single satellite parking area. Overall, satellite parking is an important component of transportation infrastructure, as it provides a convenient and affordable parking solution for travelers while also helping to alleviate congestion in the main parking area.

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the price of a burrito is $3.50.

How to solve?

Let the price of a burrito be denoted by "b" and the price of a taco be denoted by "t". Then we can set up the following system of equations:

2b + 5t = 19.50

5b + 2t = 22.50

We can solve for one variable in terms of the other in one of the equations, and substitute that expression into the other equation. For example, we can solve the first equation for b:

2b + 5t = 19.50

2b = 19.50 - 5t

b = (19.50 - 5t)/2

Now we can substitute this expression for b into the second equation:

5b + 2t = 22.50

5[(19.50 - 5t)/2] + 2t = 22.50

Simplifying and solving for t:

(97.50 - 25t)/2 + 2t = 22.50

97.50 - 25t + 4t = 45

-21t = -52.50

t = 2.50

So the price of a taco is $2.50. We can substitute this value back into one of the original equations to solve for the price of a burrito. Using the first equation:

2b + 5t = 19.50

2b + 5(2.50) = 19.50

2b + 12.50 = 19.50

2b = 7

b = 3.50

So, the price of a burrito is $3.50.

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Answer: 300 minuets

Step-by-step explanation:

Answer:

350

Step-by-step explanation:

60 miles is 1 hr. all it is, is a ratio.  multiply 60 by 5 to get your answer; 350

The perimeter of the figure is 16p + 10.

The whole length of a two-dimensional or three-dimensional shape's sides or edges is known as its perimeter. It is frequently referred to as the shape's perimeter or circumference. It is possible to determine the perimeter of many geometric forms with accuracy. The perimeter is a key idea in geometry and has several practical uses, such as determining the radius of a circular racetrack or determining the length of fencing required for a certain property.

The perimeter of a figure is the sum of the lengths of all its sides.

Thus,

Perimeter = (p - 9) + (7p + 5) + (p - 9) + (7p + 5)

Perimeter = 2p + 2(7p) + 2(5)

Perimeter = 16p + 10

Hence, the perimeter of the figure is 16p + 10.

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The expected value is the arithmetic mean of a large number of independently selected outcomes of a random variable.

a) No, X and Y are not independent since the lifetime of a part (Y) is modeled by X.

b) The joint PDF fX,Y(x,y) = x-1exp(-xy) for 1 ≤ x ≤ 2, y ≥ 0, 0 otherwise.

c) P[Y < 1] = 1 - exp(-x) for 1 ≤ x ≤ 2.

d) The marginal PDF fY(y) = exp(-xy) for 1 ≤ x ≤ 2, y ≥ 0, 0 otherwise.

e) The expected value of Y using fY(y) is 1/x for 1 ≤ x ≤ 2.

f) The conditional expected value of Y given X = x is 1/x for 1 ≤ x ≤ 2.

g) Using E[Y] = E[E[Y∣X]], the expected value of Y is 1.

h) The expected value of X + Y is 2.

i) The expected value of XY is 1.

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Using distance between two points formula, a = 0

The distance between two points (x, y) and (x', y') is given by

d = √[(x' - x)² + (y' - y)²]

Now, If the distance between the points (0, 6) and (a, 0) is 6 units, to find the value of a,

Let

So, substituting the values of the variables into the equation, we have

d = √[(x' - x)² + (y' - y)²]

6 = √[(a - 0)² + (0 - 6)²]

⇒ √[a² + (- 6)²] = 6

√[a² + 36] = 6

Squaring both sides, we have that

a² + 36  = 6²

a² + 36  = 36

a² = 36 - 36

a² = 0

a = √0

a = 0

So, a = 0

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The question is incomplete. Here is the complete question

If the distance between (0, 6) and (a, 0) os 6 units. Find the value of a

​

Step-by-step explanation:

This is an equation for a LINE.....ANY point on the line will satisfy this equation....so there are INFINITE solutions.