1kg of air at 1.02 bar , 20°c is compressed reversibly according to a law PV^1.3 = C, to a pressure of 5.5 bar. calculate the work done on the air and the heat supplied during compression.​

Using Thomson's cathode ray tube and Millikan's oil drop experiment, the charge of an electron was determined.

Thomson's cathode ray tube and Millikan's oil drop experiment were two important experiments in the history of physics. Thomson used his cathode ray tube to observe the behavior of electrons, while Millikan used his oil drop experiment to measure the charge of an electron. By combining the results of these two experiments, scientists were able to determine the charge of an electron, which is a fundamental unit of electrical charge in the study of electricity and electromagnetism.

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Answer: approximately 13.6 m/s.

Explanation: The sled's speed after it has traveled the first 100 m can be determined using the principles of kinematics.  We can use the equations of motion to solve this problem.

First, let's identify the given information:

- Initial speed (v₀) = 9.2 m/s (sled's top speed before starting down the track)

- Distance traveled (s) = 100 m (the first 100 m of the track)

- Angle of the slope (θ) = 9.0° (angle of the track)

To find the sled's speed after traveling 100 m, we need to determine the final speed (v) using the equation of motion that relates initial speed, final speed, distance, and angle:

v² = v₀² + 2as

Here's how we can calculate it step by step:

Convert the angle from degrees to radians:

θ = 9.0° = (9.0° * π) / 180 ≈ 0.157 radians

Determine the acceleration (a) using the gravitational acceleration and the angle of the slope:

a = g * sin(θ)

g ≈ 9.8 m/s² (acceleration due to gravity)

a ≈ 9.8 m/s² * sin(0.157) ≈ 1.36 m/s²

Substitute the known values into the equation of motion:

v² = (9.2 m/s)² + 2 * (1.36 m/s²) * (100 m)

Simplify and solve for v:

v ≈ √(9.2² + 2 * 1.36 * 100) ≈ 13.6 m/s

Therefore, the sled's speed after traveling the first 100 m is approximately 13.6 m/s.

the initial speed of the bullet as it was fired horizontally into the wooden block resting on a horizontal surface is 265m/s.

A conservation law states that the total linear momentum of a closed system remains constant through time, regardless of other possible changes within the system.

Given, A 5.00g bullet is fired horizontally into a 1.20kg wooden block resting on a horizontal surface.

In our case,

Mass of bullet = 5 gram = 0.005 kg

Mass of wooden block = 1.2 kg

the initial velocity of block = 0

Kinetic friction = 0.20

First, we get the velocity of the Wood.

From Conservation of Energy:

1/2m v² = μ mgs

v = √(2 μgs)

Where v is the velocity of the block,

μ is the coefficient of kinetic friction,

s is the displacement of the bullet

g is the acceleration due to gravity (9.81)

v = √(2 *0.2*9.81 * 0.31)

v = 1.1 m/s

so, the velocity of the wooden block after the collision will be 1.10 m/s

Now, we determine the velocity of the bullet. Using Conservation of Momentum.

m₁v₁ + m₂v₂ = MV

0.005 *v + 0 = (1.20 + 0.005) * 1.1

v = 1.325/0.005

v = 265 m/s

Therefore, the initial speed of the bullet as it was fired horizontally into the wooden block resting on a horizontal surface is 265m/s.

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Answer:

Below

Explanation:

Use law of conservation of momentum

momentum of system before collision = momentum of system after collision

                .5 kg * 6 m/s                          =   .5 kg * 2.57 m/s  +   .2 *  x m/s

                        3                          =    1.285 + .2x

                        1.715     = .2x

                            x = 8.575 m/s

The magnitude of the acceleration of the entire system will be 2.13m/s²  option (5) is correct.

The masses that are suspended from the table m = 2 kg and m' = 4 kg.

And the mass kept on the table is, m'' = 4 kg.

The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force will be,

f=∪×[tex]m^{//}[/tex]×g

=0.11×4×9.8

=4.321

Since the mass kept on the right side is more.

-f + m''g + (m' +m)a = m'g

Where,

a is the magnitude of the acceleration of the system.

-4.312+ 4(9.8) + (4 -2)a = 4(9.8)

2a = 4.312

a= 2.135

Thus, we can say that the magnitude of the acceleration of the entire system is 2.13m/s²

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Complete question is:

There is friction between the block and the

table.

The suspended 2 kg mass on the left is

moving up, the 4 kg mass slides to the right

on the table, and the suspended mass 4 kg on

the right is moving down.

The acceleration of gravity is 9.8 m/s

2

.What is the magnitude of the acceleration

of the system?

1. 1.67253

2. 1.9845

3. 1.75311

4. 2.47673

5. 2.1315

6. 2.058

7. 2.548

8. 1.33933

9. 1.5288

10. 2.03127

Answer in units of m/s²

The difference between the carrier's highest data speed (76.2 Mbps) and the mean of all 50 data speeds (15.95 Mbps) is 60.25 Mbps.

The difference of 60.25 Mbps between the carrier's highest data speed and the mean of all 50 data speeds is quite significant. It shows that this particular carrier has a much higher data speed than the average of the other 50 airports. This could be due to the particular location of the airport, the network infrastructure, or other factors.

An elementary reaction is a type of chemical reaction in which the reactants directly form the products in a single reaction step and with a single transition state. In contrast to a non-elementary reaction, which may involve multiple steps or intermediates, an elementary reaction is a single-step process in which the reactants are converted into products in a single step.

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Answer:

130.34 m/s²

Explanation:

see attachment

hope this helps!

Answer:

The velocity of the ball before it hit the ground was (3.59 m/s, -3.32 m/s) in the horizontal and vertical direction

Explanation:

The velocity of the ball can be calculated using the equation of motion:

v^2 = u^2 + 2as,

where

u = initial velocity,

v = final velocity,

a = acceleration due to gravity (9.8 m/s^2),

s = vertical height fallen (0.86 m).

Solving for u:

u = sqrt(v^2 - 2as)

We know the final velocity, v = 0 (the ball lands on the ground and stops), so

u = sqrt(2as) = sqrt(2 * 9.8 * 0.86) = 3.32 m/s.

The direction of the velocity before it hit the ground can be determined using horizontal distance traveled and time of flight.

The time of flight, t, can be found using:

t = sqrt(2s/a) = sqrt(2 * 0.86 / 9.8) = 0.39 s.

The horizontal velocity, vx, can be found using:

vx = d / t = 1.4 / 0.39 = 3.59 m/s.

The resultant speed of the plane would be 230.03 km/hour

Vectors are the units that have both magnitude and direction. We can directly add and subtract if they are going in the same or the opposite direction. If they are all going in the same direction, we employ the formula that will take the square root of each vector's sum of squares. In this case, the vectors are inclined to one another with angle 45° (plane flying from east to northeastern)

The formula below is used to calculate the resultant vector from two vectors that are inclined to one another. The resultant vector, R, is created when the vectors A and B are inclined at an angle Ø to one another:

                                  R² = A² + B² + 2ABCosØ

Thus, the resultant speed of the plane would be

R² = 200² + 40² + (2 × 200 × 40 × Cos 45°)

R² = 40,000 + 1,600 +11,313.7

R =√52,913.7

R = 230.03 km/hour

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When the car reaches 7 m it has a kinetic energy of 14364 J and a terminal velocity of 4.67 m/s.

Speed defines the direction in which a body or object is moving. Speed is primarily a scalar quantity. Velocity is basically a vector quantity. Rate of change of distance. Rate of change of displacement.

(a) The rate of change of displacement is known as velocity. It can be calculated by finding the ratio of displacement and total required time. The SI unit for velocity is "m/s", just like velocity.

The work done by the forward force is:

W1 = F1d = 1143 N × 7 m = 8001 J The work done by the second force is:

W2 = F2d = 909 N x 7 m = 6363 J The net work done on the car is the sum of the following he two works.

[tex]\mathrm{W_{net}}[/tex] = W1 + W2 = 8001 J + 6363 J = 14364 J According to the work energy principle, the net work done in a car is equal to the change in its kinetic energy.

[tex]\mathrm{W_{net}}[/tex] = ΔK where ΔK is the change in kinetic energy. Since the car starts from a standing start, the initial kinetic energy is 0, so ΔK equals the final kinetic energy. So it looks like this:

[tex]\mathrm{W_{net}}[/tex] = 14364 J Finally, we can convert this energy to Joules using the following formula:

1 J = 1 kg m²/s²

So it looks like this:

K = 14364 J = (2.2 × 10³ kg) × v² where v is the final velocity of the car. Solving for v gives:

v = √(K / (2.2 × 10³ kg))

= √(14364 J / (2.2 × 10³ kg))

= 4.67 m/s

So when the car reaches 7 m it has a kinetic energy of 14364 J and a terminal velocity of 4.67 m/s.

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The tension in the cord will be 6.99 N. To solve this problem we will refer to the laws of Mersenne. Mersenne's laws are regulations relating to the frequency of oscillation of a stretched string or monochord, helpful in musical tuning and musical instrument building.

This law suggests that the velocity in a string is directly proportional to the root of the applied tension and inversely proportional to the root of the linear density, that is,

v = √T/μ

Here,

v = Velocity

μ = Linear density ( mass per unit length)

T = Tension

Rearranging to find the Period we have that

T = v²μ

T = v²(m/L)

As we know that speed is equal to displacement in a unit of time, we will have to

T = (L/t)² (m/L)

T = (7.3/0.72)² (0.50/7.3)

T = 6.99 N

Therefore, the tension in the cord will be 6.99 N.

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Answer:

-11.29 m

Explanation:

The length of the incline can be calculated using the following formula:

L = (Vf^2 - Vi^2) / (2 * a)

where:

L = length of incline

Vf = final speed (15 m/s)

Vi = initial speed (2 m/s)

a = acceleration due to gravity (9.8 m/s^2 on the surface of the Earth)

Since the skier is going downhill, the acceleration is negative.

Substituting the given values into the formula:

L = (15^2 - 2^2) / (2 * -9.8)

L = (225 - 4) / -19.6

L = 221 / -19.6

L = -11.29 m

So the length of the incline is approximately -11.29 meters. This negative value indicates that the skier's final position is lower than the starting position.

The amount of work done by the applied force on the skier is 500 J.

The amount of work done by the applied force on the skier is calculated by applying the following equation as shown below.

W = Fd

where;

The amount of work done by the applied force on the skier is calculated as;

W = (25 N ) x ( 20 m )

W = 500 J

Thus, the work done by a force is defined to be the product of component of the force in the direction of the displacement and the magnitude of this displacement.

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One of the primary characteristics present in situations in which management science techniques are applied is that the management problems have only a few variables. Thus, the correct option is A.

Management science is important while doing any research, business, or study because it helps the organizations in identification of the issues which they need to solve, streamline management efforts, use resources more effectively, and also develop roadmaps for achieving the set goals.

Management problems are studied and these are so complicated that managers need help to analyze a large number of variables before doing  any research.

Therefore, the correct option is A.

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Your question is incomplete, most probably the complete question is:

One of the primary characteristics present in situations in which management science techniques are applied is ________.

A) that the management problems have only a few variables

B) that the situation deals with quantifiable factors such as sales

C) that the situation deals with the physiological, safety, social, esteem, and self-actualization needs of organization members

D) that the situation deals with assessing qualitative factors of the workplace or environment

E) that social implications are the guidelines for making a particular decision

The force exerted between the charges q1 and q3 is   -5.25 × 10⁻⁶ N and that between q2 and q3 is -2.93   × 10⁻⁶ N. Hence the net force is - 8.18  × 10⁻⁶ N .

According to Coulomb's law of force, the electrostatic force between two charges separated by a distance of r is given as follows:

Fc = Ke q1 q2 /r²

where Ke = 8.9 × 10⁹ Nm²/C²

Given the charge of  q1 = 3.97  × 10⁻⁹ C

charge of q3  = -5.95 × 10⁻⁹ C

distance r = 0.200 m

then Fc =  8.9 × 10⁹ Nm²/C²  ( 3.97  × 10⁻⁹ C) (-5.95 × 10⁻⁹ C)/(0.200 m)² = -5.25 × 10⁻⁶ N

Similarly, the force on q3  by the charge q2 is calculated as follows:

distance to q2 = 0.30 m

charge of q2 = 4.99 × 10⁻⁹ C.

Then Fc =   8.9 × 10⁹ Nm²/C²  (4.99 × 10⁻⁹ C ) (-5.95× 10⁻⁹ C)/(0.30 m)² = - -2.93 × 10⁻⁶ N

The net electric force acting on A =  3.9 × 10⁻⁵ N - (-1.9 × 10⁻⁵ N) = 5.8 × 10⁻⁵ N.

Therefore, the net electric force acting on q3 is  8.18  × 10⁻⁶ N.

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Your question is incomplete. But your complete question probably was:

Two point charges are placed on the x-axis as follows: charge  3.97 nC is located at 0.200 m (q1) and charge 4.99 nC (q3) is at -0.304 m .What is the magnitude of the total force exerted by these two charges on a negative point charge q3

= -5.95 nc that is placed at the origin?

If the sequence of amino acids of proteins changes, this is called a mutation.

Amino acids are the building blocks of proteins. They are organic molecules that contain an amino group (-NH2), a carboxyl group (-COOH), a side chain (R group) unique to each amino acid, and a central carbon atom.

There are 20 different types of amino acids that can be combined to form a protein. The specific sequence of amino acids determines the protein's three-dimensional structure and its function.

Amino acids play an important role in performing several biological and chemical functions in different parts of our body, including building and repairing the tissues, the formation and function of enzymes, food digestion.

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As long as an object is not gaining or losing mass, a constant force applied to an object for a period of time will result in a change in velocity (D)

When a constant force is applied to a large body, in accordance with Newton's second law, it's velocity will change at a rate that is constant during the acceleration. In the simplest case, when a force is applied to a moving object that is at rest, the object accelerates in the direction of the applied force.

A body that is already moving or that is being observed from a moving inertial reference frame may look to accelerate, decelerate, or change direction depending on the direction of the force as well as the directions that the object and the referencing frame are traveling in regard to one another.

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The velocity of the football that is thrown by Felipe to Lilah will be 23 km per hour.

The movement of an object in relation to another observer is known as its relative velocity. It is the pace at which one object's relative location changes in relation to another object over time.

Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8 km/h.

Then the velocity of the ball is given as,

v = 15 + 8

v = 23 km/h

The velocity of the ball will be 23 km / h.

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The necessary steps in order for finding the molecular formula of an unknown compound from mass percent data are:

The correct answer is 1-2-3-4-5.

Let's start with the information provided in the issue, which is the weight in grams of each constituent. If percentages are provided, we'll assume that there is a total mass of 100 grams, making each element's mass equal to the specified percentage.

Convert each element's mass to a mole by using its molar mass from the periodic table. Multiply the lowest calculated number of moles by each mole value. To the nearest entire number, round up. The mole ratio of the elements is indicated by subscripts in the empirical formula.

If the number is too large to round off, multiply each response by the same factor to obtain the lowest whole number multiple (x.1 – x.9). Like multiplying each solution in the problem by 4 to get 5, if one solution is 1.25. Then multiply each subscript of the empirical formula by the integer multiple

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A. Slow, legato. for a love story, we use slow and legato tempo to reflect the mood when the ice cream van interrupted the wedding ceremony.

The beats per minute are the most precise way for a composer to specify the intended speed (BPM). This means that a specific note value is designated as the beat (for instance, a quarter note), and the marking specifies that a specific number of these beats must be performed each minute.

The music's performance speed is thus determined by the tempo. So you can rapidly establish the Beats Per Minute, or BPM, by counting how many beats there are in a music played at a particular rate. If you're pushed for time, you can also double the amount of beats in 15 seconds of music by four.

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(a) Normalization factor for wavefunction 1 is, [tex]A = \sqrt{\dfrac{3^3}{{(16\pi a^5)}}[/tex], for wavefunction 2 is, [tex]B = \sqrt{\dfrac{15}{16\pi a^5}}[/tex]. The two wavefunctions are mutually orthogonal. (b) The expectation value of r for [tex]\psi_1[/tex] is 32.

(a) To normalize the wavefunctions, we need to find the normalization constants A and B such that

[tex]\int \|{\psi_1}\|^2 dV = 1[/tex] and [tex]\int \|{\psi_2}\|^2 dV = 1[/tex]

where [tex]\psi_1[/tex] and [tex]\psi_2[/tex] are the two wavefunctions given.

(i) [tex]\psi_1 = (2 - \dfrac{r}{a}) \times e^{\dfrac{-r}{2a}}[/tex]

The normalization condition for psi1 is:

[tex]\int \|\psi_1\|^2 dV = \int \{2 - \dfrac{r}{a} \times e^{\dfrac{-r}{a}}\}^2 r^2 sin\theta dr d\theta d\phi\\\\ = 1[/tex]

Evaluating the integral using spherical coordinates, we get:

[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} [(2 - r/a)^2 e^{-r/a} r^2 sin\theta]\ dr\ d\theta\ d\phi = 1\\\\\dfrac{(16\pi a^5)}{(3^3)} \times \|A\|^2 = 1\\A = \dfrac{3^3}{{(16\pi a^5)}^{0.5}}[/tex]

(ii) [tex]\psi_2 = r sin\theta\ cos\phi\ e^{\dfrac{-r}{2a}}[/tex]

Evaluating the integral using spherical coordinates, we get:

[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} r^4 sin^3\theta cos^2\phi e^{-r/a} dr\ d\theta\ d\phi = 1\\\\\dfrac{16\pi a^5}{15} \times \|B\|^2 = 1\\B = \sqrt{\dfrac{15}{16\pi a^5}}[/tex]

To confirm that the two wavefunctions are mutually orthogonal, we need to evaluate the integral [tex]\int \psi_1\times \psi_2 dV[/tex] and show that it is equal to zero. Using spherical coordinates, we get:

[tex]\int_0^\infty \int_0^\pi \int_0^{2\pi} [(2 - r/a) \times e^{-r/a} \times r sin\theta cos\phi \times e^{-r/2a}]\ r^2\ sin\theta\ dr\ d\theta\ d\phi\\\\= 8\pi a^5 \times [\int_0^\infty e^{-r/a} r^2 (2 - r/a) e^{-r/2a}\ dr] \times [\int_0^\pi sin\theta\ cos\theta\ d\theta] \times [\int_0^{2\pi} cos\phi\ d\phi]\\= 0[/tex]

Therefore, the two wavefunctions are mutually orthogonal.

(b) To evaluate the expectation values of r and r^2, we need to calculate the integrals [tex]\int psi_1 \times r\ \psi_1 dV[/tex] and [tex]\int \psi_1 \times r^2\ \psi_1 dV[/tex]. Using spherical coordinates, we get:

For psi1:

[tex]\int psi_1 \times r\ \psi_1 dV = 4\pi \int_0^\infty (2 - r/a)^2 e^{-r/a} r^4 dr\\\\ = \dfrac{32\pi a^5}{15}[/tex]

[tex]\int \psi_1 \times r^2\ \psi_1 dV = 4\pi \int (2 - r/a)^2 e^{-r/a} r^5 dr\\\\ = \dfrac{128\pi a^6}{45}[/tex]

Therefore, the expectation value of r for [tex]\psi_1[/tex] is 32.

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The correct order from dimmest to brightest as these stars would appear in the sky is Star C (0.0), Star A (0.4), Star D (4.2), Star B (5.6).

Apparent magnitude is a measure of the star brightness as seen from the Earth. Lower magnitudes indicate brighter stars and higher magnitudes indicate dimmer stars.

In the case of the four stars listed, Star C has the lowest magnitude of 0.0, making it the brightest of the four. Star A is slightly dimmer with a magnitude of 0.4. Star D is dimmer still with a magnitude of 4.2, and Star B is the dimmest of the four with a magnitude of 5.6. It's important to note that this is just a relative comparison and does not necessarily indicate the true brightness of the stars, only how bright they appear from our perspective on Earth.

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To find the resultant force and magnitude of charges in a right-angled triangle, you need to use Pythagorean theorem and principles of electrostatics respectively.

The magnitude of the charges can be determined using Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

To find the resultant force, you need to resolve each individual force into its x and y components and then add them up vectorially.

The magnitude of the resultant force can then be found using the Pythagorean theorem, which states that the magnitude of the resultant force is equal to the square root of the sum of the squares of its x and y components.

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The resultant force acting on the gate is equal to zero, the gate will not rotate and the pin can be placed at any location on the circumference of the gate.

To determine the placement of the pin on the circular gate, we need to consider the forces acting on the gate when the water reaches a height h = 10 ft.

When water reaches a height h = 10 ft, the gate is subjected to two types of forces: (1) buoyant force and (2) weight of the gate. The buoyant force acts upwards and is equal to the weight of the fluid displaced by the gate. The weight of the gate acts downwards and is equal to the mass of the gate multiplied by the acceleration due to gravity (g).

Let's assume that the gate has a uniform thickness and its density is equal to the density of water (ρ). Then, the volume of the gate can be calculated as follows:

V = (π/4) * d² * t

where d is the diameter of the gate and t is its thickness. The mass of the gate can be calculated as follows:

m = ρ * V

The buoyant force can be calculated as follows:

F_b = ρ * g * V

The weight of the gate can be calculated as follows:

F_w = m * g

The net force acting on the gate can be calculated as the difference between the buoyant force and the weight of the gate:

F_net = F_b - F_w = ρ * g * V - m * g = (ρ - ρ) * g * V = 0

Since the net force is equal to zero, the gate will not rotate and the pin can be placed at any location on the circumference of the gate.

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Answer:

When you know both the speed and direction of an object's motion, you know the velocity of the object.

Increase in small-artery pressure would increase capillary hydrostatic pressure most.

What are oncotic pressure and capillary hydrostatic pressure?

The systemic perfusion of the capillary, the arterial and venous pressures, and the variation in capillary resistance all affect the hydrostatic pressure. Oncotic pressure results from the inability of plasma proteins to easily pass the capillary membrane, particularly albumin.

Because of the hydrostatic pressure, fluid leaks through the capillary's pores and into the interstitial space as the blood travels along it. As the blood flows down the capillary from the arterial to the venous end, the pressure exerted by the blood will decrease.

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Answer:

Explanation:

The overall displacement can be found using the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the overall displacement) is equal to the sum of the squares of the other two sides.

Let's call the displacement in the northwest direction "x" and the displacement in the east direction "y". The overall displacement can be found using the equation:

√(x^2 + y^2) = √((-10)^2 + (40)^2 + (-60)^2) = √(1600 + 1600 + 3600) = √(7000) = 84.85 km

So the overall displacement of the car from the starting point is approximately 84.85 km.

0.00455 moles of air must be released from the tire to restore the pressure to 210 kPa at 50 degrees C.

The pressure rise in a 0k tire when the air temperature rises from 25 degrees C to 50 degrees C can be calculated using the ideal gas law. The formula is

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature. In this case, the temperature is rising from 25 degrees C to 50 degrees C, so the pressure will increase with the temperature.

By plugging these values into the equation, we can calculate that the pressure increase is 45.5 kPa.

To restore the pressure to its original value of 210 kPa at 50 degrees C, we need to bleed off the amount of air equal to the pressure increase. This is equal to 45.5 kPa, or 0.00455 moles. This means that 0.00455 moles of air must be released from the tire to restore the pressure to 210 kPa at 50 degrees C.

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The total energy of the system remains constant.

Option B.

The law of conservation of energy states that energy can neither be created nor destroyed but can be transferred from one form to another.

When you let go of the book,  and it is pushed up by the spring, the elastic potential energy of the spring will be converted into potential energy and kinetic energy of the block.

elastic potential energy = potential energy + kinetic energy

Thus, we can conclude that the total energy of the system is constant.

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