2) design an experiment to determine the effect of changing the temperature (cold to freezing) of the catalase on the rate of reaction

Answers

Answer 1

To determine the effect of changing the temperature on the rate of reaction of catalase, the following experiment can be designed:

Prepare a solution of catalase by dissolving it in a buffer solution of a suitable pH.

Add hydrogen peroxide to the catalase solution to initiate the reaction.

Record the initial rate of reaction by measuring the amount of oxygen produced over a set time interval (for example, every 30 seconds).

Repeat the reaction at different temperatures, starting at room temperature and gradually reducing it to below freezing.

At each temperature, repeat step 3 and measure the rate of reaction.

Plot the results to determine the effect of temperature on the rate of reaction.

By changing the temperature from cold to freezing, the rate of reaction of catalase will be affected due to the change in the activation energy of the reaction. The effect of temperature on the reaction rate can be determined by comparing the initial rate of reaction at each temperature. If the rate of reaction increases with increasing temperature, it can be concluded that the reaction is temperature dependent.

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Related Questions

which of the following is a molecule? select the correct answer below: water ozone glucose all of the above

Answers

All of the options listed are molecules. The correct answer is D.

A molecule is a combination of two or more atoms that are chemically bonded together. The bonding of atoms forms a new substance with its own unique properties, which are different from the properties of the individual atoms that make it up.

Water (H₂O) is a molecule made up of two hydrogen atoms and one oxygen atom.

Ozone (O₃) is a molecule made up of three oxygen atoms.

Glucose (C₆H₁₂O₆) is a molecule made up of six carbon atoms, twelve hydrogen atoms, and six oxygen atoms.

In summary, a molecule is a smallest particle of a substance that retains the chemical composition and properties of that substance, and all of the options listed (water, ozone, and glucose) are examples of molecules.

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assuming that the copper and lead are pure, determine the relative amounts of each kind of bb. the density of copper is 8.96 g/cm3 . the density of lead is 11.4 g/cm3

Answers

If m_c = m_l, then there is equal amounts of copper and lead.

To determine the relative amounts of each type of bull3t (copper and lead), we need to know the mass and volume of each type of bull3t. Assuming that the copper and lead are pure, the mass of each bull3t can be calculated using its density and volume.

Let's say the volume of the copper bull3t is V_c and the volume of the lead bull3t is V_l. Then, the mass of the copper bullet can be calculated as follows:

m_c = ρ_c * V_c

where ρ_c is the density of copper (8.96 g/cm3).

Similarly, the mass of the lead bull3t can be calculated as follows:

m_l = ρ_l * V_l

where ρ_l is the density of lead (11.4 g/cm3).

To determine the relative amounts of each type of bull3t, we need to compare their masses. If m_c > m_l, then there is more copper than lead. If m_c < m_l, then there is more lead than copper. And if m_c = m_l, then there is equal amounts of copper and lead.

Note: The actual masses of the bull3ts will depend on their individual volumes, which are not specified in the question. The above calculation provides only a relative comparison of the masses of the two types of bull3ts.

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compared to a metal with an astm grain size of 3, a material with a grain size number of 7 would have ____ crystals and would be ____.

Answers

compared to a metal with an ASTM grain size of 3, a material with a grain size number of 7 would have finer crystals and would be stronger.

The ASTM (American Society for Testing and Materials) grain size number is a measure of the average size of the grains in a metal. A lower number indicates a material with larger grains, while a higher number indicates smaller grains. The size of the grains affects the mechanical properties of the metal, such as strength, toughness, and ductility. In general, metals with finer grain sizes have better mechanical properties, such as increased strength and improved ductility. This is because smaller grains result in a more uniform microstructure and reduced defects, leading to improved mechanical performance. Therefore, a metal with an ASTM grain size of 7 would be expected to have finer crystals and to be stronger compared to a metal with an ASTM grain size of 3.

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1) A sample of an ideal gas has a volume of 2.27 L at 285 K and 1.10 atm. Calculate the pressure when the volume is 1.36 L and the temperature is 306 K.
2) A 7.90 L container holds a mixture of two gases at 51 °C. The partial pressures of gas A and gas B, respectively, are 0.292 atm and 0.676 atm. If 0.110 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?

Answers

Answer:

Question 1 ; 2.15 atm

Question 2; 1.078 atm

Step by step explanation:

Question 1

We can use the Ideal Gas Law to calculate the pressure: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant (8.31 J/mol·K), and T is the temperature in Kelvin.

Given the initial conditions:

V1 = 2.27 L, T1 = 285 K, and P1 = 1.10 atm

And the final conditions:

V2 = 1.36 L, T2 = 306 K

We can rearrange the Ideal Gas Law to solve for P2:

P2 = (nRT2) / V2 = (nRT1) / V1 * (V1 / V2) = (P1 * V1 * T2) / (T1 * V2) = (1.10 atm * 2.27 L * 306 K) / (285 K * 1.36 L) = 2.15 atm

Question 2

The total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases. So, after adding the third gas, the total pressure will become:

0.292 atm + 0.676 atm + 0.110 atm = 1.078 atm.

How many photons are produced in a laser pulse of 0.436 J
at 619 nm?

Answers

The number of photons that are produced in a laser pulse of 0.436 J

at 619 nm is 1.35 * 10¹⁸ photons.

What is the energy of a single photon at 619 nm wavelength?

The energy of a single photon at 619 nm wavelength

E = hc/λ

where:

h is Planck's constant = 6.63 x 10⁻³⁴ J•s.

c is speed of light = 3.0 * 10⁸ m/s

λ is wavelength = 619 nm or 6.19 * 10⁻⁷ m

E = 6.63 x 10⁻³⁴ * 3.0 * 10⁸ / 6.19 * 10⁻⁷

E = 3.21 * 10⁻¹⁹ J

1 photon is equivalent to 3.21 * 10⁻¹⁹ J

The number of photons = 0.436/3.21 * 10⁻¹⁹

The number of photons = 1.35 * 10¹⁸ photons.

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Find the mass of urea (CH4N2O) needed to prepare 52.0g of a solution in water in which the mole fraction of urea is 7.71×10−2.

Answers

The mass of urea (CH4N2O) needed to prepare 52.0g of a solution in water in which the mole fraction of urea is 7.71×10−2 is 13.62 g.

What is mole fraction ?

The term mole fraction represents the number of molecules of a particular component in a mixture divided by the total number of moles in the given mixture. It's a way of expressing the concentration of a solution.

The mass of water = 48.5 g

number of moles of water = 52.0 g/18g/mol

= 2.8 moles of water

mole fraction of urea = 7.71×10−2

but mole fraction = mole of substance/ total number of moles

Let the number of moles of urea be x

7.71 × 10−2 = x / 2.8 + x

7.71 × 10 − 2 (2.8 + x) = x

7.71 × 10 - 5.6 + 2x = x

x = 0.227 moles of urea

mass of urea in solution = number of mole × molar mass

= 0.227 moles × 60 g/mol

= 13.62 g of urea

Thus, the mass of urea (CH4N2O) needed to prepare 52.0g of a solution in water in which the mole fraction of urea is 7.71×10−2 is 13.62 g.

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Which of the following considerations are applicable when choosing a suitable recrystallization solvent? (TRUE / FALSE) Should have a boiling point that is ~ 30-50 °C above room temperature. Does not dissolve impurities at all temperatures or completely dissolves impurities at all temperatures. Should be unreactive toward the compound of interest. Offers minimal solubility of the compound to be purified at room and lower temperatures. Its solubility-temperature relationship to the compound should give a curve with a low slope. Submit Answer Tries 0/5 In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5.3 grams. If the % composition of the acetanilide impurity in the sample is 3.7 %, what is the minimum amount in mL of solvent (water) required for the recrystallization? (Answer format - e.g., 33.2 mL should be entered without any units) Compound Benzoic Acid Acetanilide Solubility in water at 25C 0.34 g/100ml 0.53 g/100mL Solubility in water at 100C 5.6 g/100ml 5.5g/100 ml Your answer Submit Answer Tries 0/10 Outlined below are statements describing the general procedure followed during the purification of a solid by recrystallization. Order the process from start to finish. ، ، ، ، ، ، Remove undissolved material by gravity filtration of hot solution. Obtain the melting point of solid and calculate % recovery. Add decolorizing charcoal to the hot solution to remove the color impurity. Isolate the crystallized solid by vacuum (suction) filtration on Buchner funnel. Dissolve the impure solid in hot recrystallization solvent. Determine the approximate volume of solvent required for recrystallization.

Answers

The considerations which are applicable in a suitable recrystallization solvent are: should have a boiling point that is ~ 30-50 °C, Should be unreactive, Offers minimal solubility and solubility-temperature relationship. Option A, C, D and E will be correct.

This statement is true. Because the solvent should have a boiling point that is around 30-50 °C higher than the melting point of the compound to be recrystallized in order to achieve efficient dissolution and crystal formation.

This statement is false. Because a good recrystallization solvent should dissolve the compound of interest well at high temperatures but not at all or only slightly at lower temperatures. Ideally, the impurities should dissolve well at all temperatures, so that they can be separated from the compound of interest during the filtration step.

This statement is true. Because the solvent should not react with the compound of interest, which would affect the purity of the final product.

This statement is true. Because the solvent should have minimal solubility for the compound to be purified at room temperature and lower temperatures, but should dissolve the compound well at higher temperatures in order to achieve efficient recrystallization.

This statement is true. Because the solubility-temperature relationship for the solvent and the compound should have a low slope in order to achieve efficient recrystallization.

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--The given question is incorrect, the correct question is

"Which of the following considerations are applicable when choosing a suitable recrystallization solvent? (TRUE / FALSE) A) Should have a boiling point that is ~ 30-50 °C above room temperature. B) Does not dissolve impurities at all temperatures or completely dissolves impurities at all temperatures. C) Should be unreactive toward the compound of interest. D) Offers minimal solubility of the compound to be purified at room and lower temperatures. E) Its solubility-temperature relationship to the compound should give a curve with a low slope."--

need help with questions 1 and 2 from part ||| asap

Answers

103ml of borax will be 7 tbsp of borax.

What is the use of borax?

Borax, commonly known as sodium borate, sodium tetraborate, or disodium tetraborate, is a white powdery chemical. It is frequently utilized as a household cleanser and laundry detergent booster. It contains boron, sodium, and oxygen in combination.

Baking soda (sodium bicarbonate) and borax (sodium tetraborate) aren't interchangeable terms. Although both salts and often used as "green" household cleaners, baking soda has a pH of 8, and borax has a pH of 9.5. Borax is a lot more alkaline than baking soda as a result.

Given,

1 tbsp is 14.8ml

So 7 tbsp will be 14.8*7 i.e. 103.6ml

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magnesium has three naturally occurring isotopes with the following masses and natural abundances: isotope mass (amu) abundance (%) mg-24 23.9850 78.99 mg-25 24.9858 10.00 mg-26 25.9826 11.01 part a choose the sketch of the mass spectrum of magnesium.

Answers

Mg-24 has a mass of 23.9850 and abundance of 78.99%.

Mg-25 has a mass of 24.9858 and abundance of 10.00%.

Mg-26 has a mass of 25.9826 and abundance of 11.01%.

What is abundance?

When a substance is present in large quantities and is essentially unaltered by the reaction, it is said to be a reactant that is present in abundance in a chemical reaction. Abundance differs from excess in that excess refers to any reactant other than the limiting reagent; the amount by which a reactant is in excess is frequently specified, such as with terms like "twofold excess," which denotes that there is twice as much reactant as is required for the limiting reagent to completely react. In this case, if the reaction is successful, the amount of excess reactant will have been cut in half.

Sketch of graph is given below↓↓↓

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Explain the gold foil experiment that was done by Ernest Rutherford and what was learned from it:

Answers

Answer:

Physicist Ernest Rutherford established the nuclear theory of the atom with his gold-foil experiment. When he shot a beam of alpha particles at a sheet of gold foil, a few of the particles were deflected. He concluded that a tiny, dense nucleus was causing the deflection.

Given 10.0 g of each of the following elements (N2, O2, C, S) choose the correct answer from the following choices. Highest number of atoms: Choose... + Greatest molar mass: Choose... Greater number of molecules: Ny or O, Choose.... Calculate the number of moles of Natoms in 1.00 x1022 Ny molecules.

Answers

The number of moles of N atoms in 1.00 x1022 Ny molecules is 1.66 ₓ 10⁻² mol.

What do you mean by mole ?

The term mole is defined as the amount of substance of a system which contains as many elementary entities.

1 mole is equal to 6.023 × 10 ²³ molecules.

10 gm of Nitrogen gas having number of mol = mass/ molar mass

n =10 / 28

n = 0.3571 mol

number of nitrogen molecule is 0.3571 × 6.0221023 molecules

= 2.151023 molecules

number of nitrogen atoms = 20.3571 × 6.0221023 atoms

= 4.301023 atoms

b. 10 gm of oxygen gas having no of mol = mass / molar mass

n = 10/32

n= 0.3125 mol

number of oxygen atoms = 0.3125 × 6.0221023 molecules

= 1.881023 molecules

number of oxygen atoms = 20.3125 × 6.0221023 atoms

= 3.761023 atoms

c. 10 gm of carbon having no of mol = mass / molar mass

n = 10 / 12

n= 0.83 mol

number of Carbon atoms = 0.83 × 6.0221023 atoms

= 4.9991023 atoms

d. 10 gm of sulfur having no of mol = mass / molar mass

n = 10 / 32

n= 0.3125 mol

number of nitrogen atoms = 0.3125 × 6.0221023 atoms

= 1.881023 atoms

So, the highest number of atom is 10 gm Carbon.

and greatest molar mass has sulfur and oxygen if sulfur is taken as octaatomic as sulfur has greatest molar mass.

here nitrogen has the greatest number of molecule.

Therefore, 6.022× 10²³ molecules of N2 gas contain 1 mol

so, 1 × 10²² molecule of N2 gas having  

= 0.166 ₓ 10-1

= 1.66 ₓ 10⁻² mol.

Thus, the number of moles of N atoms in 1.00 x1022 Ny molecules is 1.66 ₓ 10⁻² mol.

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In a chemical reaction involving the formation of an intermediate activated complex, which step must always be exothermic? a.Reactants- Activated Complex b.Reactants -Products c.Products-Activated Complex d.Activated-Complex products

Answers

In a chemical reaction involving the formation of an intermediate activated complex, the step from reactants to the activated complex must always be exothermic. Option A is correct.

This step is called the activation energy, and it represents the energy required to form the activated complex, which is a high-energy transition state between the reactants and the products. The formation of the activated complex is exothermic because the activated complex is higher in energy than the reactants and lower in energy than the products.

The energy difference between the reactants and the activated complex is the activation energy, which is usually overcome by heat, light, or some other form of energy. Once the activation energy has been supplied, the reaction proceeds to form the products, which are lower in energy than the activated complex.

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If 111 moles of Li contains 6.68 x 1025 atoms of Li, which one or more of the following choices is also equal to 111 moles of the substance in the choice?

Question options:
6.68 x 10^(25) atoms of Fe
6.68 x 10^(25) molecules of PCl3
6.68 x 10^(25) ionic units of MgBr3
All of the above

How do I get started when answering this question? I just got it by guessing. Is there anyway to know for future reference?

Answers

According to the concept of Avogadro's number, all of the above choices is equal to 111 moles of the substance.

What is Avogadro's number?

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

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Calculate the number of milliliters of lead (density 11.3 g/mL) having a mass of 4.145 kg.

Answers

The number of milliliters of lead is: 368.81 mL

To calculate the number of milliliters of lead (density 11.3 g/mL) having a mass of 4.145 kg, you can use the following equation:

mass ÷ density = volume

Therefore, 4.145 kg ÷ 11.3 g/mL = 368.81 mL

It is also important to remember that while this equation is useful for calculating the volume of a sample of a substance, it is not applicable to calculating the volume of a compound that contains multiple elements.

In such cases, the molar mass of the compound must be used instead. Additionally, the equation only works for substances with a constant density, as the density of a substance can vary depending on its temperature and pressure.

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start by giving the mlnxm shorthand for each complex. then, determine the metal oxidation state, dn electron count, and total valence electron count of the following complexes: a. fe(co)6 b. [co(en)2cl2] c. (ticp2cl)2 d. rh(pph3)3cl e. [(mecn)hgme] f. oso

Answers

The metal oxidation state, dn electron count, and total valence electron count of the following complexes are: a. Fe(CO)6: Metal oxidation state = 0, dn electron count = 6, total valence electron count = 18.

What is metal oxidation state?

Metal oxidation state is the degree of oxidation of a metal atom in an ion or molecule. It is an integer assigned to an element to indicate the number of electrons gained or lost when an atom of the element forms a chemical bond. Oxidation states are typically represented using Roman numerals, where positive oxidation states indicate a net gain of electrons, while negative oxidation states indicate a net loss of electrons. Oxidation states are important in understanding chemical bonding and redox reactions.

b. [Co(en)2Cl2]: Metal oxidation state = 3, dn electron count = 2, total valence electron count = 16

c. (TiCP2Cl)2: Metal oxidation state = +4, dn electron count = 2, total valence electron count = 20

d. Rh(PPh3)3Cl: Metal oxidation state = +3, dn electron count = 3, total valence electron count = 24

e. [(MeCN)HgMe]: Metal oxidation state = +2, dn electron count = 4, total valence electron count = 16

f. OSo: Metal oxidation state = 0, dn electron count = 2, total valence electron count = 10

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When 1.0 g of gasoline burns, it releases 11 kcal of heat. The density of gasoline is 0.74 g/mL. How many megajoules are released when 1.0 gal of gasoline burns?

Answers

It will going to release 129 MJ of heat.

What is gasoline?

Mass of gasoline = 1.0 g, Heat released = 11 kcal. Density of gasoline = 0.74 g/mL

Here, we are asked to calculate heat in megajoules, released when 1.0 gal of gasoline burns.

First, let’s find the volume of 1.0 gal gasoline in mL = 1.0 gal gasoline  = 3785.41 mL

Now, let’s find the mass of gasoline in g:

      Mass = Density  volume

                 = 0.74 g/mL  3785.41 m        = 2801.20 g.

Given, 1 g releases 11 kcal. Let’s find the heat released by 2800 g:

= 2801.20 g

=  30813.2 kcal

Now, let’s convert the heat in kcal to MJ:

       1 kcal = 0.004186 MJ

Therefore, heat in megajoules will be:   = 30813.2 kcal = 128.98 MJ

Therefore, It will going to release 129 MJ of heat.

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name the three major subatomic particles. Give their charges and approximate atomic masses (in amu)

Answers

Answer:

Proton (charge of +e, in the nucleus), Neutron (0 charge, in the nucleus), and Electron (charge of –e, outside the nucleus).

Explanation:

A gas has a pressure of 1.43 atm and occupies
a volume of 7.7 L. If the gas is compressed to
a volume of 1.64 L, what will its pressure be,
assuming constant temperature?

Answers

Answer:

Explanation:

The pressure of a gas can be calculated using the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in kelvin.

Assuming that the number of moles of gas and the temperature remain constant during the compression, the pressure of the gas after compression can be calculated as follows:

P2 = (nRT) / V2 = (nRT) / 1.64 L

where P2 is the pressure after compression and V2 is the volume after compression. To find P2, we need to substitute the known values into the equation:

P2 = (1.43 atm * 7.7 L) / 1.64 L = 6.76 atm

So, the pressure of the gas after compression will be 6.76 atm.

In the balanced chemical reaction shown below, what is the molar ratio of O2 to CO2?

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Multiple choice question.

A)
5 to 4

B)
4 to 3

C)
5 to 3

D)
3 to 1

Answers

Answer:

C) 5 to 3

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Ethylene burns in oxygen to form carbon dioxide and water vapor:

C2H4(g)+ 3 O2(g)-->2 CO2(g)+ 2 H2O(g)

How many liters of water can be formed if 1.25 liters of ethylene are consumed in this reaction? (Assume STP)

_____ L H2O (3 sig figs)

Answers

Answer:

1.25 L of C2H4 is equal to:

1.25 L / 22.4 L/mol = 0.0558 moles

From the balanced chemical equation, we see that for every 1 mole of C2H4 that reacts, 2 moles of H2O are formed.

So, for 0.0558 moles of C2H4:

0.0558 moles * 2 moles H2O/mole C2H4 = 0.1116 moles of H2O

0.1116 moles * 22.4 L/mol = 2.51 L H2O (3 sig figs)

For this profile, which elementary reaction rate is faster; intermediates converting to products or intermediates converting back to reactants? A. The rate of converting intermediates to reactants will be faster; because this reaction has a lower barrier than the reaction that converts intermediates back to products B. The rate of converting intermediates to products will be faster, because this reaction has a lower barrier than the reaction that converts intermediates back to reactants

Answers

The rate of converting intermediates to products will be faster, because this reaction has a lower barrier than the reaction that converts intermediates back to reactants.  

Then the correct option is A.

This is because the reaction that converts intermediates to products is an exothermic reaction, meaning it releases energy and is therefore more likely to occur.

An elementary reaction is a chemical reaction in which the reactants directly form the products in a single reaction step and with a single transition state. It is a reaction that cannot be broken down into simpler steps and is considered to be a basic unit of chemical kinetics.

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Which organic compound has a branched hydrocarbon group. Select one: a. 2-propanol. b. normal propyl acetate. c. acetone. d. 2-butanone.

Answers

The correct option is D. 2-butanone organic compound has a branched hydrocarbon group.

Natural compounds are a substance that consists of covalently- bonded carbon and hydrogen and frequently with other elements. organic compounds examples are benzoic Acid, fragrant compounds, benzoic aldehyde, propanoic acid, butanoic acid, malonic acid, amines, heterocyclic compounds, VOC, benzoic acid, and diethyl malonate.

In chemistry, many authors bear in mind that an organic compound is any chemical compound that includes carbon-hydrogen or carbon-carbon bonds, although, the definition of "natural" versus "inorganic" varies from author to writer, and it's far a subject of debate. The chemicals of living matter are called organic compounds due to their affiliation with organisms and due to the fact they're carbon-containing compounds. organic compounds, which are the compounds associated with existence procedures, are the difficult count of a number of natural chemistry.

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Identify the safety equipment designed to deal with each emergency listed. cuts or minor burns Choose... chemicals on clothes Choose... chemicals in eyes Choose... large fire on the benchtop Choose... fire on a person, Choose... first aid kit eyewash station fire blanket fire extinguisher safety shower

Answers

Eyewash station for chemicals in the eyes, a fire blanket for fire on a person, a fire extinguisher for a large fire on the benchtop, and a first aid kit for cuts or minor burns.

Eyewash station:

For chemicals in the eyes, an eyewash station provides immediate flushing of the affected area to help prevent damage and remove any hazardous material. This should be located close to where the chemicals are being used and easily accessible in the event of an emergency.

Fire blanket:

A fire blanket can be used to smother a small fire on a person, such as clothing that has caught fire. The blanket is placed over the person and the fire is suffocated by cutting off the oxygen supply.

Fire extinguisher:

A fire extinguisher is the primary piece of equipment for fighting a small fire, such as a fire on a benchtop. It is important to choose the correct type of extinguisher for the type of fire that is occurring, as using the wrong type can make the fire worse.

First aid kit:

A first aid kit can be used to treat cuts or minor burns. This kit should contain items such as bandages, antiseptic wipes, and pain relievers. Having a first aid kit on hand can help to prevent minor injuries from becoming more serious and can provide a measure of comfort to the person who is injured.

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State the number of atoms of oxygen in the reactants and in the products for the following equation: 3NO2(g) + H2O(l) →→ NO(g) + 2HNO3(aq

Answers

The number of atoms of oxygen in the reactants is 5 (3 from NO₂ and 2 from H₂O) and the number of atoms of oxygen in the products is 5 (1 from NO and 8 from HNO₃).

3NO₂(g) + H₂O(l) →→ NO(g) + 2HNO₃(aq)

Atom: Atoms are made up of smaller particles such as electrons, protons, and neutrons. These particles determine the properties of an atom and the elements they form.

Oxygen: Oxygen is the chemical element having symbol O and its atomic number will be 8. It is a member of the chalcogen group in the modern periodic table, a highly reactive nonmetal, and an oxidizing agent that readily forms oxides with most elements as well as with other compounds.

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Normal saline is a solution of aqueous sodium chloride with a concentration of 0.90% (glmL): Express this concentration in molarity; then indicate whether the osmotic pressure of each of these solutions is hypotonic, isotonic, or hypertonic compared to normal saline: a_ 1.0 M aq: KCI b. 0.5 M aq: K2SO4 C_ 4.3 M aq NHACI d. 0.15 M aq: sugar

Answers

The concentration of 0.90% aqueous sodium chloride can be expressed in molarity as follows:

0.90 g/mL of sodium chloride = 0.0090 g/mL × 1 mole / 58.44 g = 0.000155 M

Next, we can compare the osmotic pressure of each solution to normal saline:

A) 1.0 M aq: KCl is hypertonic compared to normal saline. The osmotic pressure of a solution is directly proportional to its concentration. Therefore, a 1.0 M solution of KCl has a higher concentration and higher osmotic pressure than normal saline, which makes it hypertonic.

B) 0.5 M aq: K2SO4 is hypotonic compared to normal saline. A 0.5 M solution of K2SO4 has a lower concentration and lower osmotic pressure than normal saline, which makes it hypotonic.

C) 4.3 M aq: NH4Cl is hypertonic compared to normal saline. A 4.3 M solution of NH4Cl has a higher concentration and higher osmotic pressure than normal saline, which makes it hypertonic.

D) 0.15 M aq: sugar is hypotonic compared to normal saline. A 0.15 M solution of sugar has a lower concentration and lower osmotic pressure than normal saline, which makes it hypotonic.

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Write an equation that shows the formation of a cobalt(III) ion from a neutral cobalt atom.

Answers

The equation that shows the formation of cobalt (III) ion from the neutral atom of cobalt is written as below:

[tex]\rm Cu \rightarrow Cu^{3+} + 3 e^{-}[/tex]

What is oxidation ?

Oxidation is the process of reaction with oxygen or donation of electrons to form the higher oxidation state. When a neutral atom donates one electron to other atom, it gains positive charge. Thus oxidizes to one higher oxidation state.

Cobalt is a transition metal exhibiting variable oxidation states as other transition metals. The possible oxidation states of cobalt are  +1, +2 and +3.

When cobalt atom donates 3 electrons from its valence shell. It forms the ion Co³⁺. The reaction can be represented as written above. The number of electrons donated is written in the right of the arrow.

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According to the latest report of transparency International, which is the country having maximum corruption in the world​

Answers

Answer:

Denmark, Finland, New Zealand, Norway, Singapore, and Sweden are perceived as the least corrupt nations in the world, ranking consistently high among international financial transparency, while the most apparently corrupt are Somalia (scoring 12), Syria and South Sudan (both scoring 13).

The compound copper(II) iodide is a strong electrolyte. Write the reaction when solid copper(II) iodide is put into water.
Include states of matter in your answer.

Answers

Answer:

Explanation:The compound copper(II) Iodide is a strong electrolyte. Write the reaction when copper(ll) Iodide is put into water: The compound iron(III) sulfate is a strong electrolyte. Write the reaction when Iron(III) sulfate is put into water: Write the net ionic equation for the precipitation of iron (III) sulfide from aqueous solution: Write the net ionic equation for the following molecular equation. HI is a strong electrolyte. HF is a weak electrolyte. KF(aq) + HI(aq) arrow KI(aq) + HF(aq) Use H^+ for the hydronium ion. Write the net ionic equation for the following molecular equation. Fe(s) + Pb(NO3)2(aq) arrow Fe(NO3)2(aq) + Pb(s)

Assuming equal concentrations and complete dissociation, arrange these aqueous solutions by their freezing points. K3PO4, Na2Co3, Na2Co3

Answers

The correct order for the freezing point of the solution will be [tex]\mathrm{K_3PO_4 < Na_2CO_3 < NaNO_3}[/tex]

What is freezing ?

Freezing is the process of cooling a substance to a temperature below its freezing point, which is the temperature at which a liquid turns into a solid. This process occurs naturally when the temperature of a liquid decreases to the freezing point or below. When a liquid freezes, its molecules slow down and become arranged in a solid crystal lattice structure. Freezing is often used in food preservation, as freezing temperatures prevent the growth of microorganisms and slow down the breakdown of chemical compounds. Freezing can also be used for other purposes, such as medical applications, where tissue samples are frozen for later analysis.

The number of ions formed by the dissociation of 1 molecule of [tex]\mathrm{Na_2CO_3, NaNO_3 \quad}[/tex] and [tex]\mathrm{ K_3PO_4}[/tex] are 3,2 and 4 respectively.

Hence, the correct order fro the vant Hoff,s factor i and the depression in the freezing point will be [tex]\mathrm{NaNO_3 < Na_2CO_3 < K_3PO_4}[/tex]

Hence, the correct order for the freezing point of the solution will be [tex]\mathrm{K_3PO_4 < Na_2CO_3 < NaNO_3}[/tex]

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Correct question:

Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. Na2Co3, NaNo3, K3PO4.

A 8.0
×
10

2
M
solution of a monoprotic acid has a percent dissociation of 0.57
%
.
Determine the acid ionization constant (
k
a
)
for the acid.

Answers

The acid ionization constant for the acid is 1.40 x 10^-10.

The acid ionization constant (Ka) can be calculated using the equation:

Ka = [H+][A-] / [HA]

where [H+] and [A-] are the concentrations of the hydrogen ion and the conjugate base, respectively, and [HA] is the concentration of the undissociated acid.

Given that the percent dissociation is 0.57%, the concentration of the dissociated species can be calculated as follows:

[A-] = 0.57% * 8.0 x 10^-2 M = 4.56 x 10^-5 M

[H+] = [A-]

Since the dissociation is very small, we can assume that the concentration of the undissociated acid is equal to the initial concentration of the solution:

[HA] = 8.0 x 10^-2 M

So, the value of Ka can be calculated as:

Ka = [H+][A-] / [HA] = (4.56 x 10^-5 M)^2 / (8.0 x 10^-2 M) = 1.40 x 10^-10.

Therefore, the acid ionization constant for the acid is 1.40 x 10^-10.

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