Answer:
C. observations
Explanation:
a scientist have to observe somethng to find the answers or solve problems
T or F? potential energy is limited to electormagnetic, mechanical, and nuclear energy.
A roofer needs to get shingles onto a roof. Pulling the shingles up manually uses 1,549 N or force. The roofer decides to use a system of pulleys. Using the pulleys, 446 N are required to lift the shingles. What is the mechanical advantage of the system of pulleys?
Answer:
Mechanical advantage of pulleys = 3.47 (Approx)
Explanation:
Given:
Manual force = 1,549 N
Pulleys force = 446 N
Find:
Mechanical advantage of pulleys
Computation:
Mechanical advantage of pulleys = Manual force / Pulleys force
Mechanical advantage of pulleys = 1,549 / 446
Mechanical advantage of pulleys = 3.4730
Mechanical advantage of pulleys = 3.47 (Approx)
2
Which of the following has the most kinetic energy?
A.
a 250 kg motorcycle moving at a speed of 45 m/s
OB. a 0.003 kg hummingbird moving at a speed of 16.7 m/s
C.
a 3500 kg elephant moving at a speed of 3 meters per second
OD
a 5000 kg truck that is not moving at all
Reset
Submit
Answer:
My answer to the question is "250kg motorcycle moving at a speed of 45m/s.
When it is necessary to place flares around a truck on a two-way roadway with a clear view, one must be placed beside the truck; the other two must be placed:
Answer:
during an accident
Explanation:
so the truck doesn't hit cars
What should not be used to support a scaffold because they could collapse, sending the structure to the ground?
Answer:
Cinder blocks
Explanation:
From safety training guides, whenever there is inadequate support, poor
construction, or a movement in the components of the scaffold such as the coupler as well as the base upon which the scaffold structure is built, there will be a great danger of collapse.
In light of this safety rule, Cinder blocks such as sandcrete blocks, bricks e.t.c shouldn't be used to support scaffold because they have a high tendency of being crushed under load
Is material medium required for sound waves propagation??? Give examples
Explanation:
Hey there!!!
As sound is a mechanical wave,it requires the medium to propagate. The most common waves are:
Air is themost common medium through which the sound travels easily.Water is also a factor that transfers the sound by vibrating water molecules. and solids are also medium to transfer or propagate sound waves.Hope it helps..
A woman stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.90 of her regular weight.
Answer:
1 m/s² down
Explanation:
"Calculate the acceleration of the elevator, and find the direction of acceleration."
Sum of forces in the +y direction:
∑F = ma
N − mg = ma
0.9 mg − mg = ma
-0.1 mg = ma
a = -0.1 g
a = -1 m/s²
What mathematical relationship between variables is suggested by a graph showing a diagonal line from the lower left to the upper right of the
graph?
a
Inverse
B
Linear
C
Quadratic (power)
Answer:
B; Linear
Explanation:
An aluminum bar has a mass of 9 kg in the air. Calculate its volume. Now imagine that you submerge the aluminum bar in water hanging it from a rope. Calculate the apparent weight it would have in the water.
Answer:
55.7 N
Explanation:
The density of aluminum is 2710 kg/m³. So its volume is:
V = (9 kg) / (2710 kg/m³)
V = 0.00332 m³
The apparent weight is the actual weight minus the buoyant force.
N = mg − B
N = mg − ρVg
N = g (m − ρV)
N = (9.8 m/s²) (9 kg − (1000 kg/m³) (0.0332 m³))
N = 55.7 N
. For a body of Mass ‘m’ moving in a circle of radius ‘r’ if its velocity is halved, what will be the effect on the value of centripetal force?
what is relative velocity in one dimension if va and vb are the velocities of two body a and b respectively then prove vab=va -vb
Answer:
Relative velocity is nothing but the velocity of one body with respect to the velocity of some other body.
Explanation:
Relative velocity may be defined as the rate at which the change of separation takes place between any two object.The relative velocity of any object A w.r.t. another object B when they are in motion is nothing but the rate of change of their position from one another.
Now, let the velocity of object A be [tex]$ v_A$[/tex]
and velocity of object B is [tex]$ v_B$[/tex]
Therefore, relative velocity of a object A when compared to the velocity of object B is given by [tex]$v_{AB}=v_A - v_B$[/tex].
during a crash a dummy with the mass of 60.0 kg hits a airbag that exerts a constant force in the dummy the acceleration of the dummy is 250 m/2 what force did the airbag exert on the dummy?
Explanation:
F = ma
F = (60.0 kg) (250 m/s²)
F = 15,000 N
During a crash, a dummy with a mass of 60 kg hits an airbag, then the airbag will exert 15,000 N force on the dummy.
What is acceleration?The rate of change in an object's velocity concerning time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.
There are several types of acceleration :
Uniform AccelerationNon-Uniform AccelerationAverage AccelerationAccording to the question, the given values are :
Mass, m = 60 kg
Acceleration, a = 250 m/s²
F = ma
F = (60.0 kg) × (250 m/s²)
F = 15,000 N
Hence, the force exerted by the airbag will be 15,000 N.
To get more information about Acceleration :
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true or false. Distance is always at the top of the triangle.
True
False
Answer:
TRUE
Explanation:
Answer:
Answer is True
Explanation:
Mark as Brainliest I hope help you
Calculate the kinetic energy of abody
of mass 5kg moving with
Velocity of
a
3mls-
Answer:
The kinetic energy is 22.5J .
Explanation:
Assuming that the formula to find kinetic energy is K.E = 1/2×m×v² where m represents the mass and v is the speed. Then, you have to substitute it :
[tex]k.e = \frac{1}{2} \times m \times {v}^{2} [/tex]
[tex]let \: m = 5,v = 3[/tex]
[tex]k.e = \frac{1}{2} \times 5 \times {3}^{2} [/tex]
[tex] k.e = \frac{1}{2} \times 5 \times 9[/tex]
[tex]k.e = \frac{1}{2} \times 45[/tex]
[tex]k.e = 22.5 \: joules[/tex]
(Correct me if I am wrong)
Help me please !!!!!! I really need help !!!!!! A spring is compressed, resulting in its displacement to the right. What happens to the spring when it is released? The spring exerts a restoring force to the right and returns to its equilibrium position. The spring exerts a restoring force to the right and compresses even further. The spring exerts a restoring force to the left and stretches beyond its equilibrium position. The spring exerts a restoring force to the left and returns to its equilibrium position.
Answer:the spring exerts a restoring force to the left and returns to its equilibrium position
Explanation:
Answer:
The spring exerts a restoring force to the left and returns to its equilibrium position.
Explanation:
The green book is 30 cm long, 15 cm wide and 3 cm high. What is the Volume?
Answer: 1,350cm³
Explanation:
Volume = LWH
= 30 × 15 × 3 = 1,350cm³
Which statement best compares the accelerations of two objects in free fall?
Answer:
increasing the masses of the objects and decreasing the distance between the objects
Answer:the objects have the same acceleration
Explanation:
Imagine you and your friend are trying to rearrange the furniture in your classroom. You push on a desk with a force of 100 n to the right ,your friendpushes on the same desk with a force of 80 n to the left .What is the net force on the desk
Answer:20n Force :Right
Explanation:
The Answer To the equation is 20n because If the net force is opposite ways you subtract and the net force is the highest number !
what was the acceleration of the cart with Low fan speed cm/s squared? what was the acceleration of the cart with medium fan speed cm/s squared? what was the acceleration of the cart with high fan speed cm/s squared?
Explanation:
The attached figure shows data for the cart speed, distance and time.
For low fan speed,
Distance, d = 500 cm
Time, t = 7.4 s
Average velocity,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500}{7.4}\\\\v=67.56\ cm/s[/tex]
Acceleration,
[tex]a=\dfrac{v}{t}\\\\a=\dfrac{67.56}{7.4}\\\\a=9.12\ cm/s^2[/tex]
For medium fan speed,
Distance, d = 500 cm
Time, t = 6.4 s
Average velocity,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500}{6.4}\\\\v=78.12\ cm/s[/tex]
Acceleration,
[tex]a=\dfrac{v}{t}\\\\a=\dfrac{78.12}{6.4}\\\\a=12.2\ cm/s^2[/tex]
For high fan speed,
Distance, d = 500 cm
Time, t = 5.6 s
Average velocity,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{500}{5.6}\\\\v=89.28\ cm/s[/tex]
Acceleration,
[tex]a=\dfrac{v}{t}\\\\a=\dfrac{89.28}{5.6}\\\\a=15.94\ cm/s^2[/tex]
Hence, this is the required solution.
Answer:low fan speed 18.0
Medium fan speed 24.0
High fan speed 32.0
Explanation:
I am looking at the answers
Question 3
What natural event do scientists blame for the desertification taking place in South Africa?
Answer:
Explanation:
Overgrazing and woodcutting are responsible for most of the desertification of rangelands, cultivation practices inducing accelerated water and wind erosion are most responsible in the rain-fed croplands, and improper water management leading to salinization is the cause of the deterioration of irrigated lands.
test your hypothesis: how will you use the computer model to test your hypothesis? what steps will you follow? what data will you record? conduct your experiment and record your results.
Answer:
what is a or b because in the question it dosent give me the answer choses that i need
A trapezoid is a 4-sided polygon which has 2
parallel sides.
Write an expression that represents the
perimeter of a trapezoid whose sides have
length a, b, c and d.
Use this expression to find the perimeter of
the trapezoid when a= 12. b
16. c = 16.
and d = 20.
Quinn is testing the motion of two projectiles x and y by shooting them from a sling shot. What can we say best describes the motion of the projectiles ? Assume air resistance is not a factor
Explanation:
A projectile motion may be defined as that form of a motion that is experienced by an object or a particle which is projected near the surface of the Earth and the particle moves along the curved path subjected to gravity force only.
Thus a projectile motion is always acted upon by a constant acceleration due to gravity in the down ward direction.
In the context, Quinn shoots two particle x and y from his sling shot and he observes that both his projectiles travels in a parabola curve in the air. Both the object x and y touches the ground a distance apart from him which is known as the range and it depends upon the velocity of the projectile. Both the projectile reaches a maximum height and then drop on the ground in a parabola shape.
B. The vertical velocity of projectile Y is changing, and the horizontal velocity of projectile X is constant.
A force of 400 N is applied to move a truck through a distance of 30 metres. What work is
done ?.
Answer:
[tex]\huge \boxed{\mathrm{12000 \ J}}[/tex]
Explanation:
Work done (J) = Force (N) × Distance (m)
W = 400 × 30
W = 12000
The work done is 12000 J.
What was the significant change that Glenn Seaborg made to Mendeleev’s periodic table?
Answer:
The Seaborg introduced the whole new row to the periodic table called actinides.
Explanation:
The american scientist Glenn Seaborg has many important contribution the chemistry. His work made a significant change in the mendeleev's periodic table. He introduced new row that is placed below the lanthanides row, called actinides.
He was co-discoverer or principle discoverer of plutonium and einsteinium. He was responsible for the discovery of more than 100 medical isotopes.
Thus, the Seaborg introduced the whole new row to the periodic table called actinides.
How does work affect energy between objects so it can cause a change in the form of energy?
Work transfers energy.
Work changes energy.
Work increases energy.
Work decreases energy.
Answer:
A. Work transfers energy.
Explanation:
Work can cause a change in the form of energy because work transfers energy.
Law of conservation of energy
The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.
Work - energy theoremThe work energy theorem states that work done an object is equal to kinetic energy of the object. In other words, work transfers energy.
Thus, work can cause a change in the form of energy because work transfers energy.
Learn more about work-energy theorem here: https://brainly.com/question/22236101
Find the slope of the line containing the two points (1,-1) and 7-5,-3). (1 point)
a
-1
b
-1/3
ос
1/3
Od
2
e
3
Answer:
[tex]m = \frac{-2}{3}[/tex]
Explanation:
Given
Points: (1,-1) and (-5,3)
Required
Determine the slope
The slope of a line is represented by m and is calculated as thus;
[tex]m = \frac{y_1 - y_2}{x_1 - x_2}[/tex]
Where
[tex](x_1,y_1) = (1,-1)[/tex]
[tex](x_2,y_2) = (-5,3)[/tex]
Substitute these values in the given formula
[tex]m = \frac{-1 - 3}{1 - (-5)}[/tex]
[tex]m = \frac{-1 - 3}{1 +5}[/tex]
[tex]m = \frac{-4}{6}[/tex]
Simplify fraction
[tex]m = \frac{-2}{3}[/tex]
Hence, the slope of the line is [tex]m = \frac{-2}{3}[/tex]
Answer:
The answer is 1/3
Explanation:
Change in y/Change in x
-2/-6=1/3
Part 1: Newton’s Laws Observe the virtual skateboarder coming down the hill and over the ramp. Describe how each of Newton’s laws of motion can be observed in this action. You can choose the dry, wet, or muddy conditions, or some combination of these. Newton’s First Law of Motion The skateboard riding down a hill with mud once the skateboard reaches the bottom it slows down due to frictional force acting in the opposite direction. Newton’s Second Law of Motion Newton’s Third Law of Motion
Answer:
the FIRST LAW NEWTON's skater goes down at a constant speed.
eaching the ramp in skidding, it has an acceleration due to the decrease in friction force. This is NEWTON'S SECOND LAW
NEWTON'S THIRD LAW, in the Normal force which is a reaction to the support of the skating
Explanation:
This problem asks to describe Newton's laws in a skater.
When going down a hill the skater acquires a constant speed, since the friction grows with the speed until it reaches the value of the weight component, In this case we see that the sum of the external forces is zero and According to the FIRST LAW NEWTON's skater goes down at a constant speed.
When reaching the ramp in skidding, it has an acceleration due to the decrease in friction force. This is NEWTON'S SECOND LAW
in this same part we can appreciate NEWTON'S THIRD LAW, in the Normal force which is a reaction to the support of the skating on the ramp and the planes the force of the skateboard on the ramp.
The force of friction of that stops the skateboard is equal to the product of mass and acceleration of the skateboard.
The skateboard riding down a hill with mud once the skateboard reaches the bottom it slows down due to frictional force acting in the opposite direction.
The force of the skateboard is equal in magnitude to the frictional force but in opposite direction.
Newton's first law of motion states an object at rest or uniform motion in s straight line will continue in that form unless acted upon by an external force.
The skateboard riding down a hill with mud once the skateboard reaches the bottom it slows down due to frictional force acting in the opposite direction.Newton's second law of motion states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.
The force of friction of that stops the skateboard is equal to the product of mass and acceleration of the skateboard.Newton's third law of motion states that for every action there is equal and opposite reaction.
The force of the skateboard is equal in magnitude to the frictional force but in opposite direction.Learn more about Newton's law of motion here: https://brainly.com/question/10454047
Adapt the velocity equation v=v0 + at to solve for average acceleration where the ball starts at t = 0.0 seconds and v0 = 0.00 meters/second
Answer:
The adapted expression for average acceleration is [tex]a = \frac{v}{t'}[/tex].
Explanation:
Let be [tex]v = v_{o} + a\cdot t[/tex], which can be adapted by using the following substitution:
[tex]t = t'-t_{o}[/tex]
Where:
[tex]t'[/tex] - Final instant, measured in seconds.
[tex]t_{o}[/tex] - Initial instant, measured in seconds.
[tex]v = v_{o}+a\cdot (t-t_{o})[/tex]
Where:
[tex]v[/tex] - Final velocity, measured in meters per second.
[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.
[tex]a[/tex] - Average acceleration, measured in meters per square second.
Now, average acceleration is cleared:
[tex]a = \frac{v-v_{o}}{t'-t_{o}}[/tex]
Given that [tex]t_{o} = 0\,s[/tex] and [tex]v_{o} = 0\,\frac{m}{s}[/tex], then:
[tex]a = \frac{v}{t'}[/tex]
Answer:
a = (v-v0)
____ where v = final velocity, v0
t
Explanation:
Using algebra, , where v = final velocity, v0 = initial velocity, and t = time. So,
= -9.3 m/s2.
express 0.0097 in scientific notation
Explanation:
Move the decimal point until it is behind the first non-zero digit.
In this case, we move it 3 places to the right so it is behind the 9.
Therefore, 0.0097 = 9.7×10⁻³.