1. What are at least 3 effects of the oceanic plate/continental plate convergent boundary?

2. Where can you find an example of this type of convergent boundary? Which country, continent, or ocean?

Answer:

The temperature of the mixture is 60°C

Explanation:

We can write the energy of water as follows:

E = m×C×T

Where E is energy in Joules, m is mass of water, C is specific heat of water = 4.184J/g°C and T is temperature

Replacing fot both samples:

E = 20g×4.184J/g°C×30°C

E = 2510.4J

E = 40g×4.184J/g°C×75°C

E = 12552J

The total energy of the mixture is 12552J + 2510.4J = 15062.4J

Mass = 60g:

15062.4J = 60g×4.184J/g°C×T

60°C = T

Answer: 20.0 g of hydrogen chloride must simultaneously be formed

Explanation:

The balanced chemical reaction is :

[tex]NH_4Cl\rightarrow NH_3+HCl[/tex]

According to the law of conservation of mass, mass can neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side.

Thus mass of reactants = mass of products

Given : mass of ammonium chloride = mass of reactants = 29.4 g

mass of ammonia = 9.4 g

mass of products = mass of ammonia + mass of hydrogen chloride

9.4 g +mass of hydrogen chloride = 29.4 g

mass of hydrogen chloride = 20.0 g

Answer:

9.52 × 10³ J

Explanation:

There is some info missing but I found it on the web.

Calculate the energy required to heat 179g of ethanol from -2.2 °C to 19.6 °C. Assume the specific heat capacity of ethanol under these conditions is 2.44 J/g.°C. Be sure your answer has the correct number of significant digits.

Step 1: Given data

Step 2: Calculate the temperature change

ΔT = 19.6 °C - (-2.2 °C) = 21.8 °C

Step 3: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 2.44 J/g.°C × 179 g × 21.8 °C

Q = 9.52 × 10³ J

Answer:

See attached picture.

Explanation:

Hello!

In this case, since C2H3Cl is an organic compound we need a central C-C parent chain to which the three hydrogen atoms and one chlorine atom provides the electrons to get all the octets except for H as given on the statement.

In such a way, on the attached picture you can find the required Lewis dot structure without formal charges and with all the unshared electron pairs, considering there is a double bond binding the central carbon atoms in order to compete their octets.

Best regards!

The lewis structure of given molecule is given below. Carbon has 4 electron. out of which electron make bond with carbon and one with hydrogen and chlorine.

If the compound's molecular formula is known, electron dot structures or Lewis dot formulas can be drawn. It describes the type of bond and the placement of the atoms within the molecule that are joined together. In homage of American chemist Gilbert Newton Lewis, molecules are depicted as having a Lewis electron dot structure or simply a Lewis structure. The lewis structure of given molecule is given below.

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Answer:

Sanitize

Explanation:

Answer:

Molarity of a solution = 0.3 mol/liter

Explanation:

Given:

Moles of solute = 15 moles

Amount of solution = 50 liters

Find:

Molarity of a solution

Computation:

Molarity of a solution = Moles of solute / Amount of solution

Molarity of a solution = 15 / 50

Molarity of a solution = 0.3 mol/liter

Answer:

More slowly than

Larger than

Weaker

Explanation:

The vapor pressure of a solution describes how quickly a solution will turn into vapour. If we say that a solution has a high vapour pressure, we are actually saying that the solution turns into vapour more quickly.

Acetone has a higher vapour pressure than water so acetone turns to vapour quicker than water.

Vapour pressure has a lot to do with the magnitude of intermolecular forces in solution. The stronger the magnitude of intermolecular forces, the lower the vapor pressure and the more slowly the solution evapourates.

So, the hydrogen bonds in water provides stronger intermolecular forces than dispersion and dipole interaction in acetone. Hence, water vaporizes more slowly than acetone.

2 L Ne

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

0.07 mol Ne (g)

Step 2: Identify Conversions

STP - 22.4 L per mole

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 1 sig fig.

1.568 L Ne ≈ 2 L Ne

Answer:

D Flat Top Hills Can Be Plateaus or mesas

Explanation:

Answer:

Please put question in!

Explanation:

Answer:

HCL, NACL and CO are the examples of chemical formulas

Answer:

C) The law of conservation of matter

Explanation:

Conservation means keeping/ retaining something, in this case it is matter. Hope this helps!

Answer:

false.nowadays humans are destroying forest,extracted more minerals,making pollution. in my view.

The question is incomplete, the complete question is;

When 1 mole of P4O10(s) reacts with H2O(l) to form H3PO4(aq) according to the following equation, 453 kJ of energy are evolved.

P4O10(s) + 6H2O(l)When 1 mole of P4O10(s) reacts4H3PO4(aq)

Is this reaction endothermic or exothermic? _________endothermicexothermic

Answer:

The reaction is exothermic

Explanation:

An exothermic reaction refers to any reaction in which heat was EVOLVED. The word was stressed to indicate that it holds the key to answering the question correctly.

We were told in the question that heat was evolved, hence the reaction is exothermic in nature.

The balanced thermochemical equation of the reaction is :

P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(aq) ____ ΔH = -453 kJ

Answer:

have lower boiling points than alcohols of similar molecular weights.

Explanation:

Alkenes are hydrocarbons of the general molecular formula CnH2n. Alkenes are nonpolar hydrocarbons that are insoluble in water.

We must recall that alcohols are able to associate in water due to hydrogen bonding. This causes alcohols to have a relatively higher boiling point than alkenes of comparable molecular weight. Hencethe answer above.

Answer:

it is a substance

Explanation:

because sodium is an element which its consistent is only sodium atom

Answer:

Xenon

Atomic Number: 54

Explanation:

Periodic Table

Answer:

Xenon

Explanation:

Xenon is a chemical element with symbol Xe and atomic number 54.

Answer:

the five major branches of chemistry are organic, inorganic, analytical, physical, and biochemistry.

Answer:

it takes two hydrogen atoms for every oxygen atom to produce this reaction, so the mole ratio between hydrogen and oxygen is 2:1

Answer:

[tex]m=69.3kg[/tex]

Explanation:

Hello!

In this case, since the density is computed by dividing the mass of the substance by its occupied volume (d=m/V), we first need to realize that 0.8206 g/mL is the same to 0.8206 kg/L, which means we first need to compute the volume in L:

[tex]V=22.3gal*\frac{3.78541L}{1gal}=84.415L[/tex]

Then, solving for the mass in d=m/V, we get m=d*V and therefore the mass of gasoline in that full tank turns out:

[tex]m=0.8206g/L*84.415L\\\\m=69.3kg[/tex]

Best regards!

7.53 × 10²³ molecules NaOH

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

50.0 g NaOH

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of NaOH - 22.99 + 16.00 + 1.01 = 40 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

7.5275 × 10²³ molecules NaOH ≈ 7.53 × 10²³ molecules NaOH

Answer:

it's the 2 I'm pretty sure

Explanation:

please give me a heart

Answer:

Explanation:

sd dsf sd f sdf sdf

Answer:

Collision theory states that the rate of a chemical reaction is proportional to the number of collisions between reactant molecules. The more often reactant molecules collide, the more often they react with one another, and the faster the reaction rate.

hope it helps

mark me brainliest

Answer:

[tex]t=1.712min[/tex]

Explanation:

Hello!

In this case, since the radioactive decay equation is:

[tex]\frac{A}{A_0}=2^{-\frac{t}{t_{1/2} }[/tex]

Whereas A stands for the remaining amount of this sample and A0 the initial one. In such a way, since the sample of rutherfordium is reduced to one-third of its nuclei, the following relationship is used:

[tex]A=\frac{1}{3} A_0[/tex]

And we plug it in to get:

[tex]\frac{\frac{1}{3} A_0}{A_0}=2^{-\frac{t}{t_{1/2}} } \\\\\frac{1}{3}=2^{-\frac{t}{t_{1/2}} }[/tex]

Now, as we know its half-life, we can compute the elapsed time for such loss:

[tex]log(\frac{1}{3})=log(2^{-\frac{t}{t_{1/2}} })\\\\log(\frac{1}{3})=-\frac{t}{t_{1/2}} }*log(2)[/tex]

[tex]t=-\frac{log(\frac{1}{3})t_{1/2}}{log(2)} \\\\t=1.71min[/tex]

Best regards!

Answer: The hydroxide concentration of this sample is [tex]3.85\times 10^{-7}[/tex]

Explanation:

When an expression is formed by taking the product of concentration of ions raised to the power of their stoichiometric coefficients in the solution of a salt is known as ionic product.

The ionic product for water is written as:

[tex]K_w=[H^+]\times [OH^-][/tex]

[tex]7.7\times 10^{-14}=[H^+]\times [OH^-][/tex]

As [tex][H^+]=[OH^-][/tex]

[tex]2[OH^-]=7.7\times 10^{-14}[/tex]

[tex][OH^-]=3.85\times 10^{-7}[/tex]

Thus hydroxide concentration of this sample is [tex]3.85\times 10^{-7}[/tex]

Answer:

We need to add 900 mL of water.

Explanation:

To know the amount of water to add first we need to calculate the concentration of KOH when the pH is 12 and when is 11:

[tex] 14 = pH + pOH [/tex]

[tex] pOH = -log[OH] [/tex]

[tex] OH = 10^{-pOH} [/tex]

When pH = 12 (initial):

[tex]pOH_{i} = 14 - 12 = 2[/tex]

[tex]OH_{i} = 10^{-2}=0.01 M[/tex]

When pH = 11 (final):

[tex]pOH_{f} = 14 - 11 = 3[/tex]

[tex]OH_{f} = 10^{-3} = 0.001 M[/tex]

Now, by using the following equation we can find the volume of the solution to achieve a pH = 11:

[tex]C_{i}V_{i} = C_{f}V_{f}[/tex]

[tex]V_{f} = \frac{C_{i}V_{i}}{C_{f}} = \frac{0.01 M*100 mL}{0.001 M} = 1000 mL[/tex]

Finally, to bring 100 mL of the initial solution to 1000 mL we need to add the following amount of water:

[tex]1000 mL = V_{KOH} + V_{H_{2}O}[/tex]

[tex] V_{H_{2}O} = 1000 mL - V_{KOH} [/tex]

[tex] V_{H_{2}O} = 1000 mL - 100 mL = 900 mL [/tex]

Therefore, we need to add 900 mL of water.

I hope it helps you!            

The amount of water that needs to be added will be 900 mL

For finding the amount of water added we have to calculate the concentration of KOH at pH=12 and pH=11

[tex]14=pH+_pOH[/tex]

[tex]_pOH=-Log[OH][/tex]

[tex]OH=10^{-_pOH}[/tex]

[tex]_pOH_f=14-11=3[/tex]

When pH = 12 (initial):

[tex]_pOH_i=14-12=2[/tex]

[tex]_pOH_i=10^{-2}=0.01[/tex]

When pH = 11 (final):

[tex]_pOH_i=10^{-2}=0.01[/tex]

[tex]_pOH_f=14-11=3[/tex]

Now, by using the following equation we can find the volume of the solution to achieve a pH = 11:

[tex]C_iV_i=C_fV_f[/tex]

[tex]V_f=\dfrac{C_iV_I}{C_f} =\dfrac{0.01\times100}{0.001} =1000\ mL[/tex]

Finally, to bring 100 mL of the initial solution to 1000 mL we need to add the following amount of water:

[tex]1000=V_{KOH}+V_{H_2O}[/tex]

[tex]V_{H_2O}=1000mL-V_{KOH}[/tex]

[tex]V_{H_2O}=1000-100=900mL[/tex]

Thus the amount of water that needs to be added will be 900 mL

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