100 POINTS PLEASE HELP IM BEGGING U I NEED TO PASS (summer school)

100 POINTS PLEASE HELP IM BEGGING U I NEED TO PASS (summer School)

Answers

Answer 1

Answer:

choice 3 3√7

Step-by-step explanation:

Answer 2

Answer:

3√7.... that the answer


Related Questions

The port of South Louisiana, located along miles of the Mississippi River between New Orleans and Baton Rouge, is the largest bulk cargo port in the world. The U.S. Army Corps of Engineers reports that the port handles a mean of million tons of cargo per week (USA Today, September). Assume that the number of tons of cargo handled per week is normally distributed with a standard deviation of million tons.
A. What is the probability that the port handles less than 5 million tons of cargo per week?
B. What is the probability that the port handles 3 or more million tons of cargo per week?
C. What is the probability that the port handles between 3 million and 4 million tons of cargo per week?
D. Assume that 85% of the time the port can handle the weekly cargo volume without extending operating hours. What is the number of tons of cargo per week that will require the port to extend its operating hours?

Answers

Answer:

(A) Probability that the port handles less than 5 million tons of cargo per week is 0.7291.

(B) Probability that the port handles 3 or more million tons of cargo per week is 0.9664.

(C) Probability that the port handles between 3 million and 4 million tons of cargo per week is 0.2373.

(D) The number of tons of cargo per week that will require the port to extend its operating hours is 3.65 million tons.

Step-by-step explanation:

We are given that the port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge.

The U.S. Army Corps of Engineers reports that the port handles a mean of 4.5 million tons of cargo per week with a standard deviation of 0.82 million tons.

Let X = Number of tons of cargo handled per week

SO, X ~ Normal([tex]\mu=4.5,\sigma^{2}=0.82^{2}[/tex])

The z score probability distribution for normal distribution is given by;

                               Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean = 4.5 million tons

            [tex]\sigma[/tex] = standard deviation = 0.82 million tons

(A) Probability that the port handles less than 5 million tons of cargo per week is given by = P(X < 5 million tons)

        P(X < 5) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{5-4.5}{0.82}[/tex] ) = P(Z < 0.61) = 0.7291

The above probability is calculated by looking at the value of x = 0.61 in the z table which has an area of 0.7291.

(B) Probability that the port handles 3 or more million tons of cargo per week is given by = P(X [tex]\geq[/tex] 3 million tons)

        P(X [tex]\geq[/tex] 3) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\geq[/tex] [tex]\frac{3-4.5}{0.82}[/tex] ) = P(Z [tex]\geq[/tex] -1.83) = P(Z [tex]\leq[/tex] 1.83)

                                                                          = 0.9664

The above probability is calculated by looking at the value of x = 1.83 in the z table which has an area of 0.9664.

(C) Probability that the port handles between 3 million and 4 million tons of cargo per week is given by = P(3 million tons < X < 4 million tons)

     P(3 million tons < X < 4 million tons) = P(X < 4) - P(X [tex]\leq[/tex] 3)

 

      P(X < 4) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{4-4.5}{0.82}[/tex] ) = P(Z < -0.61) = 1 - P(Z [tex]\leq[/tex] 0.61)

                                                = 1 - 0.7291 = 0.2709

      P(X [tex]\leq[/tex] 3) = P( [tex]\frac{X-\mu}{\sigma}[/tex] [tex]\leq[/tex] [tex]\frac{3-4.5}{0.82}[/tex] ) = P(Z [tex]\leq[/tex] -1.83) = 1 - P(Z < 1.83)

                                                 = 1 - 0.9664 = 0.0336

The above probability is calculated by looking at the value of x = 0.61 and x = 1.83 in the z table which has an area of 0.7291 and 0.9664 respectively.

Therefore, P(3 < X < 4) = 0.2709 - 0.0336 = 0.2373

(D) Now, it is given that 85% of the time the port can handle the weekly cargo volume without extending operating hours, that means;

           P(X > x) = 0.85     {where x is the required no. of tons of cargo}

           P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{x-4.5}{0.82}[/tex] ) = 0.85

           P(Z > [tex]\frac{x-4.5}{0.82}[/tex] ) = 0.85

In the z table, the critical value of x which represents top 85% area is given as -1.036, that is;

                      [tex]\frac{x-4.5}{0.82} = -1.036[/tex]  

                    [tex]{x-4.5} = -1.036\times 0.82[/tex]

                     x  =  4.5 - 0.85 = 3.65 million tons

Hence, the number of tons of cargo per week that will require the port to extend its operating hours is 3.65 million tons.

For a large supermarket chain in a particularâ state, aâ women's group claimed that female employees were passed over for management training in favor of their male colleagues. The company denied thisâ claim, saying it picked the employees from the eligible pool at random to receive this training.â Statewide, the large pool of more than 100 eligible employees who can be tapped for management training is 40â% female and 60â% male. Since this programâ began, 35 of the 50 employees chosen for management training were male and 15 were female.
Complete parts (a) and (b).
(a) Is there sufficient evidence to support the women's claim?
(b) Compute a 95% confidence interval and write your conclusions.

Answers

Answer:

1) As the P-value (0.097) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the women's claim that female employees were passed over for management training in favor of their male colleagues.

2) The 95% confidence interval for the population proportion is (0.173, 0.427).

The populations proportion (π=0.4) is included in this confidence interval, so the claim has no enough evidence to be supported.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that female employees were passed over for management training in favor of their male colleagues.

We use the women's part for sample and population proportions.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi=0.4\\\\H_a:\pi<0.4[/tex]

The significance level is 0.05.

The sample has a size n=50 persons.

The sample proportion is p=0.3.

[tex]p=X/n=15/50=0.3[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.4*0.6}{50}}\\\\\\ \sigma_p=\sqrt{0.0048}=0.069[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.3-0.4+0.5/50}{0.069}=\dfrac{-0.09}{0.069}=-1.299[/tex]

This test is a left-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=P(z<-1.299)=0.097[/tex]

As the P-value (0.097) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that female employees were passed over for management training in favor of their male colleagues.

b) We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.3.

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.3*0.7}{50}}\\\\\\ \sigma_p=\sqrt{0.0042}=0.0648[/tex]

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

[tex]MOE=z\cdot \sigma_p=1.96 \cdot 0.0648=0.127[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=p-z \cdot \sigma_p = 0.3-0.127=0.173\\\\UL=p+z \cdot \sigma_p = 0.3+0.127=0.427[/tex]

The 95% confidence interval for the population proportion is (0.173, 0.427).

The populations proportion (π=0.4) is included in this confidence interval, so the claim has no enough evidence to be supported.

The population of a small town in central Florida has shown a linear decline in the years 2002-2012. In 2002 the population was 34200 people. In 2012 it was 29300 people.

A) Write a linear equation expressing the population of the town, P , as a function of t , the number of years since 2002. Include the entire equation as your answer.
B) If the town is still experiencing a linear decline, what will the population be in 2015?

Answers

I think answer should be b.

Please help with this!

Answers

Answer:

166 quarters,  40 dimes

Step-by-step explanation:

x - quarters

y - dimes

      x  +        y =  206

0.25x + 0.10y = 45.50

y = 206 - x

0.25x + 0.10(206 - x) = 45.50

0.25x + 20.6 - 0.10x = 45.50

0.15x = 45.50 - 20.6

0.15 x = 24.9

x = 24.9/ 0.15 = 166 quarters

y =206 - 166 = 40 dimes

Check:

0.25*166+ 0.10*40 = 45.50

45.50 = 45.50

Factor completely, then place the answer in the proper location on the grid.
21a2-57a+ 30

Answers

Answer:

3 (7 a - 5) (a - 2)

Step-by-step explanation:

Factor the following:

21 a^2 - 57 a + 30

Factor 3 out of 21 a^2 - 57 a + 30:

3 (7 a^2 - 19 a + 10)

Factor the quadratic 7 a^2 - 19 a + 10. The coefficient of a^2 is 7 and the constant term is 10. The product of 7 and 10 is 70. The factors of 70 which sum to -19 are -5 and -14. So 7 a^2 - 19 a + 10 = 7 a^2 - 14 a - 5 a + 10 = a (7 a - 5) - 2 (7 a - 5):

3 a (7 a - 5) - 2 (7 a - 5)

Factor 7 a - 5 from a (7 a - 5) - 2 (7 a - 5):

Answer: 3 (7 a - 5) (a - 2)

State who is correct and explain why

Answers

Answer:

12.4+3√7 is  irrational

Step-by-step explanation:

12.4 is a rational number

3√7 is an irrational number

The sum of a rational number and an irrational number is irrational.

So, 12.4+3√7 is  irrational

The area of the figure below is 9 ft. What is the
height of the triangle?​

Answers

Answer:

4 ft

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

9 = 1/2 (4.5)h

9 =2.25 h

Divide each side by 2.25

9/2.25 = 2.25h/2.25

4 =h

Answer:

Hieght=4

hope it helps u...

Step-by-step explanation:

Is 144m,165m,219m a right triangle

Answers

Answer:

Yes

Step-by-step explanation:

For a triangle to be rights angled.

It should follow Pythagoras theorem.

Pythagoras theorem states that if sides containing right angle is  a and b

then  is given by

hypotenuse =  [tex]\sqrt{a^2+b^2}[/tex]

As hypotenuse is always the greatest side

Out of the given sides 144m,165m,219m

219 can only be hypotenuse

Thus side containing right angle will be 144m and 165m .

Lets plug these value in formula of Pythagoras theorem

[tex]hypotenuse = \sqrt{144^2 + 165^2} \\hypotenuse = \sqrt{20,736 + 27,225} \\hypotenuse = \sqrt{47961} \\hypotenuse = 219\\[/tex]

As we can see that hypotenuse calculated by us is same as given in problem.

Thus the given triangle is right angled.

at the audtions, 40 studens tried out for the school show choir, but only 12 will be chosen. How many different ways can the show choir be formed

Answers

Answer:D

Step-by-step explanation:

It’s a permutation

Find the equation of the line. Write the equation of the line in standard form.
Vertical line; through (-4,-8).

Answers

Answer:

  x = -4

Step-by-step explanation:

The equation of a vertical line in standard form is ...

  x = constant

In order for this line to go through the point with x-coordinate -4, the constant must be -4:

  x = -4

Find the coordinates of the other endpoint of the​ segment, given its midpoint and one endpoint.​ (Hint: Let​ (x,y) be the unknown endpoint. Apply the midpoint​ formula, and solve the two equations for x and​ y.)

Midpoint (-15,2) endpoint (-12,11)
What is the other endpoint?

Answers

Answer:

The other endpoint of the​ segment is [tex](-18,-7)[/tex].

Step-by-step explanation:

The midpoint of the points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by the following formula:

                                          [tex](x_m,y_m)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )[/tex]

where [tex](x_m,y_m)[/tex] = coordinates of the midpoint.

We know that the midpoint is (-15, 2) and an endpoint is (-12, 11). Substituting the information we have gives:

                                         [tex](-15,2)=(\frac{x_1-12}{2}, \frac{y_1+11}{2} )[/tex]

To find [tex]x_1[/tex] we need to solve this equation:

[tex]-15=\frac{x_1-12}{2} \\\\\frac{x_1-12}{2}=-15\\\\\frac{2\left(x_1-12\right)}{2}=2\left(-15\right)\\\\x_1-12=-30\\\\x_1-12+12=-30+12\\\\x_1=-18[/tex]

and to find [tex]y_1[/tex] we need to solve this equation:

[tex]2= \frac{y_1+11}{2} \\\\\frac{y_1+11}{2}=2\\\\\frac{2\left(y_1+11\right)}{2}=2\cdot \:2\\\\y_1+11=4\\\\y_1=-7[/tex]

The other endpoint of the​ segment is [tex](x_1,y_1)=(-18,-7)[/tex].

To study the effectiveness of a certain adult reading program, researchers will select a random sample of adults who are eligible for the program. The selected adults will be given a pretest before beginning the program and a posttest after completing the program. The difference in the number of correct answers on the pretest and the number of correct answers on the posttest will be recorded for each adult in the sample. Which of the following is the most appropriate inference procedure for the researchers to use to analyze the results?a) A one-sample z-interval for a population proportion.b) A one-sample t-interval for a sample mean difference.c) A matched-pairs t-interval for a population mean difference.d) A matched-pairs t-interval for a sample mean difference.e) A two-sample t-interval for a difference between means.

Answers

Answer:

c) A matched-pairs t-interval for a population mean difference

Step-by-step explanation:

Matched-Pairs t-Test. A matched-pairs t-test is used to test whether there is a significant mean difference between two sets of paired data.

A matched pair t test is used for comparison between means of two sets of paired data.

Thus, Option C: A matched-pairs t-interval for a population mean difference. is correct choice.

Given that:

The selected sample of people will have to give pretest and then training and then post-test and the difference in the scores is recorded.

The researches want to identify the resultant difference so as to identify the effectiveness of the program.

Explanation:

For such type of cases, we use matched pair t test.

A matched pair t test is used to see if there is significant difference between means of two sets of paired data.

By paired data, we mean the data in both set which is paired.

Since the person is same who gives pre and post  test after training, thus the data is paired.

Also since the difference is to be analyzed to check the significance of the reading program, thus matched pair t test is perfect fit here.

Thus, option C: A matched pairs t-interval for a population mean difference is correct option.

Learn more about t-tests here:

https://brainly.com/question/1189751

What is the following quotient?

StartFraction 2 Over StartRoot 13 EndRoot + StartRoot 11 EndRoot EndFraction
StartRoot 13 EndRoot minus 2 StartRoot 11 EndRoot
StartFraction StartRoot 13 EndRoot + StartRoot 11 EndRoot Over 6 EndFraction
StartFraction StartRoot 13 EndRoot + STartRoot 11 EndRoot Over 12 EndFraction
StartRoot 13 EndRoot minus StartRoot 11 EndRoot

Answers

Answer: on edge i got D,   sq rt 13-sq rt 11

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

edge

If f(x) = 4x + 3 and g(x) = x - 9,
which statement is true?
Click on the correct answer.
2 is in the domain of fºg.
2 is not in the domain of fºg.

Answers

Answer:

2 isnt the domain

Step-by-step explanation:

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Answers

Answer:

a. [tex]f^-^1(x)=\frac{x}{4} +3[/tex]

b. [tex]f(-9)=-48[/tex]

c. [tex]f^-^1(-9)=\frac{3}{4}[/tex]

Step-by-step explanation:

In a, the -1 means inverse of f(x). To find the inverse, you rewrite the equation in terms of x and y. You replace the x with y and y with x. Then you solve for y.

[tex]f^-^1(x)=4x-12[/tex]

[tex]y=4x-12[/tex]

[tex]x=4y-12[/tex]

[tex]x+12=4y[/tex]

[tex]\frac{x}{4} +3=y[/tex]

[tex]f^-^1(x)=\frac{x}{4} +3[/tex]

In b, all you have to do is plug in -9 into f(x).

[tex]f(9)=4(9)-12[/tex]

[tex]f(9)=-48[/tex]

In c, you plug in -9 into inverse function f.

[tex]f^-^1(-9)=\frac{3}{4}[/tex]

A $30 shirt is marked, "Get 1/3 off. What is the sale price of the shirt?

Answers

Answer:

$20 after the applied coupon

Step-by-step explanation:

The required sale price of the shirt after getting  1/3 off is $20.

What are percentages?

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

Here,
A $30 shirt is marked, "Get 1/3 off.
The sale price of the shirt,
= 30 - 1 / 3×30
= 30 - 10
= $ 20

Thus, the required sale price of the shirt after getting  1/3 off is $20.

Learn more about percentages here:

brainly.com/question/13450942

#SPJ1

What’s the correct answer for this?

Answers

Answer:

B.

Step-by-step explanation:

Data

Center = (2, -16)

A (2, -13)

P (-1, -16)

Equation

(x - h)² + (y - k)² = r² or

(x₁ - h)² + (y₁ - k)² = (x₂ - h)² + (y₂ - k)²

Substitution

(2 - 2)² + (-13 + 16)² = (-1 - 2)² + (-16 + 16)²

The signs in my equation and the one in the options are different but the results are the same

What is the price per square inch of the better buy: A large pizza with an 18 inch diameter for $20, or a medium pizza with a 14 inch diameter for $14?

Answers

Answer:

The large pizza has the lower cost per square inch, so it is the better buy.

Step-by-step explanation:

A pizza has the format of a circle.

The area of a circle with radius r is given by the following equation:

[tex]A = \pi r^{2}[/tex]

A large pizza with an 18 inch diameter for $20

The radius is half the diameter, so [tex]r = 9[/tex].

In square inches, the area is:

[tex]A = \pi*9^{2} = 81\pi = 254.47[/tex]

254.47 square inches cost $20. So the price per square inch is 20/254.47 = 0.0786.

Medium pizza with a 14 inch diameter for $14:

Radius is 7. So

[tex]A = \pi*7^{2} = 49\pi = 153.938[/tex]

153.938 square inches cost $14. So the price per square inch is 14/153.938 = 0.0909.

The large pizza has the lower cost per square inch, so it is the better buy.

The authors of the paper "Statistical Methods for Assessing Agreement Between Two Methods of Clinical Measurement"† compared two different instruments for measuring a person's ability to breathe out air. (This measurement is helpful in diagnosing various lung disorders.) The two instruments considered were a Wright peak flow meter and a mini-Wright peak flow meter. Seventeen people participated in the study, and for each person air flow was measured once using the Wright meter and once using the mini-Wright meter.
Subject Mini-Weight Meter Weight Meter
1 512 494
2 430 395
3 520 516
4 428 434
5 500 476
6 600 557
7 364 413
8 380 442
9 658 650
10 445 433
11 432 417
12 626 656
13 260 267
14 477 478
15 259 178
16 350 423
17 451 427
(a) Suppose that the Wright meter is considered to provide a better measure of air flow, but the mini-Wright meter is easier to transport and to use. If the two types of meters produce different readings but there is a strong relationship between the readings, it would be possible to use a reading from the mini-Wright meter to predict the reading that the larger Wright meter would have given. Use the given data to find an equation to predict Wright meter reading using a reading from the mini-Wright meter. (Round your values to three decimal places.)

Answers

Answer:

Step-by-step explanation:

Given data;

n = 17

[tex]\sum x =7692[/tex]

[tex]\sum x^2=3685124[/tex]

[tex]\sum y =7656\\\\ \sum xy=3662682[/tex]

Slope:

[tex]\hat B_1=\frac{n \sum xy - \sum x \sum y}{n \sum x^2 - ( \sum x)^2} \\\\=0.96994[/tex]

≅ 0.970

y - intercept :

[tex]\hat B_0 = \frac{\sum y}{n} - \hat B\frac{\sum x}{n} \\\\=11.48178[/tex]

≅ 11.482

a)

Equation :

[tex]\hat y = 11.482+0.970x[/tex]

b)

Predicted wright meter reading

[tex]\hat y = 11.48178+0.96994(563)\\\\=557.558[/tex]

c)Predicted wright meter reading

[tex]\hat y = 11.48178+0.96994(342)\\\\= 343.201[/tex]

help what are the answers im so stuck!

$75 to $25

7,500 people to 8,200 people

Last year, Sandro bought an ipod for $145. Now the price is $199. What is the percent of change?

The price of a share of stock was $97.50 on Monday. By Friday that same week, the price had decreased to $85.50. What was the percent of change

Answers

Answer:

  see below

Step-by-step explanation:

A percentage change is computed as follows:

  percent change = ((new value) -(original value))/(original value) × 100%

For your first one, this looks like ...

  percent change = ($25 -$75)/$75 × 100% = (-50/75) × 100% = -0.667×100%

  percent change = -66.7%

__

When there are a lot of similar calculations to do, I like to use a spreadsheet. See below for the other percentage changes (rightmost column).

What’s the correct answer for this?

Answers

Answer:

B.

Step-by-step explanation:

Yes, because the product of their slopes are -1. Rest explanation in the attached file. Hope it helps :)

Answer:

AB(y = ax + b) contains A(2, 1) and B(3, 4)

=> 2a + b = 1

    3a + b =4

=> a = 3, b= -5 => Slope AB = a = 3

CD (y = cx + d) contains C(-2, -1) and D(1, -2)

=> -2c + d = -1

       c  + d = -2

=> c = -1/3, d = -5/3 => Slope CD = c =-1/3

If AB is perpendicular to CD, then Slope's AB x Slope's CD = -1

Check:

a x c = 3 x (-1/3) = -1

=> AB is perpendicular to CD

=> Option B is correct.

Hope this helps!

:)

If you are buying at item at a store for a price of $77, and there is a 7.5% tax added on
top, what would be the total amount due at the register, to the nearest cent?

Answers

Answer:

82.76

Step-by-step explanation:

77 x 7.5%=5.775

5.775 +77

what is the volume please help.

Answers

Answer:

72 in³

Step-by-step explanation:

THe volume = area of the base × height

area of the base (trapezoid) = [(8×(12+6)]÷2 = 72

height = 1

then

the volume = ((8×(12+6))÷2)×1 = 72

An association between which ear is used for cell phone calls and whether the subject is left-handed or right-handed. The study is reported in "Hemispheric Dominance and Cell Phone Use," by Seidman et al., JAMA Otolaryngology—Head & Neck Surgery, Vol. 139, No. 5. The study began with a survey e-mailed to 5000 people belonging to an otology online group, and 717 surveys were returned. (Otology relates to the ear and hearing.)

Sampling Method
Assume that the population consists of all students currently in your statistics class. Describe how to obtain a sample of six students so that the result is a sample of the given type.

a. Simple random sample
b. Systematic sample
c. Stratified sample
d. Cluster sample

Answers

Answer:

Explained below.

Step-by-step explanation:

In this case we need to select a sample of 6 students from the entire statistics class.

(a)

A simple random sample is a part of a statistical population in which every individual of the population has an equal probability of being selected.

Assigning each individual of the population a unique number and using a computer or random number generator for selection is a procedure to select a simple random sample.

So, we can assign unique numbers to each student in the class and use a random number generator to select any six.

(b)

Systematic sampling is a kind of probability sampling method in which individuals from a larger population are nominated according to a random initial point and a static, periodic interval.  

For instance, consider a study where the researcher first selects a name randomly from the alphabetized order and then follow a fixed pattern of selecting every 10th person from the population.

Suppose there are n students in the class.

And the first student selected is the kth student. Then the remaining five can be selected in a equal interval of k students.

That is, the second student selected will be the 2kth student, the 3rd will be the 3kth, the 4th will be the 4kth, the 5th will be the 5kth and the 6th will be the 6kth.

The sample selected will be a systematic random sample.

(c)

Stratified sampling is a kind of sampling in which whole population is distributed into homogeneous subgroups before one takes a sample. These subgroups are called strata which is mutually exclusive or related.

In this process the population members cannot be excluded.

To select six students we first divide the entire class into 6 subgroups or 6 strata.

Then select one student from each group.

The sample selected will be a stratified random sample.

(d)

Cluster Sampling is a method to randomly select samples from a population that is too enormous for simple random sampling.  

Using cluster sampling, the experimenter distributes the entire population into distinct groups, called clusters.  

Then, a simple random sample of clusters is chosen from the population. Then the experimenter performs the analysis on data from the sampled clusters.

To select a cluster sample, first divided the entire class into various small groups consisting of 2 or 3 students each.

Then select a simple random sample of these groups to select 6 students.

The sample selected will be a cluster sample.

Which expression is equivalent to 25a+5b-13

Answers

An expression that is equivalent to 25a+5b-13 can be:
5(5a+b)-13

Neeed Help ASAP Quick

Answers

Answer:

4; 7

Step-by-step explanation:

Small box = 25 and Large box = 50

small box = x and large box = x+3

25x+50(x+3)=450

25x+50x+150=450

75x=300

x=4

Large box = 4+3 = 7

Therefore, 4; 7

I hope this helped and have a good rest of your day!

3kg of tomatoes cost $34.20 how much will 34 kg cost

Answers

Answer:

64.40$

Step-by-step explanation:

Answer:

3kg = $34.20

34kg= ?

x= (34 x $34.20)/3

x= 1162,80/3

x= $387,60

Two random samples of 30 individuals were selected. One sample participated in an activity which simulates hard work. The average breath rate of these individuals was 17 breaths per minute. The other sample did some normal walking. The mean breath rate of these individuals was 14. Find the 90% confidence interval of the difference in the breath rates if the population standard deviation was 4.2 for breath rate per minute.

Answers

Answer:

[tex] (17-14) -1.64 \sqrt{\frac{4.2^2}{30} +\frac{4.2^2}{30}}=1.222[/tex]

[tex] (17-14) +1.64 \sqrt{\frac{4.2^2}{30} +\frac{4.2^2}{30}}=4.778[/tex]

So then we can conclude at 90% of confidence that the difference in the two means is between 1.222 and 4.778 beats per minute

Step-by-step explanation:

For this case we have the following info given:

[tex] \bar X_1 = 17[/tex] sample mean for the first sample

[tex] \bar X_2 = 14[/tex] sample mean for the second sample

[tex]\sigma =4.2[/tex] represent the population deviation

[tex] n_1= n_2 =30[/tex] represent the sample size ofr each case

We can construct the confidence interval for the difference of means with the following formula:

[tex] (\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{\sigma^2_1}{n_1} +\frac{\sigma^2_2}{n_2}}[/tex]

And the confidence for this case is 90% or 0.9 so then the significance level is [tex]\alpha=1-0.9=0.1[/tex] and [tex]\alpha/2 =0.05[/tex] the critical value for this case is:

[tex] z_{\alpha/2}=1.64[/tex]

And replacing we got:

[tex] (17-14) -1.64 \sqrt{\frac{4.2^2}{30} +\frac{4.2^2}{30}}=1.222[/tex]

[tex] (17-14) +1.64 \sqrt{\frac{4.2^2}{30} +\frac{4.2^2}{30}}=4.778[/tex]

So then we can conclude at 90% of confidence that the difference in the two means is between 1.222 and 4.778 beats per minute

A number is randomly selected from 10 to 20. X is the event of selecting
a number divisible by 3. Y is the event of selecting a prime number.
a) Draw a Venn diagram to represent the information.

b) Are events X and Y mutually exclusive? Explain.

c) Find P(X) and P(Y).

Answers

Answer:

not sure

Step-by-step explanation:

can someone explain?  

The correct answer is a

Order the following numbers from least to greatest

Please help me

Answers

Answer:

(5/4), (1.3), (1 8/25)

Step-by-step explanation:

5/4 as a decimal is 1.25

1.3 comes next

1 and 8/25 as a decimal is 1.32

1.25 < 1.3 < 1.32

Answer:

5/4 (1.25) , 1.3, 1 8/25 (0.32)

Step-by-step explanation:

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