Answer:
Physical measures: Reduction of internal friction, high static friction tire system
chemist. : air-fuel ratio as efficient
Explanation:
A go-Kart is a vehicle that can be with a motor or with pedals, which is in contact with the ground.
Physical measures that help increase vehicle speed are:
* Reduction of internal friction, use bearings, with greased joints to reduce friction
* Decreased friction when forward creating an aerodynamic raindrop shape, sharp at the front and with a rapid descent at the rear, but without abrupt cuts to the geometry
* Path difference for air passing through the top and bottom, to create a downward force help lower the car by increasing speed
* A high static friction tire system so you can move faster on surfaces and take turns faster
* A shifting system to have an effective torque either pedal or motor, gear shifting system
From the point of chemist.
* Obtain an air-fuel ratio as efficient as possible to increase the force per unit of fuel.
WHAT IS A VARIABLE?
Group of answer choices
A QUANTITY THAT CAN HAVE MORE THAN A SINGLE VALUE
A QUANTITY THAT CAN HAVE ONLY A SINGLE VALUE
A QUANTITY THAT ALWAYS HAS THE SAME VALUE
Answer:
The Answer is the first one " A quantity that can have more than a single value!
Explanation:
Hope this helps!
Answer A variable is a quantity that may change within the context of a mathematical problem or experiment. Typically, we use a single letter to represent a variable. The letters x, y, and z are common generic symbols used for variable:
Explanation:
A variable is any characteristics, number, or quantity that can be measured or counted. A variable may also be called a data item. Age, sex, business income and expenses, country of birth, capital expenditure, class grades, eye colour and vehicle type are examples of variables
a wave is represented by the equation y=0.5 sin0.6×(x-60t) where the distance x is measured in cm and time t is seconds. what is the wave length of the wave
Answer:
lamda=10.5m
Explanation:
using the equation of progressive wave.
y=Asin(wt-kx)
comparing the two equations together, we have
kx=0.6x , k=0.6
k=2π/λ
0.6=2*3.142/λ
cross multiply
0.6λ=6.284
divide both sides by 0.6
λ=6.284/0.6
λ=10.47m
approximate
λ=10.5m
lan walked 6.8 kilometers to his friend’s house. What is the distance in meters?
Answer:
1 kilometer= 1000 meters
6.8 kilometers= 6800 meters
Explanation:
If E=1/2Av^2+Bmx find the dimensions of A and B(Where E is energy,v,m and x are velocity,mass and distance respectively)
Answer:
A = [kg]
B = [m/s²]
Explanation:
E = ½ Av² + Bmx
Substitute the units:
[J] = ½ A [m/s]² + B [kg] [m]
A Joule written in base units is:
1 J = 1 Nm = 1 kg m²/s²
Each term must have the same units.
[kg m²/s²] = A [m/s]²
[kg m²/s²] = A [m²/s²]
A = [kg]
[kg m²/s²] = B [kg] [m]
B = [m/s²]
A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hits the ground. From what height above the ground did it fall
Answer:
The object fell from about 38.14 meters
Explanation:
We can use the formula for displacement under accelerated motion due to gravity to find the velocity of the object had 30 m before hitting the ground :
[tex]y_f-y_i=v_i * \,t-\frac{9.8}{2} \,t^2\\0-30=v_i \,(1.5)-4.9\,(1.5)^2\\-18.975=v_i\,(1.5)\\v_i=-12.65\,\,\frac{m}{s}[/tex]
Now, knowing this velocity, we can find the time it took to fall from the initial position to 30 m before hitting the ground:
[tex]v_f=v_i-g\,*\,t\\-12.65=0-g \,*\,t\\t=\frac{12.65}{g} \\t\approx1.29\,\,s[/tex]
And now we can find what is the total distance covered in 1.5 s plus 1.29 seconds for this free falling object:
[tex]y_f-y_i=v_i * \,t-\frac{9.8}{2} \,t^2\\0-y_i=0-\frac{9.8}{2} \,(2.79)^2\\-y_i=-38.14\\y_i=38.14\,\,m[/tex]
If the magnetic field is held constant at 3.0 T and the loop is pulled out of the region that contains the field in 0.2 s, what is the magnitude of the average induced emf in the loop
Answer:
emf = 15 * Area and if A is given in square meters, the units of the emf will be Volts
Explanation:
Assuming that the area of the loop of current (A) is known, the magnitude of the induced emf can be calculated using Faraday-Lenz's Law:
[tex]emf=|-\frac{\Delta\,\Phi}{\Delta \,t} |=|\frac{A\,B}{\Delta \,t}|=|\frac{A\,(3)}{0.2}|=15\,A[/tex]
and if the area (A) is given in square meters, the emf will directly come in units of Volts.
Define ideal machine its types and example of each three?
Explanation:
Hey, there!!
Ideal machines are defined as the machines which gives 100% (efficiency) output result without losing the input work. There is possibility have a machine with 100% efficiency but the machines like pulley and lever are somehow.
For reason for pulley is when it is rotated up to 360° it takes the the load to the desired height. so, it is considered as ideal machine.For lever it amplifies tge the input work to produce output work.Hope it helps....
The free-fall acceleration at the surface of planet 1 is 15 m/s2. The radius and the mass of planet 2 are twice those of planet 1. Part A What is g on planet 2
Answer:
3.75m/s²
Explanation:
g= GM/r²
For planet 1
[tex]g_{1}[/tex]= GM/r² (i)
[tex]g_{1}[/tex] = 15m/s²
for planet 2
radius= 2*r= 2r
g= GM/r
[tex]g_{2}[/tex]= GM/(2r)²
[tex]g_{2}[/tex]= GM/4r²
[tex]g_{2}[/tex]= GM/r² *1/4
from (i)
[tex]g_{2}[/tex]= [tex]g_{1}[/tex] *1/4
[tex]g_{2}[/tex] = 15/4
[tex]g_{2}[/tex] = 3.75m/s²
Which describes the substances that form covalent bonds? a metal and a metalloid a metal and a nonmetal two nonmetals two metals
Answer:
Two non metals
Explanation:
Covalent bonding is a chemical bonding that involves sharing of electrons
a metal and a metalloid can be described as a metallic bond.
a metal and a nonmetal is an example that describes an ionic bonding
While two non metals is a typical example of a covalent bonding.
Therefore, two non metals describes the substances that form covalent bonds
Answer:
C
Explanation:
simple answer
A box has a mass of 75 g. It has a length of 2.0 cm, a width of 2.0 cm and a height of 3.0 cm. What is the density?
Answer:
6.25 g/cm³
Explanation:
2 cm * 2 cm * 3 cm = 12 cm³ (volume)
75 g / 12 cm³ = 6.25 g/cm³
O ln a hydraulic press , a force Of 400 N is exerted on
a piston of area 0.001m2? The load -bearing piston has
an area of 0.2m² . Determine the presure exerted by the
hydraulic fluid
Explanation:
Pressure = force / area
P = 400 N / 0.001 m²
P = 400,000 Pa
Sumin runs 50 meters from her house to the park down the street. She then keeps running in the same direction to her friend's house 150 Meters from the park. She then turns around and goes back to the park. What is Sumin's average velocity during her run if it takes her 2 minutes to complete?
A. 25 m/s
B.2.92 m/s
C.3.33 m/s
D.0.417 m/s
Answer:
d. 0.417 m/s
Explanation:
v= ▲x/t
(350-150)/120 s
= .417 m/s
What minimum separation between two parallel plates of glass (nglass =1.5) produces constructive interference for the reflected light with a 710 nm wavelength if the gap between the plates is filled with oil with noil =1.8?
Answer:
The value is [tex]t = 9.861 *10^{-8} \ m[/tex]
Explanation:
From the question we are told that
The refractive index of glass is [tex]n_{glass} = 1.5[/tex]
The wavelength is [tex]\lambda = 710 nm = \frac{710}{1 * 10^9} = 710*10^{-9} \ m[/tex]
The refractive index of oil is [tex]n_{oil} = 1.8[/tex]
Generally the condition for refractive index is mathematically represented as
[tex]2 * t = [m + \frac{1}{2} ] \frac{\lambda}{n_{oil}}[/tex]
Where t is the separation between two parallel plates of glass , now at minimum m which is the order of maxima produced is = 0
So
[tex]2 * t = [0 + \frac{1}{2} ] \frac{710 *10^{-9}}{1.8}[/tex]
[tex]t = 9.861 *10^{-8} \ m[/tex]
Please help ASAP!! I need a good grade on this!!!!
What is Momentum Quick Check
1) A billiard ball moves with 3 kg•m/s of momentum and strikes three other billiard balls. What is the total momentum of the balls after the collision?
A)3kg•m/s
B)It depends on the mass of each ball
C)More than 3kg•m/s
D)Less than 3kg•m/s
An object has a mass of 5kg and a velocity of 20m/s. What is the momentum of the object?
A)4kg•m/s
B)0.25kg•m/s
C)25kg•m/s
D)100kg•m/s
A small rock bounces off the windshield of a moving car and experienced a large change in velocity. How does the car’s momentum change?
A)It has a much smaller change in momentum that that of the rock in the opposite direction
B)it has a change in momentum greater than that of the rock in the opposite direction
C)it has a change in momentum equal to that of the rock in the opposite direction
D)it does does not change
Two objects in a closed system collide while moving directly toward each other. Each has a mass of 1.00kg and is moving at 1.80 m/s. What is the total momentum after the collision?
A)1.80 kg•m/s
B)3.60 kg•m/s
C)0.90 kg•m/s
D)0.00 kg•m/s
An object has a velocity of 5m/s and a momentum of 100 kg•m/s. What is the mass of the object?
A) 500 kg
B) 20 kg
C) 0.05 kg
D) 105kg
Answer:
1A) 3kg * m/s
2D) 100
3, Guess: A smaller change of momentum
4, Guess: A, 1.80
5B) 20
Explanation:
(1) The total momentum of the balls after collision is 3 kg.m/s
(2) The momentum of the object is 100 kg.m/s
(3) The change in the car's momentum is equal to change in the rock's momentum in opposite direction.
(4) The total momentum of the objects is 0 kg.m/s
(5) The mass of the object is 20 kg.
(1) From the principle of conservation of linear momentum, total initial momentum before collision is equal to the momentum after collision.
initial momentum = final momentum
Thus, the total momentum of the balls after collision is 3 kg.m/s
(2) Linear momentum is defined as the product of mass and linear velocity of an object.
momentum of the object is calculated as;
P = mv
P = 5 x 20
P = 100 kg.m/s
(3) Apply the principle of conservation of linear momentum;
[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2 v_2[/tex]
In order to ensure that momentum is conserved;
if u₁ is smaller than u₂, then v₁ must be greater than v₂Let u₁ represents the initial velocity of the small rock and u₂ is the initial velocity of the moving car. In this case, the momentum of the car is bigger.
To conserve the momentum, the final velocity of the rock v₁ must be greater than the final velocity of the car. When this happens, the rock will experience a large change in velocity.
From the equation above will have;
[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2 v_2\\\\m_1u_1 - m_1v_1 = m_2v_2 - m_2u_2\\\\\Delta P_{rock} = \Delta P_{car}[/tex]
Thus, the change in the car's momentum is equal to change in the rock's momentum in opposite direction.
(4) In a closed system the momentum will be conserved;
Initial momentum = final momentum
Total momentum = final momentum + Initial momentum
The total momentum = 1 x 1.8 + 1 x (-1.8)
Note: the negative sign is because one is moving in opposite direction
The total momentum = 1.8 kg.m/s - 1.8 kg.m/s = 0 kg.m/s
(5) The mass of the object is calculated as;
[tex]m = \frac{P}{v} \\\\m = \frac{100}{5} \\\\m = 20 \ kg[/tex]
Learn more here:https://brainly.com/question/24424291
A basketball is rolling rightward onto the court with a speed of 4.0\,\dfrac{\text m}{\text s}4.0 s m 4, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction, and slows down with a constant leftward acceleration of magnitude 0.50\,\dfrac{\text m}{\text s^2}0.50 s 2 m 0, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction over 14\,\text m14m14, start text, m, end text.
Answer:
Final velocity, v = 1.41 m/s.
Explanation:
It is given that,
Initial velocity of the basketball, u = 4 m/s
Acceleration of the ball, a = -0.5 m/s² (as it slows down)
We need to find the velocity of the basketball after rolling for 14 m. It is a concept of equation of motion in kinematics. Using third equation of motion as :
[tex]v^2=u^2+2ad[/tex]
v is final velocity
[tex]v^2=(4)^2+2\times (-0.5)\times 14\\\\v=\sqrt 2\ m/s\\\\v=1.41\ m/s[/tex]
So, the final velocity of the basketball is 1.41 m/s.
Answer:
1.41
Explanation:
to make you guys feel more secure, i got it from kahn academee
A particle has a displacement of 12m towards east, then 5m towards north and then 6m vertically
upwards what is the magnitude of the sum of these displacements ?
1) 10.28m
2) 14.32m
3) 22.42m
4) 30.82m
Answer:
D = 14.31 m
Explanation:
It is given that,
Displacement due east is 12 m
Displacement due north is 5 m
Displacement in vertically upward direction is 6 m
We need to find the magnitude of the sum of these displacements. We know that, vertically upward, east and north are mutually perpendicular direction. So, the resultant is given by :
[tex]R=\sqrt{12^2+5^2+6^2} \\\\R=\sqrt{144+25+36} \\\\R=14.31\ m[/tex]
So, the magnitude of the sum of these displacements is 14.31 m.
Lanzamos desde el suelo una pelota con un ángulo de 45° y queremos colarla en una cesta que está a 7 m de distancia horizontal y a 3.5 m de altura. Calcular con qué velocidad hay que lanzarla.
Answer:
v₀ = 11.72 m / s
Explanation:
This is a missile launch exercise. Let's write the relations for the final position
x = v₀ₓ t
y = [tex]v_{oy}[/tex] t - ½ g t²
Let's use trigonometry to find the initial velocities
sin 45 = v_{oy} / v₀
cos 45 = v₀ₓ / v₀
v_{oy} = v₀ sin 45
v₀ˣ = v₀ cos45
we substitute
x = v₀ cos 45 t
y = v₀ sin 45 t - ½ g t²
in this equation system we have two unknowns and two equations for which it can be solved, let's substitute the values
7 = v₀ 0.707 t
3.5 = v₀ 0.707 t - ½ 9.8 t²
we clear the time in the first equation and substitute in the second
3.5 = v₀ 0.707 (7 / v₀ 0.707) - 4.9 (7 / v₀ 0.707) 2
3.5 = 7 - 480.345 / v₀²
480.345 / v₀² = 7-3.5
v₀² = 480.345 / 3.5
v₀ = √ 137.24
v₀ = 11.72 m / s
11 kg is a familiar weight for a bag of flour. You are baking cookies for a Save The Rain Forest fund drive. It takes 500 g of flour to make one batch of cookies. How many batches of cookies can you make with one bag of flour
Answer: 22 batches.
Explanation:
Given that 11 kg is a familiar weight for a bag of flour. Also, it is given that It takes 500 g of flour to make one batch of cookies.
How many batches of cookies can you make with one bag of flour
Let's first convert 11 kg into grams (g) by multiplying it by 1000
11 × 1000 = 11000 g
Divide 11000 by 500
11000/500 = 22
Therefore, 22 batches of cookies can be made with one bag of flour.
The statement "Chimpanzees like to eat fruit" is an example of a(n)
a. qualitative observation
C. inference
b. quantitative observation
d. prediction
Answer:
inference
Explanation:
took the test hope I helped :p
equals distance divided by time.
speed
distance
time
O acceleration
Answer:
[tex]speed[/tex]Explanation:
Rule:
Speed= Distance/ TimeHope this helps!
A football is kicked from ground level with an initial velocity of 23.6 m/s at angle of 57.5° above the horizontal. How long, in seconds, is the football in the air before it hits the ground? Ignore air resistance.
Answer:
6 seconds is the best answer
It will take 6 seconds to the football in the air.
What is Initial velocity?Velocity is the rate that the position of an item changes relative to time. When forces are applied to an item, it accelerates. This acceleration affects the velocity.
The object's initial velocity, vi, is its speed before acceleration changes it. The new velocity, which has increased for a while, is the final velocity, or vf.
Initial Velocity, denoted as u, is the velocity at time period t = 0. It is the speed at which motion first occurs. There are four equations for starting velocity: The starting velocity is expressed as u = v - at if time, acceleration, and final velocity are given.
Therefore, It will take 6 seconds to the football in the air.
To learn more about Velocity, refer to the link:
https://brainly.com/question/18084516
#SPJ2
A child goes down a slide, starting from rest. If the length of the slide is 2 m and it takes the child 3 seconds to go down the slide, what is the child's acceleration?
Answer:
0.44 m/s^2
Explanation:
initial velocity = 0 (since the child starts from rest)
distance covered by the child = 2 m (the length of the slide)
time taken = 3 sec
acceleration of the child = ?
using Newton's equation of motion
s = [tex]ut + \frac{1}{2}at^{2}[/tex]
where s is the distance covered by the child
u is the initial velocity
a is the acceleration
t is the time spent
substituting values, we have
2 = 0(3) + [tex]\frac{1}{2}a*3^{2}[/tex]
2 = 9a/2
4 = 9a
a = 4/9 = 0.44 m/s^2
Pendulum on a Fixed Pivot
Match each point from the pendulum to the correct percentage of PE.
3 points
0% 98% 100%
Point 1
Point 3
Point 5
Point 1
Point 3
Point 5
Answer:
Point 1. most extreme point. PE 100%
Point 3 point at mid-height PE 50%
Point 5 lowest point PE 0%
Explanation:
The energy in a pendulum is conserved if we ignore the friction of the air, the total energy is
Em = ½ k A²
at each point the energy can be written as a potential part and a kinetic part
Em = PE + K
where Pe is the potential energy and K the kinetic energy
In the entire trajectory the energy passes from one form to the other.
In general there are some points of very high interest.
Point 1. most extreme point in this case the pendulum is stopped and the
Em = PE 100%
Point 3. point at mid-height
Em = PE + K
at this point the energy is 50% of each
Point 5. lowest point, at this point the body has a height of ero so its potential energy is zero
Em = K 100%
potential energy is 0%
Hey ... guys can you please help me...
A lorry is travelling with a velocity of 30 m/s came to rest in 5s .What is it acceleration?
Answer:
The answer is 6 m/s^2.
Explanation:
by using the formula,
a = v-u/t
Select the correct answer.
Where do congressional leaders usually refer a proposed bill after its introduction?
A.
a conference committee
B.
a standing committee
C.
an ad hoc committee
D.
the floor
Answer:
B. a standing committee
Explanation:
got it right on Edmentum/Plato <3
30 points plus brainliest for best answer no funny answers Assignment: Waves Concept Map Exploration Your concept map will compare the manner in which energy is transferred by mechanical waves and electromagnetic waves. Include the following somewhere in your concept map: • types of energy transferred • medium required (if applicable) for transfer of energy • speed of energy transfer through various mediums (solid, liquid, gas) Concept Idea Bank: mechanical waves transfer light energy can pass through matter electromagnetic waves do not require a medium transfer sound energy require a medium travel is slowed as density of travel is faster as density of matter increases matter increases 1. Think about the kind of map that would be best to use to organize and compare mechanical and electromagnetic waves. 2. Review the rubric that will be used to grade this assignment. 3. Create your concept map. 4. When you have completed the concept map, don’t forget to submit it for a grade. Describe the functional relationship between the two quantities in the graph.
Answer:
Waves: "The phenomenon in which any number of particles or the energy packets that originates from a transmitter travels in a direction and it is somehow directed towards a receiver end is called as waves."
Electromagnetic wave: The type of waves which do not require any sort of medium for the transformation process of the energy, as it is directed towards from a transmitter towards a receiver.
For example: Radio, IR , Ultra sonic waves etc.
Mechanical waves: The type of waves which requires some medium to transfer the energy packets from one place to another, or from one point to the other using some medium. As the medium can be solids,liquids, or any gaseous forms.
For example: Sound waves, seismic waves etc.
Explanation:
The transfer of energy in Mechanical waves and Electromagnetic waves:
Both, the waves are much different due ones basic requirement of a medium while the other don't require one. As the density of any medium if increased it will increase the speed of the wave propagation. And this any medium being more denser will result in high speed form mechanical waves.
While, the electromagnetic waves can pass through matters or elements easily with out having any obstruction faced in its path because presence of medium is no requirement for the wave propagation.
I hope this helps!!
Please helppp....What are 5 examples of real science
Answer:
dynamics
kinematics
fluid mechanisms
earth science and
physics
Expand (2x + y) (2x - y).
Answer: 4x²-y²
Explanation:
FORMULA
a²-b²=(a+b)(a-b)
-----------------------------
(a+b)(a-b)=a²-b²
(2x+y)(2x-y)=(2x)²-(y)²
=4x²-y²
Hope this helps!! :)
Please let me know if you have any question
If a snail travels at 5 m/s, how far will it travel in 90 seconds?
Answer:
in 90 seconds It'll travel 450m At constant speed of 5m/s
Answer:
d = 450 m
Explanation:
d
use the formula v = ----
t
v = 5 m/s
t = 90 seconds
d
5 m/s = -------------
90 sec
d = 5 m/s ( 90 sec)
d = 450 m
While practicing S-turns, a consistently smaller half-circle is made on one side of the road than on the other, and this turn is not completed before crossing the road or reference line. This would most likely occur in turn:_______
Answer:
The answer is "4-5-6 because the bank is growing too quickly in the beginning of its turn".
Explanation:
The S-turns is also known as the reference technique, in which the ground track of the aircraft on both sides of a defined ground-based straight-line distance represents 2 different but equivalent circles.
Throughout the S-turns, on either side of the road, a progressively smaller half-circle is formed, and this turn does not stop until the road or reference line is crossed during the early part of the turn, the twists increase too quickly.