1. A 500 g piece of silver at 250°C is submerged in 1000 g of water at 5°C to be cooled. Determine the
final temperature of the silver and water. Given Cwater = 4180 J/kg°C and Csilver = 240 J/kg°C.

Answers

Answer 1

Taking into account the definition of calorimetry,  the final temperature of the silver and water is 11.84 °C.

Calorimetry

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m. c is the specific heat substance. ΔT is the temperature variation.

Final temperature of the silver and water

In this case, you know:

For silver:Mass of silver= 500 g= 0.5 kg (being 1000 g= 1 kg)Initial temperature of silver= 250 °CFinal temperature of silver= ?Specific heat of silver= 240 [tex]\frac{J}{kgC}[/tex] For water:Mass of water = 1000 g= 1 kgInitial temperature of water= 5 ºCFinal temperature of water= ?Specific heat of water = 4180 [tex]\frac{J}{kgC}[/tex]

Replacing in the expression to calculate heat exchanges:

For silver: Qsilver= 240 [tex]\frac{J}{kgC}[/tex]× 0.5 kg× (Final temperature of silver - 250 C)

For water: Qwater= 4180 [tex]\frac{J}{kgC}[/tex] × 1 kg× (Final temperature of water - 5 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the silver gives up will be equal to the heat that the water receives. Therefore:

- Qsilver = + Qwater

And the final temperature of the silver is equal to the temperature of the water (Final temperature of silver= Final temperature of water= Final temperature). Then:

- 240 [tex]\frac{J}{kgC}[/tex]× 0.5 kg× (Final temperature - 250 C)= 4180 [tex]\frac{J}{kgC}[/tex] × 1 kg× (Final temperature - 5 C)

Solving:

- 120 [tex]\frac{J}{C}[/tex]× (Final temperature - 250 C)= 4180 [tex]\frac{J}{C}[/tex]× (Final temperature - 5 C)

120 [tex]\frac{J}{C}[/tex]× (250 C - Final temperature) = 4180 [tex]\frac{J}{C}[/tex]× (Final temperature - 5 C)

120 [tex]\frac{J}{C}[/tex]×250 C - 120 [tex]\frac{J}{C}[/tex]×Final temperature = 4180 [tex]\frac{J}{C}[/tex]×Final temperature - 4180 [tex]\frac{J}{C}[/tex]×5 C

30,000 J - 120 [tex]\frac{J}{C}[/tex]×Final temperature = 4180 [tex]\frac{J}{C}[/tex]×Final temperature - 20,900 J

50,900 J= 4300 [tex]\frac{J}{C}[/tex]×Final temperature

50,900 J÷ 4300 [tex]\frac{J}{C}[/tex]= Final temperature

11.84 °C= Final temperature

Finally,  the final temperature of the silver and water is 11.84 °C.

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Related Questions

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Answers

Answer:

6km

Explanation:

3hours X 2km = 6 kilometres

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That looks like photosynthesis to me and I think that should be an endothermic reaction because it requires energy.

Discuss how the motion of the stunt cyclist relates to the forces acting on the stunt cyclist during the collision

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Answer:

hello your question is incomplete hence I will give you a general answer on how a stunt cyclist performs his stunts successfully

answer ;

The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.

In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

[tex]V_{min} = \sqrt{\frac{r.g}{u} }[/tex]

Explanation:

The stunt cyclist trying to perform some sort of stunt with the bicycle will be faced with some forces like the static fiction between the tires of the bicycle and wall and also a centripetal force.

In order to overcome the centripetal force the minimal grip of the bicycle must be equal to the weight and the speed at which the cyclist must go can be represented as :

[tex]V_{min} = \sqrt{\frac{r.g}{u} }[/tex]

where ; r = radius of the tunnel where the stunt is to be performed

            g = gravitational speed

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On planet Q, g = 2.24 m/s2. If the mass of planet Q is 8.96
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(m/kg))
a
8.95 x 1032 m
b 5.17 x 10 m
C 1.26 108 m
d 9.23 x 1024 m
e
4.72 x 106 m

Answers

Answer:

5.17 x 10^5

Explanation

The correct answer is (b) [tex]5.17*10^{5}m[/tex]

Let us consider an object of mass m on the planet Q.

On planet Q, let the acceleration due to gravity be g = 2.24 m/[tex]s^{2}[/tex]

Mass of the planet is M = [tex]8.96*10^{21} kg[/tex]

Let its radius be R

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Gravitational Force acting on the object:

[tex]mg=\frac{GMm}{R^{2} }[/tex]

[tex]R=\sqrt{\frac{GM}{g} } \\R=\sqrt{\frac{6.67*10^{-11}*8.96*10^{21} }{2.24} }\\R=5.17*10^{5} m[/tex] is the radius of the planet Q.

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what's 4 x 5
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4 x 5 is equal to 20. Use a calculator it’s way faster :))

Answer:

4 × 5 = 5 + 5 + 5 + 5 = 20

Explanation:

Pick one factor and add it.

Why is the overall charge of the atom neutral or zero?
A. The zero charge on the neutrons in the nucleus create a neutral atom.

B. The number of protons is equal to the number of electrons

C. Equal numbers of neutrons, protons, and electrons work together to keep the charge of the atom neutral or zero.

D. Atoms are not electrical and therefore have no charge.

Answers

Answer:

B

Explanation:

this is because the neutrons do not have a charge, the things that have charge in an atom are electrons and protons.

and in the nucleus of an atom, there are protons and neutrons so you can see that A is not the answer

if you see the periodic table, you will know that the number of electrons and protons are equal, so the charges cancel each other out, hence the charge of an atom will be neutral

let me give you a tip which I got from my teacher, never write there is no charge in the atom, this suggests that there is no protons or electrons.

instead, write, the it is neutral

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Answers

Answer:

Acceleration of one cyclist=[tex]2.67m/s^2[/tex]

Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.

Explanation:

We are given that

Initial velocity of one cyclist, u=0 m/s

Final velocity of one cyclist, v=8m/s

Time, t=3 s

Initial velocity of another cyclist, u'=0

Final velocity of another cyclist, v'=30m/s

Time, t'=8 s

We know that

Acceleration, [tex]a=\frac{v-u}{t}[/tex]

Using the formula

[tex]a=\frac{8-0}{3}=\frac{8}{3}=2.67m/s^2[/tex]

Acceleration of one cyclist=[tex]2.67m/s^2[/tex]

Acceleration of another cyclist, a'=[tex]\frac{30-0}{8}m/s^2[/tex]

Acceleration of another cyclist, a'=[tex]3.75m/s^2[/tex]

Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.

If a girl walks 6km due west changes directions and walk another 5km due north. Find her displacement in both magnitude and direction

Answers

Answer:

the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.

Explanation:

Given;

6km due west, and

5km due north

The magnitude of her displacement is calculated by forming a right angled triangle. The hypotenuse side of the triangle is the girl's displacement.

d² = 5² + 6²

d² = 25 + 36

d² = 61

d = √61

d = 7.81 m

The direction of the girl is calculated as;

[tex]tan \ \theta = \frac{6}{5} \\\\tan \ \theta = 1.2\\\\\theta = tan^{-1} (1.2)\\\\\theta = 50.2^0[/tex]

Therefore, the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.

PLS ANSWER FAST TIMED TEST WILL GIVE BRAINLY!!!!!!!!!


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Answers

the answer would be true

Answer:

The answer iis true

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It is much easier to carry your backpack when it is empty rather than when it's full of textbooks (or soaked from the rain).

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Answers

Answer:

V=14

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A 2 kg ball is thrown down with 50J of energy from a height of 10m, what is its velocity before it strikes the ground (neglect air resistance)

Answers

Answer:

Explanation:

Given the following data;

Mass = 2kg

Energy = 50J

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To find the speed

Kinetic energy can be defined as the energy possessed by a body due to its motion.

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True

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I took the test

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Answers

Answer:

Explanation:

We shall find first the distance where electric field is E/4 .

Let the charge be Q and distance be d where electric field is E . From the coulomb's Law

E = k Q / d²

Let distance be d₁ where field is E/4

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Answer:

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Answer:

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The way they are used seems somewhat irrelevant.

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Answers

Lithium fluoride will be most soluble in water because it is most strongly ionic.

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Solubility is the amount of a substance that dissolves in a given volume of solvent at a particular temperature.

Solubility is affected by:

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Answer:

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Explanation: hope this helps

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Answer:

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Answer:

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What is the net force in this image?


a
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e
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Answers

Answer:

4000N left

Explanation:

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6000N-2000N

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Answers

some knee pads for soccer

The effect of collision during a soccer game can be minimized by wearing a shin protection gear called the shin guard.

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As for football, the most vulnerable part of the body which is usually prone to damage during collision is the shin or knee.

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Answer: B) Frequency

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