The term "activation energy" refers to the energy difference between the reactant and the transition state.
The least amount of energy required to initiate a reaction is called activation energy. The activation energy controls the pace at which the reaction happens, whereas the Gibbs free energy specifies where the equilibrium will settle down and how many products are created at the end of the process.
The activation energy must be provided in order for the molecule to reach the transition state because it is a high-energy state. Reactant molecules don't stay in the transition state for very long since it is unstable; instead, they move on to the next phase of the chemical reaction right away.
During phase transition, both free energy and entropy change. The rate of entropy increases as the temperature rises because it causes the molecules to move more randomly.
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Why are endergonic and exergonic reactions typically coupled?A) Newton's laws of motion state that every action has an equal and opposite reaction. Therefore, in a chemical reaction, energy must both be released and absorbed.B) The free energy released from the exergonic reaction is used to drive the non-spontaneous endergonic reaction.C) An exergonic reaction will proceed too slowly without an endergonic reaction to stabilize the transition state.D) In order to maintain equilibrium, the heat lost in an exergonic reaction is absorbed by the endergonic reaction, to keep the free energy at 0.
`The endergonic and exergonic reactions typically coupled because the correct option is .B) The free energy released from the exergonic reaction is used to drive the non-spontaneous endergonic reaction.
The exergonic reaction is the reaction in which the free energy is released. The gibbs free energy is negative for the exergonic reaction. The exergonic reaction is released in this reaction.
The endergonic reaction is the reaction in which the free energy is absorbed. The gibbs free energy is positive for the endergonic reaction. The endergonic reaction absorbed the energy.
Thus, they are coupled as The free energy released from the exergonic reaction is used to drive the non-spontaneous endergonic reaction.
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The dissolving process occurs at the _________ of the solute.
Responses
A basebase
B surfacesurface
The enzyme fumarase catalyzes the reaction:
fumarate + H2O → malate. The turnover number for this enzyme and substrate is 800 per minute. How long would it take one molecule of fumarase to produce 7850 product molecules? Ans: ____ min
It would take one molecule of fumarase approximately Turnover for 9.8125 minutes to produce 7850 product molecules.
To calculate the time it would take one molecule of fumarase to produce 7850 product molecules, we need to divide the total number of product molecules by the enzyme's turnover number. Fumarase is an enzyme that catalyzes the reaction of fumarate to L-malate in the citric acid cycle. This reaction is an important step in cellular respiration and energy production in living cells. Fumarase speeds up the reaction by lowering the activation energy required for the conversion to occur, allowing the reaction to occur more quickly and efficiently.
Turnover number = 800 per minute
Product molecules = 7850
Time = 7850 / 800 = 9.8125 minutes
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When silver nitrate and sodium sulfate react, a precipitate forms. What mass of the precipitate is obtained when 100. Ml of 0. 100 m sodium sulfate is added to 150. Ml of 0. 100 m silver nitrate? if 1. 50 g of the precipitate was isolated. What is the percent yield?.
The mass of the precipitate, Ag₂SO₄ obtained is 2.34 g
Determination of the mole of Na₂SO₄
Volume of Na₂SO₄ = 100 mL = 100 / 1000 = 0.1 L
Molarity of Na₂SO₄ = 0.1 M
Mole of Na₂SO₄ =?
Mole = Molarity x Volume
Mole of Na₂SO₄ = 0.1 × 0.1
Mole of Na₂SO₄ = 0.01 mole
Determination of the mole of AgNO₃
Volume of AgNO₃ = 150 mL = 150 / 1000 = 0.15 L
Molarity of AgNO₃ = 0.1 M
Mole of AgNO₃ =?
Mole = Molarity x Volume
Mole of AgNO₃ = 0.1 × 0.15
Mole of AgNO₃ = 0.015 mole
Determination of the limiting reactant
Na₂SO₄ + 2AgNO₃(aq) → Ag₂SO₄(s) + 2NaNO₃(aq)
From the balanced equation above,
1 mole of Na₂SO₄ reacted with 2 moles AgNO₃
Therefore,
0.01 mole of Na₂SO₄ will react with = 0.01 × 2 = 0.02 mole of AgNO₃
From the above calculation, we can see that a higher amount of AgNO₃ (i.e 0.02 mole) than what was given (i.e 0.015 mole) is needed to react completely with 0.01 mole of Na₂SO₄.
Therefore, AgNO₃ is the limiting reactant and Na₂SO₄ is the excess reactant.
Determination of the mole of the precipitate, Ag₂SO₄ obtained
Na₂SO₄ + 2AgNO₃(aq) → Ag₂SO₄(s) + 2NaNO₃(aq)
From the balanced equation above,
2 moles of AgNO₃ reacted to produce 1 mole of Ag₂SO₄.
Therefore,
0.015 mole of AgNO₃ will react to produce = 0.015 / 2 = 0.0075 mole of Ag₂SO₄
Determination of the mass of precipitate, Ag₂SO₄ obtained
Mole of Ag₂SO₄ = 0.0075 mole
Molar mass of Ag₂SO₄ = (2×108) + 32 + (16×4) = 312 g/mol
Mass of Ag₂SO₄ =?
Mass = mole × molar mass
Mass of Ag₂SO₄ = 0.0075 × 312
Mass of Ag₂SO₄ = 2.34 g
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does temperature affet how high a ball bounces science project
The temperature of the ball is one element that might affect how it bounces. A ball will bounce higher than a cold one if it is warmer. This is due to two factors.
When the temperature of a hollow ball changes, the air pressure inside the ball also changes. The balls bounced higher when they were hot and lower when they were cold. The air temperature inside the ball and the rubber's elasticity were both impacted by the temperature shift, which also changed the height of the ball's bounce. The sum of a ball's material characteristics surface textures, constituent materials, air content, hardness or softness, etc. affects the height of its bounce.
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What is the LD50 for sodium cyanide?
LD50, which stands for "Lethal Dose 50," is a measure of the toxic dose of a substance required to cause death in 50% of the test subjects. Sodium cyanide (NaCN) is a highly toxic chemical used in various industrial processes. It is important to understand the LD50 of sodium cyanide to ensure the safety of workers and the general public.
The LD50 of sodium cyanide varies based on the route of exposure and the species of test subject. According to the Merck Index, the oral LD50 for sodium cyanide in rats is around 50 mg/kg. This means that if a rat were to ingest 50 mg of sodium cyanide per kilogram of body weight, it would result in death for 50% of the rats. However, it is important to note that the LD50 for sodium cyanide can vary depending on the species of test subject, with the LD50 being higher for larger animals such as dogs and lower for smaller animals such as mice.
In addition to oral exposure, sodium cyanide can also be toxic through inhalation and skin contact. The inhalation LC50 (Lethal Concentration 50) of sodium cyanide in rats is approximately 20 mg/m3, meaning that if a rat were to inhale air containing 20 mg of sodium cyanide per cubic meter, it would result in death for 50% of the rats. The dermal LD50 of sodium cyanide in rabbits is approximately 200 mg/kg, meaning that if 200 mg of sodium cyanide were applied to the skin of a rabbit per kilogram of body weight, it would result in death for 50% of the rabbits.
In conclusion, sodium cyanide is a highly toxic chemical that can cause death through various routes of exposure. The LD50 of sodium cyanide varies based on the route of exposure and the species of test subject, with oral exposure being the most toxic in rats. It is important to understand the LD50 of sodium cyanide to ensure the safety of workers and the general public.
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in this reaction, you observed several different cu species which had different physical attributes. select the appropriate chemical formula(s) that corresponds to a sky blue solution
The color of a solution can often give us a clue about the type of species present in it. In a chemical reaction, the observation of a sky blue solution suggests the presence of copper (Cu) species. The exact chemical formula of these species can vary, depending on the conditions of the reaction.
Copper (Cu) can exist in different oxidation states, ranging from +1 to +2. When dissolved in water, these different oxidation states of Cu can form different species, each with its unique properties. The most common Cu species present in a sky blue solution are Cu^2+ and Cu(OH)2^-.
Cu^2+ is a positively charged ion and is the result of Cu in its +2 oxidation state. This ion is highly soluble in water and has a blue color.
Cu(OH)2^- is a negatively charged ion and is formed from the reaction of Cu^2+ with hydroxide (OH-) ions in water. This species also contributes to the blue color of the solution.
In summary, the appropriate chemical formula for a sky blue solution is Cu^2+ and Cu(OH)2^-. These species are responsible for the blue color of the solution and are likely the result of copper in its +2 oxidation state reacting with hydroxide ions in water.
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a liquid has an enthalpy of vaporization of 30.8 kj/mol. at 273 k it has a vapor pressure of 102 mmhg. what is the normal boiling point of this liquid? (1mm hg
A liquid has an enthalpy of vaporization of 30.8 kj/mol. at 273 k it has a vapor pressure of 102 mmhg. The normal boiling point of this liquid is 320 K
In order to get the normal boiling point of the liquid, we will use the Clausius-Clapeyron equation expressed according to the equation:
ln [tex]\frac{P2}{P1}[/tex] = (ΔHvap/R) . ([tex]\frac{1}{T1}[/tex] - [tex]\frac{1}{T2}[/tex])
where:
P1 is the vapor pressure of that substance at T1
P2 is the vapor pressure of that substance at T2
ΔHvap is the enthalpy of vaporization.
R is the gas constant - usually expressed as 8.31 J/Kmol
Since we are looking for the normal boiling point, we can set P2 = 1 atm (101.3 kPa) and T2 = the normal boiling point temperature.
Rearranging the equation to solve for T2:
T2 = (ΔHvap/R) * [tex](1/T1 - 1/P2)^{-1}[/tex] + T1
Plugging in the values we have:
T2 = (30.8 kJ/mol) / (8.31 J/mol*K) * [tex](1/273 K - 1/101.3 kPa)^{-1}[/tex] + 273 K
Solving for T2, the normal boiling point temperature is approximately 320.2 K ≈ 320 K
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according to collision theory, what is/are the essential qualification(s) that must occur for a reaction to form products? choose one or all that apply. not all molecular collisions lead to the formation of products. in fact, only a small fraction of collisions lead to product formation. according to collision theory, what is/are the essential qualification(s) that must occur for a reaction to form products? choose one or all that apply. reacting particles must have the proper orientation. reacting particles must only be gaseous. reacting particles must have sufficient mass. reacting particles must collide. reacting particles must have sufficient energy.
According to collision theory, the essential qualification(s) that must occur for a reaction to form products are reacting particles must have the proper orientation, reacting particles must collide and reacting particles must have sufficient energy. Therefore, option A, D and E are correct.
What is collision theory ?According to collision theory, for a chemical reaction to occur, the reacting particles must collide with one another. The reaction rate is determined by the frequency of collisions. According to the theory, reacting particles frequently collide without reacting.
Collision theory, as the name implies, describes how collisions, specifically collisions between particles, result in chemical change. The formation of entirely new substances is referred to as chemical change.
Thus, option A, D and E are correct.
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how many moles of water will be produced when 38 moles of sulfuric acid is consumed
Answer:
Explanation:
The conversion of sulphur to sulfuric acid, though it goes through several steps, is:
2 S + 3 O2 + 2 H2O → 2 H2SO4
OK, so the equation says for every 2 moles of S you will get two moles of sulfuric acid. With a little simple math, then, the ratio of S to H2SO4 is 2:2 which is the same as 1:1.
While not correct by convention, you can write the above equation as
S + 3/2 O2 + H2O → H2SO4
And then the relationship between S and H2SO4 is more clear.
assume that the extinction coefficient for dhfr is uncertain by /- 5 percent. what is the full range of concentrations is consistent with this uncertainty?
When the extinction coefficient for DHFR (dihydrofolate reductase) is uncertain by +/- 5%, it means that the actual value of the extinction coefficient could be 5% higher or 5% lower than the reported value.
To determine the full range of concentrations that are consistent with this uncertainty, we need to calculate the minimum and maximum values of the extinction coefficient based on the +/- 5% uncertainty.
For example, if the reported extinction coefficient is 10,000 M^-1 cm^-1, Minimum value would be 9,500 M^-1 cm^-1 (10,000 - 500)
Maximum value would be 10,500 M^-1 cm^-1 (10,000 + 500).
The full range of concentrations that are consistent with this uncertainty can then be calculated by using the minimum and maximum values of the extinction coefficient in the appropriate equation. For example, if we are using the extinction coefficient to calculate the concentration of DHFR in a sample, we would use the minimum and maximum values of the extinction coefficient in the calculation to determine the full range of concentrations that are consistent with the +/- 5% uncertainty.
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Which two elements are present in the sample?
chlorine and mercury
chlorine and neon
helium and mercury
helium and neon
The sample contains helium and neon elements.
What do helium and neon mean?The two lightest noble gases, helium and neon, have traditionally been placed in Group 18 of the Periodic Table of Elements, alongside argon and other unreactive or moderately reactive gaseous elements (krypton, xenon, radon), and oganesson.
A helium-neon laser, also known as a He-Ne laser, is a type of gas laser whose high energetic medium gain medium is a mixture of helium and neon in a 10:1 ratio at a total pressure of about 1 torr inside a small electrical discharge.
Helium has only two electrons in its outer electron shell. Neon and Argon have 8 electron outer shells, and all three have filled outer shells.
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Mohammad observed that his water boiled much more quickly than his isopropyl alcohol. His peer group suggested some experimental error that may caused this to happen. Which 2 experimental errors most likely caused the invalid data a. He could have mixed up the labels on the containers b. The heating vessel or hot plate was not at the same temperature c. His procedure was correct but tested a type of water that boils more quickly than isopropyl alcohol d. The boiling vessel might have been dirty so the solutions got mixed
Answer:
Mohammad observed that his water boiled much more quickly than his isopropyl alcohol. His peer group suggested some experimental error that may caused this to happen. Which 2 experimental errors most likely caused the invalid data a. He could have mixed up the labels on the containers b. The heating vessel or hot plate was not at the same temperature c. His procedure was correct but tested a type of water that boils more quickly than isopropyl alcohol d. The boiling vessel might have been dirty so the solutions got mixed
Explanation:
How many moles are in 300 g of Sulfur?
Answer:
there are 300/32 moles in 300 g, i.e. 9.375 moles.
Perform the conversions between energy units.
814 kJ= J
2815 kcal= kJ
5.65×106 J= kcal
As 1 Kilojoules is equals to 1000 joules, then the conversion of energy units:
814 kJ= 814,000 J
2815 kcal= 11,844.35 kJ
5.65×106 J= 13,438.8 kcal
What is energy unit?Simply put, energy is the ability to perform work. It can appear in kinetic, potential, electrical, chemical, nuclear, thermal, and other forms. It is divided into two categories: renewable energy and non-renewable energy.
It's interesting that James Prescott Joule, a British physicist whose work helped establish the concept of energy, has his name preserved as the name of this international unit. In terms of SI base units, the unit can be represented as follows: When examining the unit in its simplest form, 1-N.m is equal to 1 joule:
1J = 1kg · (m/s)² = 1 kg·m²/s²
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What is the ratio of a conjugate acid to a conjugate base if the ph of the solution is 5. 1 and the pka of the acid is 6. 5
10:1 , Because this conjugate base is a component of a salt of this acid and a strong base, the solution of acid X and its conjugate base is a buffer solution.
What is conjugate base formula?The formula of the conjugate base is the formula of the acid less one hydrogen. The reacting base becomes its conjugate acid. The formula of the conjugate acid is the formula of the base plus one hydrogen ion.
The Henderson-Hasselbalch equation, pH = pKa + log([A]/[HA]), can be used to calculate the pH of a buffer. The equilibrium concentrations of the conjugate acid-base pair utilised to form the buffer solution are denoted by [HA] and [A] in this equation.Because a base's conjugate acid ("B") is "BH," we can abbreviate "the pKa of the conjugate acid of a base" as its pKaH. As a result, the pKaH of pyridine is 5.2 while the pKaH of piperidine is 11.
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The following compounds, listed with their boiling points, are liquid at -10°C: butane, -0.5°C; etha- nol, 78.3°C; toluene, 110.6°C. At -10°C, which of these liquids would you expect to have the highest vapor pressure? Which the lowest? Explain.
The pressure of a vapor in a closed system that is in thermodynamic equilibrium with its condensed phases is known as vapor pressure.
Is toluene prohibited in the United States?Toluene is regarded as one of the "toxic trinity" of hazardous compounds, along with formaldehyde and dibutyl phthalate, that are present in polishes and give them their hard finish. The trio is prohibited in many other nations, but if it is stated on the ingredient list, it is OK in the United States.
Is toluene very toxic?Toluene is regarded instantly harmful to life and health at levels of 500 ppm. Some persons may be more sensitive than others to the effects of inhaled solvents as a result of genetic variations. Some employees exposed to toluene levels deemed safe at work have developed occupational asthma.
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which path is the critical path? pathactivityexpected activity timeactivity variance a-b-ca2.83.25 b4.00.44 c3.17.25 d-e-fd4.00.11 e5.00.44 f7.00.44 g-h-ig3.33.44 h6.00.44 i4.17.25
The critical path is the path with the longest expected duration. In the given example, the critical path is A-B-C-D-E-F-G-H-I, with an expected duration of 33.44.
This path has the highest duration and the highest variance, meaning that any delays along this path will have the greatest effect on the overall project duration.
The critical path is a key concept in project management, and it is important to understand how it works in order to properly manage a project. The critical path is defined as the longest sequence of activities that must be completed in order for a project to be finished on time.
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The following are acid-base conjugate pairs except:
A. C6H5CO2H
and C6H5CO−2
B. H3O+ and OH−
C. CH3NH+3
and CH3NH2
D. HS− and S2−
C6H5CO2H and C6H5CO⁻² are acid-base conjugate pairs. Thus, option A is correct.
What is an example of a conjugate acid base pair?A conjugate acid-base pair is composed of two bases which only differ by the presence or absence of a proton. As a consequence, NH4+ is the conjugate acid of NH3, and NH3 is the conjugate base of NH4+. The conjugate base of F- is F, whereas the conjugate acid of F is HF.
What is the benzoic acid c6h5co2h's conjugate base?Benzoic acid contains the same unionised acid (C6H5COOH), conjugate base (C6H5COO-), and hydrogen ion elements as formic acid.
What is the conclusion of the Bronsted-Lowry theory?The base is a chemical which takes an H+ ion or a proton to produce its conjugate acid, and the acid is a molecule which contributes an H+ ion or a proton to form its conjugate base, according to the Bronsted-Lowry theory.
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Why the formula of sodium chloride is NaCl?
The sole two components of sodium chloride are sodium (Na) and salt, which is chlorine's positively charged ionic form (Cl). Its chemical name is NaCl for this reason.
What makes sodium chloride known as NaCl?
Most people use the term "salt" to refer to sodium chloride, or table salt. Ionic bonds between sodium ions & chloride ions result in the formation of sodium chloride. The formula is NaCl because there is one saline cation (Na+) per each chloride anion (Cl-) (Fig. 1).
Does NaCl accurately reflect the sodium chloride chemical formula? If not, why not?
Because of this, sodium chloride isn't a molecule. The empirical formula for the -1:1 ratio of the various elements is available. There is a chloride particle for every sodium ion. So (Na+Cl)n is the empirical formula of sodium chloride.
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does aluminum oxide or magnesium oxide have higher lattice energy
Magnesium oxide have higher lattice energy than aluminium oxide. Because of larger size of aluminium oxide its lattice energy is less than magnesium oxide.
Enthalpy is the term that is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, it is observed that enthalpy is directly proportional to specific heat capacity of a substances.
Enthalpy can be formulated as,
q = n × ΔH
where,
q = amount of heat
n = no of moles
ΔH = enthalpy
n = w / M.M
w = given mass
M.M = molar mass
Lattice energy is also directly proportional to product of charges on ions and inversely proportional to size of the ions. Since the charges are same, the only difference is in size of cation. Al is larger in size so, it has lesser lattice energy.
Therefore, because of larger size of Al, lattice energy of aluminium oxide is lower than magnesium oxide.
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find the average rate of change of the function over the given interval. f(t)=7 cost a. π 2,π b.
The average rate of change of the function f(t) = 7 cos(t) over the interval [π/2, π] is 0.
What is average rate of change of a function ?The average rate of change of a function over an interval is the total change in the function value divided by the length of the interval. In this case, the function f(t) = 7 cos(t) goes from a maximum value of 7 to a minimum value of -7 as t increases from π/2 to π, so the total change in the function value is -7 - 7 = -14. The length of the interval [π/2, π] is π - π/2 = π/2. So, the average rate of change over the interval is -14 / (π/2) = -14π/π = -14.
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If you used the method of initial rates to obtain the order for no2 , predict what reaction rates you would measure in the beginning of the reaction for initial concentrations of 0. 200 m , 0. 100 m , and 0. 050 m no2.
If the order of reaction with respect to NO2 is 1, I would expect to observe the following initial rates:
[tex]For[/tex] [tex][NO2] = 0.200 M, rate = k * [NO2]^1 = k * 0.200^1 = k * 0.200[/tex]
[tex]For [NO2] = 0.100 M, rate = k * [NO2]^1 = k * 0.100^1 = k * 0.100[/tex]
[tex]For [NO2] = 0.050 M, rate = k * [NO2]^1 = k * 0.050^1 = k * 0.050[/tex]
The strategy for initial rates is a typical approach to deciding the order of a reaction regarding a given reactant. The idea is to measure the initial rate of reaction for various initial concentrations of that reactant.
Then utilize the data to decide the relationship between the reaction rate and the concentration of that reactant.
Let us assume that the reaction has the general form:
aA + bB - > products
where An and B are the reactants and an and b are the orders of reaction concerning each reactant. The rate of the reaction is given by the expression:
[tex]rate = k * [A]^a * [B]^b[/tex]
where k is the rate constant, which is autonomous of the reactant concentrations.
To utilize the strategy for initial rates, we would measure the initial rate of reaction for various initial concentrations of one of the reactants.
Suppose A. On the off chance that the order of reaction concerning A will be a, we would hope to notice the accompanying relationship between the initial rate and the concentration of A:
[tex]rate = k * [A]^a[/tex]
In this way, if the order of reaction with respect to NO2 is 1, we would expect to observe the following initial rates:
[tex]For[/tex] [tex][NO2] = 0.200 M, rate = k * [NO2]^1 = k * 0.200^1 = k * 0.200[/tex]
[tex]For [NO2] = 0.100 M, rate = k * [NO2]^1 = k * 0.100^1 = k * 0.100[/tex]
[tex]For [NO2] = 0.050 M, rate = k * [NO2]^1 = k * 0.050^1 = k * 0.050[/tex]
Thus, if the reaction order for NO2 is 1, we would hope to notice a linear relationship between the initial rate and the concentration of NO2, with the initial rate decreasing as the concentration of NO2 decreases.
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LAB: SOIL PARTICLES
You have learned that soil is made of weathered rock, water, air, and organic material. The size of particles is an important soil characteristic. According to the United States Department of Agriculture (USDA), there are three main particle sizes—sand, silt, and clay. Clay is particles smaller than 0.002 mm. Sand is particles larger than 0.05 mm. Particles in between are silt. The size of particles in soil determines how much water the soil will hold. Small particles hold more water than large particles.
Soil usually settles into different layers called horizons. The arrangement of horizons is the soil profile. In this experiment, you will observe how particle size affects the soil profile.
Describe how particle size affects the settling of soil.
Which type of soil do you think will settle to the bottom of the container faster?
1 1/2 cups potting soil
1 1/2 cup sand
3 wide-mouthed juice bottles with lids
Masking tape
Pen
Water
Make masking tape labels for each juice bottle. Label one "soil" and the other "soil and sand."
Fill both bottles 3/4 full of water.
Slowly pour 1 cup of soil into the water in the "soil" bottle. Observe the behavior of the soil particles.
Fill the "soil" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Slowly pour 1 cup of sand into the water in the "sand" bottle. Observe the behavior of the soil particles.
Fill the "sand" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Add the 1/2 cup of sand to the remaining 1/2 cup of soil. Mix thoroughly with the spoon.
Slowly pour the sand and soil mixture into the water in the "soil and sand" bottle. Observe the behavior of the particles.
Fill the "soil and sand" bottle the rest of the way with water. Secure the lid tightly and shake the bottle. Put the bottle on a flat surface where nothing will disturb it.
Leave both bottles undisturbed for 8 hours.
Look at the bottles again after 8 hours and record your observations.
Data
What did you notice about the way the soil particles sank in the water? How was it different from the way the soil and sand particles sank?
What does the soil look like in the "soil" bottle? How is it different from the soil in the "soil and sand" bottle?
In the "soil and sand" bottle, which type of soil is on the bottom? Why?
The amount of each size particle in soil is the particle size distribution. Do you think this is a good way to determine particle size distribution? Why or why not?
State whether your hypothesis was supported or disproved, and then explain why it was supported or disproved using your data. Summarize your observations and answer one or more of the following questions: How does this lab relate to what I have been learning? How does this experiment relate to things I have seen in my own life? What could be done to improve this experiment?
Heading and title
Hypothesis, procedure, data, post lab, and conclusion section headings
Each section is thorough and complete
Lab report typed into a word processor (such as Microsoft Word) and saved
Typed lab document uploaded to Ignitia and submitted
1. I noticed that the soil particles settled out of the water with the larger, heavier particles settling out first and on the bottom, and each layer has smaller and lighter particles in it.
2. Sand settled on the bottom because they are heavier and have more mass than the smaller particles such as silt and clay.
3. Yes, this is a good way to determine particle size distribution. The method used in the experiment allows for the separation of soil particles based on their size and weight, which is a good indicator of their distribution in the soil sample.
4. The results in this experiment may look different when done in different locations because the particle size distribution of soil can vary depending on the location, climate, and geology of the area. Soils in different locations may have different compositions, including different amounts of sand, silt, and clay, which can affect the results of the experiment. Additionally, the sedimentation rate of the particles can also be influenced by factors such as the temperature, the presence of organic matter, and the presence of clay minerals, which can further affect the results.
How many milliliters of sterile water should be added to 125 ml of sucrose so the resultant solution is a 4% solution?.
Answer:
Explanation:
:
4. A physician asks the pharmacy to prepare 0.5 L of a 1:5000 epinephrine solution. The available solution is 1:1000. How many milliliters of sterile water should be added to 125 mL of sucrose so the resultant solution is a 4% solution?
A:
a. 21.5 mL b. 50 mL c. 3125 mL d. 31.25 mL
What happens to the concentration of reactants at equilibrium?
The concentration of reactants at equilibrium is equal to the concentration of the product.
At the equilibrium, the concentration of the reactants and the products will be exactly equal. The Number of the reactants reacting in the chemical reaction will be equal to the number of the products formed in the chemical reaction.
If the concentration of the reactants decreases , the position of the equilibrium moves to the left side , that is at the reactant side. The equilibrium defined as the state of the balance. Chemical equilibrium can be expressed as the state of the system in which the reactant concentration and the product concentration do not change.
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A gas with a volume of 650 mL and a pressure of 680 mm Hg is allowed to expand to a volume of 1200 mL. What is the new pressure of the gas in mm Hg?
Answer:
The new pressure will be
1000 L
how to find relative error of molar mass of oxygen gas
To find relative error of molar mass of oxygen gas Calculate the difference between the measured value and the true value, and divide it by the true value and then multiply it by 100%.
Relative error of molar mass of oxygen gas can be calculated as follows:
Determine the true value of the molar mass of oxygen gas, which is the accepted standard value.
Measure the molar mass of a sample of oxygen gas using a suitable instrument such as a mass spectrometer.
Calculate the difference between the measured value and the true value, and divide it by the true value.
Multiply the result by 100% to obtain the relative error as a percentage.
The relative error is an expression of the accuracy of the measurement relative to the true value. A smaller relative error indicates a more accurate measurement. The relative error of molar mass measurements can be affected by several factors, including the quality of the equipment used, the accuracy of the measurement procedure, and the purity of the sample being analyzed.
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what is the concentration of a reactant after 22.0 s if the initial concentration is 0.150 m and the rate constant is 5.4 x 10⁻² s⁻¹?
The concentration of a reactant after [tex]\rm 22.0 s[/tex], given an initial concentration of 0.150 M and a rate constant of 5.4 x 10⁻² s⁻¹, is 0.0410 M.
Concentration of a solution is defined as the amount of solute present in a given amount of solvent or solution.
To find the concentration of a reactant after 22.0 s, we can use the following first-order rate law equation:
[tex]\rm ln\dfrac{([A]_t}{[A]_0)} = -kt[/tex]
Where,
[tex]\rm [A]_t[/tex] is the concentration of the reactant at time t,
[tex]\rm [A]_0[/tex] is the initial concentration of the reactant,
k is the rate constant, and t is the time elapsed.
Rearranging this equation, we get:
[tex]\rm [A]_t = [A]_0 \times e^{(-kt)}[/tex]
Plugging in the values, we get:
[tex]\rm [A]_t = 0.150\times e^{(-5.4 \times 10^{-2} \times 22.0)}[/tex]
= 0.0410 M
Therefore, 0.0410 M is the remaining concentration of the reactant after 22.0 s.
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a 0.20 m solution of an unknown weak acid has ph = 1.00. what is the ka value of this acid?
The dissociation constant of a weak acid with 0.2 molar concentration and ph =1 is 1.0x 10-8
Let take a weak acid HA dissociation of HA here
HA (aq) + H2O(l)⇌A−(aq) + H3O+(aq)
Given pH=1
As you know, the pH of the solution is defined as
pH=−log([H3O+])
we can write the equation as
log([H3O+]) = −pH
This is equivalent to
10log([H3O+]) =10−pH
which gets you
[H3O+] =10−pH
In your case, you will have
[H3O+] =10−1.0 = 1.0⋅10−1 M
Now, notice that every mole of HA that ionizes produces 1 mole of A−, the conjugate base of the acid, and 1 mole of hydronium cations.
This means that, at equilibrium, the solution has
[A−]=[H3O+] → produced in a 1:1 mole ratio
In your case, you have
[A−]=1.0⋅10−1M
This means that, at equilibrium, the concentration of the weak acid will be equal to
[HA]=[HA]initial−[H3O+]
In your case, you will have
[HA]=0.01 M−1.0⋅10−1M
[HA]=0.00999 M
By definition, the acid dissociation constant, Ka, will be equal to
Ka=[A−]⋅[H3O+] [HA]
Plug in your values to find
Ka=1.0⋅10−5M⋅1.0⋅10−5. M 0.00999M
Ka=1.001⋅10−8 M Ka=1⋅10−8
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