Answer:
Resistance is quadrupled.
Explanation:
Solving this requires us to use the formula of resistivity.
Resistivity is usually said to be the measure of the resistance of a particular size of any given material to the electrical conduction. It is mathematically represented as
ρ = RA/L, where
ρ = the resistivity of the given material
R = the resistance of the material
A = the area of the material
L = length of the material.
From the question, we're told that the length is doubled with the resistivity and density remaining constant. If the density is constant, this makes the volume constant as well.
Volume, V = A * L. We're then told that the length is doubled. If the length is doubled, for the volume to remain constant, then the area must be halved.
Volume, V = A/2 * 2L
Making, Resistance R, subject of the formula, we have
R = ρL/A.
Since resistivity is constant and the area is halved, we then have
R = 2L / (1/2A)
R = 4L / A
If the length is doubled, we have the resistance to be quadrupled
Hello everyone I have a question for you today. So you know we have discovered black holes and have theorized about white holes so let me ask you without you going to the internet and looking it up what would happen if a white hole and a black hole collided?
Answer:
White hole is an impossible object in universe. ... This means that in a hypothetical universe where there is a black and a white hole, in a short time after their first interaction the white hole will become another black hole so that the system will end up with two black holes.
A stone is dropped from the top of a cliff. The splash it makes when striking the water below is heard 6.9 s later. How high is the cliff?
The density of gold is 19.3g/cm³.what is the value in kilograms per cubic meter?
What is used to measure the radiation?
Answer:
geiger counter with geiger mueller
1. A perspex box has a 10 cm square base and contains water to a height of 10 cm. A piece of rock of mass 600g is lowered into the water and the level rises to 12 cm.
(a) What is the volume of water displaced by the rock?
(b) What is the volume of the rock?
(c) Calculate the density of the rock
Answer:
(a) The volume of water is 100 cm³
(b) The volume of the rock is 20 cm³
(c) The density of the rock is 30 g/cm³
Explanation:
The given parameters of the perspex box are;
The area of the base of the box, A = 10 cm²
The initial level of water in the box, h₁ = 10 cm
The mass of the rock placed in the box, m = 600 g
The final level of water in the box, h₂ = 12 cm
(a) The volume of water in the box, 'V', is given as follows;
V = A × h₁
∴ The volume of water in the box, V = 10 cm² × 10 cm = 100 cm³
The volume of water in the box, V = 100 cm³
(b) When the rock is placed in the box the total volume, [tex]V_T[/tex], is given by the sum of the rock, [tex]V_r[/tex], and the water, V, is given as follows;
[tex]V_T[/tex] = [tex]V_r[/tex] + V
[tex]V_T[/tex] = A × h₂
∴ [tex]V_T[/tex] = 10 cm² × 12 cm = 120 cm³
The total volume, [tex]V_T[/tex] = 120 cm³
The volume of the rock, [tex]V_r[/tex] = [tex]V_T[/tex] - V
∴ [tex]V_r[/tex] = 120 cm³ - 100 cm³ = 20 cm³
The volume of the rock, [tex]V_r[/tex] = 20 cm³
(c) The density of the rock, ρ = (Mass of the rock, m)/(The volume of the rock)
∴ The density of the rock, ρ = 600 g/(20 cm³) = 30 g/cm³
How long would it take a machine to do 5.000
joules of work if the power rating of the machine
is 100 watts?
A. 5,000 sec
B.
50 sec
C.
10 sec
D. 0.2 sec
Answer : B
Answer:
a
Explanation:
How long would it take a machine to do 5.000
joules of work if the power rating of the machine
is 100 watts?
The given machine will take 50 s to complete the work. the power is the rate of performing work.
What is power?It can be defined as the rate of performing work. It can also be written as the amount of work divided by the time it takes to complete the work.
[tex]p = \dfrac wt[/tex]
So
[tex]t = \dfrac w p[/tex]
Where,
[tex]p[/tex] - power = 100 watt = 100 J/s
[tex]t[/tex] - time = ?
[tex]w[/tex]- work = 5000 J
Put the values in the formula,
[tex]t = \dfrac{ 5000 \rm \ J} {100 \rm \ J/s}\\\\t = 50 \rm \ s[/tex]
Therefore, the given machine will take 50 s to complete the work.
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Two students Tim and Alane travel to South Dakota. Tim stands on Earth’s surface and enjoys some sunshine. At the same time, Alane descends into a gold mine where neutrinos are detected, Although the photon at the surface and the neutrinos in the mine arrive at the same time, they have had very different histories. Describe the differences.
Answer:
Explanation:
Neutrinos are otherwise called leptons. They are principal particles. A lepton is a rudimentary half-spin molecule that doesn't go through solid reactions. Neutrinos are not usually charged and exceptionally light weighted so they once in a while interface with other matter. Neutrinos are light weighted. Their mass is around 10⁻⁷ kg. A neutrino possesses a small radius, too little to ever be estimated. A little span and very less mass make them imperceptible. Since neutrinos have next to no mass. they travel at almost the speed of light and thus they arrive at the outside of the Sun in only 2 seconds, dissimilar to photons which take convoluted ways to arrive at the Sun's surface in a huge number of years.
The photon and neutrino, both were made in the Sun's center yet on various occasions. The neutrino is only a couple of minutes old though the photon is around 1,000,000 years of age. At the point when the photon was made in the Sun's center. it needed to venture out to the outside of the Sun. in any case, rather because of its hefty mass and cooperation with other matter, it headed out a crisscross way to the surface. Ordinarily, it was repulsed and it was sent back to the middle where it needed to begin once more. It required a large number of years for a photon to arrive at the outside of the Sun.
Nonetheless, when it arrived at the Sun's surface, it required just 8.8 minutes for the photon to arrive at Earth. The neutrino was anyway made only a couple of minutes prior in the Sun's center. Since it has an entirely irrelevant mass, little size, and no charge, it didn't interface with its environmental factors. So it just required 2 seconds for the neutrino to arrive at the Sun's surface. When it arrived at the Sun's surface, it arrived at the earth in about 8.8 minutes. with the photon. So both, photon and neutrino have various histories as the two of them were made at a hole of around 1,000,000 years.
in winter soap does not dissolve properly in winter why
Answer:
In winter, the temperature of the water is very low which makes the soap dissolve in a very small amount. ... Since the water molecules move faster, they come in contact with soap more often causing it to dissolve faster
Hope it helps...
Have a great day : )
A large box slides across a frictionless surface with a velocity of 12 m/s and a mass of 4
kg, collides with a smaller box with a mass of 2 kg that is stationary. The boxes stick
together. What is the velocity of the two combined masses after collision?
8 m/s
O m/s
12 m/s
4 m/s
us 12:18
What is one way that gas giants differ from the terrestrial planets?
A. The gas giants have hard surfaces.
B. The gas giants have massive atmospheres.
C. The gas giants are much smaller.
D. The gas giants are made of rocks and ice.
uniform solid sphere has a mass of 1.765 kg and a radius of 0.854 m.a. Find the torque required to bring the sphere from rest to an angular velocity of 317 rad/s, clockwise, in 15.5 s.b. What magnitude force applied tangentially at the equator would provide the needed torque
Answer:
a) the torque required is 10.53 N-m
b) The magnitude force applied tangentially is 12.33 N
Explanation:
Given the data in the question;
mass m = 1.765 kg
radius r = 0.854 m
first we calculate the moment of inertia;
[tex]I[/tex] = [tex]\frac{2}{5}[/tex]mr²
we substitute
[tex]I[/tex] = [tex]\frac{2}{5}[/tex] × 1.765 × (0.854)²
[tex]I[/tex] = 0.514897 kg.m²
a)
Find the torque required to bring the sphere from rest to an angular velocity of 317 rad/s, clockwise, in 15.5 s
ω[tex]_{initial[/tex] = 0
ω[tex]_{final[/tex] = 317 rad/s
t = 15.5 s
we know that; ω[tex]_{final[/tex] = ω[tex]_{initial[/tex] + ∝t
so we substitute
317 = 0 + ∝(15.5)
∝ = 317 / 15.5
∝ = 20.4514 rad/s²
so
ζ = [tex]I[/tex] × ∝
we substitute
ζ = 0.514897 × 20.4514
ζ = 10.53 N-m
Therefore, the torque required is 10.53 N-m
b)
What magnitude force applied tangentially at the equator would provide the needed torque.
ζ = F × r
we substitute
10.53 = F × 0.854
F = 10.53 / 0.854
F = 12.33 N
Therefore, magnitude force applied tangentially is 12.33 N
write the definition
Heredity, Dominant allele, recessive allele, probability, genotype, phenotype
Explanation:
Heredity: The passing on of physical or mental characteristics genetically from one generation to another.
Dominant allele: In genetics, dominance is the phenomenon of one variant of a gene on a chromosome masking or overriding the effect of a different variant of the same gene on the other copy of the chromosome. The first variant is termed dominant and the second recessive.
Answer:
Heredity: the passing on of physical or mental characteristics genetically from one generation to another.
Dominant Allele: a variation of a gene that will produce a certain phenotype, even in the presence of other alleles.
Recessive Allele: a variety of genetic code that does not create a phenotype if a dominant allele is present.
Probablity: used to measure the chance or likelihood of an event to occur.
Genotype: an organism's complete set of genetic material
Phenotype: the set of observable characteristics of an individual resulting from the interaction of its genotype with the environment.
When magma cools quickly, what kind of texture or
crystals does a rock have?
a. Fine-grained or small crystals
b. a mixture of all types of grains or sizes of crystals
c. Medium-grained or medium crystals
d. Coarsc-grained or large crystals
Answer:
a
Explanation:
when magma cools Crystal's form because the solution is super saturated with respect to some minerals if the magma cools quickly the crystals do not have much time to form hence they are small and also the resulting rock is fine grained
Select the correct answer.
Why are the requirements to become a congressional representative and a senator different?
A.
The framers didn’t want senators to worry about their constituents as often as representatives do.
B.
The framers gave senators more lawmaking powers and responsibilities than representatives.
C.
The framers wanted senators to be more mature and more experienced than representatives.
D.
The framers thought senators and representatives should have reasons to argue with each other.
The framers wanted senators to be more mature and more experienced than representatives. (C)
Answer:
C -> The framers wanted senators to be more mature and more experienced than representatives.
A window air conditioner that consumes 2 kW of electricity when running and has a coefficient of performance of 3 is placed in the middle of a room, and is plugged in. The rate of cooling or heating this air conditioner will provide to the air in the room when running is:
Answer: Q= QH - QL
= W + QL - QL
= W
= 1 kj/8
Explanation:
Since the net rate is positive the room will be heated.
a car travels at the speed of 117km/h.How far will the car travels in 50 minutes
Answer:
117/60*50
Explanation:
Trust me bc I'm smart
A sheet of glass having an index of refraction of 1.49 is to be coated with a film of material having an index of refraction of 1.62 in order that green light with a wavelength of 534 nm (in air) will be preferentially transmitted via constructive interference. (a) What is the minimum thickness of the film that will achieve the result
Answer:
the required minimum thickness is 179.19 nm
Explanation:
Given the data in the question;
Refraction index of air n₁ = 1
Refraction index of sheet n₂ = 1.49
Refraction index of film n₃ = 1.62
wavelength of green light λ = 534 nm
In the data given, n₂ > n₃
so, this case has no pie-phase shift,
the condition for constructive interference will be;
mλ = 2Ln₂
L = mλ / 2n₂
so we substitute
L = m(534) / 2( 1.49 )
L = m( 534/ 2.98 )
L = m( 179.19 nm )
so for minimum value of L,
let m = 1
such that, L[tex]_{min[/tex] will be;
L[tex]_{min[/tex] = 1 × ( 179.19 nm )
L[tex]_{min[/tex] = 179.19 nm
Therefore, the required minimum thickness is 179.19 nm
What is the magnitude of velocity for a 3,100 kg car possessing 4,100 kg•m/s of momentum?
Answer:
my c-ock and balls be rotating im gunna be hxrny all day every day im gunna f-u-ck u and r-ape ur family girls should go back to the kitchen and hope not to be beat by their husband uh yea mhm girls desurve to be r-aped f-u-ck buck suck c-u-ck
Explanation:
Answer:
3.75
Explanati
An object is accelerated by a net force in which direction?
A. at an angle to the force
B. in the direction of the force
C. in the direction opposite to the force
D. Any of these is possible.
Answer:
B. in the direction of the force
Explanation:
Sana nakatulong
2. A test reveals that 150 J of work is required to lift an object 3 m at a
constant speed. What is the weight of the object?
0 50 N
25N
55N
O 75N
Answer:
50N
Explanation:
W=Fd
150=F(3)
50N=F
An electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. The initial speed of the electron is 5.69 x 106 m/s. The capacitor is 2.00 cm long, and its plates are separated by 0.150 cm. Assume that the electric field between the plates is uniform everywhere and find its magnitude.
Answer:
magnitude is 1382.59 N/C
Explanation:
Given the data in the question;
The time taken is;
t = x / v
we substitute;
t = ( 2 × 10⁻²) / ( 5.69 × 10⁶ )
t = 3.5149 × 10⁻⁹ s
next, the acceleration is;
a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]
a = 2.42826 × 10¹⁴ m/s²
now, the electric field is;
E = ma / q
we know that;
mass of electron m = 9.11 × 10⁻³¹ kg,
charge of electron q = 1.60 × 10⁻¹⁹ coulomb
we substitute
E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹
E = 2.21214 × 10⁻¹⁶ / 1.60 × 10⁻¹⁹
E = 1.3826 × 10²¹
E = 1382.59 N/C
Therefore, magnitude is 1382.59 N/C
A small glider is placed against a compressed spring at the bottom of an air track that slopes upward at an angle of 38.0 ∘ above the horizontal. The glider has mass 9.00×10−2 kg. The spring has 590 N/m and negligible mass. When the spring is released, the glider travels a maximum distance of 1.70 m along the air track before sliding back down. Before reaching this maximum distance, the glider loses contact with the spring.
Required:
a. What distance was the spring originally compressed?
b. When the glider has traveled along the air track 0.80 m from its initial position against the compressed spring, is it still in contact with the spring? What is the kinetic energy of the glider at this point?
Answer:
x = 0.056 m
ΔKE = 0.489 J
Explanation:
Given that
Angle, θ = 38°
Length, L = 1.7 m
Mass, m = 0.09 kg
Spring constant, K = 590 N/m
If we use the Work-Energy theorem, then we know that Potential Energy, PE = Kinetic Energy, KE
This is mathematically written as
1/2kx² = mgH
The height, H we can get by using the relation
H = L.Sinθ
H = 1.7 * Sin 38
H = 1.7 * 0.6157
H = 1.047 m
Next, we use the Work-Energy theorem
1/2kx² = mgH
1/2 * 590 * x² = 0.09 * 9.8 * 1.047
295 * x² = 0.9234
x² = 0.9235 / 295
x² = 0.00313
x = √0.00313
x = 0.056 m
If the spring loses contact at x = 0.056, definitely, it will also lose contact at x = 0.8
Then we use the formula
ΔKE = mg(H - H1)
ΔKE = mg(xsinθ - x2.sinθ)
Where, x = 1.7 , x2 = 0.8
ΔKE = 0.09 * 9.8 (1.7 * sin 38 - 0.8 * sin 38)
ΔKE = 0.882(1.047 - 0.493)
ΔKE = 0.882 * 0.554
ΔKE = 0.489 J
How fast were both runners traveling after 4 seconds?
40
Distance (in yards)
30
20
10
1
2.
3
0
Time in seconds
Answer:
they were fast ⛷⛷
The tendency for an object to remain at rest in continue in motion is called:
Inertia
Motion
Gravity
Force
Answer:
A Inertia
Explanation:
Name one similarity and one difference between a set and a bump in volleyball??
One similarity is the use of physical body whereas one difference is that one is exercise and the other is a sport.
One similarity and one differenceOne similarity between a set and a bump in volleyball is the movement and use of legs and hands.
Whereas one difference between a set and a bump in volleyball is that completing several reps of a particular exercise in a row is called a set while on the other hand, the basic pass in volleyball is known as bump.
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A train travels at a speed of 70km/h and travels a distance of 630 km. How long did it take the train to complete its journey?
Answer:
9 hr
Explanation:
Speed = distance/time
Let the time taken by the train be t.
=> 70 = 630/t
=> t = 630/70
=> t = 9
it take 9 hr to complete its journey
Answer:
9 hours
Explanation:
Using the formula to solve motion problems: d=r*t (Distance = Rate * Time)
Given:
Distance = 630 km
Rate (Speed) = 70 km/h
Time = Distance / Time
Time = 630/70
= 9
A disk drive plugged into a 120V outlet operates on a voltage of 12V . The transformer that powers the disk drive has 125 turns on its primary coil.
Part A) Should the number of turns on the secondary coil be greater than or less than 125? greater than or less than
Part B) Explain
Part C) Find the number of turns on the secondary coil.
Answer:
(A-) Number of turns in secondary coil will be less than 125.
(B-) EXPLAIN- The voltage is to be lowered. The voltage will be reduced from 120 to 9 volts. As a result, a step down transformer will be used, indicating that the secondary coil's number of turns would be less than 125.
(C-) The number of turns on the secondary coil is 12.5
Explanation:
STEP DOWN TRANSFORMER - A step-down transformer transforms high voltage (HV) and low current from the transformer's primary side to low voltage (LV) and high current on the secondary side. A phase down transformer is the opposite of this.In electrical networks and transmission lines, a step-down transformer can be used in a number of ways.
Step down transformer formula-
[tex]V_s=\frac{N_s\times V_p}{N_p}[/tex]
We are given with the -
Primary voltage [tex]V_p[/tex] = 120V
Secondary voltage [tex]Vs=12V[/tex]
Number of primary turns [tex]N_p=125[/tex]
To calculate the number of turns on the secondary coil -Since , the transformer ratio is given as -
[tex]\frac{N_s}{N_p} =\frac{V_s}{V_p}[/tex]
So, the number of turns on the secondary coil is - [tex]N_s=N_p\times\frac{V_p}{V_s}[/tex]
Putting , the given values -:
[tex]125\times\frac{12}{120}[/tex]
= 12.5
Therefore , the number of turns on secondary coil is 12.5 .
Sound travels at a speed of 330 meters/second. If Denise hears a police siren 150 meters away, approximately how long did it take for the siren sound to
travel from the police vehicle to her?
Answer:
It went about 2 meters away
Explanation:
A hollow sphere is attached to the end of a uniform rod. The sphere has a radius of 0.64 m and a mass of 0.48 kg. The rod has a length of 1.78 m and a mass of 0.50 kg. The rod is placed on a fulcrum (pivot) at X = 0.34 m from the left end of the rod.
(a) Calculate the moment of inertia (click for graphical table) of the contraption around the fulcrum. kg m2
(b) Calculate the torque about the fulcrum, using CCW as positive. N.m
(c) Calculate the angular acceleration of the contraption, using CCW as positive. rad/s2
(d) Calculate the linear acceleration of the right end of the rod, using up as positive. m/s2
The image of this hollow sphere and uniform rod is missing, so i have attached it.
Answer:
A) J = 0.7443 kg•m²
B) T = 1.9169 N•m CCW
C) α = 2.5754 rad/s²
D) a = 3.966 m/s²
Explanation:
A) The moment of inertia J of the contraption around the fulcrum is given by the formula;
J = Jℓ + Jr
Let's calculate Jℓ
Jℓ = [((0.34²/3) × 0.50 × 0.34)/1.78] + (0.48 × (0.34 + 0.64)²)
Jℓ = 0.4647 kg•m²
Now, let's Calculate Jr
Jr = ((1.78 - 0.34)²/3) × ((1.78 - 0.34)/1.78) × 0.50
Jr = 0.2796 kg•m²
Thus;
J = 0.4647 + 0.2796
J = 0.7443 kg•m²
(b) Using CCW as positive, Torque in Nm is calculated as;
T = Tℓ - Tr
Let's calculate Tℓ
Tℓ = [(0.48 × (0.64 + 0.34)) + (0.50 × 0.34/1.78) × 0.34/2)] × 9.81
Tℓ = 4.7739 N•m CCW
Now, let's Calculate Tr;
Tr = [(0.50 × (1.78 - 0.34)/1.78) × (1.78 - 0.34)/2)] × 9.81
Tr = 2.857 N•m CW
Thus;
T = 4.7739 - 2.857
T = 1.9169 N•m CCW
(c) The angular acceleration α of the contraption, using CCW is gotten from the formula;
α = T/J
α = 1.9169/0.7443
α = 2.5754 rad/s²
(d) The linear acceleration a of the right end of the rod, using up as positive is given by;
a = α*(1.78 - 0.34)
a = 2.5754 × 1.54
a = 3.966 m/s²
A) the moment of inertia of the contraption is 0.7443 kgm²
B) The torque about the fulcrum is 1.9169 Nm
C) Angular acceleration of the contraption is 2.5754 rad/s²
D) The linear acceleration of the contraption is 3.966 m/s²
Moment of inertia:(A) The moment of inertia I of the contraption around the fulcrum is given by :
[tex]I = [(0.34^2/3) \times 0.50 \times 0.34)/1.78 + (0.48 \times (0.34 + 0.64)^2)] + [(1.78 - 0.34)^2/3) \times (1.78 - 0.34)/1.78) \times 0.50][/tex]
I = 0.4647 + 0.2796
I = 0.7443 kgm²
(B) Using CCW as positive, Torque in Nm is given by;
T = [(0.48 × (0.64 + 0.34)) + (0.50 × 0.34/1.78) × 0.34/2)] × 9.81 - [(0.50 × (1.78 - 0.34)/1.78) × (1.78 - 0.34)/2)] × 9.81
T = 4.7739 - 2.857
T = 1.9169 Nm
(C) The angular acceleration (α) of the contraption is given by:
α = T/I
since, torque is defined as T = Iα
α = 1.9169/0.7443
α = 2.5754 rad/s²
(D) The linear acceleration (a) of the right end of the rod
a = αr
where r is the distance from the pivot
a = α × (1.78 - 0.34)
a = 2.5754 × 1.54
a = 3.966 m/s²
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which one is odd copper,plastic,rubber
Answer:
It's plastic.
trust me it's plastic, i've rad it somewhere.
All of them have something that's not like the others.
-- Rubber is the only one on the list that has two repeated letters.
-- Plastic is the only one on the list thagt has no repeated letters.
-- Plastic is the only one on the list that has no 'r' in its name.
-- Copper is the only one on the list that is an element, not a compound.
-- Copper is the only good electrical conductor on the list.
-- Plastic is the only one on the list with more than six letters in its name.
-- Rubber is the only one on the list with no 'p' in its name.
-- Plastic is the only one on the list that doesn't end in "-er".