Explanation:
1. W = F x D
F = W/D
F = 120/6 = 20Newton
2. P. E = mgh
P. E = 1.5x10x2 = 30Joules
3. It means that the energy the body possesses at that point is 20Joules
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Why there has to be a driving force to keep the car moving at a constant speed?
Explanation:
For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. ... an object falling at terminal velocity experiences the same air resistance as its weight.
if you dropped a ball and you dropped a hammer will the two objects fall at the same speed or will they fall at a different speed
Answer:
they would fall at different speeds
Explanation:
The speed at which each falls is dependent on air resistance
helppp mee pllleasse
Answer:
up swelling moves water horizontally
Please help! Question is attached.
Answer:
a. 6
b. 6 m/s²
c. 300 m to the right
d. 30 secs
Explanation:
slope = rise /run
60-0/10-0
= 6
b. slope = acceleration = 6 m/s²
c. d=ut+1/2at²
t=10 (segment A last for 10 secs)
u - initial velocity = 0
so d = 0(10)+1/2*6*10²
=300 m
A 2 kg mass starts from rest and slides down an inclined plane 4 m long in 1 second. What net force is acting on the mass along the incline *.
The net force acting on the mass along the incline is equal to 16 Newton.
Given the following data:
Mass = 2 kgDistance = 4 metersTime = 1 secondsTo determine the net force acting on the mass along the incline:
First of all, we would find the acceleration of the mass by using the second equation of motion:
[tex]S = ut+ \frac{1}{2} at^2\\\\4 = 0(1) + \frac{1}{2} a(1)^2\\\\4=\frac{a}{2}\\\\a=2\times 4[/tex]
Acceleration, a = 8 [tex]m/s^2[/tex]
For the net force, we would apply Newton's Second Law of Motion:
[tex]F_{net} = mass \times acceleration\\\\F_{net} =2 \times 8[/tex]
Net force = 16 Newton.
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calculate the density, in g/l, of sf6 gas at 27°c and 0.500 atm pressure.
The density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
The given parameters:
temperature of the SF₆ gas, T = 27 ⁰C = 273 + 27 = 300 Kpressure of the SF₆ gas, P = 0.5 atmThe molecular mass of the SF₆ gas is calculated as follows;
M of SF₆ = 32 + (6 x 19) = 146 g/mol
The density of the SF₆ gas is calculated by applying ideal gas law as follows;
[tex]PV = nRT\\\\PV = \frac{m}{M} RT\\\\PM = \frac{m}{V} RT\\\\PM = \rho RT\\\\\rho = \frac{PM}{RT}[/tex]
where;
[tex]\rho[/tex] is the density of the gasR is the ideal gas constant = 0.0821 L.atm/mol.K[tex]\rho = \frac{0.5 \times 146}{0.0821 \times 300} \\\\\rho = 2.96 \ g/l[/tex]
Thus, the density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.
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what is heliocentric?
Answer:
having or representing the sun as the centre, as in the accepted astronomical model of the solar system.
Explanation:
Heliocentrism is the astronomical model in which the Earth and planets revolve around the Sun at the center of the Universe. Historically, heliocentrism was opposed to geocentrism, which placed the Earth at the center.
Gold density = 19.30,
Silver density = 10.49,
Lead density = 11.34.
They have the same mass but are made of different metals. Each one is lowered into a beaker of water. Use the data above to decide which one will cause the biggest rise in water level.
A) Gold
B) Silver
C) Lead
D) All will cause the same rise in water level
Density of water=1g/cm^3
Now all metals has greater mass in comparison to water.
Higher the mass higher the rise[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]
[tex]\\ \sf\longmapsto Density\propto Mass[/tex]
Higher the density higher the massGold has higher mass hence it will cause the biggest rise.
Option A
Silver will cause biggest rise in water
What is density ?Density of an object is a measure of its mass per unit volume.
density = mass / volume
since all have same mass , so metal which have higher volume will cause the biggest rise in water level .
since , density is inversely proportional to volume , hence material having low density will have higher volume
hence , silver will cause biggest rise in water
correct option B) Silver
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What type of machine is used to measure the location of an earthquake epicenter.
Answer:
Seismometer
Explanation:
Seismometer measures Earth quake epicenter while seismograph measures Earth quake size
lonic Naming Practice
Write the name of the following chemical compound:
Na3Cl1
Answer:
sodium chloride. .....
A 0.5kg ball falls from a building that Is 50m high. how much kinetic energy will it have when it has fallen half way to the ground?
You get in your car after work and turn on the radio. What type of communication does the radio use?.
Answer:
Radio waves
Explanation:
The radio operates by the principles of radio wave.
Electromagnetic wave is a type of wave which does not require material medium for its propagation. A radio wave is an example of electromagnetic wave.
The radio operates in the principle of electromagnetic wave because it does not require material medium for its propagation and it has one of the longest frequency of electromagnetic spectrum.
Thus, we can conclude that the radio operates by the principles of radio wave.
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what is the mass of an object if it’s weight on earth is 1150N
Answer:
calculate it by using formula w=m×g
The mass of an object if its weight on earth is 1150N is 117.347 kg.
What is Weight?The weight of an object is defined as the force that acts on the object due to gravity. Sometimes weight is defined as a vector quantity, the force of gravity acting on an object. Others define weight as a scalar quantity, the magnitude of the force of gravity.
It is gravitational force of attraction on an object which is caused by the presence of a massive second object like Earth or Moon. Weight is expressed by multiplying the mass times the acceleration due to gravity.
W=mg
Where, W= weight of the object
m= Mass of the object
g= Acceleration due to gravity i.e. [tex]9.8[/tex] [tex]m/s^2[/tex]
In above information,
W= 1150N
g= [tex]9.8[/tex] [tex]m/s^2[/tex]
Using the formula
m=W/g
m=1150/9.8
m=117.347 kg
Thus, the mass of an object if its weight on earth is 1150N is 117.347 kg.
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a block weighing (Fg) 500 N is resting on a steel table ( us=0.74) the minimum force start this block moving is?
The minimum force required to start this block moving is 370 N.
The given parameters;
weight of the block, W = 500 Ncoefficient of static friction, [tex]\mu_s[/tex] = 0.74The minimum force required to start this block moving is calculated as follows;
[tex]F= \mu_s F_n[/tex]
where;
[tex]F_n[/tex] is the normal force on the block which is equal to the weight of the block
[tex]F= \mu_s F_n \\\\F= \mu_s W\\\\F = 0.74 \times 500 \\\\F= 370 \ N[/tex]
Thus, the minimum force required to start this block moving is 370 N.
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help -----------------------------------------
Answer:
H,G,E,D,C,B,A,I,F
Explanation:
F is an ignious intrusion and I cross cuts H to A so it must be newer.
Which wave has the longest wavelength?
Answer:
A
Explanation:
Will give brainliest!
Answer:
chemical symbol
Explanation:
Propose a hypothesis for how the position of the ball will affect the amount of its gravitational pull energy
throwing a ball up initially has a lot of kinetic energy because it is moving upwards ( kinetic energy is energy which a body possesses by virtue of being in motion.) this all then get converted to gravitational potential energy, and for a moment it is stationary before it begins to fall again. by the time it has returned again, all the gravitational potential energy has turned back into kinetic.
what is the net force on a car moving in a straight line with a constant velocity
Answer:
For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. The resultant force on the car is zero.
Explanation:
hope this helps
Answer:
zero
Explanation:
The acceleration of the car is zero, and and in this case the velocity is also zero. When your car is moving at constant velocity down a street, the net force must also be zero, according to Newton's First Law.
A group of waves is propagated at a speed that is ________ the speed of the individual waves in deep water.
A boulder of mass 10 kg rolls over a cliff and reaches the beach below with a velocity of 15 m/s. Find:
a. the kinetic energy of the boulder as it lands;
b. the potential energy of the boulder when it was at the top of the cliff
c. the height of the cliff.
Answer:
formular kinetic energy=1/2 ×vHelp me quick!!! please!!
Calculate the power of an engine which raises a mass of 1000 kg to a height of 40 m in 10 s.
Answer:
39.240 W
Explanation:
Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is [tex]w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J[/tex]
At this point we can simply apply the definition of power, that is [tex]P = \frac wt[/tex], to get the power of the engine is [tex]39.240 W[/tex]
Answer:
P=39200W
Explanation:
P=(mgh)/t
P=(40×9.8×1000)/10
P=39200W
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Direct contact is necessary for which type of energy transfer?
A. Conduction
B. Sound Waves
C. Conduction
D. Convection
Answer:
Conduction
Explanation:
Because when a molecule is transferred to another molecule then this in going into direct contact
For example if we have a pan and it is boiling well the heat that is on the pan holder that stays in place and it won`t move anywhere else like there is Radiation and Convection but for this question the answer would be Conduction
weight of 1 kg becomes 1/6 on moon. If radius of moon is 1.76×10^6 m, then the mass of moon will be
Answer:
7.65 x 10^22kg
sorry if im wrong!
Question #4
What is the charge on Can 2 at the moment
shown in panel B?
Question #5
What is the charge on the ball at the
moment shown in panel B?
A. Same as Van de Graaff
B. Opposite of Van de Graaff
C. Neutral
A. Same as Van de Graaff
B. Opposite of Van de Graaff
C. Neutral
Answer:
Q4
A
Q5
B
Explanation:
BRAINLIEAST IW8W9 HAHAH YAN NA PO TALAGA
The magnitude of vector A is 2.5 m and is directed towards east. The magnitude and direction of A /2 will be
The magnitude and direction of half of the given vector A is 1.25 m east.
The given parameters;
magnitude of vector A = 2.5 m eastA vector can be described with both magnitude and direction. The magnitude of the vector is the scalar or numeric representation of the vector.
When the scalar representation has direction, we term the quantity a vector quantity.
The magnitude of half of the given vector is calculated as follows;
[tex]\frac{A}{2} = \frac{2.5 \ m}{2} = 1.25 \ m\ east[/tex]
Thus, the magnitude and direction of half of the given vector A is 1.25 m east.
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A driver is moving forward and stepping on the gas pedal. Which
position-time graph best depicts this motion?
Answer:
D
Explanation:
Can someone help me with the entire magnetism gizmo. I can’t get on gizmo, but it has to be done
Answer:
sure how can i help my g gggg
An object is at rest. There are several forces acting on the object, but the net force is zero. If all the
forces acting on the object were to suddenly double in size, would the object start moving? Why or why not?
Answer:
no
Explanation:
because the heaver an object the harder it is to move s the force will not be able to move it
2. What are the challenges of wind energy that causes decrease in the electrical production?
3. Give two solutions:
1. Modification in the structure of the turbine
2. Modification in the function of the turbine.
4. You must estimate the cost in each solution, and which one is more affordable and efficient for the municipality to go for.
5. You must make sure that there is minimal energy loss.
Levelized production cost is a big challenge in the production of wind energy.
The main challenge in the production of wind energy is the high production cost. It has to minimize the Levelized Production Cost (LPC) which is the ratio between energy production cost and economic lifetime. This problem can be solved by doing modification in the structure of the turbine as well as we must ensure minimal energy loss.
The modification in the structure can produce more electrical energy and reduce the energy loss also provides more profit to the company so we can conclude that levelized production cost is a big challenge in the production of wind energy.
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