16. By how much leeway (both percentage and mass) would you have in the selection of the mass of the object in the previous problem if you did not wish the new period to be greater than 2.01 s or less than 1.99 s?

Please show all of your work.

This is defined as a propagation of disturbances from place to place in a regular and organized way.

The answers provided above are therefore the most appropriate choices in this scenario.

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Answer: Light waves do not require a medium to propagate and As a wave's frequency increases, more energy is carried by the wave in a given time period.

Explanation:

Answer:

Bowling ball

Explanation:

The bowling ball's mass will make it roll down the incline faster than the lighter volleyball.

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Answer:

Temperature on Jupiter and Saturn are too high for methane to condense.

Explanation:

However, methane can condense on Uranus and Neptune because they are farther from the sun and hence colder.

Answer:

anywhere between 100000 to about 400000 human years .

Explanation:

It would weigh less bc the higher you are the less gravity there is.

Answer:

if you doctor suspect that you have COPD , they will calculate your fev1/fvc ratio . this represent the percentage of your lung capacity that you can explain in one second. the higher your percentage , the larger your lung capacity and the healthier your lungs

The ratio  [tex]\frac{FEV1}{FVC}[/tex]  indicates the diameter of an airway. The greater the value, the more quickly air can pass through the airway.

The volume of air in the lungs at different stages of the respiratory cycle is referred to as lung volumes and lung capacities. An adult human male's entire lung capacity is around 6 liters of air.

The ratio  [tex]\frac{FEV1}{FVC}[/tex]  indicates the diameter of an airway. The greater the value, the more quickly air can pass through the airway. As a result, the lower the resistance, the broader the airway becomes.

Hence the lower the resistance, the broader the airway becomes.

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The answers to your questions are as listed below

A) The total momentum of the system is :  < - 167, 133, 87 >   kg m/s

B) Velocity of the center of mass of this system : < - 10.44 , 8.31, 5.44 > m/s

C) Total kinetic energy of the system : 5159.5 J  

D) Translational kinetic energy of the system :  1660.84 J

E) kinetic energy relative to the center of mass : 3498.66 J

Given data :

m₁ = 4 kg ,   V₁ = < 10, -5, 15 > m/s

m₂ = 9 kg,   V₂ = < -15, 5, -3 > m/s

m₃ = 3 kg    V₃ = < -24, 36, 18 > m/s.

Total momentum = Σ mv

= < 4*10 + 9*(-15) + 3*(-24), 4*(-5) + 9*5 + 3*36, 4*15 + 9 (-3) + 3*18 >

= < - 167, 133, 87 >   kg m/s

Velocity = < - 167 / 16 , 133/ 16, 87/ 16 >

              =  < - 10.44 , 8.31, 5.44 > m/s

Total Kinetic energy = 1/2 m₁v₁² + 1/2 m₂v₂²  + 1/2 m₃v₃²  --- ( 1 )

where : v² = v₁² + v₂² + v₃²

therefore

Total kinetic energy = 700 + 1165.5 + 3294

                                  = 5159.5 J  

Translational kinetic energy ( Kcm ) = 1/2 ( m₁ + m₂ + m₃ ) * Velocity²

                                                           = 1/2 ( 16 ) * (  - 10.44² + 8.31² + 5.44² )

Hence translational kinetic energy = 1660.84 J

E) The Kinetic energy of the system relative to the center of mass

Krel = Ktotal - Kcm

       = 5159.5 - 1660.84

       = 3498.66 J

Hence we can conclude that the answers to your questions are as listed above.

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Answer:

Ocean acidification reduces the amount of carbonate, a key building block in seawater. This makes it more difficult for marine organisms, such as coral and some plankton, to form their shells and skeletons, and existing shells may begin to dissolve.

Answer:

The intake of carbon dioxide (CO2) from the atmosphere causes ocean acidification, which is the continual decline in the pH value of the Earth's oceans. The burning of fossil fuels by humans is the primary cause of ocean acidification. The amount of carbon dioxide absorbed by the ocean grows in lockstep with the amount of carbon dioxide in the atmosphere. This causes a sequence of chemical reactions in the seawater, which has a negative impact on the, however, their rine life that lives beneath the surface. Carbonic acid is formed when carbon dioxide dissolves in seawater (H2CO3). The pH value of the ocean surface is estimated to have decreased from approximately 8.25 to 8.14 between 1751 and 1996, representing a nearly 30% increase in H+ ion concentration in the world's oceans (note that the pH scale is logarithmic, so a change of one pH unit equals a tenfold change in H+ ion concentration). The pH of the ocean in 2020 will be 8.1, according to the National Oceanic and Atmospheric Administration.

Explanation:

Answer:

The units for specific heat can either be joules per gram per degree (J/goC) or calories per gram per degree

Explanation:

Answer:

8 oz

Explanation:

Answer:

The buoyant force on a submerged object depends upon the volume of the object.

Explanation:

Answer:

There are 602 calories in 10 ounces of Ground Beef (85% Lean / 15% Fat).  serving sizes of Ground Beef

Explanation:

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The range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.

The frequency of the visible light is determined  by using the following formulas relating speed of light and frequency of light.

c = fλ

where;

f = c/λ

f = (3 x 10⁸) / (300 x 10⁻⁹)

f = 1 x 10¹⁵ Hz

f = c/λ

f = (3 x 10⁸) / (700 x 10⁻⁹)

f = 4.29 x 10¹⁴ Hz

Thus, the range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.

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According to Hooke 's law

[tex]\\ \rm\rightarrowtail \nu=k\sqrt{\dfrac{\ell}{m}}[/tex]

[tex]\\ \rm\rightarrowtail \nu\propto \dfrac{1}{\sqrt{m}}[/tex]

Hence lower the mass higher the frequency

Answer:

Potential energy.

Explanation:

Batteries are a form of chemical energy which  is stored in the bonds of molecules contained within the battery acid, batteries are a form of potential energy making chemical potential energy too.

Answer:

A

Explanation:

Direct because it's still passes electricity through ir

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

where;

ω = 2π x (5.25 / 3)

ω =  11 rad/s

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

v = ωr

where;

v = 11r m/s

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Answer:

It can have many set of perpendicular component but the most important one is 3 AND 4

Explanation:

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The maximum velocity of the piston when the auto engine is running at the given speed is 25.68 m/s.

The angular speed of the automobile in radian per second is calculated as follows;

ω = 2πN

ω = 2π x (3590 /60 s)

ω = 375.94 rad/s

The maximum velocity of the piston is calculated using the following formula;

v(max) = Aω

v(max) = 0.0683 x 375.94

v(max) = 25.68 m/s

Thus, the maximum velocity of the piston when the auto engine is running at the given speed is 25.68 m/s.

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Answer:

[tex]\sqrt{v^{2} + 2\, g\, y}[/tex].

Explanation:

Apply the SUVAT equation [tex]{v_{1}}^{2} - {v_{0}}^{2} = 2\, a\, x[/tex] to the vertical component of the soccer ball's motion to find the vertical velocity right before the ball lands. In this equation:

Rearrange this equation to find an expression for the vertical velocity [tex]v_{1}[/tex] in terms of [tex]y[/tex] and [tex]g[/tex]:

[tex]\begin{aligned}v_{1} &= \sqrt{{v_{0}}^{2} + 2\, a\, x} \\ &= \sqrt{2\, g\, y}\end{aligned}[/tex].

Since air friction is negligible, the horizontal velocity of the ball would stay unchanged. Thus, the horizontal velocity of the ball would still be [tex]v[/tex] right before the ball lands.

Notice that these two components of velocity are perpendicular to one another. Thus, find the combined velocity of the ball right before landing could be found using Pythagorean's Theorem:

[tex]\sqrt{v^{2} + {v_{1}}^{2}} = \sqrt{v^{2} + 2\, g\, y}[/tex].

Answer:

hello.

Negative acceleration is also called deceleration.

Explanation:

If the velocity of the object does not change with time, it has zero acceleration.

The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s

Given data :

Distance of star from earth = 4.3 light years

Observers time = 3.7 years

Observers time = 3.7 * 365 * 24 * 60 * 60

Distance of star from earth = 4.3 * 9.46 * 10¹⁵

The velocity the spacecraft must travel will be calculated using the equation

V = distance / time

   = ( 4.3 * 9.46 * 10¹⁵ ) / ( 3.7 * 365 * 24 * 60 * 60 )

   = 3.49 * 10⁸ m/s

Hence we can conclude that The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s

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Attached below is the missing detail related to the question

The constant velocity must the spacecraft travels from the earth will be 3.49×10⁸ m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Distance of earth from stars = 4.3 light year

The given time = 3.7 year

One year converted into the second as;

[tex]\rm 1 \ year = 3.7 \times 365 \ days \ \times 24 \ hour \times 60 \ minute \times 60 \ sec \\\\ 1 year = 116 \times 10^6 \ sec[/tex]

1 light-year into a kilometer as;

[tex]\rm 4.3 \ light year = 4.3 \times 9.46 \times 10^{15 metre} \\\\[/tex]

At what constant velocity must a spacecraft travel from the earth if it is to reach the star in 3. 7 years,

The velocity of the spacecraft's travel from the earth will be;

[tex]\rm V = \frac{d}{t} \\\\ V= \frac{4.3 \times 9.46 \times 10^{15}}{3.7 \times 365 \times 24 \times 60 \times 60 } \\\\\ V= 3.49 \times 10^8 \ m/sec[/tex]

Hence the constant velocity must the spacecraft travels from the earth will be  3.49×10⁸ m/sec.

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Answer:

6m/s

Explanation:

a = (v-u)/t

acceleration, a

initial velocity, u

final velocity, v

time, t

substitute values and you'll get the answer

Answer:

6 m/s

Explanation:

The new period of the pendulum when it is taken to the new planet is  double of its period on Earth.

The period of a pendulum is given by the following formula;

[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]

where;

The acceleration due to gravity of the new planet is calculated as follows;

[tex]g_E = \frac{GM_E}{R_E^2} = 9.81 \ m/s^2 \\\\g(new \ planet) = \frac{G(4M_E)}{(4R_E)^2} = \frac{4GM_E}{16R_E^2} = \frac{GM_E}{4R_E^2} = \frac{9.81}{4} = 2.45 \ m/s^2[/tex]

[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\T =\frac{2\pi \sqrt{l} }{\sqrt{g} } \\\\T_1\sqrt{g_1} = T_2\sqrt{g_2} \\\\T_E\sqrt{g_E} = T\sqrt{g} \\\\T = \frac{T_E\sqrt{g_E}}{\sqrt{g} } \\\\T = \frac{T_E \times \sqrt{9.81} }{\sqrt{2.45} } \\\\T = 2T_E[/tex]

Thus, the new period of the pendulum when it is taken to the new planet is double of its period on Earth.

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Answer:

C. In a valley .

.............................

(a)The window panes are transparent  

(b)The colors of the panes are due to the wavelengths of light that the glass allows to pass through.

The glasses which allows the light rays to pass through them are called as the transparent glasses.

or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that is perceived by the human eye.[1] Visible light is usually defined as having wavelengths in the range of 400–700 nanometres (nm),

corresponding to frequencies of 750-420 terahertz, between the infrared (with longer wavelengths) and the ultraviolet (with shorter wavelengths

Hence  the  window panes are transparent the colors of the panes are due to the wavelengths of light that the glass allows to pass through.

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Answer:

The windowpanes are- transparent.

The color of the panes are due to the wavelengths of light that the glass- allows to pass through

Explanation:

For A 100-cm long dipole is excited by a sinusoidally varying current with an amplitude i0=2 , the time average power radiated  is mathematically given as

P=0.1577w

Generally, the equation for the   is mathematically given as

[tex]\lambda =\frac{c}{f}[/tex]

Therefore

[tex]\lambda=\frac{3\times 10^{8}}{10^{6}}[/tex]

lambda=300m

In conclusion, for the power

[tex]P=40\pi^{2}(I_{0})^{2}(\frac{l}{\lambda})^{2}\\\\P=40* (3.14)^{2}\times6^{2} (\frac{1}{300})^{2}[/tex]

P=0.1577w

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The time-averaged power radiated by the dipole if the oscillating frequency is 150 MHz is 0.1577 w.

The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or down a wire is defined as the wavelength.

Given that the current is 2 amp, while the frequency is 150 MHz. Therefore, the wavelength can be written as,

[tex]\lambda = \dfrac cf = \dfrac{3 \times 10^8}{10^6} = 300\rm\ m[/tex]

Now, the power can be written as,

[tex]P=40 \pi^2 \times (I_o)^2 \times (\dfrac{l}{\lambda})^2\\\\P = 40 \times \pi ^2 \times 6^2 \times (\dfrac{1}{300})^2\\\\P = 0.1577\rm\ w[/tex]

Hence,  the time-average power radiated by the dipole if the oscillating frequency is 150 MHz is 0.1577 w.

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The percent of the silo filled with corn at 10 hours is 90.98%.

Silos are used in order to maximize the grain storage life and preserve them. They are round and tall towers with high capacity for commercial or industrial purposes.  

As the silo is in shape of cylinder, volume of the cylinder is

V = πr²h

where r = d/2 = 19/2 =9.5 ft

and h = 32 ft

Substitute the values, we get the volume of silo,

V = 3.14 x (9.5)² x 32 = 9068.32 ft³

The silo is filled with the constant rate. After 10 hours, in silo, the amount of corn will be gone doubled as compared to that of in 5 hours.

Amount of corn after 10 hours = 4125 x 2 = 8250 ft³

Percentage of silo filled in 10 hours = (amount after 10 hrs / total amount) x 100

Substitute the values, we get

=(8250 /9068.32 ) x 100 %

=90.98 %

Thus, the percent of the silo filled with corn at 10 hours is 90.98%.

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The time taken for the car's tires to complete one full rotation when it car drives down the road at 6m/s. The tires on the car have a diameter of .7m. is 0.37 s.

Time is the measure of the duration of past , present or future event.

To calculate the time taken for the tires to complete one full rotation, we use the formula below.

Formula:

Where:

Make t the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, The time taken for the car's tires to complete one full rotation is 0.37 s.

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