1 Figure 13.17 shows the screen of an oscilloscope. The time-base of the oscilloscope is set at 500 us div?.
Calculate the time period of the signal and hence its frequency.

1 Figure 13.17 Shows The Screen Of An Oscilloscope. The Time-base Of The Oscilloscope Is Set At 500 Us

Answers

Answer 1

Answer:

Explanation:

Time-base of the oscilloscope is set at 500 [tex]\mu s[/tex]/div. It means, one block in horizontal direction represents 500 microseconds. The period of the wave is the time to complete one oscillation and in the picture there is two-block for complete one oscillation, so the period and oscillation are:

[tex]T=(2)(500) =100 \mu s \rightarrow f=\frac{1}{T}=\frac{1}{100 \times 10^{-6}}=10000 Hz[/tex]

Answer 2

the time period of the signal is 1200μs and hence its frequency is 833 Hz

What is oscilloscope ?

An oscilloscope is a sort of electronic test tool that shows fluctuating electrical voltages visually as a two-dimensional plot of one or more signals as a function of time. The primary goals are to display repeating or single waveforms on the screen that would otherwise occur too quickly for the human eye to discern. The exhibited waveform may then be analysed for amplitude, frequency, rising time, time interval, distortion, and other features. Previously, these values were calculated by manually measuring the waveform against the scales incorporated into the instrument's screen. Modern digital equipment may immediately compute and show these parameters.

Given,

Time knob = 500 μs/div

wavelength of wave in oscilloscope =  2.4 div

Period of time of the wave is 2.4 div×500 μs/div = 1200μs

frequency of the wave is 1/T = 1/12μs = 833 Hz

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Related Questions

What is the mass of a toy car if it has 5 J of potential energy and is sitting on top of a track that has a height of 2m?

(PE= m x g x h) (hint g=9.8 m/s2)

Answers

Explanation:

PE=mgh

5=m(9.8)(2)

m=5/19.6

m=0.2251 kg

m=225.1 grams

2. Calculate the work done by a 47 N force pushing a 0.025 kg pencil 0.25 m against a force of 23 N.

Answers

Answer: 6 J

Explanation:

Total force applied = 47 N Assuming that direction of movement of pencil and applied force is same. Work done by force in moving the pencil W = Force × Distance through which force moves ⇒ W = 47 × 0.25 = 11.75 J .-.-.-.-.-.-.-.-. In case we are asked useful work done then we calculate net force used for pushing the pencil: Net force used for pushing the pencil = 47 − 23 = 24 N Assuming that direction of movement of pencil and net force is same. Useful Work done by force in moving the pencil W u = Force × Distance ⇒ W u = 24 × 0.25 = 6 J

The work done the pushing force is required.

The work done by the pushing force is [tex]6\ \text{J}[/tex]

[tex]F_1[/tex] = Pushing force = 47 N

[tex]F_2[/tex] = Opposing force = 23 N

m = Mass of object = 0.025 kg

s = Displacement = 0.25 m

Work done is given by

[tex]W=F_ns[/tex]

[tex]\Rightarrow W=(47-23)\times 0.25[/tex]

[tex]\Rightarrow W=6\ \text{J}[/tex]

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how does gravity change as it nears an object​

Answers

What subject is this?

A, B, or C for this question?

Answers

Answer:

A. right before it hits the ground.

Explanation:

because all the way down, it is building kinetic energy.

Calculate the wave speed (in m/s) for the following waves:


a) A sound wave in steel with a frequency of 500 Hz and a wavelength of 3.0 meters. (2pts)







b) a ripple on a pond with a frequency of 2 Hz and a wavelength of 0.4 meters. (2pts)









Calculate the wavelength (in meters) for the following waves:



A wave on a slinky spring with a frequency of 2 Hz travelling at 3 m/s. (2pts)







An ultrasound wave with a frequency 40,000 Hz travelling at 1450 m/s in fatty tissue. (2pts)









Calculate the frequency (in Hz) for the following waves:



A wave on the sea with a speed of 8 m/s and a wavelength of 20 meters. (2pts)







A microwave of wavelength 0.15 meters travelling through space at 300,000,000 m/s. (2pts)

Answers

Answer: A : 250 is the answer

B; The frequency of a wave is the number of complete oscillations (cycles) made by the wave in one second.

Instead, the wavelength is the distance between two consecutive crests (highest position) or 2 troughs (lowest position) of the wave.

In this problem, we are told that the leaf does two full up and down bobs: this means that it completes 2 full cycles in one second. Therefore, its frequency is

where  is called Hertz (Hz). So, the correct answer is

Explanation:

#Wavespeed

#1

[tex]\\ \rm\Rrightarrow v=\nu\lambda=500(3)=1500m/s[/tex]

#2

[tex]\\ \rm\Rrightarrow v=2(0.4)=0.8m/s[/tex]

#Wavelength

#1

[tex]\\ \rm\Rrightarrow \lambda=\dfrac{v}{\nu}=\dfrac{3}{2}=1.5m[/tex]

#2

[tex]\\ \rm\Rrightarrow \lambda= \dfrac{1450}{40000}=0.03625m[/tex]

#Frequency

[tex]\\ \rm\Rrightarrow \nu=\dfrac{v}{\lambda}=\dfrac{8}{20}=0.4Hz[/tex]

#2

[tex]\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8}{15\times 10^{-2}}=0.2\timee 10^{10}=2\times 10^9Hz[/tex]

what is acceleration due to gravity? ​

Answers

The acceleration due to gravity is 9.81m/s^2

The acceleration due to gravity is 9.8 m/s^2.

I need to know what the answer is to this

Answers

A pull between two objects, for example, between an object and Earth. When forces on an object are balanced, there is no change in speed or direction.

So the answer is I agree

Answer:

i think its the top one

Explanation:

pls tell me if im wrong  

is water wet? If water is not wet does that make it dry?

Answers

Answer:

Water isn't wet by itself, but it makes other materials wet when it sticks to the surface of them.

Explanation:

Answer:

water is wet

it is a liquid

Explanation:

The knot at the junction is in equilibrium under the influence of four forces acting on it. The F force acts from above on the left at an angle of α with the horizontal. The 5.7 N force acts from above on the right at an angle of 50◦ with the horizontal. The 6.2 N force acts from below on the right at an angle of 44◦ with the horizontal. The 6.7 N force acts from below on the left at an angle of 43◦ with the horizontal.
1. What is the magnitude of the force F?
2. What is the angle a of the force F in the figure above?

Answers

The knot is in equilbrium, so there is no net force acting on it. Starting with the unknown force and going clockwise, denote each force by F₁, F₂, F₃, and F₄, respectively. We have

F₁ + F₂ + F₃ + F₄ = 0

Decomposing each force into horizontal and vertical components, we have

F cos(180º - α) + (5.7 N) cos(50º) + (6.2 N) cos(-44º) + (6.7 N) cos(-137º) = 0

F sin(180º - α) + (5.7 N) sin(50º) + (6.2 N) sin(-44º) + (6.7 N) sin(-137º) = 0

Recall that cos(180º - x) = - cos(x) and sin(180º - x) = sin(x), so these equations reduce to

F cos(α) ≈ - 3.22 N

F sin(α) ≈ 4.51 N

(1) Recall that for all x, sin²(x) + cos²(x) = 1. Use this identity to solve for F :

(F cos(α))² + (F sin(α))² = F ² ≈ 30.73 N²   →   F5.5 N

(2) Use the definition of tangent to solve for α :

tan(α) = sin(α) / cos(α) ≈ 1.399   →   α ≈ 126º

or about 54º from the horizontal from above on the left of the knot.

(a) The magnitude of the force F acting on the knot is 5.54 N.

(b) The angle α of the force F is 54.4⁰.

The given parameters:

F force at α 5.7 N force at 50⁰6.2 N force at 44⁰6.7 N force at 43⁰

The net vertical force on the knot is calculated as follows;

[tex]F_y = Fsin(\alpha) + 5.7 sin(50) - 6.2 sin(44) - 6.7 sin(43)\\\\F_y = F sin(\alpha) -4.51\\\\Fsin(\alpha) = 4.51[/tex]

The net horizontal force on the knot is calculated as follows;

[tex]F_x = -F cos(\alpha) + 5.7 cos(50) + 6.2cos(44) - 6.7cos(43)\\\\F_x = -Fcos(\alpha) + 3.22\\\\Fcos(\alpha) = 3.22[/tex]

From the trig identity;

[tex]sin^2 \theta + cos^ 2 \theta = 1\\\\[/tex]

[tex](Fsin(\alpha))^2 + (Fcos(\alpha))^2 = (4.51)^2 + (3.22)^2\\\\F^2(sin^ 2\alpha + cos^2 \alpha) = 30.71\\\\F^2(1) = 30.71\\\\F = \sqrt{30.71} \\\\F = 5.54 \ N[/tex]

The angle α of the force F is calculated as follows;

[tex]Fsin(\alpha) = 4.51\\\\sin(\alpha) = \frac{4.51}{F} \\\\sin(\alpha ) = \frac{4.51}{5.54} \\\\sin(\alpha ) = 0.814\\\\\alpha = sin^{-1}(0.814)\\\\\alpha = 54.5 \ ^0[/tex]

Find the image uploaded for the complete question.

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When putting the ball on the tee you want half of the golf ball to _________.


Question 1 options:

be above the club


be below the club


be in front of the club


be behind the club

Answers

Answer:

be in front of the club

Explanation:

The ball should be highest off the ground for a driver. The general recommendation is that the bottom of the golf ball on a tee should be level with the top of the driver; for long and mid-irons, push the tee into the ground so that only about a quarter-inch is above ground.

During which time Interval does the object travel approximately 10 meters?

OA. O seconds to 3 seconds
OB. 3 seconds to 5 seconds
OC. 5 seconds to 7 seconds
OD. 7 seconds to 8 seconds
OE. 8 seconds to 10 seconds

Answers

Answer:

[tex]OA. \: O \: seconds \: to \: 3 \: seconds[/tex]

A campus shuttle bus makes 1 revolution per second round a circular track of radius 100 cm. Determine its periodic time. ​

Answers

The periodic time of the campus shuttle is = 1 sec

What is periodic time ?

The periodic time is also known as  revolution per second is the time it takes object in motion ( revolving ) to pass through a point twice ( usually the starting position ) of the object and it calculated as :

For a simple pendulum = 2π√L/g

But a campus shuttle bus in motion

since it takes

1 revolution = 1 sec therefore the time period is = 1 sec

Hence we can conclude that the periodic time of the campus shuttle = 1 second.

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a 2 kg ball traveling at 5m/s collides with a 1 kg ball at rest. After the collision the 1 kg ball moves off with a speed of 7 m/s. Find the final speed of the 2 kg ball.

Answers

According to the Conservation of Momentum:

m1vo1 + m2vo2 = m1vf1 + m2vf2

2(5) + 1(0) = 2vf1 + 1(7)

10 + 0 = 2vf1 + 7

3 = 2vf1

vf1 = 3/2 m/s

When a light ray traveling in a higher index of refraction material passes into a lower index of refraction material, the light ray Group of answer choices Travels in a straight line without changing direction Bends toward the axis perpendicular to the surface between the materials Bends away from the axis perpendicular to the surface between the materials

Answers

The light ray ; ( C ) Bends away from the axis perpendicular to the surface between the materials

Snell's law

Snell's law states that the ratio of the sines of the angles of incidence is equal to the ratio of the refractive indexes of the materials surface through which the light rays pass through. therefore

As the light ray travels from a material with a higher index of refraction into a material with a lower index of refraction at the axis that is perpendicular to the surface which is in between the materials the light ray will bend away due to Snell's law .

Hence we can conclude that The light ray Bends away from the axis perpendicular to the surface between the materials.

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Explain why we need to study the climate.

Answers

Answer:The current focus of climate science involves carbon dioxide (CO2)emissions. Carbon dioxide in the atmosphere acts as a blanket over the planet by trapping long wave radiation, which would otherwise radiate heat away from the planet. As the amount of carbon dioxide increases, so will its warming effect.

Explanation:

Kepler's work revealed that the Earth was at the center of the circular orbits of the planets at the center of the elliptical orbits of the planets orbiting the Sun in an elliptical orbit O at one focus of the elliptical orbit of the planets​

Answers

Answer:

  orbiting the Sun in an elliptical orbit

Explanation:

When orbits are circular, the center and the focus are the same point. For an elliptical orbit, the orbited object is at one focus of the ellipse. Kepler found planetary orbits to be elliptical with the sun at one focus.

__

As with a lot of scientific theories, it only explained some of the motion. As with a lot of scientific theories, explaining the discrepancies resulted in new discoveries.

Answer:

at one focus of the elliptical orbit of the planets.

Harry is pushing a car down a level road at 2.0 m/s with a force of 243 N. The
total force acting on the car in the opposite direction, including road friction and
air resistance, is which of the following?
a. Slightly more than 243 N.
b. Exactly equal to 243 N.
c. Slightly less than 243 N.

Answers

Answer:

C, slightly less than 243 N

Explanation:

Road friction and air resistance aren't that much on a force. Try pushing something and see how much friction there is. Not that much.

a car moving at a speed shows that the force applied to the car is greater than the frictional force and air resistance

c. Slightly less than 243 N.

What is an independent variable?

Answers

The independent variable is the variable that changes or controls
a variable whose variation does not depend on that of another.

48. Final Velocity Your sister drops your house keys down
to you from 4.3 m What is the velocity of the keys when you
catch them?​

Answers

Answer:

There is a difference between the words 'drops' and 'throws'

If an object is dropped, it's initial velocity is 0 but if the same object is thrown, it has some initial velocity

Since 'the sister' DROPS the keys, the initial velocity will be 0 m/s

We are given:

u=0 m/s

s = 4.3 m

a = 9.8 m/s/s (gravity)

From the third equation of motion:

v² - u² = 2as

Replacing the known values

v² - (0)² = 2(9.8)(4.3)

v² = 84.28

v = 9.2 m/s (approx)

Hence, the final velocity of the keys is 9.2 m/s

Which information did the Glomar Challenger study in 1968?

the rate of seafloor spreading
the direction of seafloor spreading
the age of rocks in various places in the ocean
the contents of rocks in various places in the ocean

Answers

Explanation:

Glomar Challenger studies about the "age of rocks in various places in the ocean" in 1968. EXPLANATION: Glomar Challenger was a "deep sea research vessel" for marine geology and oceanography studies.

I hope this helps you :)

Answer:

c no cappp :)

Explanation:

An image of the Earth-moon-sun system is shown.The moon remains in orbit around Earth because of the force of —

Answers

The reason the moon stays in orbit is because of the force of gravity- a universal force that attracts objects.

Please I need help with this :(

Answers

three charged particals are located at the corners of an equil triangle shown in the figure showing let (q 2.20 Uc) and L 0.650

At low pressures and high temperatures, the density of a gas

Answers

Answer:

Higher denisty

Explanation:

High pressure=high denisty

A man slides on snow without friction starting at 8.96m/s at the top of an inclined plane with height 8.21m. What is his speed at the bottom of a plane?​

Answers

Answer:

V2 = 15.53 [m/s]]

Explanation:

In order to solve this problem we must use the principle of energy conservation, where potential energy is transformed into kinetic energy. At the bottom is taken as a reference level of potential energy, where the value of this energy is equal to zero.

Above the inclined plane we have two energies, kinetics and potential. While when the sled is at the reference level all this energy will have been transformed into kinetic energy.

[tex]E_{1}=E_{2}\\ m*g*h+(\frac{1}{2} )*m*v_{1} ^{2}=\frac{1}{2}*m*v_{2} ^{2} \\(9.81*8.21)+(0.5*8.96^{2} )=(0.5*v_{2}^{2} )\\(0.5*v_{2}^{2} )=120.68\\v_{2} ^{2}=241.36\\v_{2} =\sqrt{241.36}\\ v_{2} =15.53[m/s][/tex]

A body, with a volume of 2 m3, weighs 40 kN. Determine its weight when
submerged in a liquid with SG = 1.59.

Answers

Answer:

8.8 kN

Explanation:

V = 2 m³, W = 40 kN, SG = 1.59

Bouyant force N = 1.59 * 1000 kg/m³ * 9.81 N/kg * 2 m³ = 31.2 kN

So the weight becomes 40 - 31.2 = 8.8 kN

Can someone help pleaseeee

Answers

Answer:

Motion with constant velocity of magnitude 1 m/s (uniform motion) for 4 seconds in a positive direction and then for 2 seconds uniform motion with constant velocity of magnitude 3 m/s in reverse direction .

Explanation:

The graph shows a constant velocity of 1 m/s for 4 seconds in the positive direction. After that, between 4 seconds and 6 seconds, the object reverses its motion with constant velocity of magnitude 3m/s.

Two hockey pucks are moving toward each other. The mass of the first puck is half the mass of the second puck. Initially, the first puck is going at a speed of 5.0 m/s to the right, while the second puck is going at a speed of 2.0 m/s. The first puck rebounds with a speed of 9.0 m/s. What is the final speed of the second puck

Answers

The final speed of the second puck is 5 m/s.

What is speed?

Speed can be defined as the rate of change of distance with respect to time.

To calculate the final speed of the second puck, we use the formula below.

Formula:

mu+m'u' = mv+m'v'................ Equation 1

Where:

m = mass of the first puckm' = mass of the second pucku = initial velocity of the first pucku = initial velocity of the second puckv = final velocity of the first puckv' = final velocity of the second puck.

Make v' the subject of the equation

v' = (mu+m'u'-mv)/m'.............. Equation 2

Assuming,

The mass of the first puck is y The left direction is negative and the right direction is positive

From the question,

Given:

m = ym' = 2yu = 5 m/su' = -2 m/sv = -9 m/s ( rebounds)

Substitute these values into equation 2

v' = [(y×5)+(2y×(-2))-(y×(-9))]/2yv' = (5y-4y+9y)/2yv' = 10y/2yv' = 5 m/s

Hence, The final speed of the second puck is 5 m/s.

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You measured the length, diameter and mass of two different cylinders. In both cases, you found that the length had 3 significant figures and that length was the measurement with the fewest number of significant digits. If you found the weight densities to be 38119 N/m^3 and 38081 N/m^3 and you round these values to the correct number of significant figures, can you conclude the two cylinders are made of the same material (do they have the same weight density)?

a. Not enough information given.
b. Yes.
c. No.

Answers

Answer:

Weight Density 1 = 38100 N/m³

Weight Density 2 = 38100 N/m³

b. Yes

Explanation:

The formula for volume of cylinder is:

V = πr²l

where,

V = Volume

r = radius

l = length of cylinder

So, if length has the 3 significant figures which is least in all values, Then the volume must also be in 3 significant figures. The formula for weight density is:

Weight Density = Weight/Volume

Here, the volume has the least significant figures of 3, therefore, the weight densities must also have 3 significant figures:

Weight Density 1 = 38119 N/m³

Weight Density 1 = 38120 N/m³

Weight Density 1 = 38100 N/m³

Weight Density 2 = 38119 N/m³

Weight Density 2 = 38120 N/m³

Weight Density 2 = 38100 N/m³

Hence, the answer is:

b. Yes

A boy of mass 40kg eats bananas contains of 980 joule. If this energy is used to lift him up from ground,the height to which he can climb is

Answers

Answer:

h = 2.49 [m]

Explanation:

In order to solve this problem we must use the definition of potential energy, which tells us that energy is equal to the product of mass by gravity by height.

The potential energy can be calculated by means of this equation:

Ep = m*g*h

where:

Ep = potential energy = 980 [J]

m = mass = 40 [kg]

g = gravity acceleration = 9.81 [m/s^2]

h = elevation [m]

Now replacing:

980 = 40*9.81*h

h = 2.49 [m]

Describe the buoyant force and explain how
it relates to Archimedes principle.

Answers

Answer:

Archimedes' principle states that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.

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