Answer:
1.625g
Explanation:
The half - life of a radioactive substance is the time taken for half of it to decay to half of its original composition.
For the given specie, the original composition is 26g and the half life is 15hrs:
At time 0hrs Mass = 26g
For the first half life at time 15hrs Mass = 13g
30hrs Mass = 6.5g
45hrs Mass = 3.25g
60hrs Mass = 1.625g
Imagine you are a TV sports commentator for a major car race. What techniques could
you use to describe the action to your audience?
Answer:
friction , magnetism etc
What are the three longest wavelengths for standing waves on a270-cm-long string that is fixed at both ends
Answer:
The answer is below
Explanation:
a) What are the three longest wavelengths for standing waves on a 270-cm-long string that is fixed at both ends? b. If the frequency of the second-largest wavelength is 50.0 Hz, what is the frequency of the third-longest wave length?
Solution:
a) The wavelengths (λ) for standing waves is given by the formula:
[tex]\lambda_m=\frac{2*length\ of\ string}{m}\\\\Where\ m=1,2,3,.\ .\ .\\\\Given\ that\ length\ of\ string = 270\ cm=2.7\ m,\ m=1,2,3(three\ longest\ wavelengths)\\\\Hence:\\\\\lambda_1=\frac{2(2.7)}{1}=5.4\ m\\\\\lambda_2=\frac{2(2.7)}{2}=2.7\ m \\\\\lambda_3=\frac{2(2.7)}{3}=1.8\ m[/tex]
b) The frequency (f) and wavelength (λ) is given by:
fλ = constant
Hence:
[tex]f_2\lambda_2=f_3\lambda_3\\\\f_2=50\ Hz\\\\2.7*50=f_3(1.8)\\\\f_3=\frac{2.7*50}{1.8} \\\\f_3=75\ Hz[/tex]
The three longest wavelengths for the standing waves on a 270-cm long string that is fixed at both ends are:
1. 5.4 meters.
2. 2.7 meters.
3. 1.8 meters.
Given the following data:
Length of string = 270 cm to m = [tex]\frac{270}{100} =2.7\;m[/tex]To determine the three (3) longest wavelengths for these standing waves:
Mathematically, the wavelength for standing waves is given by the formula:
[tex]\lambda_n = \frac{2L}{n}[/tex]
Where:
[tex]\lambda_n[/tex] is the wavelength for standing waves.L is the length of string.Note: n = 1, 2, and 3.
When n = 1:
[tex]\lambda_1 = \frac{2\times 2.7}{1} \\\\\lambda_1 = 5.4 \;meters[/tex]
When n = 2:
[tex]\lambda_2 = \frac{2\times 2.7}{2} \\\\\lambda_2 = 2.7 \;meters[/tex]
When n = 3:
[tex]\lambda_3 = \frac{2\times 2.7}{3} \\\\\lambda_3 =\frac{5.4}{3} \\\\\lambda_3 = 1.8 \;meters[/tex]
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Which example best matches the term refraction? (17 Points)
O A. Light spreads out after it travels through a keyhole
O B. A straw in a glass of water looks bent
O C. Seeing your image in a lake
O D. An orchestra of different sounds coming together to make a larger sound
Answer:
B
Explanation:
Just answerd that question!!!
Hope it helped!!!
.
what makes 97 of the water on earth unfit for drinking
Answer:
presence of salt in oceanic water makes 97 of the water on the earth unfit for drinking
A medicine ball has a mass of 8.0 kg and is thrown with a speed of 3.0 m/s. What is its kinetic energy?
O A 12 J
O
B. 24 J
C. 36 J
0 D. 192 J
Answer:
C. 36J
Explanation:
KE = ½ m V²
= ½ × 8 × 3²
= 4 × 9
= 36 J
Which team sport utilizes judges to determine the points earned?
Answer:
Rhythmic Gymnastics
Explanation:
What is the velocity of a dropped object after it has fallen for 12 s?
Hellow!
For this use the next formula:
Vf = Vo + gt
Initial velocity is zero, so the formula simplificate:
Vf = gt
Data:
Vf = Final velocity = ?
g = Gravity = 9.8 m/s²
t = Time = 12 s
Replacing according our data:
Vf = 9.8 m/s² * 12 s
Vf = 117.8 m/s
The final velocity will be 117.8 meters per second.
please help me this is timed .
Find x if a = 3.0 m/s^2
Answer:
x = 50 N
Explanation:
Given that we have a net force, a mass, and acceleration, we can use the fundamental formula for force found in newton's second law which is F = m × a.
Given a mass of 150 kg, and an acceleration 3.0m/s². We can substitute these two values in our formula to calculate the magnitude of these forces or it's net force to identify the unknown force acting on our known force for this situation to work.
_______
F (Net force) = F2 (Second force which we are given) - F1 (First force) = m × a
m (mass which we are given) = 150 kg
a (acceleration which we are given) = 3.0m/s
________
So F = m × a → F2 - F1 = m × a →
500 - F1 = 150 × 3.0 → 500 - F1 = 450 →
-F1 = -50 → F1 = 50
A spring has an unstretched length of 16 cm . A 110 g mass hanging from the spring stretches it to an equilibrium length of 24 cm . Part APart complete Suppose the mass is pulled down to where the spring's length is 32 cm . When it is released, it begins to oscillate. What is the amplitude of the oscillation
Answer:
the amplitude of the oscillation is 8 cm
Explanation:
The computation of the amplitude of the oscillation is shown below:
= Length of the spring - length of the equilibrium
= 32 cm - 24 cm
= 8 cm
By deducting the length of the equilibrium from the length of the spring we can get the amplitude of the oscillation and the same is to be considered
hence, the amplitude of the oscillation is 8 cm
A bungie jumper of mass 50kg is attached to a bungie with a constant of 100Nm. The unstretched length of the bungie is 15m. What is the maxmimum velocity of the jumper
Answer:
v = 18.5 m /s
Explanation:
The velocity of the jumper will go on increasing until his weight is more than the restoring force created in the bungle.
mg = kx
50 x 9.8 = 100 X
X = 4.9 m
Total fall = 15 + 4.9 = 19.9 m
kinetic energy gained due to fall by 19.9 m
= mgh = 50 x 9.8 x 19.9 = 9751 J
energy lost due to stored elastic energy in bungie
= 1/2 k x²
= .5 x 100 x 4.9²
= 1200.5 J
Remaining kinetic energy = 9751 - 1200.5 = 8550.5 J
1/2 m v² = 8550.5
.5 x 50 x v² = 8550.5
v² = 342
v = 18.5 m /s
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
Complete Question
The speed of a transverse wave on a string of length L and mass m under T is given by the formula
[tex]v=\sqrt{\frac{T}{(m/l)}}[/tex]
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
Answer:
[tex](m/l)=\frac{10}{V^2}[/tex]
Explanation:
From the question we are told that
Speed of a transverse wave given by
[tex]v=\sqrt{\frac{T}{(m/l)}}[/tex]
Maximum Tension is [tex]T=10.0N[/tex]
Generally making [tex](m/l)[/tex] subject from the equation mathematically we have
[tex]v=\sqrt{\frac{T}{(m/l)}}[/tex]
[tex]v^2=\frac{T}{(m/l)}[/tex]
[tex](m/l)=\frac{T}{V^2}[/tex]
[tex](m/l)=\frac{10}{V^2}[/tex]
Therefore the Linear mass in terms of Velocity is given by
[tex](m/l)=\frac{10}{V^2}[/tex]
how does the tilt of earth affect the hours of daylight north of the tropical of cancer at the time of year shown?
Answer:
look it tilts and light
is college football playoffs the best way to determine the national champion?
Answer:
No it is Not because win ratio is differs say Ohio only won 7 out of 7 games and e
was in the playoffs while Alabama won 11 out of 11 games so it is harder to win 11 out of 1a games and it is easier to win 7 out of 7
Explanation: would like brainliest but u don’t have to
what tells you whether you are feeling hot, cold or in pain?
A. Nerves/Neurons
B. Spinal Cord
C. Brain
D. Skin
Answer:
i think its skin..think so this answre help you
what can you conclude about the force of gravity?
Answer:
All objects, irrespective of their mass, experience the same acceleration g when falling freely under the influence of gravity at the same point on the Earth. If gravity is the only force acting on an object, the sum of kinetic energy and gravitational energy is constant. ...
Answer:
Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects.The Earth's gravitational force accelerates objects when they fall. It constantly pulls, and the objects constantly speed up.Gravity is the force of attraction between two objects with mass and is dependent on the distance between these objects. Gravity is the force that repels two objects that have opposite charges. It is dependent upon the charges of the objects.
Explanation:
The large window air conditioner in Anita Breeze's room draws 11 amps of current. The unit runs for 8.0 hours during the course of a day. Determine the quantity of charge that passes through Anita's window AC during these 8.0 hours.
Answer:
quantity of charge that passes through Anita's window AC, Q = 316800 C
Explanation:
given data
current I = 11 amps
runs t = 8.0 hours
solution
we get here quantity of charge that passes through Anita's window AC
the quantity of charge passing Q = I × t .................1
Q = 11 A × ( 8 hr )× ( 3600 s/hr)
so
quantity of charge that passes through Anita's window AC, Q = 316800 C
The quantity of charge that passes through Anita's window AC, will be
Q = 316800 C
What is Current?
The current is defined as the quantity of charge flowing from the wire per unit time. Also defined as the rate of flow of the charge through any circuit. The formula will be given as:
[tex]\rm I=\dfrac{Q}{t}[/tex]
Now it is given that:
current I = 11 amps
runs t = 8.0 hours
The quantity of charge that passes through Anita's window AC during these 8.0 hours. Will be calculated as:
[tex]Q=I\times t[/tex]
[tex]Q=11\times 8\times 3600[/tex]
[tex]Q=316800 \ C[/tex]
Thus the quantity of charge that passes through Anita's window AC, Q = 316800 C
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In a typical badminton swing the racket is in contact with the birdy for about 0.0010 seconds. If the 0.045kg birdy acquires a speed of 67 m/s, what is the force exerted by the racket on the ball
Answer:
3015 N
Explanation:
From Newton's second law, we know that;
F.t = mv
F = force on the ball= ?
m= mass of the ball
v= velocity
F= mv/t
F= 0.045 × 67/0.0010
F= 3.015/0.0010
F= 3015 N
The force exerted by the racket on the ball is 3015 N.
The force exerted by the racket on the ball is given in the formula below.
⇒ Formula:
F = mΔv/t............... Equation 1⇒ Where:
F = force exerted by the racketm = mass of the birdyΔv = change in speedt = time.From the question,
⇒ Given:
m = 0.045 kgΔv = 67 m/st = 0.0010 seconds.⇒ Substitute these values into equation 1
F = 0.045(67)/0.001F = 3015 NHence, The force exerted by the racket on the ball is 3015 N
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All of the following are ways in which sports psychologists help athletes except __________.
A.
staying motivated
B.
managing fear of failure
C.
improving performance
D.
enhancing memory
Please select the best answer from the choices provided
A
B
C
D
Answer:
D-Enhancing memory
Explanation:
An investigator is using a laser to illuminate a distant target. He decides that he needs a smaller beam, so he puts a pinhole directly in front of the laser. He finds that this actually spreads the beam out, making matters worse.
Explain what is happening.
a. The pinhole has a size comparable with the laser wavelength, so the pinhole refracts the passing laser beam.
b. The pinhole has a size smaller than the laser wavelength, so the pinhole refracts the passing laser beam.
c. The pinhole has a size smaller than the laser wavelength, so the pinhole diffracts the passing laser beam.
d. The pinhole has a size comparable with the laser wavelength, so the pinhole diffracts the passing laser beam.
Answer:
correct answer is d
The pinhole has a size comparable with the laser wavelength, so the pinhole diffracts the passing laser beam.
Explanation:
The researcher does not have a refraction problem since the medium on both sides of the pinhole is the same with the same refractive index, the problem he is having is with the diffraction of the laser beam through the pinhole, let's analyze the diffraction process that is described by the expression
a sin θ = m λ
where a is the pinlole size, λ the wavelength of the laser and m an integer.
The laser extends from the maximum of diffraction to the first zero (m = 1) of diffraction
sin θ = λ/a
when analyzing this expression we have some interesting cases
* when λ « a. the sine approaches zero therefore we are in the case of optical geometry, in this case the laser passes through the hole without being diffracted
* when λ ≈ a. the sine function has values between 0 and 1, for which a diffraction of the laser beam occurs, which increases the diameter of the same
* when λ> a. The laser does not pass through the gap since the sine cannot have values greater than 1
After this analysis, we review the answers to the exercise to find that the correct answer is d
Explain whether a tennis ball dropped from a high distance experiences an elastic collision or inelastic collision
Which is greater, the energy of one photon of orange light or the energy of one quantum ofradiation having a wavelength of 3.36 * 10^-9
The question is incomplete, here is the complete question:
Which is greater, the energy of one photon of orange light or the energy of one quantum of radiation having a wavelength of [tex]3.36\times 10^{-9}m[/tex]
Answer: The energy of one quantum of radiation having wavelength [tex]3.36\times 10^{-9}m[/tex] is greater than the energy of 1 photon of orange light.
Explanation:
To calculate the energy of one photon, we use the Planck's equation:
[tex]E=\frac{N_Ahc}{\lambda}[/tex]
where,
E = energy of radiation
[tex]N_A[/tex] = Avogadro's number = [tex]6.022\times 10^{23}mol^{-1}[/tex]
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
c = speed of light = [tex]3\times 10^8 m/s[/tex]
[tex]\lambda}[/tex] = wavelength of radiation
For orange light:For 1 photon, the term [tex]N_A[/tex] does not appear
[tex]\lambda}[/tex] = 620 nm = [tex]620\times 10^{-9}m[/tex] (Conversion factor: [tex]1nm=10^{-9}m[/tex] )
Putting values in above equation, we get:
[tex]E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8m/s}{620\times 10^{-9}m}\\\\E=3.206\times 10^{-19}J[/tex]
For one quantum of radiation:[tex]\lambda}[/tex] = [tex]3.36\times 10^{-9}m[/tex]
Putting values in above equation, we get:
[tex]E=\frac{6.022\times 10^{23}mol^{-1}\times 6.626\times 10^{-34}Js\times 3\times 10^8m/s}{3.36\times 10^{-9}m}\\\\E=3.56\times 10^{7}J/mol[/tex]
Hence, the energy of one quantum of radiation having wavelength [tex]3.36\times 10^{-9}m[/tex] is greater than the energy of 1 photon of orange light.
Which element of the integumentary system is responsible for acne in adolescents?
subcutaneous adipose tissue
sweat glands
squamous cells
sebaceous glands
Acne is a long-lasting condition that affects the sebaceous glands and hair follicles in the middle layer of the skin.Acne is characterized by clogged sebaceous glands, which produce pimples and cysts.
Which part of the integumentary system is responsible for acne?
A condition of the oil glands and hair follicles is acne (sebaceous glands).To keep the skin moist, the sebaceous glands release oils (sebum).Acne and cysts can develop as a result of clogged glands. Sebum makes the skin more resistant to moisture and lubricates it to defend against abrasion.Additionally, the sebaceous gland has a natural light protection action and transfers antioxidants into and onto the skin.It has pro- and anti-inflammatory properties as well as an intrinsic antimicrobial activity. Your skin, hair, and nails make up your integumentary system.It serves as the top layer of defense against bacteria and damage to your body. The face, upper chest, and back are among the skin regions where sebaceous follicle density is highest and are frequently affected by acne vulgaris. Sebum, an oily fluid that moisturizes your skin and hair, and dead skin cells clog hair follicles, resulting in acne.Bacteria can cause infection and inflammation, which worsen acne. Other sebaceous gland functions, such as sebaceous proinflammatory lipids, various locally produced cytokines, periglandular peptides and neuropeptides, such as corticotrophin-releasing hormone, which is produced by sebocytes, and substance P, which is expressed in sebocytes, are also linked to the development of acne.To learn more about acne in adolescents refer
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A cart's initial velocity is +3.0 meters per second. What is its final velocity after accelerating at a rate of 1.5 m/s2 for 8.0 seconds?
A. 36 m/s
B. 9 m/s
C. 72 m/s
D. 15 m/s
Answer:
V = 15m/s
Explanation:
Given the following data;
Initial velocity = 3m/s
Time = 8secs
Acceleration = 1.5m/s²
To find the final velocity, we would use the first equation of motion;
V = U + at
Substituting into the equation, we have
V = 3 + 1.5*8
V = 3 + 12
V = 15m/s
A hammer strikes a nail with a 10 N force for 0.01 seconds. Calculate the impulse of the hammer.
Answer:
0.1Ns
Explanation:
Impulse is the product of Force and time
Impulse = Force * Time
Given
Force = 10N
Time = 0.01s
Substitute into the formula
Impulse = 10 * 0.01
Impulse = 10 * 1/100
Impulse = 10/100
Impulse = 0.1Ns
hence the impulse of the hammer is 0.1Ns
how do the linear momentum and kinetic energy of the two-atom system after the collision compare to these quantities before the collision g
Explanation:
Two atoms with equal masses, m, and equal speed, v, engage in a head on elastic collision. Since, the two atoms both having equal masses and equal but opposite velocity, the total linear momentum of the system is zero. Therefore, conservation of linear momentum to be conserved , the velocities before and after collision are same. Similarly, in elastic collision total kinetic energy is also conserved. The kinetic energy before and after collision are same.
A track 400 m in periphery is to be laid out on the practice field. Each semicircular end must have a radius of at least 20 m, and each straight section must be at least 100 m. How should the track be laid out so that it encompasses the least area
Answer:
r = 31.8
Explanation:
To start with, we make the following assumptions. Let
r be the radius of semicircular end
l be the length of straight section
a be the area inside track, then
p = 2πr + 2l = 400
a = πr² + 2rl
2πr + 2l = 400
l = 200 - πr, substituting for l in area,
a = πr² + 2r(200 - πr)
a = πr² + 400r - 2πr²
a = 400r - πr²
In order to find our minimum area, we differentiate with respect to r and then it equate to zero
da/dr = 400 - 2πr = 0
r = 200/π, substituting for r in equation for l,
l = 200 - πr
l = 0 m
And since this is not possible, l must be 100 m (the minimum), and
r = (200 - 100)/π
r = 100/π = 31.8 m
In physics, every physical quantity is measured with respect to a unit. Time is measured in seconds, length is measured in meters, and mass is measured in kilograms. Knowing the units of physical quantities will help you solve problems in physics.
Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation.
F= Gm1m2 /r^2
where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In Sl units, the units of force are kg m/s^2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?
a. kg^3/ms^2
b. kgs^2/m^3
c. m^3/kgs^2
d. m/kgs^2
Answer:
Unit of G = m³/kg s²
Explanation:
The force of gravitational attraction is represented by the equation.
[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]
F is the magnitude of the gravitational attraction on either body
m₁ and m₂ are the masses of the bodies, r is the distance between them. G is the gravitational constant.
We need to find the unit of G.
Rearranging the above formula for G.
[tex]G=\dfrac{Fr^2}{m_1m_2}[/tex]
Putting units of F,m and r such that,
[tex]G=\dfrac{N\times m^2}{kg^2}\\\\\because N=kgm/s^2\\\\G=\dfrac{kg\times m\times m^2}{kg^2\times s^2}\\\\G=m^3/kgs^2[/tex]
Hence, the correct option is (c) m³/kg s².
What is the gravitational force between two students, Dylan and Sarah, if Dylan has a mass of 75 kg, Sarah has a mass of 54 kg, and their centers are separated by a distance of.45 m
Answer:
[tex]F=1.334*10^-^6[/tex]
Explanation:
From the question we are told that
Mass of Dylan [tex]M_d=75kg[/tex]
Mass of Sarah [tex]M_s=54kg[/tex]
Centers separated by[tex]C=0.45m[/tex]
Generally the equation for solving gravitational force is given by
[tex]F=\frac{G*m_1m_2}{r^2}[/tex]
[tex]F=\frac{6.67*10^-^1^1*75*54}{(0.45)^2}[/tex]
[tex]F=1.334*10^-^6[/tex]
Therefore Gravitational force is given as
[tex]F=1.334*10^-^6[/tex]
mass is 5 lb attached to a rope wound around a pulley. The radius of the pulley is 3 in. If the mass falls at a constant velocity of 5 ft/s, determine the power transmitted to the pulley, in hp.
Answer:
The power transmitted to the pulley is 0.0455 hp.
Explanation:
Given;
mass attached to the rope, m = 5 lb
radius of the pulley, r = 3 in
constant rate of fall of the mass, v = 5 ft/s
acceleration due to gravity, g = 32.2 ft/s²
1 lbf = 32.2 lb.ft/s²
The power transmitted to the pulley is calculated as;
P = Fv
P = (mg)v
[tex]P = 5 \ lb \ \times \ 32.2 \ \frac{ft}{s^2} \ \times \ 5 \ \frac{ft}{s} \ \times \ \frac{1 \ lbf}{32.2 \ lb.ft/s^2} \ \ = 25 \ \frac{ft.lbf}{s} \\\\[/tex]
in horse power, the power transmitted is calculated as;
[tex]P = \frac{25 \ ft.lbf}{s} \ \times \ \frac{1 \ hp}{550 \ ft.lbf/s} \ \ = 0.0455 \ hp[/tex]
Therefore, the power transmitted to the pulley is 0.0455 hp.
help plz, will give brainliest!!!!
Answer:
It looks like a total of 9 meters
Explanation:
the dot on the graph for 1910 sits JUST below the mark for 10 meters