1.If you looked back at Earth from the moon, what phase would Earth have when the moon was full? New? First quarter? Waxing crescent?

Answers

Answer 1

The phase that the Earth would have when the Moon was full if we looked from the moon would be new phase.

The Moon and Earth are both always partially lit by the Sun. However, from either world, you can see varied portions of that lighted half - or different phases of the Earth or moon - at any given time. The phases usually follow a pattern in which they are inverted relative or reversed to one another.

Any moon resident would see a narrow crescent Earth when the moon is nearly full. The moon, Earth, and sun form a line with Earth in the middle when we observe a full moon. The Earth would then be completely obscured by the sun's brightness, making it invisible to those on the moon. Therefore, the phase that the Earth would have looked from the Moon would be the new phase because the opposite of a full moon phase is a new moon.

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Related Questions

A student sees a mirror image of a tree in a pond on a very still day. The student is able to see a mirror image of the tree in the pond because light
striking the surface of the water -
bends downward.
bounces off.
becomes brighter.
is absorbed.

Answers

Answer:

B.

Explanation:

What causes a reflection in still water?

Reflection in water is caused when light hits the surface of still water and travels to our eye so we can see the complete image and light it's reflecting.

All materials reflect light in some way.

Hope it helped!

page 29 1.4. how is anthropology changing today? identify the ways anthropologists are adapting to the current era of intensified globalization.

Answers

Ways Anthropologists are adjusting by focusing on the ways that migration and communication patterns connect groups and by altering their study methodologies.

The anthropologist's job description:

Anthropologists as well as archaeologists both research the origin, progress, and behaviors of individuals. They examine global linguistic and cultural diversity, physical characteristics, and artifacts found in archaeology. creating research plans that include underrepresented topics. using research methods that make advantage of an extensive study design. promoting the use of collaborative techniques to co-create material

What do anthropologists study?

Anthropology compares human communities across borders and through time. For instance, we contrast the current and earlier legal and religious systems. While contrasting political systems, including family relationships, we look at multinational organizations.

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Two balls are rolling directly toward each other. One, of mass 0.25 kg, has a speed of 1.7 m/s; the other has a mass of 0.18 kg and a speed of 2.5 m/s. After the collision, the 0.25 kg ball has reversed its direction and has a speed of 0.10 m/s. What is the velocity (magnitude and direction) of the other ball?
m/s direction:
(same/opposite) direction of initial motion for ball

Answers

The velocity of the balls that rolling directly toward each other. One, of mass 0.25 kg, has a speed of 1.7 m/s; the other has a mass of 0.18 kg and a speed of 2.5 m/s. After the collision, the 0.25 kg ball has reversed its direction and has a speed of 0.10 m/s = 0 (zero)

The linear momentum of a system of interacting objects equals the linear momentum of the system after the interaction if the net force acting on the system of interacting objects is zero.

The equation:

p = mv

Where,

p = momentum

m = mass of the object

v = the velocity of the object.

p₁ = p₂

(mv + mv)₁ = (mv + mv)₂

(0.25 x 1.7) = (0.25 x (-0.10)

v₂ = 0

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A 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C. How much heat was absorbed?

Answers

A 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C. The amount of heat absorbed will be 96000 KJ.

What is Heat energy?

Thermal energy refers to the energy which is contained within a system that is responsible for the temperature. Heat is the flow of thermal energy in the system.

Given that,

Mass, m = 193.4 g

We know that,

Q₁ = mcΔt

Q₁ = 193.4 × 4200 × (131.1 - 13.5)

Q₁ = 193.4 × 4200 × 117.6

Q₁ = 95,524,128 Joules

Now, the latent heat

Q₂ = mL

Q₂ = 193.4 × 2260

Q₂ = 437,084 Joules

Now, the total heat energy required,

Q = Q₁ + Q₂

Q = 95,524,128 + 437,084

Q = 95,961,212 Joules

Therefore, the heat energy is approximately 96000 KJ.

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Your question is incomplete, most probably the complete question is:

Calculate the heat energy required to convert completely a 193.4 g sample of water at 13.5°C is heated to steam at 131.1°C, given that the specific heat capacity of water is 4200 J/(kg°C) and the specific latent heat of vaporization of water is 2260 kJ/kg.

Find the distance traveled by a climber if she climbs 10 meters up and then repels 10 meters back down. Include both magnitude and direction.

Answers

Answer:

Explanation:

Let up be the + direction.

Distance is the total length traveled.

Distance = 10 + 10 = 20 m

Displacement = 10 - 10 = 0

from a boat, the angle of elevation of the foot of a lighthouse on the edge of a cliff is 34 degrees. if the cliff is 150m high, how far from the base of the cliff is the boat

Answers

Answer:

Therefore, the boat is approximately 229.7 meters from the base of the cliff.

Explanation:

Let the horizontal distance between the boat and the foot of the lighthouse be x. Then, the angle of elevation of the top of the lighthouse from the boat is 90° - 34° = 56°.

We can use trigonometry to relate the angles and sides of the right triangle formed by the boat, the foot of the lighthouse, and the top of the lighthouse.

Taking the tangent of the angle of elevation of the foot of the lighthouse, we get:

tan(34°) = opposite/hypotenuse

tan(34°) = 150/x

Multiplying both sides by x, we get:

x * tan(34°) = 150

x = 150 / tan(34°)

x ≈ 229.7 meters

Therefore, the boat is approximately 229.7 meters from the base of the cliff.

A thin circular disk of radius R = 30 cm is oriented in the yz-plane with its center as the origin. The disk carries a total charge Q = +3 mu C distributed uniformly over its surface. Calculate the magnitude of the electric field due to the disk at the point x = 15 cm along the x-axis. 4.98 times 10^5 N/C 2.49 times 10^5 N/C 3.32 times 10^5 N/C 9.95 times 10^5 N/C 1.99 times 10^5 N/C

Answers

The magnitude of the electric field due to the disk at the point x = 15 cm along the x-axis is approximately 2.99 x 10⁶ N/C. Rounded to two significant figures, the answer is 3.0 x 10⁶ N/C.

What is the magnitude?

The magnitude of a physical quantity is a measure of the size of that quantity, and is usually expressed using an appropriate unit of measurement. Magnitude is a way of expressing the size of something without specifying its exact size. For example, when referring to the magnitude of an earthquake, one might say "it was a magnitude 7 earthquake".

To calculate the electric field at a point on the x-axis due to a uniformly charged disk, we can use the formula:

[tex]\mathrm{E = (1/4\pi \p \epsilon_0) \times Q / r^2 \times sin(\theta)}[/tex]

where ε₀ is the permittivity of free space,

Q is the total charge on the disk, r is the distance from the center of the disk to the point where we want to calculate the electric field,

and θ is the angle between the normal to the disk and the line connecting the center of the disk to the point where we want to calculate the electric field.

In this problem, the disk is oriented in the yz-plane, so the normal to the disk is in the x-direction. The distance from the center of the disk to the point where we want to calculate the electric field is 15 cm.

The angle θ is the angle between the normal to the disk and the line connecting the center of the disk to the point where we want to calculate the electric field.

Since the disk is centered at the origin, the line connecting the center of the disk to the point on the x-axis is also in the x-direction, so θ = 0.

We can therefore simplify the formula to:

[tex]\mathrm{E = (1/4\pi \p \epsilon_0) \times Q / r^2 }[/tex]

Substituting the given values, we get:

[tex]\mathrm{E = (1/4\pi \p \epsilon_0) \times (3\mu C) / (0.15)^2 }[/tex]

We can calculate the value of 1/4πε₀ as 9 so:

[tex]\mathrm{E = (9.0 \times 10^9 \ N \cdot m^2/C^2) \times (3\mu C) / (0.15)^2 }[/tex]

E = 2.99 x 10⁶ N/C

Therefore, the magnitude of the electric field due to the disk at the point x = 15 cm along the x-axis is approximately 2.99 x 10⁶ N/C. Rounded to two significant figures, the answer is 3.0 x 10⁶ N/C.

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a position-type motion control system is in an instability condition when overshoot and oscillations occur. (true or false)

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True, a position-type motion control system is in an instability condition when overshoot and oscillations occur.

What kinds of motion control systems are there?

Motion control systems can be classified as either open loop or closed loop. The fundamental distinction between the two is that closed systems use feedback whereas open loop systems do not. The distinction between open  and closed loop systems is discussed in more detail here.

Any transient value of a parametric measurement that exceeds its steady-state or final value while transitioning from one value to another is referred to as overshoot. When a parameter transitions from one value to another, overshoot refers to the temporary values that are greater than their final (steady state) value in electronics.

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aball of mass 2kg has a diameter of 50cm falls in the pool. calculate its buoyant force and volume of water displaced?

Answers

The buoyant force and volume of water displaced are 19.6 N and 0.065 [tex]m^{3}[/tex] respectively.

Explanation:

According to Archimedes' principal, When a body is immersed fully or partially in a fluid, the the body experiences an upward force called buoyant force which is equal to the weight of fluid dispersed.

Buoyant force ([tex]F_{b}[/tex]) = mg

where, m is the mass of ball

            g is acceleration due to gravity i.e. 9.8 [tex]ms^{-2}[/tex]

From the question putting the values we get,

[tex]F_{b} =[/tex] 2×9.8 = 19.6 N

Now,

Water displaced = Volume occupied by the ball

                          [tex]= \frac{4}{3} \pi r^{3}[/tex] ( as ball is sphere)

                            {diameter of the ball = 50cm or, 0.5m  So radius =[tex]\frac{0.5}{2}[/tex]}

                          =     [tex]\frac{4}{3}*\frac{22}{7}*(\frac{0.5}{2}) ^{3}[/tex]    

                          [tex]=\frac{4}{3}[/tex] × [tex]\frac{22}{7}[/tex]×[tex]\frac{0.125}{8}[/tex]

                          [tex]= \frac{4}{3}[/tex] × [tex]\frac{22}{7}[/tex] × [tex]\frac{125}{8000}[/tex]

                          [tex]= 0.065 m^{3}[/tex]

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A cello string vibrates with a frequency of 64 Hz. If the wavelength of t waves in the string is 180 cm, calculate the wave speed.​

Answers

Answer:

V=115.2m/s

Explanation:

V=fλ

where v=wave speed,f=frequency,λ=wavelength

convert 180cm to m

1.8m

V=64×1.8

V=115.2m/s

Vector A⃗ =2i^+3j^ and vector B⃗ =2i^−2j^+4k^ .

Answers

The summation of the two vector quantities  is [tex]4 \hat{i} + \hat{j} + 4 \hat{k}[/tex].

What is vector quantity?

In physics, a vector is a quantity with both a magnitude and a direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity. A vector does not have position, while having magnitude and direction.

Ordinary quantities with a magnitude but no direction are referred to as scalars in contrast to vectors. For instance, while speed, time, and mass are scalars, displacement, velocity, and acceleration are vector quantities.

Given [tex]\vec{A} =2\hat{i} +3\hat{j}[/tex] and [tex]\vec{B} = 2 \hat{i} -2\hat{j} + 4 \hat{k}[/tex]

Hence,

[tex]\vec{A}+\vec{B} = 4 \hat{i} + \hat{j} + 4 \hat{k}[/tex]

Hence, sum of the two given vector quantity is [tex]4 \hat{i} + \hat{j} + 4 \hat{k}[/tex].

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what is the radius of the first null in the diffraction pattern at the moon? recall the formula for diffraction from a circular aperture from chapter q3.

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The radius of the first null in the diffraction pattern at the moon would be approximately 9.64 mm

The radius of the first null in the diffraction pattern at the moon can be calculated using the formula for diffraction from a circular aperture. The formula for the radius of the first null, or the first dark fringe, is given by:

r = λ × D / a,

where λ is the wavelength of light, D is the distance from the aperture to the screen, and a is the radius of the circular aperture. In the case of diffraction at the moon, the aperture is the diameter of the moon, and the screen is the observer's eye or a detector. The diameter of the moon is approximately 3,476 kilometers, and the distance from the moon to the Earth is approximately 384,400 kilometers. The wavelength of light used for observation can vary, but for visible light, it is typically in the range of 400 to 700 nanometers.

By substituting these values into the formula, we can calculate the radius of the first null in the diffraction pattern at the moon.

Let's assume a wavelength of 550 nm (visible light) and use the average value for the diameter of the moon (3,476 km) as the radius (1,738 km) in the calculation.

r = λ × D / a

= (550 × [tex]10^{-9}[/tex] m) × (384,400 × [tex]10^{3}[/tex] m) / (1,738 × [tex]10^{3}[/tex] m)

= 0.000964 m = 9.64 mm

So, the radius of the first null in the diffraction pattern at the moon would be approximately 9.64 mm when observed with a wavelength of 550 nm and the average diameter of the moon as the radius of the circular aperture.

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. A steel bar 35mm by 35mm in section and 100mm in length is acted upon by a tensile load of 180KN along its longitudinal axis and 400kN and 300kN along the axes of lateral surfaces as shown in figure 2 below. Determine: (i) change in the dimensions of the bar (ii) change in volume Take E = 205 GPa Poisson's ratio (v) = 0.3​

Answers

(i) The change in length is 8.78 x 10⁻⁸ m and the change in the width is -2.63 x 10⁻⁸ m

(ii) The change in volume of the bar is  7.53 x 10⁻¹¹ m³.

What is the change in the dimensions of the bar?

The bar undergoes elongation and reduction in cross-sectional area due to the applied loads.

Using the formula for longitudinal strain, we can calculate the change in length (ΔL) as follows:

ΔL = (180 × 10³ N) x (100 × 10⁻³ m) / (205 × 10⁹ N/m²)

ΔL = 8.78 x 10⁻⁸ m

The change in width (Δb) can be calculated using the formula for lateral strain:

Δb = -v x ΔL = -0.3 x  ΔL

Δb = -0.3 x 8.78 x 10⁻⁸ m

Δb = -2.63 x 10⁻⁸ m

The change in volume can be calculated as follows:

ΔV = (35 × 10⁻³ m)  x (35 × 10⁻³ m) x (ΔL + Δb)

ΔV =  (35 × 10⁻³ m) x  (35 × 10⁻³ m) x (ΔL - 0.3 x ΔL)

ΔV =  (35 × 10⁻³ m) x  (35 × 10⁻³ m) x (8.78 x 10⁻⁸m -2.63 x 10⁻⁸ m)

ΔV = 7.53 x 10⁻¹¹ m³

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study of bluefish locomotion found that their tail motion produces an average thrust of 0.65 N . Suppose a 1.7 kg bluefish that is coasting horizontally at 0.45 m/s suddenly begins tail motion.

Answers

Answer:

he fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion

Explanation:

The initial horizontal velocity of the bluefish is 0.45 m/s. When it begins tail motion, it experiences an additional force due to the thrust produced by the tail. The thrust produced by the tail is 0.65 N. We can use Newton's second law to find the acceleration produced by this force:

F = ma

0.65 N = 1.7 kg * a

a = 0.38 m/s^2

This acceleration will cause the velocity of the bluefish to increase over time. The distance the fish travels during this time can be calculated using the kinematic equation:

d = vit + 1/2 at^2

where d is the distance traveled, vi is the initial velocity, a is the acceleration, and t is the time. Since the fish is initially coasting horizontally, its initial vertical velocity is 0 m/s. Therefore, vi = 0.45 m/s. The time interval for which the fish is tail-motoring is not given, so let's assume it is 2 seconds:

d = (0.45 m/s)(2 s) + 1/2 (0.38 m/s^2)(2 s)^2

d = 1.78 meters

Therefore, the fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion.

what can you say about the direction of the electric field from a negative charge? the electric field from a negative charge points ...

Answers

The electric field from a negative charge points is radially inward due to a negative charge.

What is electric field?

An electric field is a physical fridge and it by the electric charges that exert a force on other charges extracting or appealing them. Electric electrocuted by electric chargers either stationary or moving the electric field is a vector field meaning that it is both thank you and direction the strength of the electric field is measured in moles per metre electric field and used in a variety of application from our generation to medical treatments.

When you move in an electric field, the electric potential changes since the electric field is a vector field. However, if you move perpendicular to the electric field, the electric potential remains unchanged. This is because the electric field strength is constant in all directions, except in the direction of the electric field. Therefore, if you move perpendicular to the electric field, the electric potential does not change.

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how much work did the movers do horizontally pushing a 46 kg crate 10.3 across a rough floor without acceleration, if the effective coefficient of friction was 0.5

Answers

The work done is  2321 J.

What is the work that is done?

We have to note that the acceleration has to do with the change in the velocity of the object with time. We are told that there is a movement of the crate as we can see. Let us note that the work that is done by the object subtracted from the work done by the friction. Thus we have that;

Work = (46 * 9.8 * 10.3) - (0.5 * 46 *9.8 *  10.3)

Work = 4643 - 2321

= 2321 J

The work that has been done is  2321 J. This is done in  moving the object

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Help please how do you do this

Answers

The impulse is given as -75 n.s

How to solve for impulse

We would first have to solve for the initial momentum and then the final momentum

The initial momentum is given as 6 x 5 = 30

The final momentum = -9 x 5 = -45

Then the impulse would be the change in momentum which is gotten as

I = Pf - Pi

I = -45 - 30

I = -75

The impulse is given as I = -75

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True/Falseat any given point, the net electric field can point in multiple directions at any given point, the net electric field is the vector sum of all component electric fields

Answers

At any given point, the net electric field can point in multiple directions at any given point, the net electric field is the vector sum of all component electric fields - False

What is the electric field?

The electric field is a measure of the electric force experienced by a charged particle in a specific location. It is a vector field, meaning it has both magnitude and direction.

The electric field at a particular point in space can be visualized as a field of force lines that emanate from positive charges and converge towards negative charges. The strength of the electric field is proportional to the number of force lines and the direction of the field is the direction that a positive test charge would experience a force if placed at that point.

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The enthalpy of vaporization of Substance X is 21.0 kj/mol and its normal boiling point is 19. C Calculate the vapor pressure of X at -98. C Round your answer to 2 significant digits.

Answers

The vapor pressure of Substance X at -98. C is 1.01 atm, rounded to 2 significant digits.

What is vapor pressure?

Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase. It is an indication of a liquid's evaporation rate. It is directly related to the vapor's temperature, and increases with increasing temperature.

ln (P2/P1) = (ΔHvap/R) * ((1/T1) – (1/T2))
where:
P2 = vapor pressure of the substance at temperature T2
P1 = vapor pressure of the substance at temperature T1
ΔHvap = enthalpy of vaporization of the substance
R = ideal gas constant
T1 = normal boiling point of the substance
T2 = temperature at which the vapor pressure is being calculated
In this case, we are trying to calculate the vapor pressure of Substance X at -98. C.
We can plug in the known values into the equation to calculate the vapor pressure of Substance X at -98. C:
ln (P2/P1) = (21.0 kj/mol/8.314 J/mol-K) * ((1/19) – (1/273))
ln (P2/P1) = 0.0087
P2 = exp (0.0087) * P1
P2 = 1.009 * P1
P2 = 1.009 * 1.00 atm (atm is the vapor pressure of Substance X at 19. C, its normal boiling point)
P2 = 1.009 atm
Therefore, the vapor pressure of Substance X at -98. C is 1.01 atm, rounded to 2 significant digits.

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An electronic package with a surface area of 1 m2 placed in an orbiting space station is exposed to space. The electronics in this package dissipate all 1950 W of its power to space through its exposed surface. The exposed surface has an emissivity of 1.0 and an absorptivity of 0.25. Given: 0 = 5.67x10-8 W/m2K4Determine the steady state exposed surface temperature of the electronic package if the surface is not exposed to the sun. If the surface is not exposed to the sun, the surface

Answers

The electronic package's steady state temperature can be calculated using the Stefan-Boltzmann Law, which states that the total energy radiated per unit surface area per unit time is proportional to the fourth power of the temperature.

The electronic package's energy balance equation is as follows:

Power absorbed minus power radiated equals power generated.

where P = absorptivity * incoming radiation P = emissivity * Stefan-Boltzmann constant * T4 Power generated = 1950 W (constant)

Because the surface is not in direct sunlight, we can assume that the incoming radiation is 0 and the power absorbed is 0.

Thus, the energy balance equation becomes:

0 - Power radiated = 1950 W

or

Power radiated = 1950 W

We can use the Stefan-Boltzmann Law to calculate the surface temperature:

Power radiated = emissivity * Stefan-Boltzmann constant * T^4

1950 W = 1 * 5.67 x 10^-8 W/m2K^4 * T^4

T^4 = (1950 / (5.67 x 10^-8))

T = ( (1950 / (5.67 x 10^-8))^(1/4))

The electronic package's steady state temperature is the temperature at which the amount of power generated by the electronics equals the amount of power radiated to space.

Full question.

An electronic package with a surface area of 1 m2 placed in an orbiting space station is exposed to space. The electronics in this package dissipate all 1 kW of its power to the space through its exposed surface. The exposed surface has an emissivity of 1.0 and an absorptivity of 0.25.Given: 0 = 5.67x10-8 W/m2K4  Determine the steady state exposed surface temperature of the electronic package (a) if the surface is exposed to a solar flux of 750 W/m2, and (b) if the surface is not exposed to the sun.

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A rod of length 2a with total charge Q uniformly distributed along its length is placed along the zaxis with its center at the origin. Find the electric field everywhere?

Answers

The electric field due to a charged rod of length 2a with total charge q uniformly distributed along its length, placed along the z axis with its center at the origin.

Through the application of Coulomb's equation and the concept of superposition, we can determine the electric field everywhere caused by the charged rod. The electric field due to a tiny piece of the rod at a point P in space is given by:

dE = k dq / r²

where

k = Coulomb's constant,

dq i= the segment's charge,

r = the segment's distance from point P, and

dE = the segment's contribution to the electric field.

We integrate this formula along the entire length of the rod, from -a to +a, to determine the total electric field at P as follows:

E = ∫ dE = k ∫ dq / r²

where the rod's length is used as the integral. The charge per unit length of the rod, or dq, can be expressed in terms of the charge density as dq = ds, where ds is an element along the rod with an infinitesimal length. r = √(s² + z²) where z is the segment's distance from the z axis, we can also describe r in terms of the distance s from the origin to the segment.

E = k ∫ dq / r^2 = k ∫ λ ds / (s² + z²)

E = k λ z ∫_{-arctan(a/z)}^{arctan(a/z)} dθ / (1 + (a/z)² tan² θ)

E = k λ z / (2πε_0) ∫_{-a/z}^{a/z} du / (1 + u²)

E = k λ z / (2πε_0) [arctan(a/z) - arctan(-a/z)]

E = k λ a / (2πε_0 z√(a² + z²))

This is the equation for the electric field produced by a charged rod of length 2a, arranged along the z axis with its center at the origin, and with total charge q evenly distributed throughout its length. The electric field radiates outward from the rod, and as you move away from the rod, its strength diminishes as 1/r².

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If the magnitude of the resultant force acting on the bracket is to be 430 N directed along the positive u axis, determine the magnitude of F. (Figure 1) Express your answer with the appropriate units. - LHẢ * * 0 Ea ? F1 - 480.5 N Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining Review your calculations, you may have made a rounding error or used the wrong number of significant figures. Part B Determine the angle o Express your answer with the appropriate units. < 1 of 1 > CHAO ? $ = 8.619 30° F = 200 N Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Review your calculations, you may have made a rounding error or used the wrong number of significant figures. F; 260 N

Answers

If the magnitude of the resultant force acting on the bracket is to be 430 N directed along the positive u-axis, the magnitude of F is as follows:

The vector components should be drawn which is acting on the bracket as follows.

The x and y components of each force are represent by the dashed arrows. Force, (in blue) is along the x-axis, thus it has no y-component.

Now, the resultant force is drawn (as stated in the question) and its components also.

After this, can now write the x and y component values of each force.

(F1)x = F1 sinϕ

(F1)y = F1 cosϕ

(F2)x =200N

(F2)y = 0

(F3)x = 260(5/13)=100N

(F3​) y =260( 12/13 )=240N

(FR)x =450 cos 30 =389.71N

(FR) y =450 sin 30 =225N

Next is to sum the forces along the x and y axes. To do this, we will establish the positive sides. Pick the forces acting up, and forces acting to the right to be positive.

+→∑(FR) x =∑(Fx)

389.71= F1 sinϕ+200+100

F1 sinϕ=89.71———————————(1)

+↑∑(FR)y=∑(Fy)

225 = F1 cosϕ−240

F1 cosϕ=465———————————(2)

The last step is to solve equations (1) and (2) simultaneously. To do so, remember the identity, sinθ/cosθ = tanθ

Solving gives us:

ϕ=10.9 and F1 = 474N

Therefore, the ϕ=10.9 and F1 = 474N

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A positive point charge Q is located at x=a and a negative point charge −Q is at x=−a. A positive charge q can be placed anywhere on the y-axis.
1) Find an expression for (Fnet)x, the x-component of the net force on q. (Give your answer in terms of Q, q, a, y and constant K.)

Answers

The expression for (F net)x when the position of Q and -Q are given, is calculated to be Fx = 2k Qqa/[(a² + y²)]^3/2 x^.

Coulomb's law establishes that the electric force exerted by a point charge q₁ on q₂ is proportional to the values of the charges and inversely proportional to the square of the distance between them. Coulomb obtained this dependence experimentally and introduced a proportionality constant in its law, k = 9 × 10⁹ N m²/c² is coulomb's constant.

Mathematically, Coulomb's law is,

F = k q₁ q₂/r² r^

Let us denote the position of the charge q on the y-axis as 'y'.

The force between 'Q' and'q' is

F₁ = k Qq/(x² + y²)

F₁x = F₁ cosθ

where,

θ is the angle between F₁ and x-axis

F₁x = [k Qq/(x² + y²)] [x/√(x² + y²)]

when x = a, F₁x = k Qqa/[(a² + y²)]^3/2

F₂x = k × -Qq/(a² + y²) × [-a/√(a² + y²)]

Thus, the x-component of the net force,

Fx = 2k Qqa/[(a² + y²)]^3/2 x^

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in the proton-proton chain select all that apply a.no neutrinos are produced.
b.energy is released because a helium nucleus has a greater mass than a hydrogen nucleus.
c.no photons are produced.
d.carbon serves as a catalyst for the nuclear reaction.
e.energy is produced in the form of gamma rays and the velocity of the created nuclei.

Answers

The proton-proton chain is a series of nuclear reactions that take place in the cores of stars and are responsible for producing energy through fusion.

Option b and e will apply for the proton-proton chain.

In the chain, hydrogen nuclei (protons) collide and combine to form helium nuclei, releasing energy in the process.

b. Energy is released because the mass of the helium nucleus formed from the combination of two hydrogen nuclei is less than the total mass of the two individual hydrogen nuclei.

This difference in mass is converted into energy according to Einstein's equation, [tex]E=mc^2[/tex], where E is energy, m is mass and c is the speed of light.

e. Energy is produced in the form of gamma rays and the velocity of the created nuclei. The high-energy gamma rays and fast-moving helium nuclei carry away the energy released in the reaction.

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determine for what energy above ef (in terms of kt) the boltzmann approximation has an error less than 1%. (b) give the value of the probability function at this energy

Answers

The probability function at this energy where the Boltzmann approximation has an error less than 1%. (b) is given by

 P(E) = (1/Z) * (1/100) * exp(-Ef/kT).

What is Boltzmann approximation?

The Boltzmann approximation states that the probability of a particle being in a state of energy E is proportional to the exponential of negative E divided by kT,

where

k is the Boltzmann constant and

T is the temperature in kelvins.

So, the probability function can be written as:

P(E) = (1/Z) * exp(-E/kT),

where

Z is the partition function, which normalizes the probabilities to add up to 1.

To find the energy above Ef (Ef is the Fermi energy) where the Boltzmann approximation has an error less than 1%, we can solve for the energy E such that P(E) is equal to 1% of the maximum probability P(Ef). We can set the following equality:

P(E) = 0.01 * P(Ef)

P(E) = 0.01 * (1/Z) * exp(-Ef/kT)

Rearranging and substituting the expression for P(E) from the Boltzmann approximation, we get:

E = Ef - kT * ln(100).

So, the energy above Ef where the Boltzmann approximation has an error less of than 1% is Ef minus kT times the natural logarithm of 100.

For the value of the probability function at this energy, we can use the expression for P(E) from the Boltzmann approximation:

P(E) = (1/Z) * exp(-E/kT)

P(E) = (1/Z) * exp(-(Ef - kT * ln(100))/kT)

P(E) = (1/Z) * (1/100) * exp(-Ef/kT).

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Determination of unknown resistance In order to determine the nature of an electric component (D) we set up an electric circuit as follows → The electric component (D) is connected to a DC generator of adjustable voltage * An ammeter (A) is connected to measure the current I that traverse (D) A voltmeter (V) is connected to measure the voltage U across (D) 1- Draw a diagram that represent this electric circuit.​

Answers

Here is a straight forward schematic showing the electrical circuit:

DC Generator ----> Component (D) ----> Ammeter (A) ----> Voltmeter (V)

What purpose does a DC generator serve?

The uses of DC generators

These generators are employed to power illumination, excite alternators, and charge cells. In Vdc railroads, they are utilized to supply dc current voltage for diesel generator. They are found in Stepper motor whenever rotary encoder is necessary.

How do DC generators operate?

A copper coil rotated in a magnetosphere induces a voltage, which is how a current (DC) generator operates. The voltage that is produced in the coil depends on how quickly the coil spins in the magnetosphere.

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the ampacity adjustment factors of 310.15(b)(3)(a) shall not apply to conductors installed in surface metal raceways where the __________.

Answers

conductors are not subjected to additional heat due to the raceway installation.that the raceway provides increased cooling and/or ventilation.

What is the ventilation ?

Ventilation is the process of providing fresh air to an enclosed space and removing stale air from the same space. It is an important factor in maintaining the quality of air in an environment, both in terms of temperature, humidity, and gaseous pollution. Ventilation is accomplished by either mechanically or naturally moving air from an area of high pressure, where it is typically warmer, to an area of lower pressure, where it is typically cooler. Mechanical ventilation is typically used in closed buildings or spaces, such as homes, offices, and industrial buildings, while natural ventilation relies on the natural flow of air through open windows, doors, and other openings.

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Rocks in the asteroid belt are traveling around the Sun at a distance of 3.2 Astronomical Units (AU). According to Kepler's Third Law, what is the orbital period of these rocks?
Recall Kepler's Third Law can be written as
P 2 = a 3
if the period is measured in (Earth) years and the distance is measured in AU. Follow the steps in Example 3.1 (just with a different distance value).
Pick the answer that's closest to your result:

Answers

The orbital period of the rocks in the asteroid belt is approximately 5.73 years.

What is the average distance, a, between the sun and the asteroid, expressed in astronomical units?

The distance from the Sun to the asteroid belt is between 2-4 AU, or between 300 and 600 million kilometers (186-272 million mi).

Using Kepler's Third Law, we have:

P² = a³

where P is the orbital period of the rocks in years, and a is the semi-major axis of their orbit in astronomical units (AU).

Substituting a = 3.2 AU, we get:

P² = (3.2 AU)³

P² = 32.768 AU³

P = [tex]\sqrt{32.768}[/tex] years

P ≈ 5.73 years

Therefore, the orbital period of the rocks in the asteroid belt is approximately 5.73 years.

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Internal hard disk is Select one: a. Removable but not fixed b. Not fixed c. Removable d. Fixed​

Answers

Internal hard disk is Removable but not fixed. Thus, option A is the correct answer.

What is Hard disk?

A hard disk drive (HDD) is a type of non-volatile storage device that stores digital data on rapidly rotating disks (platters) coated with magnetic material. Hard disk drives are commonly used in computers as the primary storage for the operating system and for user data, as well as in other devices such as external hard drives, network-attached storage (NAS) devices, and digital video recorders (DVRs). An HDD consists of one or more disks that spin at high speeds (usually 5,400 or 7,200 RPM) and are read from and written to by magnetic read/write heads that move across the disk surfaces. The data is stored on the disk in magnetic patterns, and the read/write heads can detect and change these patterns to read and write data.

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A light bulb that has a resistance of 3 Ω is connected to a 9 V battery.
What current will the bulb draw? A. 1/3 A B. 3 A C. 6 A D. 12 A E. 27 A
What is the bulb’s power? A. 1/3 W B. 3 W C. 6 W D. 12 W E. 27 W

Answers

Answer:

see below

Explanation:

We have ,

R = 3Ω V = 9V

So , from V = iR ,

i = V/R

i = 9/3 A

i = 3A [ option B ]

again, we know that, Power = v²/R , so ;

P = 9²/3 W

P = 27W [ option E ]

and we are done!

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