1. A temperature unit is known as a

The visible spectrum is composed of red, orange,yellow,  green, blue, violet, indigo.

The visible spectrum refers to the portion of the electromagnetic spectrum that can be seen with the eyes. All other portions of the electromagnetic spectrum are invisible.

The question is incomplete as the details are missing. The visible spectrum is composed of red, orange,yellow,  green, blue, violet, indigo.

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For a mass m1 on the frictionless table, the speed m1 must rotate a with radius r if m2 is to remain hanging at rest is mathematically given as

[tex]v=\sqrt{m1/m2*xg}[/tex]

Generally, the equation for the Force  is mathematically given as

Fc=Fw

Therefore

[tex]\frac{m1v1}{x}=m2g[/tex]

[tex]v=\sqrt{m1/m2*xg}[/tex]

In conclusion,  if m2 is to remain hanging at rest the speed of ratio of m1 is calcuylated using

[tex]v=\sqrt{m1/m2*xg}[/tex]

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The value of the velocity for the mass m₁ on the frictionless table will be [tex]\rm v = \sqrt{\frac{m_1}{m_2 xg} }[/tex]. Velocity is a time-based component. Its unit is m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity.

The given data in the problem is

m is the mass

g is the acceleration of free fall =10m/sec²

v is the velocity

From the balancing equation of force the centripetal force is equal to the weight;

[tex]\rm F_c= m_2 g \\\\ \rm \frac{m_1v_1^2}{x} = m_2 g \\\\ v= \sqrt{\frac{m_1}{m_2xg} } \\\\[/tex]

Hence the value of the velocity for the mass m₁ on the frictionless table will be [tex]\rm v = \sqrt{\frac{m_1}{m_2 xg} }[/tex].

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Answer: 13%

Explanation: The reason this is 13 is because you can eat carlories and you can also be an amazing person 200 calories and 7 grams

Answer:

The energy of these two photons would be the same as long as their frequencies are the same (same color, assuming that the two bulbs emit at only one wavelength.)

Explanation:

The energy [tex]E[/tex] of a photon is proportional to its frequency [tex]f[/tex]. The constant of proportionality is Planck's Constant, [tex]h[/tex]. This proportionality is known as the Planck-Einstein Relation.

[tex]E = h\, f[/tex].

The color of a beam of visible light depends on the frequency of the light. Assume that the two bulbs in this question each emits light of only one frequency (rather than a mix of light of different frequencies and colors.) Let [tex]f_{1}[/tex] and [tex]f_{2}[/tex] denote the frequency of the light from each bulb.

If the color of the red light from the two bulbs is the same, those two bulbs must emit light at the same frequency: [tex]f_{1} = f_{2}[/tex].

Thus, by the Planck-Einstein Relation, the energy of a photon from each bulb would also be the same:

[tex]h\, f_{1} = h\, f_{2}[/tex].

Note that among these two bulbs, the brighter one appears brighter soley because it emits more photons per unit area in unit time. While the energy of each photon stays the same, the bulb releases more energy by emitting more of these photons.

The orientation with the largest magnetic torque on the dipole is Orientation B (See attached image).

The torque on the dipole is defined as:

τ = µ×B,

where B is the external magnetic field.

The magnitude of this torque is µB sinθ, where θ is the angle between B and µ

Magnetic Torque is highest when;

→     →

µ ⊥ β

That is when θ  = 90°. Hence B is the correct answer. Please see attached image.

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Answer:

b

Explanation:

Answer:

B. 240Ω

Explanation:

The formula between voltage, current and resistance is:

voltage = current × resistance

So resistance = voltage ÷ current

Therefore resistance = 120 ÷ 0.5

Resistance = 240Ω

Explanation:

Transverse wave

Longitudinal wave

Answer:

1.In dry cells, manganese dioxide acts as a ‘depolariser'.

In the depolarization process, the depolariser is used to remove hydrogen and doesn't allow the voltage to get reduced due to polarisation of the cell . Manganese oxide was used as a depolariser in Leclanché cell .

In zinc-carbon dry cell, the manganese dioxide takes in electrons as it is converted to Manganese III oxide (Mn2O3)

2.The fuse breaks the circuit if a fault in an appliance causes too much current flow. This protects the wiring and the appliance if something goes wrong. The fuse contains a piece of wire that melts easily. If the current going through the fuse is too great, the wire heats up until it melts and breaks the circuit.

Answer:

PV = nRT

Explanation:

The Ideal Gas Equation shows the relation between 4 factors :-

⇒ R is the molar gas constant included so they are equal to each other, without it, they would just be proportional

The equation :-

⇒ PV = nRT

The magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.

Given the data in the question;

Coulomb's law states "that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them".

It is expressed as;

[tex]F = k\frac{q_1q_2}{r^2}[/tex]

Here, [tex]q_1\ and\ q_2[/tex]  are the two electrical charges, r is the distance between them and k is the Coulomb constant (  [tex]k = 8.98755*10^9 kgm^3/s^2C^2[/tex])

To determine the electrical force between the two charges, we substitute our values into the expression above.

[tex]F = k\frac{q_1q_2}{r^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{(1C)(1C)}{(1m)^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{1C^2}{1m^2}\\\\F = 8.98755*10^9 kgm/s^2\\\\F = 8.98755*10^9 N[/tex]

Therefore, the magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.

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The magnitude of the electrical force between the two charges is 8.987×10⁹ N.

As per the coulomb's law,  the electrical force between any two charges separated by a distance of r is given by the formula,

[tex]F = k\dfrac{q_1q_2}{r^2}[/tex]

Given that the value of q₁ and q₂ is 1 coulomb, while the distance between them is 1 meter. Also, the value of k is 8.987×10⁹ N·m²·C⁻², therefore, the force can be written as,

[tex]F = k\dfrac{q_1q_2}{r^2}\\\\F = (8.987 \times 10^{9}) \times (\dfrac{1 \times 1}{1^2})\\\\F= 8.987 \times 10^{9}\rm\ N[/tex]

Hence, the magnitude of the electrical force between the two charges is 8.987×10⁹ N.

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Answer:

Ohm’s law states that the current flowing through a conductor is directly proportional to the potential difference ( Voltage ) between the terminals of the conductor, provided that, factors such as the temperature of the conductor is kept constant

V = IR, where R is the proportionality constant.

R = resistance (measured in ohms)

V = voltage (measured in volts)

I = current (measured in amps)

Answer:

Yes

Explanation:

Displacement is the distance from the starting point to the end point. If you live and die at the same place, you will have 0m as your displacement.

Answer:

C

Explanation:

true because c is the best answer

Answer: The answer is C. It is true because the two cities are at the same latitude.

Explanation:

Hi I was doing the same test are u in flvs lol I am too if you are!

Answer:

A

Explanation:

The endocrine system has all of the body's hormones it regulates the biological processes. For example it can help brain development, nervous system development, and it can regulate blood sugar. (This is the closest to A)

Answer:

Remember a few key things:

1.) Oil comes from plants, but also animals

2.) When heat lamps are done or useless, they go to landfills

3.) Things in landfills go back to the environment after a few years or even decades.

4.) Sometimes there are all-natural oils for heat lamps

Explanation:

wavelength = l

speed of wave = v

frequency = f

v = lf → f = v/l = 2.42 × 10⁴ ÷ 1.1 = 2.2 × 10⁴ 1/s

T = 1/f = 1/ 2.2 × 10⁴ = 0.45 × 10 -⁴ s

The frequency of the sound wave produced from the drum is the speed divided by the wavelength. The frequency of the wave 22 kHz.

Frequency of a wave is the number of wave cycles per unit time. Frequency of a wave is directly proportional to the energy and inversely proportional to the wavelength.

The relation between speed of the wave c, wavelength and frequency of the wave can be written as follows:

c = νλ.

Given speed of the sound wave produced from the drum = 2.42 × 10⁴ m/s

wavelength λ = 110 cm = 1.1 m

The frequency of the sound wave  = speed/wavelength

ν = 2.42 × 10⁴ m/s / 1.1 m = 22000 Hz or 22 kHz.

Time period = 1/frequency

T = 1/ 22000 = 4.45× 10⁻⁵ seconds.

Therefore, the frequency of the wave is 22 kHz and time period of  4.45× 10⁻⁵ seconds.

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Answer:

Temporary? You have two options

If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).

If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).

Either way, the electron cloud will migrate towards the right side of the of your sphere.

Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.

Answer:

-18,750N

Explanation:

90x1000

-------------

3600

u=25m/s

v=0m/s

v^2=u^2+2as

v=0

=625+(2×a×20)

625+40a

-625=40a

a= -15.625 m/s^2

F=ma

=(1200)(-15.625)

= -18,750N

6.21 cm

where

Given:

solving step-wise:

[tex]\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}[/tex]

[tex]\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}[/tex]

[tex]\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}[/tex]

[tex]\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }[/tex]

[tex]\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2[/tex]

[tex]\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8[/tex]

[tex]\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m[/tex]

[tex]\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm[/tex]

[tex]\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm[/tex]             { rounded to nearest hundredth }

Let's see

[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\rightarrowtail 0.5=2\pi \sqrt{\dfrac{l}{9.8}}[/tex]

[tex]\\ \rm\rightarrowtail 0.783=\pi \sqrt{l}[/tex]

[tex]\\ \rm\rightarrowtail 0.2494=\sqrt{l}[/tex]

[tex]\\ \rm\rightarrowtail \ell=0.0622m[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{4}{9.8}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi(0.63887)[/tex]

[tex]\\ \rm\rightarrowtail T=1.27774\pi [/tex]

[tex]\\ \rm\rightarrowtail T=4.012s[/tex]

Answer:

F t = m Δv         impulse delivered = change in momentum

Δv = 100 * .1 / .5 = 20 m/s     original speed of puck

KE = 1/2 m v^2 = .5 * 20^2 / 2 = 100 J     initial KE of puck

E = μ m g d        energy lost by puck

Ff = μ m g = m a      deceleration of puck due to friction

a = μ  g = 9.8 * .2 = 1.96 m/s^2

v2 = a t + v1 = -1.96 * 4 + 20 = 12.2 m/s     speed of puck on striking box

m v2 = M V       conservation of momentum when puck strikes box

V = m v2 / M = 12.2 * .5 / .8 = 7.63 m/s     speed of box after collision

KE = 1/2 M V^2 = .8 * 7.63^2 / 2 = 23.3 J     KE of box after collision

KE = μ M g d     energy lost by box in sliding distance d

d = 23.3 / (.3 * .8 * 9.8) = 9.91 m     distance box slides

Explanation:

work = Force×distance

Force in this question is equal to the weight (force of gravity)

work = 1 × 1 = 1 J

Jole is the unit of work

Answer:

we'll use the electric field formula. ı wrote the formula in the photo.

Explanation:

The electric field formula is obtained by multiplying force and charge. When you apply this process I mentioned, you will find an electric field. then it is to write the given values and find the result. achievements.

At the distance for which the electric field produced by a charge of -15 μc have a magnitude equal to 8. 7×104n/c is 3.93 meters.

Electric force is the force of attraction of repulsion between two bodies.

According to the Coulombs law, the force of attraction of repulsion between charged two bodies is directly proportional to the product of charges of them and inversely proportional to the square of distance between them.

It can be given as,

[tex]F=k\dfrac{Q}{r^2}[/tex]

Here, (k) is the coulombs constant,  (Q) is the charges and (r) is the distance between the two charges.

The charge of -15 μc have a magnitude equal to 8. 7×104n/c. Put this value in the above formula,

[tex]8.7\times10^4=(8.98\times10^{9})\dfrac{15\times10^{-6}}{r^2}\\r=3.93\rm\; m[/tex]

Thus, at the distance for which the electric field produced by a charge of -15 μc have a magnitude equal to 8. 7×104n/c is 3.93 meters.

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Explanation:

formation of compounds because the electric forces compel the atoms to attract each other and formed bonds which leads to the formation of chemical compounds. The attractive or repulsive interaction between any two charged bodies is known as an electric force so the attraction between two opposite charged atoms causes the formation of compounds so we can conclude that electric forces are important for the formation of compounds.

Answer:

The just-noticeable concept.

Explanation:

Answer:

a) 1500 j

b) 3000 j

c) 34.64 m/s

Explanation:

at halfway point 1/2 of the potential energy has been converted to kinetic energy

so 1 /2 P E =  1500 j

   it will still have the OTHER half of its PE     1500 j

c) PE will be entirely converted to KE when it is at the bottom

       KE = 1/2 m v^2

       3000 = 1/2 (5)(v^2)     show   v = 34.64 m/s

The temperature difference between the wooden wall is 16⁰C, and the heat current per square metre of the wall is 7,325 W/m².

The temperature difference between the wooden wall is calculated as follows;

[tex]\frac{dQ_A}{dt } = \frac{dQ_B}{dt} \\\\\frac{K_A \Delta T_A \times A}{L_A} = \frac{K_B \Delta T _B \times A}{L_B}\\\\\frac{K_A \Delta T_A }{L_A} = \frac{K_B \Delta T _B}{L_B}\\\\\frac{0.5 \times 20}{0.1} = \frac{0.125 \times \Delta T _B }{0.02} \\\\100 = 6.25\Delta T _B\\\\\Delta T _B = \frac{100}{6.25} \\\\\Delta T _B = 16 \ ^oC[/tex]

Q = KL(ΔT)

Q = 0.5 x 0.1 x (20 + 273)

Q = 14.65 W

QA = W/A

QA = (14.65)/A

QA = 14.65/0.002

QA = 7,325 W/m²

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[tex]\\ \rm\rightarrowtail \nu=\dfrac{1}{T}[/tex]

[tex]\\ \rm\rightarrowtail T=\dfrac{1}{\nu}[/tex]

[tex]\\ \rm\rightarrowtail T=\dfrac{1}{60}[/tex]

[tex]\\ \rm\rightarrowtail T=1.67\times 10^{-4}s[/tex]

[tex]\\ \rm\rightarrowtail T=16.7\times 10^{-3}s[/tex]

[tex]\\ \rm\rightarrowtail T=16.7ms[/tex]