11
The frequency of the monochromatic light produced by a laser is 4.7 x 10-14 Hz.
A ray of light from the laser passes from a vacuum, where the speed of light is 3.0 x 108 m/
S,
into a fibre-optic cable.
(a) State
(i) what is meant by monochromatic
*
(2 Points)
(ii) the frequency (1)
Enter your answer

Answer:

La nueva presión manométrica en el neumático es 117,48 kilopascales.

Explanation:

Supongamos que el gas contenido en el neumático del automóvil se comporta como un gas ideal, cuya ecuación de estado es:

[tex]P\cdot V=n\cdot R_{u}\cdot T[/tex] (Eq. 1)

Donde:

[tex]P[/tex] - Presión absoluta del aire, medido en kilopascales.

[tex]V[/tex] - Volumen del aire, medido en metros cúbicos.

[tex]n[/tex] - Cantidad molar del aire, medida en moles.

[tex]T[/tex] - Temperatura del aire, medida en Kelvin.

[tex]R_{u}[/tex] - Constante universal de los gases ideales, medida en kilopascal-metros cúbicos por mol-Kelvin.

Si sabemos que el neumático experimenta un proceso isocórico e isomolar de calentamiento y presurización, entonces podemos reducir la ecuación de estado a la siguiente relación:

[tex]\frac{P_{A}}{T_{A}} = \frac{P_{B}}{T_{B}}[/tex] (Eq. 2)

Donde:

[tex]P_{A}[/tex], [tex]P_{B}[/tex] - Presiones absolutas inicial y final del aire, medidas en kilopascales.

[tex]T_{A}[/tex], [tex]T_{B}[/tex] - Temperaturas inicial y final del aire, medidas en Kelvin.

Despejamos la presión absoluta final del aire:

[tex]P_{B} = \frac{T_{B}}{T_{A}}\cdot P_{A}[/tex]

La presión absoluta es la suma de la presión atmosférica y la presión manométrica, todas medidas en kilopascales. La presión absoluta inicial del aire es:

[tex]P_{A} =101,3\,kPa + 207\,kPa[/tex]

[tex]P_{A} = 208,3\,kPa[/tex]

Si [tex]T_{A} = 298,15\,K[/tex], [tex]T_{B} =313,15\,K[/tex] y [tex]P_{A} = 208,3\,kPa[/tex], la presión absoluta final del aire es:

[tex]P_{B} = \left(\frac{313,15\,K}{298,15\,K} \right)\cdot (208,3\,kPa)[/tex]

[tex]P_{B} = 218,780\,kPa[/tex]

Ahora, la presión manométrica final en el neumático es:

[tex]P_{man, B} = 218,780\,kPa-101,3\,kPa[/tex]

[tex]P_{man, B} = 117,48\,kPa[/tex]

La nueva presión manométrica en el neumático es 117,48 kilopascales.

Answer:

b

Explanation:

Sir Isaac Newton explain the ocean tides result from the gravitational attraction of the Sun and Moon on the oceans of the Earth

An air mass boundary where a low moisture air mass meets a high moisture air mass is called a dry line. It is fundamental in meteorology.

A dry line is a transect line capable of splitting (dividing) the moist (atmospheric) air and dry air.

The dry line can also be defined as a roughly real boundary between two different masses of air (humid and dry).

The dry line can be used to schematize how is the movement of the most and dry air masses in a front.

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Answer:

Sound waves are greatly affected by the medium in which they travel, not just in terms of speed, but also in terms of loudness and tonal quality. Just think of the variation in loudness and sound quality of different acoustic guitars which may use the same strings, but the sound is greatly affected by the different media in which it travels, including the wood, sound cavities, even the varnish on the instrument.

Explanation:

Answer:

.3 repeating hours

Explanation:

Answer:

its Phyiscs How hard Can It Really Be

Based on astronomical records, the reasons why there is main sequence are:

A star can be defined as a giant astronomical or celestial object that comprises a luminous sphere of plasma and it is bounded together by its own gravitational force.

Generally, a star is typically made up of two (2) main hot gases and these include the following:

A main sequence refers to a type of star that fuses hydrogen in its core and it has a stable balance of outward pressure as a result of core nuclear fusion and gravitational forces that are pushing inward.

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Answer:

You can charge capacitor to any potential as long as charging voltage is less than rated voltage value of the capacitor. The voltage across a capacitor is limited by the dielectric strength of the insulating material times its thickness.

Answer:

v = 20.57 m/s

Explanation:

Given that,

Acceleration, a = 2.2 m/s²

Initial speed of the person, u = 0 (at rest)

Distance, s = 100 m

We need to find the top speed. It can be calculated using third equation of motion.

[tex]v^2-u^2=2as[/tex]

v is final speed

[tex]v=\sqrt{2as} \\\\v=\sqrt{2\times 2.2\times 100} \\\\v=20.57\ m/s[/tex]

So, the top speed of the person is 20.57 m/s.

The acceleration of gravity on the planet where the spaceship is located is 43.3m/s²

HOW TO CALCULATE ACCELERATION:

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A 4.0 kg box is pressed into a spring. The spring constant is k = 220 N/m. The box is released at the bottom of a frictionless ramp and rises to a height of y = 0.75 m as shown below.

How far was the spring compressed?

Answer: 0.52 m

Answer:

B but I still could be wrong :)

The pic isn't clear

the kidneys process it into a liquid called: A. urine

Diffraction pattern becomes narrower

Recall the term (  ROYBGIV )

R - red ( diffracted most )

O - orange

Y - yellow

B - blue

G - green

I - indigo

V - violet ( diffracted least )

The arrow is fired with an initial upward velocity of 32 ft/s.option 4 is correct.

The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component.

Velocity at any angle is resolved to get its component of x and y-direction.

The given data in the problem is;

g is the acceleration due to gravity

v₀ is the initial speed=?

h is the initial height = 4+32t-16t²

The relation of the height with the velocity and time is given according to the motion will be;

[tex]h(t)= -\frac{1}{2}gt^ 2+v_0t+h_0 \\\\[/tex]

h  = 4+32t-16t²

Hence the value of the v₀ will be 32 ft/sec.

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Answer:

Option 4

Explanation:

i got it right on ed 2022

Answer:

Explanation:

For an object falling under the influence of gravity, the mass does not affect the acceleration -- that is a constant called "g". As the mass gets larger, it takes a greater force (supplied by the greater weight) to be able to support the same acceleration. g=F/m. The weight (the force) is proportional to mass, so the fraction is the constant g.

Answer:

As the mass of an object is increased, the acceleration of the object is decreased.

My explanation:

I like to think of it as if you have a wooden car going straight forward it will go a certain speed, if you add a 1 pound weight to that very same car it will go slower than the car without the weight.

Hope this Helps! :)

Have any questions? Ask below in the comments and I will try my best to answer.

-SGO

If an object accelerates from rest, the velocity after 2.1 s, if it has a constant acceleration of 9.8 m/s² is 43.218 m/s².

To find the velocity, the given values are,

Time = 2.1 seconds

Acceleration = 9.8 m/s².

Acceleration can be defined as the rate of change of the velocity of an item with appreciation to time. Accelerations can be vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

The acceleration will remain the same at 9.8 m/s². as under free fall conditions acceleration due to gravity remains constant.

Calculation:-

V = U + at

V = 0 + 9.8 × (2.1)²

  = 9.8 × 4.41

  = 43.218 m/s².

But, the acceleration will remain the same at 9.8 m/s neglecting air resistance.

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

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#4

Resistors are connected in parallel circuit

#5

They differs

Because

For series connection

[tex]\\ \rm\rightarrowtail R_{net}=R_1+R_2\dots[/tex]

For parallel connection

[tex]\\ \rm\rightarrowtail \dfrac{1}{R_{net}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\dots[/tex]

So, here for question no. 4 and 5, we are given a Diagram, which have 3 resistors connected in parallel each having a resistance of [tex]{\bf{2\Omega}}[/tex], [tex]{\bf{3\Omega}}[/tex] and [tex]{\bf{4\Omega}}[/tex]. And we are told to find a factor which will change for the given combination, and a factor which will not change, So here, as the resistors are connected in parallel, so the voltage will remain same for all the resistors, while the Current will be different for every resistor, And that's what the reason of why we always do connection in parallel for home purposes, because, we need voltage same in every resistor of the circuit. So, the factor which will change is [tex]{\boxed{\bf{Current}}}[/tex] and the factor which willn't change is [tex]{\boxed{\bf{Voltage}}}[/tex], and if the resistors were connected in Series combination, then current should be same for all resistors, while voltage will change.

Well, if the resistors are connected in the above way we have, and if we call our Resistors as [tex]{\bf{R_{1}}}[/tex], [tex]{\bf{R_{2}}}[/tex] and [tex]{\bf{R_{3}}}[/tex], then the equivalent resistance we will be having is :

[tex]{:\implies \quad \boxed{\bf{\dfrac{1}{R_{eq.}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}}}}[/tex]

Also, we can prove this fact just with the help of the reason provided in the above question, i.e that in Parallel combination, voltage remains same, but current changes, while in Series combination, current remains same but voltage changes, so we are just gonna prove the formula for both series combination and Parallel as well

So, let's prove the formula for series combination first, so consider n resistors connected in series, let Resistors as [tex]{\bf{R_{1},R_{2},R_{3}\cdots \cdots R_{n}}}[/tex], now as current will be same through all the resistors as connected in series, so if the current [tex]{\bf{I}}[/tex] from then, same current will flow through the whole circuit and each resistors, also let the voltages of every resistors being [tex]{\bf{V_{1},V_{2},V_{3}\cdots \cdots V_{n}}}[/tex], so now by Ohm's law, we can deduce that, the current from first circuit will be [tex]{\bf{V_{1}=IR_{1}}}[/tex]...and so on for all Resistors, and now if we add all resistors, so the equivalent Voltage will just be ;

[tex]{:\implies \quad \sf V_{eq.}=V_{1}+V_{2}+V_{3}+\cdots \cdots +V_{n}}[/tex]

[tex]{:\implies \quad \sf IR_{eq.}=IR_{1}+IR_{2}+IR_{3}+\cdots \cdots IR_{n}}[/tex]

[tex]{:\implies \quad \sf I(R_{eq.})=I(R_{1}+R_{2}+R_{3}+\cdots \cdots R_{n})}[/tex]

[tex]{:\implies \quad \boxed{\bf{R_{eq.}=R_{1}+R_{2}+R_{3}+\cdots \cdots R_{n}}}}[/tex]

Therefore, we proved for series.

Now, consider n resistors connected in parallel, with resistances, [tex]{\bf{R_{1},R_{2},R_{3}\cdots \cdots R_{n}}}[/tex], now as voltage will be same through all the resistors as connected in parallel,while current will change, so let total voltage be [tex]{\bf{V}}[/tex], and current for each resistor as [tex]{\bf{I_{1},I_{2},I_{3}\cdots \cdots I_{n}}}[/tex],so by using the same concept as above we can write by using ohm's law :

[tex]{:\implies \quad \sf I_{eq.}=I_{1}+I_{2}+I_{3}+\cdots \cdots +I_{n}}[/tex]

Rewrite using ohm's law :

[tex]{:\implies \quad \sf \dfrac{V}{R_{eq.}}=\dfrac{V}{R_1}+\dfrac{V}{R_2}+\dfrac{V}{R_3}+\cdots \cdots +\dfrac{V}{R_n}}[/tex]

[tex]{:\implies \quad \sf V\dfrac{1}{R_{eq.}}=V\bigg(\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\cdots \cdots +\dfrac{1}{R_n}\bigg)}[/tex]

[tex]{:\implies \quad \boxed{\bf{\dfrac{1}{R_{eq.}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}+\cdots \cdots +\dfrac{1}{R_{n}}}}}[/tex]

Hence, we proved for Parallel combination too

Also, refer to the attachment for a better understanding, and just a point that Voltmeter is always connected in parallel while ammeter in series, and all the things above are taken in SI units

The solution of the inequality means that the band must sell more than 188 rolls of wrapping paper.

We are told that the solution to the inequality is represented with a number line that goes from 188 to 190, such that we have an open circle at 188 and all the region to the right is shaded.

The open circle means that the point itself is not a solution, and because the region at the right is shaded, the solutions are larger than 188, then the solution of this inequality will be:

188 < x.

If x represents the number of rolls of wrapping paper that the band must sell, this means that the band must sell more than 188 rolls of wrapping paper.

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Answer:

I think positive...

.....

......

Answer:

3.5 hours

Explanation:

7.0 divided by 2.0 equals 3.5.

Answer:

10 seconds

Explanation:

Hope this is right and that it helps.

You see if the skier is going 250 meters a second 250 times 10 is 2500 so it would take the skier 10 seconds.

Answer:

Explanation:

distance = 2500 meters

velocity = 250 meter/second

time = distance / velocity

       =    2500 meters    

          250 meter/second

       = 10 sec.

Answer: acceleration is directly proportional to net force when mass is constant… and that acceleration is inversely proportional to mass when net force is constant…

Explanation:

If the force is constant, then the acceleration will be inversely proportional to the mass.

If the force is constant, then the acceleration will be inversely proportional to the mass.

We have Newton's Second law of Motion.

We have to determine the relation between mass and acceleration if force is constant.

Newton's Second law of motion states that the rate of change of momentum is directly proportional to force applied.

According to the question, we have -

Force = Mass x Acceleration

F = ma

if Force is constant, then -

a = [tex]\frac{F}{a}[/tex]

Hence, if the force is constant, then the acceleration will be inversely proportional to the mass.

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Answer:

Explanation:

i just submitted the assignment ill let you know how i do

Answer:

Explanation:

Added arrows and chlorophyll to the plant.