1. Consider the following: HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (liq) ∆H = -57.62 kJ/mol
If a 25.0 mL of 0.144 M HCl (aq) at 25oC is added to 20.0 mL of 0.132 M NaOH (aq) at 25oC, calculate the final temperature of the contents. Assume the volumes are additive and that the resulting salt water solution has a density of 1.04 g/mL with a specific heat capacity of 3.93 J/goC. Note that you will also need to determine the limiting reactant.

Answers

Answer 1

Answer:

25.82°C

Explanation:

Based on the reaction, 1 mole of HCl and 1 mole of NaOH reacts, that means the reaction is 1:1. The moles of each compound are:

Moles HCl:

0.025L * (0.144mol/L) = 0.0036 moles HCl

Moles NaOH:

0.020L * (0.132mol/L) = 0.00264 moles NaOH

Thus, moles of reaction are 0.00264 moles

The heat released in a calorimeter is obtained using the equation:

Q = m*c*ΔT

Where Q is heat released in the reaction:

0.00264 moles * (-57.62kJ/mol) = 0.1521kJ = 152.1J of reaction

m is mass of the solution:

25.0mL + 20.0mL = 45mL * (1.04g/mL) = 46.8g

c is specific heat of the solution:

3.93J/gºC

And ΔT is change in temperature.

Solving for ΔT:

Q /mc = ΔT

151.2J / 46.8g*3.93J°C = 0.82°C = ΔT = Final temperature - Initial temperature.

Final temperature = 0.82°C + 25°C =

25.82°C


Related Questions

Is a diamond a homogeneous or heterogeneous mixture?

Answers

Answer:

It's a heterogeneous mixture.

Explanation:

Diamond is made of just one element: carbon. Each carbon atom in diamond is connected to four other carbon atoms, in a crystal that extends on and on. There are other forms of pure carbon where the atoms are bonded differently, notably charcoal and graphite.

Answer:

It's a heterogeneous mixture.

Explanation:

Diamond is made of just one element: carbon.

How would you calculate an object's mechanical energy?
a. Add its kinetic and potential energies. b. Multiply its kinetic and potential energies.
c. Subtract its kinetic energy from its kinetic energy.
d. Subtract its potential energy from its kinetic energy.​

Answers

Answer:

You would add its kinetic and potential energies.

Explanation:

Hope this helps!! :)

Answer:

A) Add its kinetic and potential energies

Explanation:

I got it right on Edge 2022

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