Rubber is not conducting and is called an insulator. Insulators provide resistance to the flow of electrons. Aluminum foil can be used to the copper wire to light up the bulb.
What are conductors ?Based on the conductivity, there are three types of materials namely, conductor, semiconductors and insulators. Conductors are able to allow the flow of free electron through them thus conduct electricity at room temperature.
Semiconductors only conduct at high temperature and insulators does not conduct at any temperature. Rubber is an insulator and thus used as protecting gloves for hands to prevent electric shock.
Salt crystals in the solid state are not conducting. But the salt solution is conducting due to the presence of ions.
The material which can be used connected to copper wire and a battery to light up a bulb is aluminum foil. Metals are good conductors because, its valence electrons flow freely through the material.
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Rubber, which is not conducting, is referred to be an insulator. Providing barrier to the movement of electrons is an insulator. Copper wire can be wrapped in aluminum foil to light the bulb.
How do conductors work?Three different categories of materials—conductors, semiconductors, and insulators—are categorized according to their conductivity. At normal temperature, conductors can flow free electrons through them and conduct electricity.
Insulators do not conduct at any temperature, while semiconductors only do so at high temperatures. Rubber acts as an insulator, making it ideal for use as hand protection against electric shock.
In the solid state, salt crystals are not conductors. But because ions are present, the salt solution conducts.
Therefore, Rubber, which is not conducting, is referred to be an insulator. Providing barrier to the movement of electrons is an insulator. Copper wire can be wrapped in aluminum foil to light the bulb.
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Circuits
Calculate the total Resistance, Current, and Power in the circuits
The total resistance of the circuit is 3 ohms.
The total current in the circuit is 4 A.
The power of the circuit is 48 W.
What is the total resistance of the circuit?
The total resistance of the circuit is calculated as follows;
1 / Rt = 1/R1 + 1/R2 + 1 / R3
1/Rt = 1/6 + 1/12 + 1/12
1/Rt = 0.3333
Rt = 3 ohms
The total current in the circuit is calculated as follows;
I = V / Rt
I = ( 12 ) / ( 3 )
I = 4 A
The power of the circuit is calculated as follows;
P = IV
P = ( 4 x 12 )
P = 48 W
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to what temp must 0.588 moles of ammonia gas have to be heated in a 15.0 L container in order for it to exert a pressure of 3,50 kPa?
According to the ideal gas law, 0.588 moles of NH3 gas in a 15.0 L container must be heated to a temperature of 1088.85 K or 815.85°C in order for it to impose a pressure of 3.50 atm.
What is Ideal gas law?Real gases are simplified into ideal gases to make them easier to understand. It is believed to be made up of point particles that move randomly and independently.
Additionally, it is believed that perfect gas molecules by themselves have no volume.
Three state variables—absolute pressure (P), volume (V), and absolute temperature—define an ideal gas (T). The ideal gas law, an equation that relates them, is based on their relationship.
Therefore, According to the ideal gas law, 0.588 moles of NH3 gas in a 15.0 L container must be heated to a temperature of 1088.85 K or 815.85°C in order for it to impose a pressure of 3.50 atm.
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A bottle of wine known as a magnum contains a volume of 1.5 liters. A bottle known as a jeroboam contains 0.792 U.S. gallons. How many magnums are there in 8 jeroboams?
Answer:
Explanation: =− And ..=. −=. = =. ( .. . ) ( . ..) =. Therefore = .=
A Martian is on Mars, where the acceleration
gravitational is gMars=0.38gEarth, the ball oscillates with a period of 1.5s when it swings like a pendulum. On a trip, the Martian finds himself on a planet where the ball oscillates with a period of 0.92s.
What planet is it on?
First we must find the length of the pendulum:
The planet that a Martian is on is Earth.
The formula to calculate the period from a simple pendulum
T = 2π × √(L ÷ g)
T ÷ 2π = √(L ÷ g)
(T ÷ 2π)² = L ÷ g
T² ÷ 4π² = L ÷ g
L = (T² × g) ÷ 4π²
the length of the pendulum (m)π = 3.14g = the acceleration due to gravity (m/s²)T = period (s)Compare from pendulum on Mars and another planet
g Earth = gg Mars = g₁ = 0.38 gT on Mars = T₁ = 1.5 sT on another planet = 0.92 sAssume the same pendulum on Mars is the same as the pendulum on another planet. Then the length of the two pendulums is the same.L₁ = L₂
(T₁² × g₁) ÷ 4π² = (T₂² × g₂) ÷ 4π²
T₁² × g₁ = T₂² × g₂
1.5² × 0.38g = 0.92² × g₂
2.25 × 0.38g = 0.8464 × g₂
0.855g = 0.8464 × g₂
g₂ = 0.855g ÷ 0.8464
g₂ = 1.0101g
g₂ = 1.0101 × 9.8
g₂ = 9.89
The other planet is Earth.
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Joe went 4.2 km/h south and then went 4.1 kw/h west. From start to finish, joe went 5.9 kw/h southwest. 1. What are the instantaneous velocities? 2.what is the average velocity?
(1) The instantaneous velocities are 4.2 km/h south and 4.1 km/h west
(2) The average velocity of Joe is 5.9 km/h southwest.
What are the instantaneous velocities?
The instantaneous velocities are the velocities of Joe at any given time period and it is calculated as follows;
v (1 ) = 4.2 km/h south
v ( 2 ) = 4.1 km/h west
The average velocity of Joe is calculated from the ratio of the total displacement to total time of motion.
v (avg) = ( total displacement ) / ( total time of motion )
v (avg) = 5.9 km/h southwest
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A car traveling at 3500 m/s is to stop on a 35-meter long shoulder of the road. What minimum deceleration is required?
The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.
What is deceleration?Deceleration is defined as the decrease in speed as the body moves away from the starting point.
The minimum deceleration required can be calculated using the equation of motion:
d = v^2 / (2 * a)
where d is the distance, v is the initial velocity, and a is the acceleration.
Rearranging the equation to solve for a:
a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2
In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.
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A 20×10⁹charge is moved between two points A andB that are 30mm apart and have an electric potential difference of 600v between them. calculate a) the electric field strength between A and B b)the work done on the charge.
The electric field strength between A and B 90x20=1800.
What is Electric field?The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also known as an E-field. It can also refer to a system of charged particles' physical field.
Electric charges and time-varying electric currents are the building blocks of electric fields. The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields.
Electrical technology makes use of electric fields, which are significant in many branches of physics. For instance, in atomic physics and chemistry, the electric field acts as an attractive force to hold atoms' atomic nuclei and electrons together.
Therefore, The electric field strength between A and B 90x20=1800.
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3. A football player runs at 8 m/s and plows into a 80 kg referee standing on the field causing
the referee to fly forward at 5.0 m/s. If this were a perfectly elastic collision, what would the
mass of football player be?
Answer:
Explanation:
To solve for the mass of the football player, we can use the conservation of momentum principle, which states that the total momentum before a collision is equal to the total momentum after the collision. Assuming the collision is perfectly elastic, we have:
m1 * v1 + m2 * v2 = m1 * v1' + m2 * v2'
where m1 is the mass of the football player, v1 is the initial velocity of the football player, m2 is the mass of the referee, v2 is the initial velocity of the referee, v1' is the final velocity of the football player, and v2' is the final velocity of the referee.
Since the referee is at rest before the collision, we can set v2 = 0. Plugging in the given values, we get:
m1 * 8 + m2 * 0 = m1 * (-8) + m2 * 5
Expanding and solving for m1:
8m1 = -8m1 + 80
16m1 = 80
m1 = 5 kg
So, the mass of the football player is 5 kg.
4. The Orion Nebula is shown in the Figure below. How long has the light been
traveling from this object before it arrives on Earth? The distance to Orion nebula is
1344ly.
Light has been traveling from this object before it arrives on earth for 1,500 light-years.
Why is Orion Nebula so bright?
The Orion Nebula, a colourful cloud of gas and cosmic dust, is a star-forming region. The nebula has "a rather brilliant apparent brightness because it is the nearest massive star-forming zone to Earth.
Why was Orion given that name?
The ancient Egyptians believed that the stars in the belt represented the spot where the spirit of the god Osiris would ultimately dwell. To the Arabs, the constellation appeared to be enormous. The mythological Greek hunter Orion is the subject of the constellation's name.
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The tension T2 has a magnitude of 60.0 N and the masses m₁ = 10.0 kg, m2 = 8.00 kg, and m3 = 12.0 kg. Determine the acceleration of the masses and the tension T1.
Answer: We can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by acceleration.
Let's call the acceleration of the system "a". Then the net force acting on m1 is T1 - T2 + m1 * a = 0.
The net force acting on m2 is T2 - m2 * a = 0.
And the net force acting on m3 is T2 + m3 * a = 0.
Solving these three equations, we get:
T1 = T2 + m2 * a = 60.0 N + 8.00 kg * a
m1 * a = -T2 + 60.0 N + m1 * a
m3 * a = T2 - 60.0 N + m3 * a
Substituting T2 = 60.0 N, we get:
T1 = 60.0 N + 8.00 kg * a
m1 * a = -60.0 N + 10.0 kg * a
m3 * a = 60.0 N + 12.0 kg * a
Solving for the acceleration, we get:
a = (60.0 N + 8.00 kg * a) / (10.0 kg - 8.00 kg) = (60.0 N + 8.00 kg * a) / 2.0 kg
a = (60.0 N + 8.00 kg * a) / 2.0 kg = (60.0 N) / 2.0 kg + (8.00 kg * a) / 2.0 kg
a * 2.0 kg = 60.0 N + 8.00 kg * a
a = 60.0 N / 2.0 kg + 8.00 kg * a / 2.0 kg
a * 2.0 kg - 8.00 kg * a = 60.0 N
a * 10.0 kg = 60.0 N + 8.00 kg * a
a = 60.0 N / 10.0 kg = 6.0 m/s²
Finally, we can use T1 = 60.0 N + 8.00 kg * a to find T1:
T1 = 60.0 N + 8.00 kg * 6.0 m/s² = 60.0 N + 48.0 N = 108.0 N
So the acceleration of the masses is 6.0 m/s², and the tension T1 is 108.0 N.
Explanation:
help me with the following
(a) The power required by the car climbing the inclined plane at steady speed is 15.554 kW.
(b) The power required by the car when the speed changes is 19.45 kW.
What is the power required for the car?
The power required by a car climbing the inclined plane is calculated as follows;
P = Fv
where;
v is the average velocity of the carF is the force of frictionSince the speed is steady, v = 80 km/h = 22.22 m/s
P = 700 N x 22.22
P = 15,554 W
P = 15.554 kW
When the speed of the car changes from 90 km/h to 110 km/h, the power required is calculated as;
vf = 110 km/h = 30.56 m/s
vi = 90 km/h = 25 m/s
V = ( 30.56 + 25 ) / 2 = 27.78 m/s
P = FV
P = 700 x 27.78
P = 19,446 W
P = 19.45 kW
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In your circuit toolbox, you have only three resistors ( 1=60 Ω
, 2=30 Ω
, 3=20 Ω
) and some switches that can be open or closed. Construct a circuit, filling in all four boxes, such that the equivalent resistance between A and B is 80 Ω
.
The required circuit can be constructed by arranging resistor 1 (60 Ω), resistor 3 (20Ω) in one arm and resistor 2 (30 Ω) and open switch in other arm.
What is resistor?A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.
When the circuit be constructed by arranging resistor 1 (60 Ω), resistor 3 (20Ω) in one arm and resistor 2 (30 Ω) and open switch in other arm, the equivalent resistor is = (60 + 20) Ω = 80 Ω.
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Particles q₁ = +18.1 µC, q2 = -11.2 μC, and
93 +5.67 μC are in a line. Particles q₁ and q2 are
separated by, 0.280 m and particles q2 and q3 are
separated by 0.350 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-27.7 x 10⁶ N is the net force on particle q₂..
Define a charged particle
A particle with an electric charge is said to be charged particle. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. It could also be an elementary particle like as an electron, proton, or another one that is thought to have the same charge (except antimatter).
F₁₂ = kq₁q₂/r²
k is Coulomb's constant
r is the distance between q₁ and q₂
q represent charges
F₁₂ = (9x 10⁹ x 18.1 x 10⁻³ x 11.2 x 10⁻³)/(0.28)²
F₁₂ = -23* 10⁶ N
F₂₃ = kq₂q₃/r²
F₂₃ = -(9 x 10⁹ x 11.3 x 10⁻³ x 5.67 x 10⁻³)/(0.35)²
F₂₃ = 4.7 x 10⁶ N
F(net) = F₁₂ + F₂₃
= -23* 10⁶ N + -4.7 x 10⁶ N
= -27.7 x 10⁶ N
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A 25.0 kg bumper car moving to the right at 5.00 m/s overtakes and collides elastically with a 35.0 kg bumper car moving to the right. After the collision, the 25.0 kg car slows to 1.50 m/a to the right, and the 35.0 pkg car moves 4.50 to the right. What was the velocity of the 35.0 pkg car before the collision?
Answer:
Explanation:
To determine the velocity of the 35.0 kg car before the collision, we can use the principle of conservation of momentum. The total momentum of the system before the collision is equal to the total momentum after the collision.
Momentum before collision = Momentum after collision
m1v1 + m2v2 = (m1 + m2)vf
where:
m1 = 25.0 kg (mass of first car)
m2 = 35.0 kg (mass of second car)
v1 = velocity of first car before collision
v2 = velocity of second car before collision
vf = final velocity of the combined cars after collision
Since the first car slows down to 1.50 m/s to the right after the collision, and the second car moves 4.50 m/s to the right, we can write:
vf = (v1 + v2) / 2 = (1.50 + 4.50) / 2 = 3.00 m/s
Substituting the given values into the equation for conservation of momentum, we have:
25.0 kg x 5.00 m/s + m2 x v2 = 60.0 kg x 3.00 m/s
Solving for v2, the velocity of the second car before the collision, we get:
v2 = (60.0 kg x 3.00 m/s - 25.0 kg x 5.00 m/s) / 35.0 kg = 2.14 m/s
So the velocity of the 35.0 kg car before the collision was 2.14 m/s.
Which of the following are electric insulators?
The examples of electric insulators are -
glass jar, rubber ball, tree, puddle.
What are electric insulators?Electric insulators are the materials that does not conduct electricity through them.
Given are the examples of electric insulators.
The examples of electric insulators are -
glass jar, rubber ball, tree, puddle
Therefore, the examples of electric insulators are -
glass jar, rubber ball, tree, puddle.
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need help please thanks
1. The percentage of incoming solar radiation which reflected and scattered back into space is 30%
2. Yes, solar radiation that is reflected and scattered heat the objects it strikes does.
3. The percentage of incoming solar radiation is 19% absorbed by clouds and gasses in the atmosphere.
4. 51% percentage of incoming solar radiation passes through the atmosphere and is absorbed by the Earth's surface.
5. No. The most transmit or absorb is Earth's surface.
About solar radiationIn a climate system, all processes start from radiant energy coming from the sun onto the surface of the atmosphere (air). Furthermore, this energy is forwarded to the earth's surface where along the way some of it is reflected back into space. Part of it is absorbed by the air and the rest is transmitted to the earth's surface.
Radiation that can reach the earth's surface can eventually heat the earth's surface, evaporate water, melt snow and heat the ground. The changed energy is also sent back into space in the form of radiation.
Variations in the amount of radiation received by the earth's surface and variations in the interaction between the earth and the atmosphere can cause spatial and time variations of energy changes which ultimately determine the climate of a place.
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What is the volume, in m3, of 10,000 kg of CO2 at 20 ∘C and 1.0atm pressure?
Answer:
pv=nrt
Explanation:
pv=nrt
The symbols for speed, distance, and elapsed time are, respectively. * Ax and At. The MKS units of speed, distance, and elapsed time are, respectively, meters per second, meters and seconds. Which of the following equations is incorrect by unit analysis?
The incorrect equation among them is: Δt = v/Δx.
What is physical quantity?A physical quantity is a property of a substance or system that can be measured and quantified. The algebraic multiplication of a "Numerical value" and a "Unit" can be used to express a physical quantity as a value.
Unit of distance Δx is meter.
Unit of elapsed time Δt is second.
Unit of speed v is meter per second.
Hence, the possible equations among them are:
Δx = vΔt
v = Δx/Δt
Δt = Δx/v
1/Δt = v/Δx
But the incorrect equation among them is:
Δt = v/Δx.
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Your question is incomplete, but most probably the options of the question are:
Δx = vΔt
v = Δx/Δt
Δt = Δx/v
1/Δt = v/Δx
Δt = v/Δx.
15 6. Acar moves with a velocity of 30m/s is accelerated in 6sec find final velocity and the distance during that time
Explanation:
To find the final velocity and distance traveled during the acceleration, we can use the equations of motion:
v = u + at, where v is the final velocity, u is the initial velocity (30 m/s), a is the acceleration, and t is the time (6 s)
v = 30 m/s + a x 6 s
d = ut + 0.5at^2, where d is the distance traveled
d = 30 m/s x 6 s + 0.5 x a x (6 s)^2
Since acceleration (a) is not given, we can use one equation to solve for it and substitute into the other:
v = 30 m/s + a x 6 s
a = (v - 30 m/s) / 6 s
Substitute this into the second equation to find the distance:
d = 30 m/s x 6 s + 0.5 x (v - 30 m/s) / 6 s x (6 s)^2
So, we can find the final velocity and distance traveled once the acceleration (a) is known.
A picture of a basketball on the left and a bowling ball on the right. The bowling ball is inside a white box.
Anika asks Eva to roll a basketball and then a bowling ball to her. Which requires more force to roll, and why?
The bowling ball requires more force to roll than the basketball. This is because the bowling ball has more mass than the basketball, and therefore more resistance to motion.
Why force is related to mass?Force is related to mass because the force required to move an object is proportional to its mass. This relationship is described by Newton's second law of motion, which states that the acceleration of an object is directly proportional to the force applied and inversely proportional to its mass. In mathematical form, this relationship is expressed as:
F = ma
The amount of force required to move an object is proportional to its mass and its velocity. Since the bowling ball has more mass, it requires more force to be applied in order to get it moving, and to keep it moving at a constant velocity. Additionally, because the bowling ball is inside a white box, its rolling friction is higher, further increasing the amount of force required to move it.
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[tex]\huge\bold{Question}[/tex]
An orange of mass 125 g falls from a branch to the ground 3.50 m below. (a) Relative to the ground, what is the gravitational potential energy of the orange on the branch? On the ground? (b) Relative to the branch, what is the gravitational potential energy of the orange on the branch? On the ground? J (c) During the orange's fall, what is its change in gravitational potential energy relative to the ground? Relative to the branch?
(a) Relative to the ground, the gravitational potential energy of the orange on the branch is 4.29 J and on ground is 0 J.
(b) ) Relative to the branch, the gravitational potential energy of the orange on the branch is 0 J and on ground is 4.29 J.
(c) The change in potential energy relative to the ground is -4.29 J and relative to the branch is 0 J.
What is the gravitational potential energy?
Relative to the ground, the gravitational potential energy of the orange on the branch is calculated as follows;
P.E = mgh
where;
m is the mass of the orangeh is the height of the branch above the groundg is acceleration due to gravityP.E = 0.125 kg x 9.8 m/s² x 3.5
P.E = 4.29 J
The gravitational potential energy of the orange on the ground is calculated as follows;
P.E = mgh
P.E = m x g x 0 m
P.E = 0 J
The change in potential energy = final potential energy - initial potential energy
change in potential energy = 0 J - 4.29 J = - 4.29 J
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A student runs an experiment in which a block of known mass is moving across a horizontal table in an xy-coordinate plane. As the block reaches the origin of the coordinate system, the block explodes into two pieces of masses m1 and m2. During the experiment, the velocity of the block 1.0 second before the explosion and the velocity of the two pieces 1.0 second after the explosion are measured using a motion sensor. Conservation of momentum is applied using the masses of the two pieces. However, when the velocity of the piece of mass m2 is calculated, the measured value is 10% less than the calculated value. Which of the following statements best explains the difference in the calculated and measured velocity?
Responses
Answer:
The difference in the calculated and measured velocity could be due to the fact that the motion sensor may not have been able to accurately detect the velocity of the block 1.0 second before the explosion due to the sudden change in momentum caused by the explosion. Additionally, the motion sensor may not have been able to accurately detect the velocity of the two pieces 1.0 second after the explosion due to the sudden change in momentum caused by the explosion. This could explain the 10% discrepancy between the calculated and measured velocity.
Explanation:
eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
V.
Answer:
E+V= Weird
Explanation:
If you subtract "e" repeating from E and V you'll get the equation above.
Your friend shoots an 80-g arrow through a 100-g apple balanced on william tells head. the arrow has a speed of 50 m/s before passing through the apple and 40 m/s after. determine the final speed of the apple
The final speed of the apple would be 26.9 m/s.
What is collision in physics?A collision happens when two bodies come in direct contact with each other.In this case, the two bodies exert forces on each other in a short period of time.The energy and momentum of bodies interacting undergo a change as a result of the collision.An elastic collision is an encounter (collision) between two bodies in which the total kinetic energy of the two bodies remains the same.In an ideal, perfectly elastic collision, there is no net conversion of kinetic energy into other forms such as heat, noise, or potential energy.Given is that your friend shoots an 80g arrow through a 100g apple balanced on William tells head. The arrow has a speed of 50m/s before passing through the apple and 40m/s after.
In a elastic collision, the total kinetic energy of the system remains the same. So, we can write -
[tex]$E_{1i} +E_{2i} = E_{1f} +E_{2f}[/tex] .... Eq{ 1 }
We can write as -
{1/2 x 80 x 2500} + 0 = {1/2 x 80 x 1600} + {1/2 x 100 x v²}
{1/2 x 100 x v²} = {40 x 2500} - {40 x 1600}
50v² = 40 x 900
v² = 720
v = √720
v = 26.9 m/s
Therefore, the final speed of the apple would be 26.9 m/s.
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Air bags are put into cars and other vehicles to reduce injury to passengers. How do these devices reduce injury?
Answer:
it's there to reduce movement of the passenger if hit.
Explanation:
it's quite simple really, its there because if it wasn't the person would've gone flying through the front window screen.
A light bulb at point x in the frame of reference of O blinks on and off at intervals Δt = t2 − t1. Observer O′, moving relative to O at speed u, measures the interval to be Δt ′ = t ′ 2 − t ′ 1. Use the Lorentz transformation expressions to derive the time dilation expression relating Δt and Δt ′.
The expression of time dilation is: Δt' = Δt/√(1 -(v/c)²)
What is time dilation?Think of two precise clocks that are identical, one stationary and the other travelling nearly at the speed of light. The moving clock measures a shorter amount of time than the stationary clock because of the effects of special relativity.
The time of the moving clock is said to be the "right time" if the observer is moving in the same frame of reference as the clock. The time, however, that a stationary observer records during the same time interval is extended or "dilated."
The expression of time dilation is:
Δt' = Δt/√(1 -(v/c)²)
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Find the magnitude of the sum A + B + C. Each grid Square is 5.00 N on a side. If the vector sum is to the west, enter a negative value. If the vector sum is to the east entrr a positive value.
The magnitude of the sum A + B + C is 5
What is a Vector?The term "vector" is used colloquially to describe constituents of particular vector spaces or some quantities that cannot be described by a single integer.
How to solve for the quantity
A = 15J + 20J
B= -20J
C= -10J
S= A + B + C = 15J + 20J -20J -10J
S = 5J
Therefore, S= 5
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What is the Power (Watts) dissipated in a 25 Ohm circuit if it has 3.0 Amps of current?
The amount that the valve is open is reflected by the resistance in the faucet. The diameter of the opening* in the wire determines its resistance.
What is Power?
Work is the result of a force creating a displacement. The length of time that this force exerts to generate the displacement has nothing to do with work.
The pace of the process can vary from being completed quickly to taking a while. A rock climber, for instance, takes an unusually lengthy time to raise her body a few meters up the cliff's edge.
Power= I2R, 225 is the power. The amount that the valve is open is reflected by the resistance in the faucet. The diameter of the opening* in the wire determines its resistance.
Therefore, The amount that the valve is open is reflected by the resistance in the faucet. The diameter of the opening* in the wire determines its resistance.
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Silver is more costly than iron because it is 1. Heavier 2. Scarcer 3. Whiter 4. Harder 5 ...
Answer:
scarcer
Explanation:
Silver is more costly than iron because it is scarcer as it is found only in some areas of the country... it's a rare element hence it is scarcer and more expensive..
In a physics lab, 0.500-kg cart (Cart A) moving rightward with a speed of 92.8 cm/s collides with a 1.50-kg cart (Cart B) moving leftward with a speed of 21.6 cm/s. The two carts stick together and move as a single object after the collision. Determine the post-collision speed of the two carts.
The speed of the two carts after the collision is 10 m/s.
What is momentum?
Momentum is a measure of an object's motion and is defined as the product of an object's mass and velocity. The SI unit of momentum is kilogram-meters per second (kg m/s).
In physics, momentum is an important concept in the study of motion and is related to the forces acting on an object. According to Newton's second law of motion, the momentum of an object changes when a force is applied to the object. The magnitude of the change in momentum is proportional to the size of the force and the time over which it is applied.
In collisions and other interactions between objects, the total momentum of the system is conserved, meaning that the total momentum before the interaction is equal to the total momentum after the interaction.
initial momentum = mA · vA1 + mB · vB1
final momentum = (mA + mB) · vAB2
Where:
mA = mass of cart A = 0.500 kg
vA1 = velocity of cart A before the collision = 100 m/s
mB = mass of cart B = 1.50 kg.
vB1 = velocity of cart B before the collision = - 20 m/s
vAB2 = velocity of the carts that move as a single object = unknown.
(notice that we have considered leftward as negative direction)
Since the momentum of system remains constant:
initial momentum = final momentum
mA · vA1 + mB · vB1 = (mA + mB) · vAB2
Solving for vAB2:
(mA · vA1 + mB · vB1) / (mA + mB) = vAB2
(0.500 kg · 100 m/s - 1.50 kg · 20 m/s) / (0.500 kg + 1.50 kg) = vAB2
vAB2 = 10 m/s
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