0.525 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store for $20.00 plus 6.00% TAX. The cannon emits protons at a speed of 0.741 c with respect to the ship.

What is the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction?

0.911 ANS

What is the velocity of the protons in the resting frame when the cannon is shot in the backward direction? (Use positive sign for the forward direction, and negative for the backward direction.)

Answer:

k(t) =  (sin3, cos3, 2) + [(t - 1)(cos3, -3sin3, 7)]

Step-by-step explanation:

For a path r(t), the general equation k(t) of its tangent line at a specified point r(t₀) is given by;

k(t) = r(t₀) + r'(t₀) [t - t₀]            -----------------(i)

Where

r'(t) is the first derivative of the path r(t) at a given value of t.

From the question:

r(t) =  (sin3t, cos3t, 2[tex]t^{7/2}[/tex]) and t₀ = 1

=> r(1) = (sin3, cos3, 2) at t₀ = 1

Find the first derivative component-wise of r(t) to get r'(t)

∴ r'(t) = (cos3t, -3sin3t, 7[tex]t^{5/2}[/tex])

=>r'(1) = (cos3, -3sin3, 7)

Now, at t₀ = 1, equation (i) becomes;

k(t) = r(1) + [ r'(1) (t-1)]    [substitute the necessary values]

k(t) =  (sin3, cos3, 2) + [(t - 1)(cos3, -3sin3, 7)]

Answer:

12

Step-by-step explanation:

$42.00/($3.50 per gallon) = 12 gallons

Answer:

81

Step-by-step explanation:

Given:

Simplifying:

Finding the value of:

Substituting x/y with 2/3:

Answer is 81

The value of j is equal to -4

In Algebra, the like terms are defined as the terms that contain the same variable which is raised to the same power. In algebraic like terms, only the numerical coefficients can vary. We can combine the like terms to simplify the algebraic expressions.

Given here: j - 1/3 = j/4 - 10/3

                   j-j/4    = -10/3+1/3

                     j    = -3/0.75

                     j=-4

Hence, The value of j is equal to -4

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Answer:

Perimeter = (8x-30)

Area=(X-5)(3x-10)

Step-by-step explanation:

Perimeter equation for solving is this

2(X-5+3x-10)=p

it is length plus width twice which will equal the perimeter

solving this out

2(4x-15)=p

8x-30=p

area equation for solving this is

(x-5)(3x-10)=a

I don’t know how to solve this one out but i hope the setup helps!

Answer:

8.5 =40

8+32=40

21÷3=7

21-14=7

21÷7=3

Step-by-step explanation:

The missing values are 5, 32, 3, 14, and 3 after using the arithmetic operation.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

It is given that:

8⋅______=40

8+______=40

21÷______=7

21−______=7

21⋅______=7

We can use the arithmetic operation to find the unknown values:

A number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56 etc. are the numbers.

8x5  = 40

8 + 32 = 40

21 ÷ 3 = 7

21 - 14 = 7

21 ÷ 3 = 7

Thus, the missing values are 5, 32, 3, 14, and 3 after using the arithmetic operation.

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Answer: Absolute minimum: f(-1) = -2[tex]\sqrt{6}[/tex]

              Absolute maximum: f([tex]\sqrt{12.5}[/tex]) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = [tex]t\sqrt{25-t^{2}}[/tex]

f'(t) = [tex]1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)[/tex]

f'(t) = [tex]\sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }[/tex]

f'(t) = [tex]\frac{25-2t^{2}}{\sqrt{25-t^{2}} }[/tex] = 0

For this function to be zero, only denominator must be zero:

[tex]25-2t^{2} = 0[/tex]

t = ±[tex]\sqrt{2.5}[/tex]

[tex]\sqrt{25-t^{2}}[/tex] ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = [tex]-\sqrt{2.5}[/tex] and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = [tex]t\sqrt{25-t^{2}}[/tex]

f(-1) = [tex]-1\sqrt{25-(-1)^{2}}[/tex]

f(-1) = [tex]-\sqrt{24}[/tex]

f(-1) = [tex]-2\sqrt{6}[/tex]

f([tex]\sqrt{12.5}[/tex]) = [tex]\sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}[/tex]

f([tex]\sqrt{12.5}[/tex]) = 12.5

f(5) = [tex]5\sqrt{25-5^{2}}[/tex]

f(5) = 0

Therefore, absolute maximum is f([tex]\sqrt{12.5}[/tex]) = 12.5 and absolute minimum is

f(-1) = [tex]-2\sqrt{6}[/tex].

Hello, please consider the following.

[tex]\begin{aligned}5(9x^2+9x+10) &= x(9x-40)\\&=9x^2-40x\end{aligned}\\\\<=> 45x^2+45x+50=9x^2-40x\\\\<=> (45-9)x^2+(45+40)x+50=0\\\\<=> 36x^2+85x+50=0[/tex]

We can estimate the discriminant, and then, the solutions and we take the largest one.

[tex]\Delta=b^2-4ac=85^2-4*36*50=25=5^2\\\\x_1=\dfrac{-85-5}{2*36}=\dfrac{-18*5}{18*4}=\dfrac{-5}{4}\\\\x_2=\dfrac{-85+5}{2*36}=\dfrac{-80}{72}=\dfrac{-8*10}{8*9}=\boxed{\dfrac{-10}{9}}[/tex]

Thank you

Answer:   C. (5, -2)

Step-by-step explanation:

Graph each equation:

Equation 1: y < (1/2)x - 3 -->  m = (1/2)  b = -3,   dashed line,   shaded below

Equation 2: y > -2x + 6 -->  m = -2  b = 6,   dashed line,   shaded above

or  plug the values into the equations.  It must be TRUE for both equations:

               y < (1/2)x - 3         y > -2x + 6

(7, -8)            True                   False

(2, -3)            True                   False

(5, -2)            True                   True           <-- This works!

(4, 1)             False                  True

Inequalities help us to compare two unequal expressions. The correct option is C.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

For a point to be the solution of the system of inequalities, the point when substituted in the inequalities must satisfy both the given inequalities.

A. (7, -8)

y < 1/2x – 3

-8 < (1/2)7 - 3

-8 < 0.5

y + 2x > 6

-8 + 2(7) > 6

-8 + 14 > 6

6 > 6

Since the second inequality is not satisfied, therefore, the given point is not the solution.

B. (2, -3)

y < 1/2x – 3

-3 < (1/2)2 - 3

-3 < -2

y + 2x > 6

-3 + 2(2) > 6

-3 + 4 > 6

1 > 6

Since the second inequality is not satisfied, therefore, the given point is not the solution.

C. (5, -2)

y < 1/2x – 3

-2 < (1/2)5 - 3

-3 < -2

y + 2x > 6

-2 + 2(5) > 6

-2 + 10 > 6

8 > 6

Since both the inequality are satisfied, therefore, the given point is the solution.

D. (4, 1)

y < 1/2x – 3

1 < (1/2)4 - 3

1 < -1

Since the first inequality is not satisfied, therefore, the given point is not the solution.

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Answer:   2

Step-by-step explanation:

You only need to evaluate at the limit point.

f(x) = 4 - x  ; x ≠ 2

Consider the solution if x = 2 (because the limit is x → 2)

                                          f(2) = 4 - (2)

                                                =   2

We know that f(x) = 0  ; x = 2

                                         f(2) = 0

but we are looking for the y- value it approaches - not the y-value it is.

Look at the graph.  You will see that as x gets closer and closer to 2, the y-value gets closer and closer to 2.  This is the limit.

Step-by-step explanation:

Hey, there!

Here,

[tex] = 4 {x}^{2} - 4x + 1[/tex]

[tex]or ,\: ( {2x)}^{2} - 2.2x .1 + 1[/tex]

[tex]or ,\: ( {2x - 1)}^{2} [/tex]

We got this because,

[tex]( {2x - y)}^{2} = 4 {x}^{2} - 4x + 1[/tex]

By using formula,

[tex]( {x - y)}^{2} = {x}^{2} - 2xy + 1[/tex]

Hope it helps..

Answer: (x+-0.5)²=0

Step-by-step explanation:

4x²-4x+1=0

(2x-1)²=0 ⇔ completing the square

--------------------------------------------

since the question asked for the x should be 1, then we should divide 2x by 2 so to get rid of the 2 in front of the x.

this will change the original equation into: (x+(-0.5))²=0

------------------------------------------------------------------------------------------------------------

You can also directly divide 4 from 4x²-4x+1=0 to get rid off the terms in front of x.

x²-x+0.25=0

(x-0.5)²=0

(x+(-0.5))²=0

Answer:

A.

Step-by-step explanation:

A quadrilateral is simply a shape with 4 sides, therefore it does not HAVE to be 3-D.

Answer:

Quadrilateral.

Step-by-step explanation:

A quadrilateral is a 2d shape not 3d.

Answer:

D. [tex] 192 cm^2 [/tex]

Step-by-step explanation:

The net of the pyramid is made up of 1 square base and 4 triangles

Surface area of the pyramid = area of square + 4(area of square)

[tex] S.A = (s^2)+ 4(\frac{1}{2}bh) [/tex]

Where,

s = 8

b = 8

h = 8

[tex] S.A = (8^2)+ 4(\frac{1}{2}*8*8) [/tex]

[tex] S.A = 64+ 4(32) [/tex]

[tex] S.A = 64+ 128 [/tex]

[tex] S.A = 192 cm^2 [/tex]

192 cm^2

Step-by-step explanation:

base = 8 x 8 = 64

1 triangle = 1/2 x 8 x 8 = 32

32 x 4 = 128

128+64 = 192 cm^2

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

Hence the approximate value of x₂ is 7.9156

Answer:

To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

Step-by-step explanation:

The area of any quadrilateral can be determined by multiplying the length of its base by its height. Since we know the shape here is square, we know that all sides are of equal length. From this we can work backwards by taking the square root of the area to find the length of one side. hope this helps you :)

Answer:

The range of the function [tex]f(x) = -|3\cdot x+3|[/tex] is every positive real numbers plus zero.

Step-by-step explanation:

According to definition of the absolute value, the range of absolute value covers positive real numbers or zero. A linear function is a continuous function, which means the existence of an image for every element from domain. The negative sign transforms the original range to all negative real numbers plus zero.

Hence, the range of the function [tex]f(x) = -|3\cdot x+3|[/tex] is every positive real numbers plus zero.

Answer:

5.75 L

Step-by-step explanation:

2(1500mL + 375mL + 1L)

=2(1875mL + 1L)

=2(1.875L + 1L)

=2(2.875)

=5.75

The recipe will yield 5.75 liters (L) of punch when doubled.

To find the total volume of punch that the recipe will yield if doubled, we need to add the amounts of each ingredient and then multiply by 2.

Original recipe:

Fruit punch: 1,500 mL

Pineapple juice: 375 mL

Ginger ale: 1,000 mL (since 1 L = 1,000 mL)

Total volume of punch in the original recipe:

= 1,500 mL + 375 mL + 1,000 mL

= 2,875 mL

Now, if we double the recipe, we need to multiply the total volume by 2:

Total volume of punch when doubled = 2×2,875 mL

= 5,750 mL

To convert this to liters (L), we divide by 1,000 since 1 liter is equal to 1,000 mL:

Total volume of punch when doubled = 5,750 mL / 1,000

= 5.75 L

Hence, the recipe will yield 5.75 liters (L) of punch when doubled.

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Answer:

x = ±8

Step-by-step explanation:

A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

[tex]r=\frac{ep}{1 \pm e*cos\theta}\\ \\[/tex]

From the question, the polar equation of the circle is:

[tex]r=\frac{8}{4+cos\theta}[/tex]

We have to make the equation to be in the form of [tex]r=\frac{ep}{1 \pm e*cos\theta}\\ \\[/tex]. Therefore:

[tex]r=\frac{8}{4+cos\theta}\\\\Multiply \ through\ numerator\ and\ denminator\ by\ \frac{1}{4}\\\\ r=\frac{8*\frac{1}{4} }{(4+cos\theta)*\frac{1}{4} }\\\\r=\frac{2}{4*\frac{1}{4} +cos\theta*\frac{1}{4}}\\ \\r=\frac{\frac{1}{4}*8}{1+\frac{1}{4}cos\theta}[/tex]

This means that the eccentricity (e) = 1/4 and the equation of the directrix is x = ±8

A: The probability of a number rolling less than 7 is 100% or 1 because a dice only has numbers 1,2,3,4,5, and 6. 1,2,3,4,5, and 6 are all less than 7 so you are guaranteed to roll a number less than 7.

B: The probability of a number rolling more than 7 is 0% or 0 because a dice only has numbers 1,2,3,4,5, and 6. 1,2,3,4,5, and 6 are all less than 7 so it's not possible to roll a number more than 7.

C: The probability of a number rolling to be a multiple of three is 33.33(repeating)% or 1/3. Out of 1,2,3,4,5, and 6, the multiples of 3 are, 3 and 6. 3 and 6 is two numbers out of six numbers. 2 out of 6 simplifies to 1 out of 3.

D: The probability of a number rolling to be less than 4 is 50% of 1/2. Out of the numbers, 1,2,3,4,5, and 6, only 1,2, and 3 are less than 4. 1,2, and 3 is three numbers out of six numbers. 3 out of 6 simplifies to 1 out of 2.

E: The probability of a number rolling to be an even number greater than 4 is 0.166(repeating) or 1/6. Out of the numbers, 1,2,3,4,5, and 6, 2,4, and 6 are even numbers. Out of 2,4, and 6, only 6 is greater than 4. 4 is one number out of 1,2,3,4,5, and 6 (six numbers).

F: The probability of a number rolling to be a number not less than 3 is 50% or 1/2. "Not less than" actually means greater than. In the numbers, 1,2,3,4,5, and 6, only 4,5, and 6 are greater than 3. 4,5, and 6 are three numbers. 3 out of 6 simplifies to 1 out of 2.

I don't really know the answer to the last question but anyways I hope this helped! ♡

❀ Have a good day! ❀

Step-by-step explanation:

A + B + C = 360

[2/3]A + B + [4/3]C = 360

[2/3]A + [4/3]B + C = 360

A + B + C = 360

We could extract from all of this that Cans A, B, C must have equal amount of paint inside in order to attain those conditions slated. Thus we could tell that the amount of paint in each can is 60L.

Answer:

A)60l

B)60l

Step-by-step explanation:

Answer:

i believe it is 1

Step-by-step explanation:

Answer:

the slope is 1

Step-by-step explanation:

rise/run

1/1 = 1

Answer:

a

Step-by-step explanation:

-21(-65)

= - 86

A

(0-21(6-71)

(-21-65)=-86

Answer:

Explained below.

Step-by-step explanation:

At the start of every month the price of gas started out at 100¢/gallon.

Then every day since, it has gone up 2¢/gallon.

The variables are denoted as follows:

d = the date

g = price of a gallon of gas

c = total price required to fill up my car, in cents.

(a)

The function that gives the price of gas on any given day of the month is:

g (d) = 100 + 2(d - 1)

The (d - 1) represent the number of times the price has gone up by 2¢/gallon.

(b)

The function that tells how much money it takes to fill up my car, as a function of the price of a gallon of gas is:

c (g) = 10 × g

Since the car takes 10 gallons of gas.

(c)

The composite function that gives the cost of filling up my car on any given day of the month is:

c (g (d)) = 10 × g (d)

            = 10 [100 + 2(d - 1)]

c (g (d)) = 1000 + 20 (d - 1)

(d)

On the 11th day the price of gas has increased by 2¢/gallon for the past 10 days.

Compute the total price it takes to fill up my car on the 11th of the month as follows:

c (g (d)) = 1000 + 20 (d - 1)

c (g (11)) = 1000 + 20 (11 - 1)

             = 1000 + (20 × 20)

             = 1000 + 400

             = 1400¢

Thus, the it takes to fill up my car on the 11th of the month is 1400¢.

(e)

The total price to fill the car on the nth day is 1040¢.

Compute the value of n as follows:

      c (g (d)) = 1000 + 20 (d - 1)

          1040 = 1000 + 20 (n - 1)

1040 - 1000 = 20 (n - 1)

              40 = 20 (n - 1)

          (n - 1) = 2

                 n = 3

Thus, the day on which it cost 1,040¢ to fill up the car is the 3rd day.

Answer:

(6, 0) is located on the x-axis

Explanation:

For a point to be on the x-axis, its y-value must equal 0. (6, 0) has an x-value of 6 and a y-value of 0.

"(0, 5) is located at the origin" is not true because the origin is at (0, 0).

"(0, 5) is located on the x-axis" is not true because its y-value is 5, not 0.

"(6, 0) is located at the origin" is not true because the origin is at (0, 0).

The (6, 0) is located on the x-axis option (C) is correct because the y-coordinate is zero on the x-axis.

It is defined as a representation of coordinates in a two-dimensional coordinate plane. It has a list of two elements in it, such as (x, y).

[tex]\rm Area = |\dfrac{(x_1y_2-y_1x_2)+(x_2y_3-y_2x_3)....+(x_ny_1-y_nx_1)}{2}|[/tex]

It is given that:

The points are (6, 0) and (0, 5).

After plotting on the coordinate plane,

For a point to be on the x-axis, its y-value must equal 0. (6, 0) has an x-value of 6 and a y-value of 0.

"(6, 0) is located at the origin" is not true because the origin is at (0, 0).

Thus, the (6, 0) is located on the x-axis option (C) is correct because the y-coordinate is zero on the x-axis.

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Answer:

[tex] \frac{1}{5} [/tex]

Step-by-step explanation:

[tex]0.2 \times \frac{10}{10} = \frac{2}{10} = \frac{1}{5} [/tex]

This number can't be written as a mixed number since it is proper fraction.

It's numerator is less than it's denominator.

Hope this helps ;) ❤❤❤

I prefer solving quadratic equations with the quadratic formula. The formula is great for solving any equations like ones that factoring can’t. It is also easy to memorize and type in and check with a calculator.

I always prefer quadratic formula as compared to factoring or completing the square to solve a quadratic equation.

"A quadratic equation is an algebraic equation of the second degree in 'x'. The quadratic equation in its standard form is ax² + bx + c = 0, where 'a' and 'b' are the coefficients, 'x' is the variable, and 'c' is the constant term."

In order to solve a quadratic equation, I always prefer quadratic formula as compared to the other methods.

In many cases, a quadratic equation can not be converted into a square or into factors.

Therefore, quadratic formula is the only method to solve all type of quadratic equation.

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Answer:

[See Below]

Step-by-step explanation:

Multiply 7 by 5.

*35

Now add n to it.

*35 + n

Step-by-step explanation:

Both of them had $x

Later

Jensen=x-64

Raju=x-148

Jensen=3*Raju

x-64=3(x-148)

x-64=3x-444

3x-x=444-64

2x=380

x=$190